Re: Document boosting troubles
Hi, > One problem down, two left! =) bf ==> bq did the trick, thanks. Now at > least if I can't get the DIH solution working I don't have to tack that on > every query string. > I would really recommend to use a boost function. If your rank will change in future implementations, you do not need to redefine the bq. Besides that, I think this is not only more comfortable, but also scales better. The bq-param is more for things like "boost this category" or "boost docs of an advertisement campaign" or something like that. I am not sure, since I never worked with the DIH this way, but - from my logic - the problem could be, that you do not return the row, right? If you don't, try it again when return row was added to your sourcecode. Otherwise, I can't help you, since there are no more codeexamples available at the mailing list (from what I have seen). Maybe this mailing-list topic helps you: http://lucene.472066.n3.nabble.com/Using-DIH-s-special-commands-Help-needed-td475695.html#a475695 Using DIHs special commands Help needed . There are some suggestions,... however, it seems like he wasn't able to solve the problem. > And still can't figure out what I need to do with my dismax querying to > get scores for quality of match. > I don't really understand what you mean. Can you explain it a little bit more? What, except the $docBoost, does not work as it should do? Kind regards - Mitch -- View this message in context: http://lucene.472066.n3.nabble.com/Document-boosting-troubles-tp902982p904129.html Sent from the Solr - User mailing list archive at Nabble.com.
Re: Document boosting troubles
One problem down, two left! =) bf ==> bq did the trick, thanks. Now at
least if I can't get the DIH solution working I don't have to tack that on
every query string.
Taking the quotes away from $docBoost results in a syntax error. Needs to
be quoted.
Changed it up to this and still no luck
var rank = row.get('rank');
switch (rank) {
case 1:
row.put("$docBoost",3.0);
break;
case 2:
row.put("$docBoost",2.6);
break;
case 3:
row.put("$docBoost",2.2);
break;
case 4:
row.put("$docBoost",1.8);
break;
case 5:
row.put("$docBoost",1.5);
break;
case 6:
row.put("$docBoost",1.2);
break;
case 7:
row.put("$docBoost",0.9);
break;
case 8:
row.put("$docBoost",0.7);
break;
case 9:
row.put("$docBoost",0.5);
break;
default:
row.put("$docBoost",0.1);
}
And still can't figure out what I need to do with my dismax querying to get
scores for quality of match. Thoughts?
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Re: Document boosting troubles
Sorry, I've overlooked your other question. > > rank:1^10.0 rank:2^9.0 rank:3^8.0 rank:4^7.0 rank:5^6.0 rank:6^5.0 > rank:7^4.0 rank:8^3.0 rank:9^2.0 > > This is wrong. You need to change "bf" to "bq". Bf -> boosting function Bq -> boosting query. -- View this message in context: http://lucene.472066.n3.nabble.com/Document-boosting-troubles-tp902982p903208.html Sent from the Solr - User mailing list archive at Nabble.com.
Re: Document boosting troubles
Hi,
first of all, are you sure that row.put('$docBoost',docBoostVal) is correct?
I think it should be row.put($docBoost,docBoostVal); - unfortunately I am
not sure.
Hm, I think, until you can solve the problem with the docBoosts itself, you
should use a functionQuery.
Use "div(1, rank)" as boost function (bf).
The higher the rank value, the smaller the result.
Hope this helps!
- Mitch
dbashford wrote:
>
> Brand new to this sort of thing so bear with me.
>
> For sake of simplicity, I've got a two field document, title and rank.
> Title gets searched on, rank has values from 1 to 10. 1 being highest.
> What I'd like to do is boost results of searches on title based on the
> documents rank.
>
> Because it's fairly cut and dry, I was hoping to do it during indexing. I
> have this in my DIH transformer..
>
> var docBoostVal = 0;
> switch (rank) {
> case '1':
> docBoostVal = 3.0;
> break;
> case '2':
> docBoostVal = 2.6;
> break;
> case '3':
> docBoostVal = 2.2;
> break;
> case '4':
> docBoostVal = 1.8;
> break;
> case '5':
> docBoostVal = 1.5;
> break;
> case '6':
> docBoostVal = 1.2;
> break;
> case '7':
> docBoostVal = 0.9;
> break;
> case '8':
> docBoostVal = 0.7;
> break;
> case '9':
> docBoostVal = 0.5;
> break;
> }
> row.put('$docBoost',docBoostVal);
>
> It's my understanding that with this, I can simply do the same /select
> queries I've been doing and expect documents to be boosted, but that
> doesn't seem to be happening because I'm seeing things like this in the
> results...
>
> {"title":"Some title 1",
> "rank":10,
> "score":0.11726039},
> {"title":"Some title 2",
> "rank":7,
> "score":0.11726039},
>
> Pretty much everything with the same score. Whatever I'm doing isn't
> making its way through. (To cover my bases I did try the case statement
> with integers rather than strings, same result)
>
>
>
>
>
> With that not working I started looking at other options. Starting
> playing with dismax.
>
> I'm able to add this to a query string a get results I'm somewhat
> expecting...
>
> bq=rank:1^3.0 rank:2^2.6 rank:3^2.2 rank:4^1.8 rank:5^1.5 rank:6^1.2
> rank:7^0.9 rank:8^0.7 rank:9^0.5
>
> ...but I guess I wasn't expecting it to ONLY rank based on those factors.
> That essentially gives me a sort by rank.
>
> Trying to be super inclusive with the search, so while I'm fiddling my
> mm=1<1. As expected, a q= like q=red door is returning everything that
> contains Red and door. But I was hoping that items that matched "red
> door" exactly would sort closer to the top. And if that exact match was a
> rank 7 that it's score wouldn't be exactly the same as all the other rank
> 7s? Ditto if I searched for "q=The Tales Of", anything possessing all 3
> terms would sort closer to the top...and possessing two terms behind
> them...and possessing 1 term behind them, and within those groups weight
> heavily on by rank.
>
> I think I understand that the score is based entirely on the boosts I
> provide...so how do I get something more like what I'm looking for?
>
>
>
>
> Along those lines, I initially had put something like this in my
> defaults...
>
>
> rank:1^10.0 rank:2^9.0 rank:3^8.0 rank:4^7.0 rank:5^6.0 rank:6^5.0
> rank:7^4.0 rank:8^3.0 rank:9^2.0
>
>
> ...but that was not working, queries fail with a syntax exception.
> Guessing this won't work?
>
>
>
> Thanks in advance for any help you can provide.
>
>
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Document boosting troubles
Brand new to this sort of thing so bear with me.
For sake of simplicity, I've got a two field document, title and rank.
Title gets searched on, rank has values from 1 to 10. 1 being highest.
What I'd like to do is boost results of searches on title based on the
documents rank.
Because it's fairly cut and dry, I was hoping to do it during indexing. I
have this in my DIH transformer..
var docBoostVal = 0;
switch (rank) {
case '1':
docBoostVal = 3.0;
break;
case '2':
docBoostVal = 2.6;
break;
case '3':
docBoostVal = 2.2;
break;
case '4':
docBoostVal = 1.8;
break;
case '5':
docBoostVal = 1.5;
break;
case '6':
docBoostVal = 1.2;
break;
case '7':
docBoostVal = 0.9;
break;
case '8':
docBoostVal = 0.7;
break;
case '9':
docBoostVal = 0.5;
break;
}
row.put('$docBoost',docBoostVal);
It's my understanding that with this, I can simply do the same /select
queries I've been doing and expect documents to be boosted, but that doesn't
seem to be happening because I'm seeing things like this in the results...
{"title":"Some title 1",
"rank":10,
"score":0.11726039},
{"title":"Some title 2",
"rank":7,
"score":0.11726039},
Pretty much everything with the same score. Whatever I'm doing isn't making
its way through. (To cover my bases I did try the case statement with
integers rather than strings, same result)
With that not working I started looking at other options. Starting playing
with dismax.
I'm able to add this to a query string a get results I'm somewhat
expecting...
bq=rank:1^3.0 rank:2^2.6 rank:3^2.2 rank:4^1.8 rank:5^1.5 rank:6^1.2
rank:7^0.9 rank:8^0.7 rank:9^0.5
...but I guess I wasn't expecting it to ONLY rank based on those factors.
That essentially gives me a sort by rank.
Trying to be super inclusive with the search, so while I'm fiddling my
mm=1<1. As expected, a q= like q=red door is returning everything that
contains Red and door. But I was hoping that items that matched "red door"
exactly would sort closer to the top. And if that exact match was a rank 7
that it's score wouldn't be exactly the same as all the other rank 7s?
Ditto if I searched for "q=The Tales Of", anything possessing all 3 terms
would sort closer to the top...and possessing two terms behind them...and
possessing 1 term behind them, and within those groups weight heavily on by
rank.
I think I understand that the score is based entirely on the boosts I
provide...so how do I get something more like what I'm looking for?
Along those lines, I initially had put something like this in my defaults...
rank:1^10.0 rank:2^9.0 rank:3^8.0 rank:4^7.0 rank:5^6.0 rank:6^5.0
rank:7^4.0 rank:8^3.0 rank:9^2.0
...but that was not working, queries fail with a syntax exception. Guessing
this won't work?
Thanks in advance for any help you can provide.
--
View this message in context:
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