Re: JSP pages giving out source code

2002-11-19 Thread Uma Maheswar
Hello,
Thanks for the reply. I am not the owner of the server. I have hosted my
site on some shared server. So, I do not have any admin previliages. How can
I use JK or JK2 or WARP. I have been given a directory as somename is the
root folder for my site. e.g  webapps/somename. I upload all my files here.
Can some one tell me in more detail how to prevent my jsp pages giving out
the code. How can I prevent this?

Thanks
Uma
http://www.javagalaxy.com


- Original Message -
From: Turner, John [EMAIL PROTECTED]
To: 'Tomcat Users List' [EMAIL PROTECTED]
Sent: Monday, November 18, 2002 8:53 PM
Subject: RE: JSP pages giving out source code



 Apache doesn't understand that *.jsp requests need to be sent to Tomcat.

 You need a connector (WARP, JK, or JK2), and if you already have one, it's
 misconfigured.

 John


  -Original Message-
  From: Uma Maheswar [mailto:[EMAIL PROTECTED]]
  Sent: Monday, November 18, 2002 10:17 AM
  To: Tomcat Users List
  Subject: JSP pages giving out source code
 
 
  Hello,
  Some of the links in my website to .jsp pages are giving out
  the source code
  and some or not. What is the reason?
 
  e.g http://www.javagalaxy.com/sss.jsp gives out source
  code (not true
  link)
  where as http://www.javagalaxy.com:8080/ss/s.jsp will work.
 
  How to correct this? Any one help.
 
  Uma
  http://www.javagalaxy.com
 
 
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JSP pages giving out source code

2002-11-18 Thread Uma Maheswar
Hello,
Some of the links in my website to .jsp pages are giving out the source code
and some or not. What is the reason?

e.g http://www.javagalaxy.com/sss.jsp gives out source code (not true
link)
where as http://www.javagalaxy.com:8080/ss/s.jsp will work.

How to correct this? Any one help.

Uma
http://www.javagalaxy.com


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Tomcat Problem

2002-10-05 Thread Uma Maheswar

Hello,
I cannot view the Tomcat Console. I am using Tomcat 4.0 on Win XP. Also, I
cannot start the Tomcat from
Start - Programmes - Apache Tomcat. I need to go to the Control Panel -
Admin Tools - Services and then start the Tomcat over there.

Can any one tell me what is wrong? I am also using JDK1.4.0

Thanks
Uma
Java Developer
http://www.javagalaxy.com



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Re: Tomcat Problem

2002-10-05 Thread Uma Maheswar

Hi Probst,
Sorry, I did that. Not helpful. Any other way?

Uma

- Original Message -
From: Andreas Probst [EMAIL PROTECTED]
To: Tomcat Users List [EMAIL PROTECTED]
Sent: Saturday, October 05, 2002 12:56 PM
Subject: Re: Tomcat Problem


 Hi Uma,

 it seems you installed Tomcat as a service. You could deinstall
 this service or set it to manual start. Then you should be able
 to start Tomcat manually from the script.

 On Sun, 29 Sep 2002 19:30:50 -0500 there was a message from
 Jacob Kjome (Subject: Re: Need Help ASAP w. Tomcat install!),
 where he also explained, how to install or deinstall the service
 from the command line.

 Andreas


 On 5 Oct 2002 at 7:54, Uma Maheswar wrote:

  Hello,
  I cannot view the Tomcat Console. I am using Tomcat 4.0 on Win XP. Also,
I
  cannot start the Tomcat from
  Start - Programmes - Apache Tomcat. I need to go to the Control Panel -
  Admin Tools - Services and then start the Tomcat over there.
 
  Can any one tell me what is wrong? I am also using JDK1.4.0
 
  Thanks
  Uma
  Java Developer
  http://www.javagalaxy.com
 
 
 
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Re: Tomcat Problem

2002-10-05 Thread Uma Maheswar

Hi Reynir,
I do not have any error message. If I need to start the Tomcat in my PC
running on Win XP, I need to go to Start - Control Panel - Admin Tools -
Services and then start the Tomcat. There is no other option for me than
this.

Now the Tomcat gets started if I do so. But I wanted to view its Console
(Black DOS like Window). How can I get this?

Thanks
Uma
http://www.javagalaxy.com


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Re: Tomcat Problem

2002-10-05 Thread Uma Maheswar

Hi Reynir,
I tried it, I got this messages

C:\PROGRA~1\Apache Tomcat 4.0\bincatalina run
Using CATALINA_BASE: ..
Using CATALINA_HOME: ..
Using CLASSPATH: ..\bin\bootstrap.jar;c:/j2sdk1.4.0/bin;\lib\tools.jar
Using JAVA_HOME: c:/j2sdk1.4.0/bin;
The system cannot find the path specified.
C:\PROGRA~1\Apache Tomcat 4.0\bin

But I dont see the console. My Tomcat is working when I type
http://localhost:8080 . Please suggest me.

Thanks
Uma



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Re: Tomcat Problem

2002-10-05 Thread Uma Maheswar

Reynir,
I tried this and it gave me some error messages. Can you suggest me now?

Uma


C:\PROGRA~1\Apache Tomcat 4.0\bincatalina run
Using CATALINA_BASE: ..
Using CATALINA_HOME: ..
Using CLASSPATH: ..\bin\bootstrap.jar;c:/j2sdk1.4.0/bin;\lib\tools.jar
Using JAVA_HOME: c:/j2sdk1.4.0/bin;
The system cannot find the path specified.
C:\PROGRA~1\Apache Tomcat 4.0\binset JAVA_HOME=C:\j2sdk1.4.0

C:\PROGRA~1\Apache Tomcat 4.0\bincatalina run
Using CATALINA_BASE: ..
Using CATALINA_HOME: ..
Using CLASSPATH: ..\bin\bootstrap.jar;C:\j2sdk1.4.0\lib\tools.jar
Using JAVA_HOME: C:\j2sdk1.4.0
ERROR reading ..\conf\server.xml
At Line 319 /Server/Service/Connector/
className=org.apache.catalina.connector.w
arp.WarpConnector port=8008 minProcessors=5 maxProcessors=75
enableLookups=true
acceptCount=10 debug=0

Catalina.start: java.lang.ClassNotFoundException:
org.apache.catalina.connector.
warp.WarpConnector
java.lang.ClassNotFoundException:
org.apache.catalina.connector.warp.WarpConnect
or
at java.net.URLClassLoader$1.run(URLClassLoader.java:198)
at java.security.AccessController.doPrivileged(Native Method)
at java.net.URLClassLoader.findClass(URLClassLoader.java:186)
at java.lang.ClassLoader.loadClass(ClassLoader.java:306)
at java.lang.ClassLoader.loadClass(ClassLoader.java:262)
at java.lang.ClassLoader.loadClassInternal(ClassLoader.java:322)
at java.lang.Class.forName0(Native Method)
at java.lang.Class.forName(Class.java:130)
at
org.apache.catalina.util.xml.ObjectCreate.start(XmlMapper.java:616)
at
org.apache.catalina.util.xml.XmlMapper.matchStart(XmlMapper.java:412)

at
org.apache.catalina.util.xml.XmlMapper.startElement(XmlMapper.java:91
)
at
org.xml.sax.helpers.XMLReaderAdapter.startElement(XMLReaderAdapter.ja
va:329)
at org.apache.crimson.parser.Parser2.maybeElement(Parser2.java:1490)
at org.apache.crimson.parser.Parser2.content(Parser2.java:1779)
at org.apache.crimson.parser.Parser2.maybeElement(Parser2.java:1507)
at org.apache.crimson.parser.Parser2.content(Parser2.java:1779)
at org.apache.crimson.parser.Parser2.maybeElement(Parser2.java:1507)
at org.apache.crimson.parser.Parser2.parseInternal(Parser2.java:500)
at org.apache.crimson.parser.Parser2.parse(Parser2.java:305)
at
org.apache.crimson.parser.XMLReaderImpl.parse(XMLReaderImpl.java:442)

at
org.xml.sax.helpers.XMLReaderAdapter.parse(XMLReaderAdapter.java:223)

at javax.xml.parsers.SAXParser.parse(SAXParser.java:314)
at javax.xml.parsers.SAXParser.parse(SAXParser.java:253)
at
org.apache.catalina.util.xml.XmlMapper.readXml(XmlMapper.java:228)
at org.apache.catalina.startup.Catalina.start(Catalina.java:725)
at org.apache.catalina.startup.Catalina.execute(Catalina.java:681)
at org.apache.catalina.startup.Catalina.process(Catalina.java:179)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at
sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.
java:39)
at
sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAcces
sorImpl.java:25)
at java.lang.reflect.Method.invoke(Method.java:324)
at org.apache.catalina.startup.Bootstrap.main(Bootstrap.java:243)
C:\PROGRA~1\Apache Tomcat 4.0\bin


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Re: Tomcat Problem

2002-10-05 Thread Uma Maheswar

Reynir,
I never changed the server.xml file. I dont know that stuff. Can you tell me
how to change WARP?

Thanks


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About WARP, HELP

2002-10-05 Thread Uma Maheswar

Can any one tell me about WARP? Please help me. My problem is listed below.

Thanks
Uma


 C:\PROGRA~1\Apache Tomcat 4.0\bincatalina run
 Using CATALINA_BASE: ..
 Using CATALINA_HOME: ..
 Using CLASSPATH:
 ..\bin\bootstrap.jar;c:/j2sdk1.4.0/bin;\lib\tools.jar
 Using JAVA_HOME: c:/j2sdk1.4.0/bin;
 The system cannot find the path specified.
 C:\PROGRA~1\Apache Tomcat 4.0\binset JAVA_HOME=C:\j2sdk1.4.0

 C:\PROGRA~1\Apache Tomcat 4.0\bincatalina run
 Using CATALINA_BASE: ..
 Using CATALINA_HOME: ..
 Using CLASSPATH: ..\bin\bootstrap.jar;C:\j2sdk1.4.0\lib\tools.jar
 Using JAVA_HOME: C:\j2sdk1.4.0
 ERROR reading ..\conf\server.xml
 At Line 319 /Server/Service/Connector/
 className=org.apache.catalina.connector.w
 arp.WarpConnector port=8008 minProcessors=5 maxProcessors=75
 enableLookups=true acceptCount=10 debug=0

 Catalina.start: java.lang.ClassNotFoundException:
 org.apache.catalina.connector. warp.WarpConnector
 java.lang.ClassNotFoundException:
 org.apache.catalina.connector.warp.WarpConnect
 or
 at java.net.URLClassLoader$1.run(URLClassLoader.java:198)
 at java.security.AccessController.doPrivileged(Native Method)
 at java.net.URLClassLoader.findClass(URLClassLoader.java:186)
 at java.lang.ClassLoader.loadClass(ClassLoader.java:306)
 at java.lang.ClassLoader.loadClass(ClassLoader.java:262)
 at
 java.lang.ClassLoader.loadClassInternal(ClassLoader.java:322)
 at java.lang.Class.forName0(Native Method)
 at java.lang.Class.forName(Class.java:130)
 at
 org.apache.catalina.util.xml.ObjectCreate.start(XmlMapper.java:616)
 at
 org.apache.catalina.util.xml.XmlMapper.matchStart(XmlMapper.java:412)

 at
 org.apache.catalina.util.xml.XmlMapper.startElement(XmlMapper.java:91
 )
 at
 org.xml.sax.helpers.XMLReaderAdapter.startElement(XMLReaderAdapter.ja
 va:329)
 at
 org.apache.crimson.parser.Parser2.maybeElement(Parser2.java:1490)
 at
 org.apache.crimson.parser.Parser2.content(Parser2.java:1779)
 at
 org.apache.crimson.parser.Parser2.maybeElement(Parser2.java:1507)
 at
 org.apache.crimson.parser.Parser2.content(Parser2.java:1779)
 at
 org.apache.crimson.parser.Parser2.maybeElement(Parser2.java:1507)
 at
 org.apache.crimson.parser.Parser2.parseInternal(Parser2.java:500)
 at org.apache.crimson.parser.Parser2.parse(Parser2.java:305)
 at
 org.apache.crimson.parser.XMLReaderImpl.parse(XMLReaderImpl.java:442)

 at
 org.xml.sax.helpers.XMLReaderAdapter.parse(XMLReaderAdapter.java:223)

 at javax.xml.parsers.SAXParser.parse(SAXParser.java:314)
 at javax.xml.parsers.SAXParser.parse(SAXParser.java:253)
 at
 org.apache.catalina.util.xml.XmlMapper.readXml(XmlMapper.java:228)
 at
 org.apache.catalina.startup.Catalina.start(Catalina.java:725)
 at
 org.apache.catalina.startup.Catalina.execute(Catalina.java:681)
 at
 org.apache.catalina.startup.Catalina.process(Catalina.java:179)
 at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
 at
 sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.
 java:39)
 at
 sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAcces
 sorImpl.java:25)
 at java.lang.reflect.Method.invoke(Method.java:324)
 at
 org.apache.catalina.startup.Bootstrap.main(Bootstrap.java:243)
 C:\PROGRA~1\Apache Tomcat 4.0\bin


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Re: About WARP, HELP

2002-10-05 Thread Uma Maheswar

Hi,
Its already same in the server.xml file. I am attaching the file for your
review. Please check it

Uma



!-- Example Server Configuration File --
!-- Note that component elements are nested corresponding to their
 parent-child relationships with each other --

!-- A Server is a singleton element that represents the entire JVM,
 which may contain one or more Service instances.  The Server
 listens for a shutdown command on the indicated port.

 Note:  A Server is not itself a Container, so you may not
 define subcomponents such as Valves or Loggers at this level.
 --

Server port=8005 shutdown=SHUTDOWN debug=0


  !-- A Service is a collection of one or more Connectors that share
   a single Container (and therefore the web applications visible
   within that Container).  Normally, that Container is an Engine,
   but this is not required.

   Note:  A Service is not itself a Container, so you may not
   define subcomponents such as Valves or Loggers at this level.
   --

  !-- Define the Tomcat Stand-Alone Service --
  Service name=Tomcat-Standalone

!-- A Connector represents an endpoint by which requests are received
 and responses are returned.  Each Connector passes requests on to the
 associated Container (normally an Engine) for processing.

 By default, a non-SSL HTTP/1.1 Connector is established on port 8080.
 You can also enable an SSL HTTP/1.1 Connector on port 8443 by
 following the instructions below and uncommenting the second Connector
 entry.  SSL support requires the following steps (see the SSL Config
 HOWTO in the Tomcat 4.0 documentation bundle for more detailed
 instructions):
 * Download and install JSSE 1.0.2 or later, and put the JAR files
   into $JAVA_HOME/jre/lib/ext.
 * Execute:
 %JAVA_HOME%\bin\keytool -genkey -alias tomcat -keyalg RSA (Windows)
 $JAVA_HOME/bin/keytool -genkey -alias tomcat -keyalg RSA  (Unix)
   with a password value of changeit for both the certificate and
   the keystore itself.

 By default, DNS lookups are enabled when a web application calls
 request.getRemoteHost().  This can have an adverse impact on
 performance, so you can disable it by setting the
 enableLookups attribute to false.  When DNS lookups are disabled,
 request.getRemoteHost() will return the String version of the
 IP address of the remote client.
--

!-- Define a non-SSL HTTP/1.1 Connector on port 8080 --
Connector className=org.apache.catalina.connector.http.HttpConnector
   port=8080 minProcessors=5 maxProcessors=75
   enableLookups=true redirectPort=8443
   acceptCount=10 debug=0 connectionTimeout=6/
!-- Note : To disable connection timeouts, set connectionTimeout value 
 to -1 --

!-- Define an SSL HTTP/1.1 Connector on port 8443 --
!--
Connector className=org.apache.catalina.connector.http.HttpConnector
   port=8443 minProcessors=5 maxProcessors=75
   enableLookups=true
	   acceptCount=10 debug=0 scheme=https secure=true
  Factory className=org.apache.catalina.net.SSLServerSocketFactory
   clientAuth=false protocol=TLS/
/Connector
--

!-- Define an AJP 1.3 Connector on port 8009 --
!--
Connector className=org.apache.ajp.tomcat4.Ajp13Connector
   port=8009 minProcessors=5 maxProcessors=75
   acceptCount=10 debug=0/
--

!-- Define a Proxied HTTP/1.1 Connector on port 8081 --
!-- See proxy documentation for more information about using this. --
!--
Connector className=org.apache.catalina.connector.http.HttpConnector
   port=8081 minProcessors=5 maxProcessors=75
   enableLookups=true
   acceptCount=10 debug=0 connectionTimeout=6
   proxyPort=80/
--

!-- Define a non-SSL HTTP/1.0 Test Connector on port 8082 --
!--
Connector className=org.apache.catalina.connector.http10.HttpConnector
   port=8082 minProcessors=5 maxProcessors=75
   enableLookups=true redirectPort=8443
   acceptCount=10 debug=0/
--

!-- An Engine represents the entry point (within Catalina) that processes
 every request.  The Engine implementation for Tomcat stand alone
 analyzes the HTTP headers included with the request, and passes them
 on to the appropriate Host (virtual host). --

!-- Define the top level container in our container hierarchy --
Engine name=Standalone defaultHost=localhost debug=0

  !-- The request dumper valve dumps useful debugging information about
   the request headers and cookies that were received, and the response
   headers and cookies that were sent, for all requests received by
   this instance of Tomcat.  If you care only 

Re: About WARP, HELP

2002-10-05 Thread Uma Maheswar

George,
Then which server.xml file is this taking? I got this file from
tomcat/conf/server.xml. Please advice.

Uma


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Cannot view the console

2002-10-04 Thread Uma Maheswar

Hello,
I cannot view the Tomcat Console. I am using Tomcat 4.0 on Win XP. Also, I
cannot start the Tomcat from
Start - Programmes - Apache Tomcat. I need to go to the Control Panel -
Admin Tools - Services and then start the Tomcat over there.

Can any one tell me what is wrong? I am also using JDK1.4.0

Thanks
Uma
Java Developer
http://www.javagalaxy.com


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Writing beans

2002-03-06 Thread Uma Maheswar

Hi,
I need help writing a bean inside my JSP programme. I am also attaching my JSP 
programme, please check it and do the need ful changes.


% page 
import=java.sql.*,java.io.*,javax.servlet.*,javax.servlet.http.*,java.util.* %

html
%!
 String iam,seeking,lookingfor,firstname,lastname,address,city,state,country,email;
 String userid,password1,password2,newsletter,offers,totdate;
 int slno,pincode,phone,count=0,month,date,year;
 Connection con = null;
 Statement st,st1;
 ResultSet rs,rs1;
 Calendar cal;
 java.sql.Date sqlDate;
%
%
 try
 {

  Class.forName(sun.jdbc.odbc.JdbcOdbcDriver);
  con = DriverManager.getConnection(jdbc:odbc:umasql,sa,bhavanid);
  st = con.createStatement();
  st1 = con.createStatement();

  firstname = request.getParameter(firstname);
  lastname = request.getParameter(lastname);
  address = request.getParameter(address);
  city = request.getParameter(city);
  state = request.getParameter(state);
  country = request.getParameter(country);
  pincode = Integer.parseInt(request.getParameter(zipcode));
  email = request.getParameter(email);
  phone = Integer.parseInt(request.getParameter(phone));

  userid = request.getParameter(nickname);
  password1 = request.getParameter(password1);
  password2 = request.getParameter(password2);
  newsletter = request.getParameter(newsletter);
  offers = request.getParameter(offers);

  rs1 = st1.executeQuery(select * from Dating_Register where nickname='+userid+' );
  out.println(htmlhead);
  out.println(/head); 

  if(rs1.next())
  {
   out.println(h4font color=redSorry the user already exists/font/h4);
   //printContent();
  }
  else if(!(password1.equals(password2)))
  {
   out.println(h4font color=redPlease type both the passwords same/font/h4);
   //printContent();
  }
  else
  {

   String inserting = insert into Dating_Register 
values(+count+,'+iam+','+seeking+','+lookingfor+','+firstname+','+lastname+','+address+','+city+','+state+','+country+',+pincode+,'+email+',+phone+,+sqlDate+,'+userid+','+password1+','+password2+','+newsletter+','+offers+');

   int x = st1.executeUpdate(inserting);

   out.println(centerbRegistered Successfully/b/center);
   out.println(form name=login action='/servlet/Login' method='post');
   out.println(tabletrtdNickname:/tdtdinput type=text name=userid 
size=15/td/tr);
   out.println(trtdPassword:/tdtdinput type=password name=pass 
size=15/td/tr/table);
   out.println(input type=submit value='Login' name=loginnbsp;input type=reset 
value='Reset' name=reset);
   out.println(/form);

  }

 }
 catch(Exception e)
 {
  e.printStackTrace();
 }
%

%!


 public void printContent()
 {

  This is my bean code, It is a big code, so I am not pasting it here.
   It is actually recalling the HTML page when the user already exists or the password 
is not valid. Do, I have to say out.println statement for each and every HTML line?
 }






%
/body
/html


Thank you,
Regards
Uma



Pls Help!! Uploading an image

2002-03-04 Thread Uma Maheswar

HI,
I need help from any of you. I need a programme to upload an image to the database 
while submitting a form. If any one is having the source code pls help  me.

Regards
Uma



Re: Pls Help!! Uploading an image

2002-03-04 Thread Uma Maheswar

Hi,
I tried using O'Reilly, but it is confusing. I need a simple one than that
one. Can you help me?

Uma

- Original Message -
From: [EMAIL PROTECTED]
To: Tomcat Users List [EMAIL PROTECTED]
Sent: Tuesday, March 05, 2002 2:34 AM
Subject: Re: Pls Help!! Uploading an image


 Uma,
 The O'Reilly servlets book has a good example (including
 code) where you can
 upload files (including images as part of a form).
 See
 http://www.servlets.com/cos/javadoc/com/oreilly/servlet/m
 ultipart/MultipartP
 arser.html for more info.
 Hope this helps.
 Satyakant Evani
 - Original Message -
 From: Uma Maheswar [EMAIL PROTECTED]
 To: Tomcat Users List [EMAIL PROTECTED]
 Sent: Monday, March 04, 2002 10:49 AM
 Subject: Pls Help!! Uploading an image


 HI,
 I need help from any of you. I need a programme to
 upload an image to the
 database while submitting a form. If any one is having
 the source code pls
 help  me.

 Regards
 Uma

  nope i am using tomcat from my user area ..
  both tomcat and apache run from my user area
  there is some problem with a particular .so file which it is not able to
  find
 
 
  -Original Message-
  From: brian ally [mailto:[EMAIL PROTECTED]]
  Sent: Monday, March 04, 2002 11:04 PM
  To: Tomcat Users List
  Subject: Re: java.lang.UnsatisfiedLinkError: no ocijdbc8 in shared
  library path
 
 
  Are you starting tomcat as root? On my linux box, if i su to root, all
  manner of LD_LIBRARY_PATH problems begin. i need to su - (with the
  dash). Could this be your problem?
 
  /b
 
  Abhishek Pamecha wrote:
 
  it is there..
  
  -Original Message-
  From: Toru Watanabe [mailto:[EMAIL PROTECTED]]
  Sent: Monday, March 04, 2002 2:34 PM
  To: Tomcat Users List
  Subject: Re: java.lang.UnsatisfiedLinkError: no ocijdbc8 in shared
  library path
  
  
  
  First, please make sure that Oracle client is installed
  in your machine.
  
  Abhishek Thanks buddy!
  Abhishek but ..i already did that
  Abhishek but i have a a requirement which says i have to use oci
client
  only
  Abhishek any other solution ???
  
  UnsatisfiedLinkError means JVM can't find shared library.
  You need to add shared library path to environment variable.
  
  If you use solaris or linux, then you should add following
  statement in your tomcat.sh.
  
  LD_LIBRARY_PATH=$ORACLE_HOME/lib:$LD_LIBRARY_PATH
  export LD_LIBRARY_PATH
  
  if you use HP-UX, then
  
  SHLIB_PATH=$ORACLE_HOME/lib:$SHLIB_PATH
  export SHLIB_PATH
  
  if you use Windows, then you should add following to tomcat.bat.
  
  set PATH=%ORACLE_HOME%\lib;%PATH%
  
  
  then it will be able to find shared library.
  
  regards,
  Watanabe.
  
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Re: Pls Help!! Uploading an image

2002-03-04 Thread Uma Maheswar

Dear Brett,
Could you please send me the code?

Uma

- Original Message -
From: Brett Porter [EMAIL PROTECTED]
To: 'Tomcat Users List' [EMAIL PROTECTED]
Sent: Tuesday, March 05, 2002 7:14 AM
Subject: RE: Pls Help!! Uploading an image


 You might try struts: http://jakarta.apache.org/struts

 It has an easy way to get multipart content from a form, including an easy
 example, but there is a learning curve to setting up struts itself.
 The code is not going to just appear before your eyes unfortunately :)

 - Brett

 -Original Message-
 From: Uma Maheswar [mailto:[EMAIL PROTECTED]]
 Sent: Tuesday, 5 March 2002 12:33 PM
 To: Tomcat Users List
 Subject: Re: Pls Help!! Uploading an image


 Hi,
 I tried using O'Reilly, but it is confusing. I need a simple one than that
 one. Can you help me?

 Uma

 - Original Message -
 From: [EMAIL PROTECTED]
 To: Tomcat Users List [EMAIL PROTECTED]
 Sent: Tuesday, March 05, 2002 2:34 AM
 Subject: Re: Pls Help!! Uploading an image


  Uma,
  The O'Reilly servlets book has a good example (including
  code) where you can
  upload files (including images as part of a form).
  See
  http://www.servlets.com/cos/javadoc/com/oreilly/servlet/m
  ultipart/MultipartP
  arser.html for more info.
  Hope this helps.
  Satyakant Evani
  - Original Message -
  From: Uma Maheswar [EMAIL PROTECTED]
  To: Tomcat Users List [EMAIL PROTECTED]
  Sent: Monday, March 04, 2002 10:49 AM
  Subject: Pls Help!! Uploading an image
 
 
  HI,
  I need help from any of you. I need a programme to
  upload an image to the
  database while submitting a form. If any one is having
  the source code pls
  help  me.
 
  Regards
  Uma
 
   nope i am using tomcat from my user area ..
   both tomcat and apache run from my user area
   there is some problem with a particular .so file which it is not able
to
   find
  
  
   -Original Message-
   From: brian ally [mailto:[EMAIL PROTECTED]]
   Sent: Monday, March 04, 2002 11:04 PM
   To: Tomcat Users List
   Subject: Re: java.lang.UnsatisfiedLinkError: no ocijdbc8 in shared
   library path
  
  
   Are you starting tomcat as root? On my linux box, if i su to root, all
   manner of LD_LIBRARY_PATH problems begin. i need to su - (with the
   dash). Could this be your problem?
  
   /b
  
   Abhishek Pamecha wrote:
  
   it is there..
   
   -Original Message-
   From: Toru Watanabe [mailto:[EMAIL PROTECTED]]
   Sent: Monday, March 04, 2002 2:34 PM
   To: Tomcat Users List
   Subject: Re: java.lang.UnsatisfiedLinkError: no ocijdbc8 in shared
   library path
   
   
   
   First, please make sure that Oracle client is installed
   in your machine.
   
   Abhishek Thanks buddy!
   Abhishek but ..i already did that
   Abhishek but i have a a requirement which says i have to use oci
 client
   only
   Abhishek any other solution ???
   
   UnsatisfiedLinkError means JVM can't find shared library.
   You need to add shared library path to environment variable.
   
   If you use solaris or linux, then you should add following
   statement in your tomcat.sh.
   
   LD_LIBRARY_PATH=$ORACLE_HOME/lib:$LD_LIBRARY_PATH
   export LD_LIBRARY_PATH
   
   if you use HP-UX, then
   
   SHLIB_PATH=$ORACLE_HOME/lib:$SHLIB_PATH
   export SHLIB_PATH
   
   if you use Windows, then you should add following to tomcat.bat.
   
   set PATH=%ORACLE_HOME%\lib;%PATH%
   
   
   then it will be able to find shared library.
   
   regards,
   Watanabe.
   
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Writing a bean

2002-02-25 Thread Uma Maheswar

Hi,
I wanted to write a java bean inside my JSP programme. My requirement is like this

%
Connection con = (.);
statement = con.createStatement();
request.getParameter(name);
request.getParameter(phone);
rs = st.executeQuery(select * from uma where name=+name);
if(rs.next())
{
out.println(name is present in db);
printContent();
}
else
{
int x = st.executeUpdate(insert into uma values('+name+','+phone+');
}
%
%
public void printContent()
{
I wanted to do some printing stuff here basically HTML coding.
}
%

The printContent() method is giving me errors. I get Statement Expected near the above 
method. Can any one help me? If there is any other way could any one tell me what it 
is?

Uma



integer value

2002-02-25 Thread Uma Maheswar

Hi,
I have a doubt, I have a form that has name and his phone number, both the fields are 
optional. I declared name as VARCHAR and number as INTEGER in my SQL database. When 
the user leaves the fild empty, I get an error with the number field as 
NumberFormatException. 

So , What I need to do now is, when the user leaves the field null or blank, I wanted 
to insert a default value into the database. For eg.

If(number == null)
{
number = 00;
}
if(name==null)
{
name=tomcat;
}

I know the number if statement will give error.But could you please help me with this?

Uma



Re: Java servlet and mailing

2002-02-22 Thread Uma Maheswar

Hi,
There is a ready made programme out there in www.globalleafs.com . You can
download it from our site.

Uma


- Original Message -
From: Simon [EMAIL PROTECTED]
To: Tomcat Users List [EMAIL PROTECTED]
Sent: Friday, February 22, 2002 4:01 AM
Subject: Java servlet and mailing


 Dear,

 I come from PHP world, so that i don't really know about this.

 If i need to sent out an email in my serlvet program, do i need to
download
 and install javamail?
 (I did a mail() in PHP, which calls /bin/mail indeed, most likely...)

 According to this FAQ saying:
 http://java.sun.com/products/javamail/FAQ.html#1

 Q: What is the JavaMailTM API?
 A: The JavaMailTM API is a set of abstract APIs that model a mail system.
 The API provides a platform independent and protocol independent framework
 to build Java technology based email client applications. The JavaMail API
 provides facilities for reading and sending email. Service providers
 implement particular protocols. Several service providers are included
with
 the JavaMail API package; others are available separately. The JavaMail
API
 is implemented as a Java optional package that can be used on JDK 1.1.6
and
 later. The JavaMail API is also a required part of the JavaTM 2 Platform,
 Enterprise Edition (J2EETM).

 Do I have J2SE, i don't have JavaMail right?
 So, the easy way out, is to install J2EE in the first place, rather than
 J2SE?

 I don't this sounds stupid, but please help.

 Many thanks!

 Simon.


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Checking with DB

2002-02-22 Thread Uma Maheswar

Hi,
Please help me with this. Please see the code below. It doesn't work, if I give the 
correct id and password.But it works if I say (!rs.next()). The same type of programme 
worked for me in case of other tables. Could any one pls help me solve this problem.

   String id = req.getParameter(userid);
   String pwd = req.getParameter(password);
   
   ServletOutputStream sos = res.getOutputStream();
   rs = st.executeQuery(select * from uma where userid='+user+' and 
password='+pwd+' );
   sos.println(htmlbody bgcolor=lightyellow);

   if(rs.next())
   {

sos.println(you are lucky);   
sos.println(input type='submit' value='Submit' name='submit'/p);
   }
   else
   {
sos.println(h2Get out of my site/h2);
   }
   sos.println(/body/html);
 
  
  }
  catch(Exception e)
  {
   e.printStackTrace();
  }
 }
}




Signup servlet

2002-02-19 Thread Uma Maheswar

Hi friends,
I am doing a project now. I am trying to register a user into the database using 
Signup.java (Servlet). I did the code and it worked fine till some days but giving me 
problems now. It says that any user who wants to signup is already present in the 
database. I am attaching my java file here. Please check the file and correct me where 
I am wrong. To see this error in action, please visit
http://www.globalleafs.com/Signup.html

Thanks
Uma



Re: Signup servlet

2002-02-19 Thread Uma Maheswar

sorry, Forgot the file. Please check it now.

Uma

- Original Message -
From: Ralph Einfeldt [EMAIL PROTECTED]
To: Tomcat Users List [EMAIL PROTECTED]
Sent: Tuesday, February 19, 2002 8:16 PM
Subject: AW: Signup servlet


Which file ?

Can't see an attachment.

 -Ursprüngliche Nachricht-
 Von: Uma Maheswar [mailto:[EMAIL PROTECTED]]
 Gesendet: Dienstag, 19. Februar 2002 15:36
 An: Tomcat Users List
 Betreff: Signup servlet
snip/
 the database. I am attaching my java file here. Please check
snip/

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Signup.java
Description: Binary data

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Re: Signup servlet

2002-02-19 Thread Uma Maheswar

Hi,
There is no error in this. The servlet is working fine, but the query is
giving  me problem. When the user in the database is not present also, it
says that the user is present in the database. Please check this.

Uma

- Original Message -
From: Vercesi Paolo [EMAIL PROTECTED]
To: Tomcat Users List [EMAIL PROTECTED]
Sent: Tuesday, February 19, 2002 8:26 PM
Subject: R: Signup servlet


 Could we have the error stack trace also?

 Regards
 Paolo

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Signup.java
Description: Binary data

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Signup servlet

2002-02-19 Thread Uma Maheswar




Hi friends,
I am doing a project now. I am trying to register a 
user into the database using Signup.java (Servlet). I did the code and it worked 
fine till some days but giving me problems now. It says that any user who wants 
to signup is already present in the database. I am attaching my java file here. 
Please check the file and correct me where I am wrong. To see this error in 
action, please visit
http://www.globalleafs.com/Signup.html

Thanks
Uma


Signup.java
Description: Binary data

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Getting values from different tables

2002-02-11 Thread Uma Maheswar

Hi,
I wanted to know if there is any possiblility of getting all the values from a 
Database in a single command. 

Example:
I am using it in this way in a browser select * from and here is a drop down box 
which contains table names as register,pc,signup . I select the table I need from 
the drop down box and hit the submit button. and I should get all the values from the 
database in a table. The problem is I do not have all the fields in all the databases 
same. Then how are we going to get the result.


String tables = req.getParameter(tables);
rs = st.executeQuery(select * from '+tables+' );
while(rs.next()
{ 
??
}


Help me.

Uma



Re: Inserting DATE into SQL server

2002-02-11 Thread Uma Maheswar

Hi,
Thanks for your replies. I tested both of your methods and mine too. But in
all the cases I found the date to be inserted Random as 1899 or 1905 or
so on.

cal = Calendar.getInstance();
  cal.set(year,month,date);
  sqlDate = new java.sql.Date(cal.getTime().getTime());

or

totdate = year+-+month+-+date;


I printed the selected date in the browser, I see correct date as selected
by me in the browser. But when I look at the SQL server I see the date
inserted randomly. Could you please tell me where the problem is?

Uma


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How to configure tomcat?

2002-02-07 Thread Uma Maheswar

Hi,
I have a web site www.globalleafs.com . I have downlaoded Tomcat4.0 . I have hosted my 
site with Indiaaccess,India. They are using Apache Tomcat 4.0. I wanted to configure 
my tomcat in such a way that, I can see the System.out.println statements? i.e to 
see the console of Apache Tomcat 4.0 of Indiaaccess,Mumbai in my Home PC. Is this 
possible? If so please hlep me.

Uma



Problem with IE

2002-02-07 Thread Uma Maheswar

Hi,
I am using Apache Tomcat4.0. I am doing a project in Servlets. I do not get my files 
working on IE with this kind of URL
http://globalleafs.com:8080/globalleafs/servlet/TestServlet

But the same URL works fine in Netscape. What could be the problem?

Uma






Re: Problem with IE

2002-02-07 Thread Uma Maheswar

Hi,
It is a sample one that I gave you, It is working for me too. Please try
this
http://www.globalleafs.com/Login.html

User ID: kiran
Password: kiran

and then when you try clicking on any URL, you get HTTP 404 File not found.
But the same works fine in Netscape. Please check it.

Uma
- Original Message -
From: [EMAIL PROTECTED]
To: Tomcat Users List [EMAIL PROTECTED]
Sent: Friday, February 08, 2002 9:53 AM
Subject: Re: Problem with IE


 I have connected to the URL you have mentioned using IE6 and i got
following
 response
 Connected to database inside Test Servlet.java uma uma .what version of
IE
 you are using?

 Ahmed
 - Original Message -
 From: Uma Maheswar [EMAIL PROTECTED]
 To: Tomcat Users List [EMAIL PROTECTED]
 Sent: Thursday, February 07, 2002 8:17 PM
 Subject: Problem with IE


 Hi,
 I am using Apache Tomcat4.0. I am doing a project in Servlets. I do not
get
 my files working on IE with this kind of URL
 http://globalleafs.com:8080/globalleafs/servlet/TestServlet

 But the same URL works fine in Netscape. What could be the problem?

 Uma






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Re: Problem with IE

2002-02-07 Thread Uma Maheswar

Hi Brian,
It is a sample one that I gave you, It is working for me too. Please try
this
http://www.globalleafs.com/Login.html

User ID: kiran
Password: kiran

and then when you try clicking on any URL, you get HTTP 404 File not found.
But the same works fine in Netscape. Please check it.

Uma



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Tomcat not getting installed

2002-02-04 Thread Uma Maheswar

Hi,
I am using JavaWebServer2.0(Trial Version) in WinXP. I have downloaded Tomcat (.exe) 
file. when I try to install it , it says JDK is not found. I have JDK installed with 
Visual Cafe in my PC. What should I do now?

Help me.

Uma