Re: [Neo] apoc-bundle pax-exam failure

2009-08-14 Thread Peter Neubauer
Hi Andreas,
will look at it, offline with my dev machine right now. However, I
need to read up on Sling and Karaf - very cool IMDB demo you did,
showing off a lot of advanced OSGi- Peaberry - Pax Exam practices with
Neo4j - thanks Toni and Stuart for that great work!

Let me look at the error over the weekend, then we could add some
OSGi-testcases to the APOC bundle and then be ready to apply for
moving it from laboratory into components.

/peter

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http://www.neo4j.org- New Energy for Data - The Graph Database.
http://www.ops4j.org- New Energy for OSS Communities -
Open Participation Software.
http://www.linkedprocess.org   - Distributed computing on LinkedData scale



On Fri, Aug 14, 2009 at 5:16 AM, Andreas
Kolleggerakolleg...@tembopublic.org wrote:
 Hi everyone,

 Perhaps someone (maybe Peter? hi peter!) could help me figure out what
 I'm doing wrong with pax-exam in the apoc-bundle. I'm trying to clean
 the project up a bit, and noticed that the pax exam fails if I clear
 my local repository of neo4j artifacts. During the exam, pax-runner
 fails to find the required artifacts, causing this exception...

 java.lang.RuntimeException: URL [mvn:org.neo4j/neo/1.0-
 b9-20090812.131029-32] could not be resolved.
         at
 org
 .ops4j.pax.url.mvn.internal.Connection.getInputStream(Connection.java:
 195)
         at java.net.URL.openStream(URL.java:1009)

 ...
 I'm not sure if that mvn URL is correct or not. The version is the
 expanded latest SNAPSHOT, as calculated by the maven-paxexam-plugin.

 I had to add the neo4j repository to the pom so it could download the
 artifacts, yet pax-exam doesn't seem to pick them up. I also tried
 putting the explicit version in the exam configuration using
 `mavenBundle().artifactId( neo ).groupId( org.neo4j ).version(1.0-
 b9-SNAPSHOT)` but that doesn't help.

 I'm sure there is something simple and obvious that I'm doing wrong,
 but I can't seem to figure it out.

 Thanks,
 Andreas

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Re: [Neo] Wikipedia entries for graph database, Neo4f?

2009-08-14 Thread Anders Nawroth
Hi!

There's now a Nosql article in Wikipedia, let's see if it stays!
http://en.wikipedia.org/wiki/Nosql

Don't know if graphdbs should be considered part of NOSQL, what do you 
think?

/anders

Peter Neubauer skrev:
 Hi there,
 for osme time ago I tried to get an article on Graph Databases into
 Wikipedia, but was refused, probably due to lack of trustworthy
 resources on the subject. With the buzz being higher nowadays, maybe
 we should give it another try!

 /peter

   


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Re: [Neo] Trying to understand Neo4J through IMDB example

2009-08-14 Thread Anders Nawroth
Hi  welcome Philip!

Philip Southam:
 In the hello world type of examples relationship objects returned from
 [snip]
firstNodeInstance.createRelationshipTo(secondNodeInstance,  
 MyRelationshipTypes.EXAMPLE)
 [/snip]
 seem to be ignored, in the since that no data other than the  
 relationship type is associated with it.
   

Even if no further data is associated with relationships, they still 
give the data it's structure and enable you to traverse/navigate this 
structure.

Moving on to the IMDB example, relationships makes it very easy to 
answer questions like which movies does [actor] have a role in? or 
which actors have a role in [movie]? You simply iterate over the 
ACTS_IN type relationships connected to the actor/movie node.

And as we can answer the above type of questions (and at a very high 
speed), we are also able to find the shortest path between two actors, 
a.k.a. their Bacon path.

 But introduce the binding of Role to RelTypes.ACTS_IN and I'm a little  
 confused. We can index the objects bound to nodes making the  
 properties associated with them easily query-able, but why do we bind  
 objects to relationships if we cannot easily query them?

Because we can still find them using traversal/navigation. And I can't 
really imagine the IMDB domain without Role objects! Using them, our 
application can speak the language of the domain, not having to care 
about the underlying data structure.

  I ask this  
 because I cannot figure out, using the IMDB example, how do I return  
 the Role object representing Neo if I don't know the actor or movie  
 that the character/role was in.

In the IMDB application, this is not really possible. So: good question! :-)

  In IMDB example, if the quering of  
 Roles were a requirement, is there a different way that the graph/ 
 domain could be designed to allow for this?
   

Yes. We could have made the Roles nodes, too. Instead of just a simple 
relationship we could use a relationship -- node -- relationship construct.


Please feel free to ask more questions!

/anders

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Re: [Neo] Wikipedia entries for graph database, Neo4f?

2009-08-14 Thread Anders Nawroth
Hi!

Emil Eifrem:
 On Fri, Aug 14, 2009 at 10:58, Anders Nawrothand...@neotechnology.com wrote:
   
 Don't know if graphdbs should be considered part of NOSQL, what do you
 think?
 

 Huh? Yes!
   

Well, then the definition of NOSQL @ wikipedia has to be made wider. At 
the moment it only addresses solutions to the horizontal scalability 
problem, but there are more to NOSQL than just that. Handle 
semi-structured content, scale to complexity etc.

 I still think this categorization (scroll down in mail) of emerging
 nosql databases is the best out there:

http://groups.google.com/group/nosql-discussion/msg/31f8f71a88142c68
   

What about structuring the wikipedia araticle using that? Throwing all 
implementations of NOSQL in a single bag isn't really useful. Actually 
I think *diversity* is at the core of NOSQL :-)


/anders

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Re: [Neo] neo4j Beginner Question

2009-08-14 Thread Onur AKTAS

Thank you for your response. I'm trying to understand the main concept, please 
correct me if I am wrong.

For example, there are many users of an application and each represented as 
Node.  And each User has a UserId in RDBMS. I have checked Node class and 
saw that there is a method called as  getId()  but I could not see setId() 
for mapping the User in the RDBMS to neo4j. 

Sample data: (UserId / Friends Ids)
1 - [2, 4]
2 - [1, 3]
3 - [10]
4 - [1, 3, 5]
5 - [3]

And I need to query  What are the all shortest paths from 1 to 10 for max 
length 4 
And results should be,

1 - 2 - 3 - 10 
1 - 4 - 3 - 10 
* 1 - 4 - 5 - 3 - 10 (It will not be shown because it exceeds the length 4).

You mean that it can be handled with neo4j, but how can I map each User in 
RDBMS, to Nodes by their original Ids?

Thanks.



 From: neubauer.pe...@gmail.com
 Date: Wed, 5 Aug 2009 11:16:15 +0200
 To: user@lists.neo4j.org
 Subject: Re: [Neo] neo4j Beginner Question
 
 Hi Onur
 
 2009/8/4 Onur AKTAS onur.ak...@live.com:
  Calculating,friends of friends, 3rd degree contacts or 4th degree etc. is 
  not a good idea with RDBMS. In short words, neo4j fits perfectly for these 
  kinds of jobs?
 yes, that is the kind of problems Neo4j and Graph Databases are trying
 to solve in general. Semi-structured data, havy use of relational
 information between information entities and complex analysis of high
 depth fast are some of the common use cases for using a graph
 database.
 
  Do we have a chance to scale neo4j by adding nodes, does it support 
  distributed processing? Also, can we delete any node in the graph when we 
  need to delete user or we must create the entire graph again when we need 
  any updates? Do graph objects have id's that helps us to find the node 
  quickly?
 
 Neo4j atm does not support distributed processing or partitioning the
 graph. There is high-availability and online-backup being worked on
 which feels more acute since Neo4j on a single instance scales over 1
 Billion primitives, which should be enough for most immediate
 scenarios.
 But there are of course ways to achieve a custom partitioning using
 targeted techniques - but that depends on your use case ...
 
 HTH
 
 /peter
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Re: [Neo] neo4j Beginner Question

2009-08-14 Thread Mattias Persson
2009/8/14 Onur AKTAS onur.ak...@live.com:

 Thank you for your response. I'm trying to understand the main concept, 
 please correct me if I am wrong.

 For example, there are many users of an application and each represented as 
 Node.  And each User has a UserId in RDBMS. I have checked Node class 
 and saw that there is a method called as  getId()  but I could not see 
 setId() for mapping the User in the RDBMS to neo4j.

 Sample data: (UserId / Friends Ids)
 1 - [2, 4]
 2 - [1, 3]
 3 - [10]
 4 - [1, 3, 5]
 5 - [3]

 And I need to query  What are the all shortest paths from 1 to 10 for max 
 length 4 
 And results should be,

 1 - 2 - 3 - 10
 1 - 4 - 3 - 10
 * 1 - 4 - 5 - 3 - 10 (It will not be shown because it exceeds the length 
 4).

 You mean that it can be handled with neo4j, but how can I map each User in 
 RDBMS, to Nodes by their original Ids?

You can just come up with your own property key which will represent
that RDBMS id... f.ex:

node.setProperty( rdbms_id, myRdbmsId );

The node.getId() is just the internal id the node have in neo, which
is unique, but not over time since ids can be reused if they gets
deleted.


 Thanks.



 From: neubauer.pe...@gmail.com
 Date: Wed, 5 Aug 2009 11:16:15 +0200
 To: user@lists.neo4j.org
 Subject: Re: [Neo] neo4j Beginner Question

 Hi Onur

 2009/8/4 Onur AKTAS onur.ak...@live.com:
  Calculating,friends of friends, 3rd degree contacts or 4th degree etc. 
  is not a good idea with RDBMS. In short words, neo4j fits perfectly for 
  these kinds of jobs?
 yes, that is the kind of problems Neo4j and Graph Databases are trying
 to solve in general. Semi-structured data, havy use of relational
 information between information entities and complex analysis of high
 depth fast are some of the common use cases for using a graph
 database.

  Do we have a chance to scale neo4j by adding nodes, does it support 
  distributed processing? Also, can we delete any node in the graph when we 
  need to delete user or we must create the entire graph again when we need 
  any updates? Do graph objects have id's that helps us to find the node 
  quickly?

 Neo4j atm does not support distributed processing or partitioning the
 graph. There is high-availability and online-backup being worked on
 which feels more acute since Neo4j on a single instance scales over 1
 Billion primitives, which should be enough for most immediate
 scenarios.
 But there are of course ways to achieve a custom partitioning using
 targeted techniques - but that depends on your use case ...

 HTH

 /peter
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Re: [Neo] neo4j Beginner Question

2009-08-14 Thread Neil Ellis
And then use the index-utils to find the node (it's a good simple and  
efficient integration with Lucene).

On 14 Aug 2009, at 16:10, Dan Heaver wrote:

 Onur, add a property to each node to hold the surragate key from your
 RDBMS...

 Dan

 On 14 Aug 2009, at 15:30, Onur AKTAS onur.ak...@live.com wrote:


 Thank you for your response. I'm trying to understand the main
 concept, please correct me if I am wrong.

 For example, there are many users of an application and each
 represented as Node.  And each User has a UserId in RDBMS. I
 have checked Node class and saw that there is a method called as 
 getId()  but I could not see setId() for mapping the User in the
 RDBMS to neo4j.

 Sample data: (UserId / Friends Ids)
 1 - [2, 4]
 2 - [1, 3]
 3 - [10]
 4 - [1, 3, 5]
 5 - [3]

 And I need to query  What are the all shortest paths from 1 to 10
 for max length 4 
 And results should be,

 1 - 2 - 3 - 10
 1 - 4 - 3 - 10
 * 1 - 4 - 5 - 3 - 10 (It will not be shown because it exceeds
 the length 4).

 You mean that it can be handled with neo4j, but how can I map each
 User in RDBMS, to Nodes by their original Ids?

 Thanks.



 From: neubauer.pe...@gmail.com
 Date: Wed, 5 Aug 2009 11:16:15 +0200
 To: user@lists.neo4j.org
 Subject: Re: [Neo] neo4j Beginner Question

 Hi Onur

 2009/8/4 Onur AKTAS onur.ak...@live.com:
 Calculating,friends of friends, 3rd degree contacts or 4th
 degree etc. is not a good idea with RDBMS. In short words, neo4j
 fits perfectly for these kinds of jobs?
 yes, that is the kind of problems Neo4j and Graph Databases are
 trying
 to solve in general. Semi-structured data, havy use of relational
 information between information entities and complex analysis of  
 high
 depth fast are some of the common use cases for using a graph
 database.

 Do we have a chance to scale neo4j by adding nodes, does it
 support distributed processing? Also, can we delete any node in
 the graph when we need to delete user or we must create the entire
 graph again when we need any updates? Do graph objects have id's
 that helps us to find the node quickly?

 Neo4j atm does not support distributed processing or partitioning  
 the
 graph. There is high-availability and online-backup being worked on
 which feels more acute since Neo4j on a single instance scales  
 over 1
 Billion primitives, which should be enough for most immediate
 scenarios.
 But there are of course ways to achieve a custom partitioning using
 targeted techniques - but that depends on your use case ...

 HTH

 /peter
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Re: [Neo] neo4j Beginner Question

2009-08-14 Thread Mattias Persson
// One instance per NeoService is enough
IndexService indexService = new LuceneIndexService( neoService );

and that will be your index, fully transactional and participates in
your neo transactions.

2009/8/14 Onur AKTAS onur.ak...@live.com:

 So I must build it on the top of Lucene?
 Hmm, shouldn't it be a native property of neo4j? Do we have a chance to get 
 Node's id after we insert it?
 So I can use an additional key - value based database for keeping the 
 relation between Node and User like below:
 (rdbms_user_id, neo4j_node_id)

 Is it a good idea?

 From: neil.el...@mangala.co.uk
 To: user@lists.neo4j.org
 Date: Fri, 14 Aug 2009 16:21:38 +0100
 Subject: Re: [Neo] neo4j Beginner Question

 And then use the index-utils to find the node (it's a good simple and
 efficient integration with Lucene).

 On 14 Aug 2009, at 16:10, Dan Heaver wrote:

  Onur, add a property to each node to hold the surragate key from your
  RDBMS...
 
  Dan
 
  On 14 Aug 2009, at 15:30, Onur AKTAS onur.ak...@live.com wrote:
 
 
  Thank you for your response. I'm trying to understand the main
  concept, please correct me if I am wrong.
 
  For example, there are many users of an application and each
  represented as Node.  And each User has a UserId in RDBMS. I
  have checked Node class and saw that there is a method called as 
  getId()  but I could not see setId() for mapping the User in the
  RDBMS to neo4j.
 
  Sample data: (UserId / Friends Ids)
  1 - [2, 4]
  2 - [1, 3]
  3 - [10]
  4 - [1, 3, 5]
  5 - [3]
 
  And I need to query  What are the all shortest paths from 1 to 10
  for max length 4 
  And results should be,
 
  1 - 2 - 3 - 10
  1 - 4 - 3 - 10
  * 1 - 4 - 5 - 3 - 10 (It will not be shown because it exceeds
  the length 4).
 
  You mean that it can be handled with neo4j, but how can I map each
  User in RDBMS, to Nodes by their original Ids?
 
  Thanks.
 
 
 
  From: neubauer.pe...@gmail.com
  Date: Wed, 5 Aug 2009 11:16:15 +0200
  To: user@lists.neo4j.org
  Subject: Re: [Neo] neo4j Beginner Question
 
  Hi Onur
 
  2009/8/4 Onur AKTAS onur.ak...@live.com:
  Calculating,friends of friends, 3rd degree contacts or 4th
  degree etc. is not a good idea with RDBMS. In short words, neo4j
  fits perfectly for these kinds of jobs?
  yes, that is the kind of problems Neo4j and Graph Databases are
  trying
  to solve in general. Semi-structured data, havy use of relational
  information between information entities and complex analysis of
  high
  depth fast are some of the common use cases for using a graph
  database.
 
  Do we have a chance to scale neo4j by adding nodes, does it
  support distributed processing? Also, can we delete any node in
  the graph when we need to delete user or we must create the entire
  graph again when we need any updates? Do graph objects have id's
  that helps us to find the node quickly?
 
  Neo4j atm does not support distributed processing or partitioning
  the
  graph. There is high-availability and online-backup being worked on
  which feels more acute since Neo4j on a single instance scales
  over 1
  Billion primitives, which should be enough for most immediate
  scenarios.
  But there are of course ways to achieve a custom partitioning using
  targeted techniques - but that depends on your use case ...
 
  HTH
 
  /peter
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Re: [Neo] neo4j Beginner Question

2009-08-14 Thread Neil Ellis
Ain't that cool :-)

I speak from experience it works and works well. Lucene is an efficient
index, the integration is seemless (from my experience).

On 14 Aug 2009, at 17:13, Mattias Persson wrote:

 // One instance per NeoService is enough
 IndexService indexService = new LuceneIndexService( neoService );

 and that will be your index, fully transactional and participates in
 your neo transactions.

 2009/8/14 Onur AKTAS onur.ak...@live.com:

 So I must build it on the top of Lucene?
 Hmm, shouldn't it be a native property of neo4j? Do we have a  
 chance to get Node's id after we insert it?
 So I can use an additional key - value based database for keeping  
 the relation between Node and User like below:
 (rdbms_user_id, neo4j_node_id)

 Is it a good idea?

 From: neil.el...@mangala.co.uk
 To: user@lists.neo4j.org
 Date: Fri, 14 Aug 2009 16:21:38 +0100
 Subject: Re: [Neo] neo4j Beginner Question

 And then use the index-utils to find the node (it's a good simple  
 and
 efficient integration with Lucene).

 On 14 Aug 2009, at 16:10, Dan Heaver wrote:

 Onur, add a property to each node to hold the surragate key from  
 your
 RDBMS...

 Dan

 On 14 Aug 2009, at 15:30, Onur AKTAS onur.ak...@live.com wrote:


 Thank you for your response. I'm trying to understand the main
 concept, please correct me if I am wrong.

 For example, there are many users of an application and each
 represented as Node.  And each User has a UserId in RDBMS. I
 have checked Node class and saw that there is a method called  
 as 
 getId()  but I could not see setId() for mapping the User in  
 the
 RDBMS to neo4j.

 Sample data: (UserId / Friends Ids)
 1 - [2, 4]
 2 - [1, 3]
 3 - [10]
 4 - [1, 3, 5]
 5 - [3]

 And I need to query  What are the all shortest paths from 1 to 10
 for max length 4 
 And results should be,

 1 - 2 - 3 - 10
 1 - 4 - 3 - 10
 * 1 - 4 - 5 - 3 - 10 (It will not be shown because it exceeds
 the length 4).

 You mean that it can be handled with neo4j, but how can I map each
 User in RDBMS, to Nodes by their original Ids?

 Thanks.



 From: neubauer.pe...@gmail.com
 Date: Wed, 5 Aug 2009 11:16:15 +0200
 To: user@lists.neo4j.org
 Subject: Re: [Neo] neo4j Beginner Question

 Hi Onur

 2009/8/4 Onur AKTAS onur.ak...@live.com:
 Calculating,friends of friends, 3rd degree contacts or 4th
 degree etc. is not a good idea with RDBMS. In short words, neo4j
 fits perfectly for these kinds of jobs?
 yes, that is the kind of problems Neo4j and Graph Databases are
 trying
 to solve in general. Semi-structured data, havy use of relational
 information between information entities and complex analysis of
 high
 depth fast are some of the common use cases for using a graph
 database.

 Do we have a chance to scale neo4j by adding nodes, does it
 support distributed processing? Also, can we delete any node in
 the graph when we need to delete user or we must create the  
 entire
 graph again when we need any updates? Do graph objects have id's
 that helps us to find the node quickly?

 Neo4j atm does not support distributed processing or partitioning
 the
 graph. There is high-availability and online-backup being  
 worked on
 which feels more acute since Neo4j on a single instance scales
 over 1
 Billion primitives, which should be enough for most immediate
 scenarios.
 But there are of course ways to achieve a custom partitioning  
 using
 targeted techniques - but that depends on your use case ...

 HTH

 /peter
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Re: [Neo] neo4j Beginner Question

2009-08-14 Thread Anders Nawroth
Hi!

 IndexService indexService = new LuceneIndexService( neoService );

 and that will be your index, fully transactional and participates in
 your neo transactions.
   

More information here:

http://components.neo4j.org/index-util/
http://components.neo4j.org/index-util/apidocs/index.html
http://components.neo4j.org/index-util/apidocs/org/neo4j/util/index/IndexService.html

The EmbeddedNeoWithIndexingExample.java in the APOC download could be 
useful:
http://dist.neo4j.org/neo4j-apoc-0.1.tar.gz
http://dist.neo4j.org/neo4j-apoc-0.1.zip

The download includes all libraries that you need for Neo4j + Lucene 
indexing.


/anders

 2009/8/14 Onur AKTAS onur.ak...@live.com:
   
 So I must build it on the top of Lucene?
 Hmm, shouldn't it be a native property of neo4j? Do we have a chance to get 
 Node's id after we insert it?
 So I can use an additional key - value based database for keeping the 
 relation between Node and User like below:
 (rdbms_user_id, neo4j_node_id)

 Is it a good idea?

 
 From: neil.el...@mangala.co.uk
 To: user@lists.neo4j.org
 Date: Fri, 14 Aug 2009 16:21:38 +0100
 Subject: Re: [Neo] neo4j Beginner Question

 And then use the index-utils to find the node (it's a good simple and
 efficient integration with Lucene).

 On 14 Aug 2009, at 16:10, Dan Heaver wrote:

   
 Onur, add a property to each node to hold the surragate key from your
 RDBMS...

 Dan

 On 14 Aug 2009, at 15:30, Onur AKTAS onur.ak...@live.com wrote:

 
 Thank you for your response. I'm trying to understand the main
 concept, please correct me if I am wrong.

 For example, there are many users of an application and each
 represented as Node.  And each User has a UserId in RDBMS. I
 have checked Node class and saw that there is a method called as 
 getId()  but I could not see setId() for mapping the User in the
 RDBMS to neo4j.

 Sample data: (UserId / Friends Ids)
 1 - [2, 4]
 2 - [1, 3]
 3 - [10]
 4 - [1, 3, 5]
 5 - [3]

 And I need to query  What are the all shortest paths from 1 to 10
 for max length 4 
 And results should be,

 1 - 2 - 3 - 10
 1 - 4 - 3 - 10
 * 1 - 4 - 5 - 3 - 10 (It will not be shown because it exceeds
 the length 4).

 You mean that it can be handled with neo4j, but how can I map each
 User in RDBMS, to Nodes by their original Ids?

 Thanks.



   
 From: neubauer.pe...@gmail.com
 Date: Wed, 5 Aug 2009 11:16:15 +0200
 To: user@lists.neo4j.org
 Subject: Re: [Neo] neo4j Beginner Question

 Hi Onur

 2009/8/4 Onur AKTAS onur.ak...@live.com:
 
 Calculating,friends of friends, 3rd degree contacts or 4th
 degree etc. is not a good idea with RDBMS. In short words, neo4j
 fits perfectly for these kinds of jobs?
   
 yes, that is the kind of problems Neo4j and Graph Databases are
 trying
 to solve in general. Semi-structured data, havy use of relational
 information between information entities and complex analysis of
 high
 depth fast are some of the common use cases for using a graph
 database.

 
 Do we have a chance to scale neo4j by adding nodes, does it
 support distributed processing? Also, can we delete any node in
 the graph when we need to delete user or we must create the entire
 graph again when we need any updates? Do graph objects have id's
 that helps us to find the node quickly?
   
 Neo4j atm does not support distributed processing or partitioning
 the
 graph. There is high-availability and online-backup being worked on
 which feels more acute since Neo4j on a single instance scales
 over 1
 Billion primitives, which should be enough for most immediate
 scenarios.
 But there are of course ways to achieve a custom partitioning using
 targeted techniques - but that depends on your use case ...

 HTH

 /peter
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-- 
Anders Nawroth 

Re: [Neo] neo4j Beginner Question

2009-08-14 Thread Onur AKTAS

I will take a look at them
Thanks you all, for your responses.

 Date: Fri, 14 Aug 2009 19:10:48 +0200
 From: and...@neotechnology.com
 To: user@lists.neo4j.org
 Subject: Re: [Neo] neo4j Beginner Question
 
 Hi!
 
  IndexService indexService = new LuceneIndexService( neoService );
 
  and that will be your index, fully transactional and participates in
  your neo transactions.

 
 More information here:
 
 http://components.neo4j.org/index-util/
 http://components.neo4j.org/index-util/apidocs/index.html
 http://components.neo4j.org/index-util/apidocs/org/neo4j/util/index/IndexService.html
 
 The EmbeddedNeoWithIndexingExample.java in the APOC download could be 
 useful:
 http://dist.neo4j.org/neo4j-apoc-0.1.tar.gz
 http://dist.neo4j.org/neo4j-apoc-0.1.zip
 
 The download includes all libraries that you need for Neo4j + Lucene 
 indexing.
 
 
 /anders
 
  2009/8/14 Onur AKTAS onur.ak...@live.com:

  So I must build it on the top of Lucene?
  Hmm, shouldn't it be a native property of neo4j? Do we have a chance to 
  get Node's id after we insert it?
  So I can use an additional key - value based database for keeping the 
  relation between Node and User like below:
  (rdbms_user_id, neo4j_node_id)
 
  Is it a good idea?
 
  
  From: neil.el...@mangala.co.uk
  To: user@lists.neo4j.org
  Date: Fri, 14 Aug 2009 16:21:38 +0100
  Subject: Re: [Neo] neo4j Beginner Question
 
  And then use the index-utils to find the node (it's a good simple and
  efficient integration with Lucene).
 
  On 14 Aug 2009, at 16:10, Dan Heaver wrote:
 

  Onur, add a property to each node to hold the surragate key from your
  RDBMS...
 
  Dan
 
  On 14 Aug 2009, at 15:30, Onur AKTAS onur.ak...@live.com wrote:
 
  
  Thank you for your response. I'm trying to understand the main
  concept, please correct me if I am wrong.
 
  For example, there are many users of an application and each
  represented as Node.  And each User has a UserId in RDBMS. I
  have checked Node class and saw that there is a method called as 
  getId()  but I could not see setId() for mapping the User in the
  RDBMS to neo4j.
 
  Sample data: (UserId / Friends Ids)
  1 - [2, 4]
  2 - [1, 3]
  3 - [10]
  4 - [1, 3, 5]
  5 - [3]
 
  And I need to query  What are the all shortest paths from 1 to 10
  for max length 4 
  And results should be,
 
  1 - 2 - 3 - 10
  1 - 4 - 3 - 10
  * 1 - 4 - 5 - 3 - 10 (It will not be shown because it exceeds
  the length 4).
 
  You mean that it can be handled with neo4j, but how can I map each
  User in RDBMS, to Nodes by their original Ids?
 
  Thanks.
 
 
 

  From: neubauer.pe...@gmail.com
  Date: Wed, 5 Aug 2009 11:16:15 +0200
  To: user@lists.neo4j.org
  Subject: Re: [Neo] neo4j Beginner Question
 
  Hi Onur
 
  2009/8/4 Onur AKTAS onur.ak...@live.com:
  
  Calculating,friends of friends, 3rd degree contacts or 4th
  degree etc. is not a good idea with RDBMS. In short words, neo4j
  fits perfectly for these kinds of jobs?

  yes, that is the kind of problems Neo4j and Graph Databases are
  trying
  to solve in general. Semi-structured data, havy use of relational
  information between information entities and complex analysis of
  high
  depth fast are some of the common use cases for using a graph
  database.
 
  
  Do we have a chance to scale neo4j by adding nodes, does it
  support distributed processing? Also, can we delete any node in
  the graph when we need to delete user or we must create the entire
  graph again when we need any updates? Do graph objects have id's
  that helps us to find the node quickly?

  Neo4j atm does not support distributed processing or partitioning
  the
  graph. There is high-availability and online-backup being worked on
  which feels more acute since Neo4j on a single instance scales
  over 1
  Billion primitives, which should be enough for most immediate
  scenarios.
  But there are of course ways to achieve a custom partitioning using
  targeted techniques - but that depends on your use case ...
 
  HTH
 
  /peter
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  Windows 

[Neo] neo4j with terracotta?

2009-08-14 Thread Marc Preddie
Hi All,
I was just wondering if any users of neo4j has had to opportunity to
integrate it with terracotta?

Regards,
Marc Preddie
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