Web app and Forum
Hi all I have a web application, and I wanted to add a forum for this application, i used mvnforum ( an open source forum). My question is : Can I jar two web applications in one file?? both applications use the same database. ?? any help please
Re: Web app and Forum
No, It's just I am using an open source forum, a huge project, with hundredes of class and jsp files. I thought that If I wanted to merge the forum with my web applications, it will be a nightmare :(, so I am looking for a way to sovle this On 8/18/07, David Smith [EMAIL PROTECTED] wrote: I doubt it. Webapps are intended to be independent of each other like software applications on your desktop or notebook. My question is why would you want to? Is the database some file based db like derby or berkley db? --David Mohammed Zabin wrote: Hi all I have a web application, and I wanted to add a forum for this application, i used mvnforum ( an open source forum). My question is : Can I jar two web applications in one file?? both applications use the same database. ?? any help please - To start a new topic, e-mail: users@tomcat.apache.org To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Re: Web app and Forum
You mean I deploy two war files that shares the same database? On 8/18/07, David Smith [EMAIL PROTECTED] wrote: If you are pointing both webapp and forum to the same database on the same database server and there aren't any other shared resources or reasons for them to live under the same roof, I would think it would be much easier to deploy two webapps and be done. --David Mohammed Zabin wrote: No, It's just I am using an open source forum, a huge project, with hundredes of class and jsp files. I thought that If I wanted to merge the forum with my web applications, it will be a nightmare :(, so I am looking for a way to sovle this On 8/18/07, David Smith [EMAIL PROTECTED] wrote: I doubt it. Webapps are intended to be independent of each other like software applications on your desktop or notebook. My question is why would you want to? Is the database some file based db like derby or berkley db? --David Mohammed Zabin wrote: Hi all I have a web application, and I wanted to add a forum for this application, i used mvnforum ( an open source forum). My question is : Can I jar two web applications in one file?? both applications use the same database. ?? any help please - To start a new topic, e-mail: users@tomcat.apache.org To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] - To start a new topic, e-mail: users@tomcat.apache.org To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Re: Bean and Servlet
Ok, in the first page, which use a tag, I generate 10 random numbers. and generate a SQL statement containing this numbers like the following: SELECT * FROM table WHERE id in ( 2, 3, 5, 10, etc). I use a string to hold the in statement and bound it to the whole query string. After submitting the page, I need to check the validety of the answers, for the same questions. So, I store the inStr in a session and read it in the second page. Regarding concurrency issue, I think that I don't need to synchronize random number generation. Because I don't have a problem for multiple requests to have the same set of questions. On 7/27/07, Pid [EMAIL PROTECTED] wrote: Caldarale, Charles R wrote: From: Mohammed Zabin [mailto:[EMAIL PROTECTED] Subject: Re: Bean and Servlet My Problem is that, I want to pass these numbers, Questions IDs, from the first page, which i have made it as a tag class, to Results page, which was made as servlet. Rather than hanging onto the ID within Tomcat, why not store it on the generated web page (as a hidden field) and have some script on that page include it with the next request from the client? That way you avoid all synchronization issues that can occur with simultaneous requests. It sounds like a simple form submit with (a) hidden field(s). Why do all of the rest of the ids need to be submitted as well, if you're only checking for the single correct answer? p That was my problem my buddy, by the way, when i used session, it worked fine. and you stated that this will not work I didn't say it wouldn't work, I said you had to be careful and take concurrency into account, which your code snippets did not. - Chuck THIS COMMUNICATION MAY CONTAIN CONFIDENTIAL AND/OR OTHERWISE PROPRIETARY MATERIAL and is thus for use only by the intended recipient. If you received this in error, please contact the sender and delete the e-mail and its attachments from all computers. - To start a new topic, e-mail: users@tomcat.apache.org To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Re: Bean and Servlet
On 7/27/07, Mohammed Zabin [EMAIL PROTECTED] wrote: Ok, in the first page, which use a tag, I generate 10 random numbers. and generate a SQL statement containing this numbers like the following: SELECT * FROM table WHERE id in ( 2, 3, 5, 10, etc). I use a string to hold the in statement and bound it to the whole query string. After submitting the page, I need to check the validety of the answers, for the same questions. So, I store the inStr in a session and read it in the second page. Regarding concurrency issue, I think that I don't need to synchronize random number generation. Because I don't have a problem for multiple requests to have the same set of questions. The most important issue is that for a given request, I need to submit the same collection of questions to Results page. And so, i used session to store the questions ids'. On 7/27/07, Pid [EMAIL PROTECTED] wrote: Caldarale, Charles R wrote: From: Mohammed Zabin [mailto:[EMAIL PROTECTED] ] Subject: Re: Bean and Servlet My Problem is that, I want to pass these numbers, Questions IDs, from the first page, which i have made it as a tag class, to Results page, which was made as servlet. Rather than hanging onto the ID within Tomcat, why not store it on the generated web page (as a hidden field) and have some script on that page include it with the next request from the client? That way you avoid all synchronization issues that can occur with simultaneous requests. It sounds like a simple form submit with (a) hidden field(s). Why do all of the rest of the ids need to be submitted as well, if you're only checking for the single correct answer? p That was my problem my buddy, by the way, when i used session, it worked fine. and you stated that this will not work I didn't say it wouldn't work, I said you had to be careful and take concurrency into account, which your code snippets did not. - Chuck THIS COMMUNICATION MAY CONTAIN CONFIDENTIAL AND/OR OTHERWISE PROPRIETARY MATERIAL and is thus for use only by the intended recipient. If you received this in error, please contact the sender and delete the e-mail and its attachments from all computers. - To start a new topic, e-mail: users@tomcat.apache.org To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Re: MySql Connector
Ok guys, here we are. I have define the new resource inside a Context tag inside a Host tag, as suggested by Tomcat documentation. I removed it and put it inside GlobalNamingResources tag like the following: 1. Configure naming Resource: inside GlobalNamingResources i put the following: Resource name=jdbc/DBTest auth=Container type=javax.sql.DataSource maxActive=100 maxIdle=30 maxWait=1 username=root password=exam driverClassName= com.mysql.jdbc.Driver url=jdbc:mysql://localhost:3306/exam/ 2. Inside web.xml: resource-ref descriptionOracle Datasource example/description res-ref-namejdbc/DBTest/res-ref-name res-typejavax.sql.DataSource/res-type res-authContainer/res-auth /resource-ref 3. Finally, you have to connect your server to the new resource. To do that, inside context.xml put the following: ResourceLink global=jdbc/DBTest name=jdbc/DBTest type= javax.sql.DataSource/ 4. Test your code as follow: %@ page import = java.sql.*, javax.naming.*, javax.sql.* % % Context initContext = new InitialContext(); DataSource ds = (DataSource)initContext.lookup(java:comp/env/jdbc/DBTest); Connection conn = ds.getConnection(); out.println(Connection Established); % Tomcat 6 documentation stated that you have to put naming resource definition inside the Context tag. And this was the problem, when i removed it from their it worked find and the connection established successfully. Anyways, thank you very much buddies for your time and consideration. I am always saying that the user of this mailing list are the best developers in the world. ;) On 7/26/07, Christopher Schultz [EMAIL PROTECTED] wrote: -BEGIN PGP SIGNED MESSAGE- Hash: SHA1 Mohammed, Mohammed Zabin wrote: If you looked at the exception you will find ClassNotFoundException at line 66 in the generated servlet, and this occurs withing the try block, so, i think it's a problem of Connector. You are seriously confused, here. Your code is not being compiled. Your code is not running. The fact that you have a try/catch block in your code is irrelevant. Why do you think that this occurs within the try block? Your stack trace does not include any references to your own code. It's simply not executing. And, even if this occurred within your try/catch block, you are foolishly swallowing all exceptions, meaning that you would never know what the problem was. But the strange thing is that this code worked fine on a normal java class??? Probably because your normal java class actually compiled and ran. Something is wrong with your file, not your code. - -chris -BEGIN PGP SIGNATURE- Version: GnuPG v1.4.7 (MingW32) Comment: Using GnuPG with Mozilla - http://enigmail.mozdev.org iD8DBQFGqO9T9CaO5/Lv0PARAuXgAKDBgPM+osNL0y15at28q9YITixicACgqJte QOgTrjE+1cqeih2be83XEww= =dPUB -END PGP SIGNATURE- - To start a new topic, e-mail: users@tomcat.apache.org To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Re: registering a DB2ConnectionPoolDataSource in tomcat 5.5
I didn't work on DB2 before, but i have configured Oracle and MySql database in the same way. First, you have to get the ideal connector for DB2, jar file, and place it inside CATALINA_HOME/lib, or JAVA_HOME/lib/ext. Second, Define your resource name, you already did. Thrid: Add extra information in your web.xml file like the following: resource-ref descriptionOracle Datasource example/description res-ref-namejdbc/db2universal/res-ref-name res-typejavax.sql.DataSource/res-type res-authContainer/res-auth /resource-ref After that, you have to connect your Resource name to the your server. In context.xml add the following line of code: ResourceLink global=jdbc/db2universal name=jdbc/db2universal type=javax.sql.DataSource/ One last thing, please note that you have to change the previous parameters according to your database. Hope that will help On 7/27/07, dileep_sivaraman [EMAIL PROTECTED] wrote: Hi , I am trying to register a com.ibm.db2.jcc.DB2ConnectionPoolDataSource datasource in tomcat 5.5.4. I am not getting any exception's while doing a context lookup and gives me the datasource. However the paramaeter's that are set with that Resource are always null. Server.xml GlobalNamingResources Resource name=jdbc/db2universal type=com.ibm.db2.jcc.DB2ConnectionPoolDataSource factory=com.ibm.db2.jcc.DB2DataSourceFactory serverName=PROD9S03.bankofamerica.com username=abc password=abc/ /GlobalNamingResources In my code I get the datasource as : connPoolDataSource=(DB2ConnectionPoolDataSource) envContext.lookup(jdbc/db2universal); However when I print out the serverName parameter that has been set in the resource it prints null. System.out.println(connPoolDataSource.getServerName() :+connPoolDataSource.getServerName()); OUTPUT: connPoolDataSource.getServerName() :null Can somebody tell me what I am doing wrong? -- View this message in context: http://www.nabble.com/registering-a-DB2ConnectionPoolDataSource-in-tomcat--5.5-tf4155802.html#a11823991 Sent from the Tomcat - User mailing list archive at Nabble.com. - To start a new topic, e-mail: users@tomcat.apache.org To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] - To start a new topic, e-mail: users@tomcat.apache.org To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Re: registering a DB2ConnectionPoolDataSource in tomcat 5.5
On 7/27/07, dileep_sivaraman [EMAIL PROTECTED] wrote: Hi, Thrid: Add extra information in your web.xml file like the following: resource-ref descriptionOracle Datasource example/description res-ref-namejdbc/db2universal/res-ref-name res-typejavax.sql.DataSource/res-type res-authContainer/res-auth /resource-ref Do we have to add this since I am defining the resource as global? You are right, i think that you don't have to add the above in web.xml, I tried to remove it from Oracle configuration and MySql, and it works. The most important thing, is to defing a resource in server.xml, and then linke your resource to the server enviroment in context.xml OUTPUT : PRinting out entries in java:comp/env Entry :jdbc: org.apache.naming.NamingContext PRinting out entries in java:comp/env/jdbc Entry :db2universal: org.apache.naming.ResourceLinkRef It is not null connPoolDataSource.getServerName() :null Port:446 DB Name:null Driver type :2 Timeout :0 User :null Is there any way to print out the parameters that are passed along with the Resource? Or am I doing something fundamentally wrong? Mohammed Zabin wrote: I didn't work on DB2 before, but i have configured Oracle and MySql database in the same way. First, you have to get the ideal connector for DB2, jar file, and place it inside CATALINA_HOME/lib, or JAVA_HOME/lib/ext. Second, Define your resource name, you already did. Thrid: Add extra information in your web.xml file like the following: resource-ref descriptionOracle Datasource example/description res-ref-namejdbc/db2universal/res-ref-name res-typejavax.sql.DataSource/res-type res-authContainer/res-auth /resource-ref After that, you have to connect your Resource name to the your server. In context.xml add the following line of code: ResourceLink global=jdbc/db2universal name=jdbc/db2universal type=javax.sql.DataSource/ One last thing, please note that you have to change the previous parameters according to your database. Hope that will help On 7/27/07, dileep_sivaraman [EMAIL PROTECTED] wrote: Hi , I am trying to register a com.ibm.db2.jcc.DB2ConnectionPoolDataSource datasource in tomcat 5.5.4. I am not getting any exception's while doing a context lookup and gives me the datasource. However the paramaeter's that are set with that Resource are always null. Server.xml GlobalNamingResources Resource name=jdbc/db2universal type=com.ibm.db2.jcc.DB2ConnectionPoolDataSource factory=com.ibm.db2.jcc.DB2DataSourceFactory serverName=PROD9S03.bankofamerica.com username=abc password=abc/ /GlobalNamingResources In my code I get the datasource as : connPoolDataSource=(DB2ConnectionPoolDataSource) envContext.lookup(jdbc/db2universal); However when I print out the serverName parameter that has been set in the resource it prints null. System.out.println(connPoolDataSource.getServerName() :+connPoolDataSource.getServerName()); OUTPUT: connPoolDataSource.getServerName() :null Can somebody tell me what I am doing wrong? -- View this message in context: http://www.nabble.com/registering-a-DB2ConnectionPoolDataSource-in-tomcat--5.5-tf4155802.html#a11823991 Sent from the Tomcat - User mailing list archive at Nabble.com. - To start a new topic, e-mail: users@tomcat.apache.org To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] - To start a new topic, e-mail: users@tomcat.apache.org To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] -- View this message in context: http://www.nabble.com/registering-a-DB2ConnectionPoolDataSource-in-tomcat--5.5-tf4155802.html#a11824613 Sent from the Tomcat - User mailing list archive at Nabble.com. - To start a new topic, e-mail: users@tomcat.apache.org To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Re: Bean and Servlet
What do you suggest to overcome this problem? On 7/25/07, Caldarale, Charles R [EMAIL PROTECTED] wrote: From: Mohammed Zabin [mailto:[EMAIL PROTECTED] Subject: Re: Bean and Servlet I will tell you the procedure; At each time the user clickes the first page in the site, a random numbers will be generated and stored in the session. You're missing the point. The user may click multiple times before the first request is even received by the webapp, or the browser may simply fire off multiple parallel requests, or the user may open multiple tabs for the same web site. All of the above will result in multiple concurrent requests occurring for the same session. Does your logic handle that properly? The code snippet you posted does not. - Chuck THIS COMMUNICATION MAY CONTAIN CONFIDENTIAL AND/OR OTHERWISE PROPRIETARY MATERIAL and is thus for use only by the intended recipient. If you received this in error, please contact the sender and delete the e-mail and its attachments from all computers. - To start a new topic, e-mail: users@tomcat.apache.org To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Re: MySql Connector
It's already wrapped man, i just copied the code snippet from within %%
marker ;), and for System.out, or out.println, It's still the same problem.
If you looked at the exception you will find ClassNotFoundException at line
66 in the generated servlet, and this occurs withing the try block, so, i
think it's a problem of Connector. But the strange thing is that this
code worked fine on a normal java class???
On 7/26/07, David Smith [EMAIL PROTECTED] wrote:
1. This can't be the complete jsp code. If it is, you need to minimally
wrap it in %% markers to indicate it's raw java code, not
jsp/html. Additionally your System.out.println() call would end up
going to the JVM's standard output instead of the browser.
2. The listed exception is really secondary to the main problem
occurring whenever the jsp compile fails to generate a .class file.
There has to be an earlier exception detailing the syntax problems with
the jsp.
--David
Mohammed Zabin wrote:
This is my jsp code:
try {
Class.forName(org.gjt.mm.mysql.Driver);
String url = jdbc:mysql://localhost:3306/exam;
Connection con = DriverManager.getConnection(url,root,
exam);
Statement stmt = con.createStatement();
ResultSet rs = stmt.executeQuery(Select type from
questions);
while( rs.next() ) {
System.out.println( rs.getString(type) );
}
} catch( Exception e ) {
}
and this is what i got:
*exception*
org.apache.jasper.JasperException: org.apache.jasper.JasperException:
Unable to load class for JSP
org.apache.jasper.servlet.JspServletWrapper.getServlet(
JspServletWrapper.java:154)
org.apache.jasper.servlet.JspServletWrapper.service(
JspServletWrapper.java:320)
org.apache.jasper.servlet.JspServlet.serviceJspFile(
JspServlet.java:320)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:266)
javax.servlet.http.HttpServlet.service(HttpServlet.java:803)
*root cause*
org.apache.jasper.JasperException: Unable to load class for JSP
org.apache.jasper.JspCompilationContext.load(
JspCompilationContext.java:600)
org.apache.jasper.servlet.JspServletWrapper.getServlet(
JspServletWrapper.java:142)
org.apache.jasper.servlet.JspServletWrapper.service(
JspServletWrapper.java:320)
org.apache.jasper.servlet.JspServlet.serviceJspFile(
JspServlet.java:320)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:266)
javax.servlet.http.HttpServlet.service(HttpServlet.java:803)
*root cause*
java.lang.ClassNotFoundException: org.apache.jsp.mySql_jsp
java.net.URLClassLoader$1.run(URLClassLoader.java:200)
java.security.AccessController.doPrivileged(Native Method)
java.net.URLClassLoader.findClass(URLClassLoader.java:188)
org.apache.jasper.servlet.JasperLoader.loadClass(JasperLoader.java
:134)
org.apache.jasper.servlet.JasperLoader.loadClass(JasperLoader.java
:66)
org.apache.jasper.JspCompilationContext.load(
JspCompilationContext.java:598)
org.apache.jasper.servlet.JspServletWrapper.getServlet(
JspServletWrapper.java:142)
org.apache.jasper.servlet.JspServletWrapper.service(
JspServletWrapper.java:320)
org.apache.jasper.servlet.JspServlet.serviceJspFile(
JspServlet.java:320)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:266)
javax.servlet.http.HttpServlet.service(HttpServlet.java:803)
Any suggestions, please?
On 7/25/07, Christopher Schultz [EMAIL PROTECTED] wrote:
-BEGIN PGP SIGNED MESSAGE-
Hash: SHA1
Mohammed,
Mohammed Zabin wrote:
I have the following error:
org.apache.jasper.JasperException: Unable to compile class for JSP:
Uhh... you have a syntax error in your JSP code. Fix that, then we'll
get back to configuration issues. You didn't give enough information to
help with the JSP syntax error.
- -chris
-BEGIN PGP SIGNATURE-
Version: GnuPG v1.4.7 (MingW32)
Comment: Using GnuPG with Mozilla - http://enigmail.mozdev.org
iD8DBQFGp2lm9CaO5/Lv0PARAvlRAJ45KuixS2Fy75ssMLQLwUYhA+DjOACgtiTN
nZhKt8DoIGh8UFwV+Ri6qWI=
=syvt
-END PGP SIGNATURE-
-
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-
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Re: MySql Connector
This is my jsp code:
try {
Class.forName(org.gjt.mm.mysql.Driver);
String url = jdbc:mysql://localhost:3306/exam;
Connection con = DriverManager.getConnection(url,root, exam);
Statement stmt = con.createStatement();
ResultSet rs = stmt.executeQuery(Select type from
questions);
while( rs.next() ) {
System.out.println( rs.getString(type) );
}
} catch( Exception e ) {
}
and this is what i got:
*exception*
org.apache.jasper.JasperException: org.apache.jasper.JasperException:
Unable to load class for JSP
org.apache.jasper.servlet.JspServletWrapper.getServlet(JspServletWrapper.java:154)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:320)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:320)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:266)
javax.servlet.http.HttpServlet.service(HttpServlet.java:803)
*root cause*
org.apache.jasper.JasperException: Unable to load class for JSP
org.apache.jasper.JspCompilationContext.load(JspCompilationContext.java:600)
org.apache.jasper.servlet.JspServletWrapper.getServlet(JspServletWrapper.java:142)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:320)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:320)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:266)
javax.servlet.http.HttpServlet.service(HttpServlet.java:803)
*root cause*
java.lang.ClassNotFoundException: org.apache.jsp.mySql_jsp
java.net.URLClassLoader$1.run(URLClassLoader.java:200)
java.security.AccessController.doPrivileged(Native Method)
java.net.URLClassLoader.findClass(URLClassLoader.java:188)
org.apache.jasper.servlet.JasperLoader.loadClass(JasperLoader.java:134)
org.apache.jasper.servlet.JasperLoader.loadClass(JasperLoader.java:66)
org.apache.jasper.JspCompilationContext.load(JspCompilationContext.java:598)
org.apache.jasper.servlet.JspServletWrapper.getServlet(JspServletWrapper.java:142)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:320)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:320)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:266)
javax.servlet.http.HttpServlet.service(HttpServlet.java:803)
Any suggestions, please?
On 7/25/07, Christopher Schultz [EMAIL PROTECTED] wrote:
-BEGIN PGP SIGNED MESSAGE-
Hash: SHA1
Mohammed,
Mohammed Zabin wrote:
I have the following error:
org.apache.jasper.JasperException: Unable to compile class for JSP:
Uhh... you have a syntax error in your JSP code. Fix that, then we'll
get back to configuration issues. You didn't give enough information to
help with the JSP syntax error.
- -chris
-BEGIN PGP SIGNATURE-
Version: GnuPG v1.4.7 (MingW32)
Comment: Using GnuPG with Mozilla - http://enigmail.mozdev.org
iD8DBQFGp2lm9CaO5/Lv0PARAvlRAJ45KuixS2Fy75ssMLQLwUYhA+DjOACgtiTN
nZhKt8DoIGh8UFwV+Ri6qWI=
=syvt
-END PGP SIGNATURE-
-
To start a new topic, e-mail: users@tomcat.apache.org
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Re: Bean and Servlet
I have changed like this: pageContext.getRequest().setAttribute(InQry, qry); and retrieve it in the servlet like this: inQry = (String)request.getAttribute(InQry); But when using request attributes, inQry will be null when retrieved? On 7/26/07, Mohammed Zabin [EMAIL PROTECTED] wrote: What do you suggest to overcome this problem? On 7/25/07, Caldarale, Charles R [EMAIL PROTECTED] wrote: From: Mohammed Zabin [mailto:[EMAIL PROTECTED] Subject: Re: Bean and Servlet I will tell you the procedure; At each time the user clickes the first page in the site, a random numbers will be generated and stored in the session. You're missing the point. The user may click multiple times before the first request is even received by the webapp, or the browser may simply fire off multiple parallel requests, or the user may open multiple tabs for the same web site. All of the above will result in multiple concurrent requests occurring for the same session. Does your logic handle that properly? The code snippet you posted does not. - Chuck THIS COMMUNICATION MAY CONTAIN CONFIDENTIAL AND/OR OTHERWISE PROPRIETARY MATERIAL and is thus for use only by the intended recipient. If you received this in error, please contact the sender and delete the e-mail and its attachments from all computers. - To start a new topic, e-mail: users@tomcat.apache.org To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Re: Bean and Servlet
Well, I will descript the problem exactly. the first page use a tag class to render a random question from database, and their possible answers, the user must choose the right answer and submit the form for processing. I need the random question numbers, which are question ids to *Results*servlet. *Results* servlet is a servlet that must display the same questions that was displayed in the Questions page to run a query against the database to display the questions and the correct and wrong answers. My Problem is that, I want to pass these numbers, Questions IDs, from the first page, which i have made it as a tag class, to Results page, which was made as servlet. I tried to use request.setAttribute(Ids, ids); but when retrieve it in Results servlet, I got *null. * That was my problem my buddy, by the way, when i used session, it worked fine. and you stated that this will not work, but i think that storing these ids in a session is a good choice, isn't it? If you have any comments please post it. On 7/26/07, Caldarale, Charles R [EMAIL PROTECTED] wrote: From: Mohammed Zabin [mailto:[EMAIL PROTECTED] Subject: Re: Bean and Servlet What do you suggest to overcome this problem? In the seven messages you've posted in this thread, you've never really explained what this attribute is being used for; nor have you answered the question of whether or not it's used only for the duration of a single request or is applicable to everything a given user does with this particular webapp. Until you give us some idea of what your intent is (as opposed to code snippets), I don't think anyone can really answer your questions. If you do need to store attributes in a session, you will need at least some synchronization logic to see if the attribute is already present, since multiple requests can easily be using the Session object concurrently. - Chuck THIS COMMUNICATION MAY CONTAIN CONFIDENTIAL AND/OR OTHERWISE PROPRIETARY MATERIAL and is thus for use only by the intended recipient. If you received this in error, please contact the sender and delete the e-mail and its attachments from all computers. - To start a new topic, e-mail: users@tomcat.apache.org To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Re: MySql Connector
For test purposes, i have wrote the following code as a java program and it
worked fine, but when I tried it in a jsp page i got the following error:
Class.forName(com.mysql.jdbc.Driver);
String url = jdbc:mysql://localhost:3306/exam;
Connection con = DriverManager.getConnection(url,root, exam);
Statement stmt = con.createStatement();
ResultSet rs = stmt.executeQuery(Select type from questions);
while( rs.next() ) {
System.out.println( rs.getString(type) );
}
org.apache.jasper.JasperException: Unable to compile class for JSP:
Stacktrace:
org.apache.jasper.compiler.DefaultErrorHandler.javacError(DefaultErrorHandler.java:85)
org.apache.jasper.compiler.ErrorDispatcher.javacError(ErrorDispatcher.java:330)
org.apache.jasper.compiler.JDTCompiler.generateClass(JDTCompiler.java:415)
org.apache.jasper.compiler.Compiler.compile(Compiler.java:308)
org.apache.jasper.compiler.Compiler.compile(Compiler.java:286)
org.apache.jasper.compiler.Compiler.compile(Compiler.java:273)
org.apache.jasper.JspCompilationContext.compile(JspCompilationContext.java:566)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:308)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:320)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:266)
javax.servlet.http.HttpServlet.service(HttpServlet.java:803)
On 7/25/07, Mohammed Zabin [EMAIL PROTECTED] wrote:
In cotrast, i have installed Oracle and worked very well, but MySql didn't
work with me. I am using Connecter/J from MySql website, the beta version, I
put the jar file in the CATALINA_HOME/lib, and i add it to the CLASSPATH.
and I followed the instructions provided in Tomcat documentation, exactly,
Didn't work :(
On 7/24/07, David Smith [EMAIL PROTECTED] wrote:
I've never dealt with Oracle but have done a lot of MySQL installs
without a single failure. Your config outside of the web.xml doesn't
look wrong in any way.
You might want to put the resource-ref block in your web.xml as
described in the how-to's. It doesn't hurt and is part of the servlet
spec.
--David
Mohammed Zabin wrote:
No, the same error, You know what David?? I put nothing in web.xml, I
am
confused about this issue, when to use web.xml, and it might be the
reason
behind the unsuccessfull MySql Connection, I follow the same procedure
I
followed to configure Oracle DBCP, I think it must work for MySql,
right?
On 7/24/07, David Smith [EMAIL PROTECTED] wrote:
Try this variant of your code:
Context initContext = new InitialContext();
DataSource ds =
(DataSource)initContext.lookup(java:comp/env/jdbc/TestMySql);
Connection conn = ds.getConnection ();
out.println(Connection Established);
Essentially when you lookup java:comp/env/jdbc/TestMySql, that's the
full JNDI path to the DataSource and returns a DataSource type
object,
not a Context type object.
--David
Mohammed Zabin wrote:
Ok thank you, I did the following as you have stated:
1. in server.xml:
Resource name=jdbc/TestMySql auth=Container
type=javax.sql.DataSource
maxActive=100 maxIdle=30 maxWait=1
username=root password=exam driverClassName=
com.mysql.jdbc.Driver
url=jdbc:mysql://localhost:3306/exam/
2. in context.xml
ResourceLink global=jdbc/TestMySql name=jdbc/TestMySql type=
javax.sql.DataSource/
3. in my test page:
Context initContext = new InitialContext();
Context envContext =
(Context)initContext.lookup(java:comp/env/jdbc/TestMySql);
DataSource ds = (DataSource)envContext.lookup(jdbc/TestMySql);
Connection conn = ds.getConnection();
out.println(Connection Established);
And i put nothing in web.xml, I have the following error:
org.apache.jasper.JasperException: Unable to compile class for JSP:
Stacktrace:
org.apache.jasper.compiler.DefaultErrorHandler.javacError (
DefaultErrorHandler.java:85)
org.apache.jasper.compiler.ErrorDispatcher.javacError(
ErrorDispatcher.java:330)
org.apache.jasper.compiler.JDTCompiler.generateClass (
JDTCompiler.java:415)
org.apache.jasper.compiler.Compiler.compile(Compiler.java:308)
org.apache.jasper.compiler.Compiler.compile(Compiler.java:286)
org.apache.jasper.compiler.Compiler.compile(Compiler.java:273)
org.apache.jasper.JspCompilationContext.compile(
JspCompilationContext.java:566)
org.apache.jasper.servlet.JspServletWrapper.service(
JspServletWrapper.java:308)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java
:320)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java
:266)
javax.servlet.http.HttpServlet.service(HttpServlet.java:803)
On 7/23/07, David Smith [EMAIL PROTECTED] wrote:
A few things to consider:
1
Re: MySql Connector
This is all the exception message, I looked inside logs folder, i found an
empty file, it continas nothing :~
On 7/25/07, David Smith [EMAIL PROTECTED] wrote:
Your stack trace appears to be incomplete. Could you post more? It
appears to be a compile error and should cite the code in question.
--David
Mohammed Zabin wrote:
For test purposes, i have wrote the following code as a java program
and it
worked fine, but when I tried it in a jsp page i got the following
error:
Class.forName(com.mysql.jdbc.Driver);
String url = jdbc:mysql://localhost:3306/exam;
Connection con = DriverManager.getConnection(url,root, exam);
Statement stmt = con.createStatement();
ResultSet rs = stmt.executeQuery(Select type from questions);
while( rs.next() ) {
System.out.println( rs.getString(type) );
}
org.apache.jasper.JasperException: Unable to compile class for JSP:
Stacktrace:
org.apache.jasper.compiler.DefaultErrorHandler.javacError(
DefaultErrorHandler.java:85)
org.apache.jasper.compiler.ErrorDispatcher.javacError(
ErrorDispatcher.java:330)
org.apache.jasper.compiler.JDTCompiler.generateClass(
JDTCompiler.java:415)
org.apache.jasper.compiler.Compiler.compile(Compiler.java:308)
org.apache.jasper.compiler.Compiler.compile(Compiler.java:286)
org.apache.jasper.compiler.Compiler.compile(Compiler.java:273)
org.apache.jasper.JspCompilationContext.compile(
JspCompilationContext.java:566)
org.apache.jasper.servlet.JspServletWrapper.service(
JspServletWrapper.java:308)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java
:320)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:266)
javax.servlet.http.HttpServlet.service(HttpServlet.java:803)
On 7/25/07, Mohammed Zabin [EMAIL PROTECTED] wrote:
In cotrast, i have installed Oracle and worked very well, but MySql
didn't
work with me. I am using Connecter/J from MySql website, the beta
version, I
put the jar file in the CATALINA_HOME/lib, and i add it to the
CLASSPATH.
and I followed the instructions provided in Tomcat documentation,
exactly,
Didn't work :(
On 7/24/07, David Smith [EMAIL PROTECTED] wrote:
I've never dealt with Oracle but have done a lot of MySQL installs
without a single failure. Your config outside of the web.xml doesn't
look wrong in any way.
You might want to put the resource-ref block in your web.xml as
described in the how-to's. It doesn't hurt and is part of the
servlet
spec.
--David
Mohammed Zabin wrote:
No, the same error, You know what David?? I put nothing in
web.xml, I
am
confused about this issue, when to use web.xml, and it might be the
reason
behind the unsuccessfull MySql Connection, I follow the same
procedure
I
followed to configure Oracle DBCP, I think it must work for MySql,
right?
On 7/24/07, David Smith [EMAIL PROTECTED] wrote:
Try this variant of your code:
Context initContext = new InitialContext();
DataSource ds =
(DataSource)initContext.lookup(java:comp/env/jdbc/TestMySql);
Connection conn = ds.getConnection ();
out.println(Connection Established);
Essentially when you lookup java:comp/env/jdbc/TestMySql, that's
the
full JNDI path to the DataSource and returns a DataSource type
object,
not a Context type object.
--David
Mohammed Zabin wrote:
Ok thank you, I did the following as you have stated:
1. in server.xml:
Resource name=jdbc/TestMySql auth=Container
type=javax.sql.DataSource
maxActive=100 maxIdle=30 maxWait=1
username=root password=exam
driverClassName=
com.mysql.jdbc.Driver
url=jdbc:mysql://localhost:3306/exam/
2. in context.xml
ResourceLink global=jdbc/TestMySql name=jdbc/TestMySql
type=
javax.sql.DataSource/
3. in my test page:
Context initContext = new InitialContext();
Context envContext =
(Context)initContext.lookup(java:comp/env/jdbc/TestMySql);
DataSource ds =
(DataSource)envContext.lookup(jdbc/TestMySql);
Connection conn = ds.getConnection();
out.println(Connection Established);
And i put nothing in web.xml, I have the following error:
org.apache.jasper.JasperException: Unable to compile class for
JSP:
Stacktrace:
org.apache.jasper.compiler.DefaultErrorHandler.javacError (
DefaultErrorHandler.java:85)
org.apache.jasper.compiler.ErrorDispatcher.javacError(
ErrorDispatcher.java:330)
org.apache.jasper.compiler.JDTCompiler.generateClass (
JDTCompiler.java:415)
org.apache.jasper.compiler.Compiler.compile(Compiler.java:308)
org.apache.jasper.compiler.Compiler.compile(Compiler.java:286)
org.apache.jasper.compiler.Compiler.compile(Compiler.java:273)
org.apache.jasper.JspCompilationContext.compile(
JspCompilationContext.java:566
Re: MySql Connector
I did this, but i think that there is an option to enable logging, do u know
it?
On 7/25/07, David Smith [EMAIL PROTECTED] wrote:
I'm starting to think there's something really funny (ie broken) with
your tomcat install. Could you clean install another instance of tomcat
(preferably downloaded from the tomcat website) and check the code there?
--David
Mohammed Zabin wrote:
This is all the exception message, I looked inside logs folder, i
found an
empty file, it continas nothing :~
On 7/25/07, David Smith [EMAIL PROTECTED] wrote:
Your stack trace appears to be incomplete. Could you post more? It
appears to be a compile error and should cite the code in question.
--David
Mohammed Zabin wrote:
For test purposes, i have wrote the following code as a java program
and it
worked fine, but when I tried it in a jsp page i got the following
error:
Class.forName(com.mysql.jdbc.Driver);
String url = jdbc:mysql://localhost:3306/exam;
Connection con = DriverManager.getConnection(url,root, exam);
Statement stmt = con.createStatement();
ResultSet rs = stmt.executeQuery(Select type from questions);
while( rs.next() ) {
System.out.println( rs.getString(type) );
}
org.apache.jasper.JasperException: Unable to compile class for JSP:
Stacktrace:
org.apache.jasper.compiler.DefaultErrorHandler.javacError(
DefaultErrorHandler.java:85)
org.apache.jasper.compiler.ErrorDispatcher.javacError(
ErrorDispatcher.java:330)
org.apache.jasper.compiler.JDTCompiler.generateClass(
JDTCompiler.java:415)
org.apache.jasper.compiler.Compiler.compile(Compiler.java:308)
org.apache.jasper.compiler.Compiler.compile(Compiler.java:286)
org.apache.jasper.compiler.Compiler.compile(Compiler.java:273)
org.apache.jasper.JspCompilationContext.compile(
JspCompilationContext.java:566)
org.apache.jasper.servlet.JspServletWrapper.service(
JspServletWrapper.java:308)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java
:320)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:266)
javax.servlet.http.HttpServlet.service(HttpServlet.java:803)
-
To start a new topic, e-mail: users@tomcat.apache.org
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
Re: Bean and Servlet
Thank you I solve it using session, particularly: pageContext.getSession().setAttribute(InQry, qry); and retreive it in the servlet like this: String inQry = (String)request.getSession().getAttribute(InQry); But, I have a question regarding DBCP, it is not wrong to have more than one CP, isn't it? I mean is it allowed to have a Resource for Oracle and another for MySql? On 7/24/07, David Smith [EMAIL PROTECTED] wrote: Can you post the relevant parts of how/where you call this servlet? I've never had a problem retrieving a request attribute after it was added and before the end of the request. --David Mohammed Zabin wrote: Actually, I wanted to pass this list from within a Tag to be used inside another Servlet class, (i.e. the tag class after finishing rendering its elements, goes to a servlet, so, i need to pass this list to that servlet. As i have stated above, i used the following to store the list in the request object: [code]pageContext.getRequest().setAttribute(QList, list);[/code] In the servlet, i used the following to retrive the list: ListInteger list = (ListInteger)request.getAttribute( QList); I tried to access the above list by a small code snippet that prints its size: [code]out.println( list.size() );[/code] But i got an exception stating that a NullPointerException has occured at the size printing statement. That's mean, i think, the list didn't stored correctly in the request object, am I true? On 7/23/07, David Smith [EMAIL PROTECTED] wrote: Typical design is servlet forwarding to jsp for view. Tags being jsp elements occur after servlets have executed. So you can see how your problem is a little curious in that jsps don't typically forward to servlets. If you are forwarding a request from jsp to servlet, let us know. However if you are storing a object in a request during jsp execution intending it to be available to the servlet on the next request, that doesn't work. The request is cleared and recycled when jsps finish writing to the client. When a new request comes in, the request attribute list is empty. If you need this list to live between requests, you need to place it in the session. --David Mohammed Zabin wrote: Thank you Johnny, To be specific this is my question Hi all I am trying to pass an object from a tag to a servlet. i did the following, 1. In the tag class, i put: pageContext.getRequest().setAttribute(QList, list); The above Tag will go to a servlet, i need to read the above request attribute in the servlet, how can i do this?, i tried ListInteger list = (ListInteger)request.getAttribute(QList); , but when i tried to access the read list, it gave me NullPointerException...What do u think? On 7/23/07, Johnny Kewl [EMAIL PROTECTED] wrote: Hi Mohammed, Cant say I really understand the question In general this is what the Session Objects are for So say you have a servlet and a JSP page and say the servlet makes the bean with the Array List in it then if you session.setAttribute(MyBean, MyBean); you can get it (MyBean) back when the next call comes into say the JSP page Now if you read up on this you will see you can also set 'request' objects and these are good for when you say dispatch a request to a JSP page from the servlet and want to pass a bean across. Anyway... if you just google for servlet session and setAttribute you will be on your way... I think ;) This area of servlet programming is one of the things that make it such a powerful technology. Have fun... - Original Message - From: Mohammed Zabin [EMAIL PROTECTED] To: Tomcat Users List users@tomcat.apache.org Sent: Monday, July 23, 2007 11:18 AM Subject: Bean and Servlet Hi All What is the best way to pass a list collection from a Bean to a Servlet? Thank you - To start a new topic, e-mail: users@tomcat.apache.org To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] - To start a new topic, e-mail: users@tomcat.apache.org To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] - To start a new topic, e-mail: users@tomcat.apache.org To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Re: MySql Connector
Ok thank you, I did the following as you have stated: 1. in server.xml: Resource name=jdbc/TestMySql auth=Container type=javax.sql.DataSource maxActive=100 maxIdle=30 maxWait=1 username=root password=exam driverClassName= com.mysql.jdbc.Driver url=jdbc:mysql://localhost:3306/exam/ 2. in context.xml ResourceLink global=jdbc/TestMySql name=jdbc/TestMySql type= javax.sql.DataSource/ 3. in my test page: Context initContext = new InitialContext(); Context envContext = (Context)initContext.lookup(java:comp/env/jdbc/TestMySql); DataSource ds = (DataSource)envContext.lookup(jdbc/TestMySql); Connection conn = ds.getConnection(); out.println(Connection Established); And i put nothing in web.xml, I have the following error: org.apache.jasper.JasperException: Unable to compile class for JSP: Stacktrace: org.apache.jasper.compiler.DefaultErrorHandler.javacError(DefaultErrorHandler.java:85) org.apache.jasper.compiler.ErrorDispatcher.javacError(ErrorDispatcher.java:330) org.apache.jasper.compiler.JDTCompiler.generateClass(JDTCompiler.java:415) org.apache.jasper.compiler.Compiler.compile(Compiler.java:308) org.apache.jasper.compiler.Compiler.compile(Compiler.java:286) org.apache.jasper.compiler.Compiler.compile(Compiler.java:273) org.apache.jasper.JspCompilationContext.compile(JspCompilationContext.java:566) org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:308) org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:320) org.apache.jasper.servlet.JspServlet.service(JspServlet.java:266) javax.servlet.http.HttpServlet.service(HttpServlet.java:803) On 7/23/07, David Smith [EMAIL PROTECTED] wrote: A few things to consider: 1. Either place your Resource definition in server.xml as a GlobalResource *OR* in your webapp's context.xml file. 2. If you have the Resource defined in the GlobalResources, that's the only time you need to use a ResourceLink element in context.xml. 3. Drop the autoReconnect parameter in your mysql URL. It has it's uses, but not in a pooled environment. 4. You should probably be attempting to use the path java:comp/env/jdbc/TestMySQL (note the lack of a '/' before comp) as described in the JNDI howto on tomcat's website. I think I saw you using java:/comp/env/jdbc/TestMySQL in one of your posts. 5. Please post relevant messages from your logs if this isn't working. --David Mohammed Zabin wrote: Would you please be more specific? which file you mean? I have created Oracel connection Pool as the stated way above, and it's worked fine, shall i put resource defeninitoin in context.xml only? On 7/22/07, Pid [EMAIL PROTECTED] wrote: You only need one resource definition. You only need a resource link definition if your resource is a global one. Simplify your configuration and then post the error message from the logs so we can see Tomcat says is wrong. p Mohammed Zabin wrote: Hi All I have confiured oracle connection pool on my tomacat 6, and it worked fine. When i came to configure MySql, I repeated the same steps for Oracle databse, with considering the specfication of MySql database. But it's didn't work. Any Help please about configuring MySql, I downloaded MySql connector from mysql website and place it in CATALINA_HOME/lib directory, and i put the following: 1. in server.xml file: Resource name=jdbc/TestMySql auth=Container type=javax.sql.DataSource maxActive=100 maxIdle=30 maxWait=1 username=* password=* driverClassName= com.mysql.jdbc.Driver url=jdbc:mysql://localhost:3306/exam?autoReconnect=true/ 2. in web.xml file resource-ref descriptionOracle Datasource example/description res-ref-namejdbc/TestMySql/res-ref-name res-typejavax.sql.DataSource/res-type res-authContainer/res-auth /resource-ref 3. in context.xml file (on server's context.xml file): Resource name=jdbc/TestMySql auth=Container type=javax.sql.DataSource maxActive=100 maxIdle=30 maxWait=1 username=* password=* driverClassName= com.mysql.jdbc.Driver url=jdbc:mysql://localhost:3306/exam/ 4. in cotext.xml file ( In my web application's context.xml file): ResourceLink global=jdbc/TestMySql name=jdbc/TestMySql type= javax.sql.DataSource/ Any Help please? - To start a new topic, e-mail: users@tomcat.apache.org To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Re: MySql Connector
No, the same error, You know what David?? I put nothing in web.xml, I am confused about this issue, when to use web.xml, and it might be the reason behind the unsuccessfull MySql Connection, I follow the same procedure I followed to configure Oracle DBCP, I think it must work for MySql, right? On 7/24/07, David Smith [EMAIL PROTECTED] wrote: Try this variant of your code: Context initContext = new InitialContext(); DataSource ds = (DataSource)initContext.lookup(java:comp/env/jdbc/TestMySql); Connection conn = ds.getConnection(); out.println(Connection Established); Essentially when you lookup java:comp/env/jdbc/TestMySql, that's the full JNDI path to the DataSource and returns a DataSource type object, not a Context type object. --David Mohammed Zabin wrote: Ok thank you, I did the following as you have stated: 1. in server.xml: Resource name=jdbc/TestMySql auth=Container type=javax.sql.DataSource maxActive=100 maxIdle=30 maxWait=1 username=root password=exam driverClassName= com.mysql.jdbc.Driver url=jdbc:mysql://localhost:3306/exam/ 2. in context.xml ResourceLink global=jdbc/TestMySql name=jdbc/TestMySql type= javax.sql.DataSource/ 3. in my test page: Context initContext = new InitialContext(); Context envContext = (Context)initContext.lookup(java:comp/env/jdbc/TestMySql); DataSource ds = (DataSource)envContext.lookup(jdbc/TestMySql); Connection conn = ds.getConnection(); out.println(Connection Established); And i put nothing in web.xml, I have the following error: org.apache.jasper.JasperException: Unable to compile class for JSP: Stacktrace: org.apache.jasper.compiler.DefaultErrorHandler.javacError( DefaultErrorHandler.java:85) org.apache.jasper.compiler.ErrorDispatcher.javacError( ErrorDispatcher.java:330) org.apache.jasper.compiler.JDTCompiler.generateClass( JDTCompiler.java:415) org.apache.jasper.compiler.Compiler.compile(Compiler.java:308) org.apache.jasper.compiler.Compiler.compile(Compiler.java:286) org.apache.jasper.compiler.Compiler.compile(Compiler.java:273) org.apache.jasper.JspCompilationContext.compile( JspCompilationContext.java:566) org.apache.jasper.servlet.JspServletWrapper.service( JspServletWrapper.java:308) org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java :320) org.apache.jasper.servlet.JspServlet.service(JspServlet.java:266) javax.servlet.http.HttpServlet.service(HttpServlet.java:803) On 7/23/07, David Smith [EMAIL PROTECTED] wrote: A few things to consider: 1. Either place your Resource definition in server.xml as a GlobalResource *OR* in your webapp's context.xml file. 2. If you have the Resource defined in the GlobalResources, that's the only time you need to use a ResourceLink element in context.xml. 3. Drop the autoReconnect parameter in your mysql URL. It has it's uses, but not in a pooled environment. 4. You should probably be attempting to use the path java:comp/env/jdbc/TestMySQL (note the lack of a '/' before comp) as described in the JNDI howto on tomcat's website. I think I saw you using java:/comp/env/jdbc/TestMySQL in one of your posts. 5. Please post relevant messages from your logs if this isn't working. --David Mohammed Zabin wrote: Would you please be more specific? which file you mean? I have created Oracel connection Pool as the stated way above, and it's worked fine, shall i put resource defeninitoin in context.xml only? On 7/22/07, Pid [EMAIL PROTECTED] wrote: You only need one resource definition. You only need a resource link definition if your resource is a global one. Simplify your configuration and then post the error message from the logs so we can see Tomcat says is wrong. p Mohammed Zabin wrote: Hi All I have confiured oracle connection pool on my tomacat 6, and it worked fine. When i came to configure MySql, I repeated the same steps for Oracle databse, with considering the specfication of MySql database. But it's didn't work. Any Help please about configuring MySql, I downloaded MySql connector from mysql website and place it in CATALINA_HOME/lib directory, and i put the following: 1. in server.xml file: Resource name=jdbc/TestMySql auth=Container type=javax.sql.DataSource maxActive=100 maxIdle=30 maxWait=1 username=* password=* driverClassName= com.mysql.jdbc.Driver url=jdbc:mysql://localhost:3306/exam?autoReconnect=true/ 2. in web.xml file resource-ref descriptionOracle Datasource example/description res-ref-namejdbc/TestMySql/res-ref-name res-typejavax.sql.DataSource/res-type res-authContainer/res-auth /resource-ref 3. in context.xml file (on server's context.xml file): Resource name=jdbc/TestMySql auth=Container type=javax.sql.DataSource
Re: Bean and Servlet
I will tell you the procedure; At each time the user clickes the first page in the site, a random numbers will be generated and stored in the session. So, i think that each user has its own numbers, right? On 7/24/07, Caldarale, Charles R [EMAIL PROTECTED] wrote: From: Mohammed Zabin [mailto:[EMAIL PROTECTED] Subject: Re: Bean and Servlet Thank you I solve it using session, particularly: pageContext.getSession().setAttribute(InQry, qry); Are you sure you want to do that? If multiple requests from the browser are being processed concurrently, any data at session scope will be shared amongst them. - Chuck THIS COMMUNICATION MAY CONTAIN CONFIDENTIAL AND/OR OTHERWISE PROPRIETARY MATERIAL and is thus for use only by the intended recipient. If you received this in error, please contact the sender and delete the e-mail and its attachments from all computers. - To start a new topic, e-mail: users@tomcat.apache.org To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Re: MySql Connector
In cotrast, i have installed Oracle and worked very well, but MySql didn't work with me. I am using Connecter/J from MySql website, the beta version, I put the jar file in the CATALINA_HOME/lib, and i add it to the CLASSPATH. and I followed the instructions provided in Tomcat documentation, exactly, Didn't work :( On 7/24/07, David Smith [EMAIL PROTECTED] wrote: I've never dealt with Oracle but have done a lot of MySQL installs without a single failure. Your config outside of the web.xml doesn't look wrong in any way. You might want to put the resource-ref block in your web.xml as described in the how-to's. It doesn't hurt and is part of the servlet spec. --David Mohammed Zabin wrote: No, the same error, You know what David?? I put nothing in web.xml, I am confused about this issue, when to use web.xml, and it might be the reason behind the unsuccessfull MySql Connection, I follow the same procedure I followed to configure Oracle DBCP, I think it must work for MySql, right? On 7/24/07, David Smith [EMAIL PROTECTED] wrote: Try this variant of your code: Context initContext = new InitialContext(); DataSource ds = (DataSource)initContext.lookup(java:comp/env/jdbc/TestMySql); Connection conn = ds.getConnection(); out.println(Connection Established); Essentially when you lookup java:comp/env/jdbc/TestMySql, that's the full JNDI path to the DataSource and returns a DataSource type object, not a Context type object. --David Mohammed Zabin wrote: Ok thank you, I did the following as you have stated: 1. in server.xml: Resource name=jdbc/TestMySql auth=Container type=javax.sql.DataSource maxActive=100 maxIdle=30 maxWait=1 username=root password=exam driverClassName= com.mysql.jdbc.Driver url=jdbc:mysql://localhost:3306/exam/ 2. in context.xml ResourceLink global=jdbc/TestMySql name=jdbc/TestMySql type= javax.sql.DataSource/ 3. in my test page: Context initContext = new InitialContext(); Context envContext = (Context)initContext.lookup(java:comp/env/jdbc/TestMySql); DataSource ds = (DataSource)envContext.lookup(jdbc/TestMySql); Connection conn = ds.getConnection(); out.println(Connection Established); And i put nothing in web.xml, I have the following error: org.apache.jasper.JasperException: Unable to compile class for JSP: Stacktrace: org.apache.jasper.compiler.DefaultErrorHandler.javacError( DefaultErrorHandler.java:85) org.apache.jasper.compiler.ErrorDispatcher.javacError( ErrorDispatcher.java:330) org.apache.jasper.compiler.JDTCompiler.generateClass( JDTCompiler.java:415) org.apache.jasper.compiler.Compiler.compile(Compiler.java:308) org.apache.jasper.compiler.Compiler.compile(Compiler.java:286) org.apache.jasper.compiler.Compiler.compile(Compiler.java:273) org.apache.jasper.JspCompilationContext.compile( JspCompilationContext.java:566) org.apache.jasper.servlet.JspServletWrapper.service( JspServletWrapper.java:308) org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java :320) org.apache.jasper.servlet.JspServlet.service(JspServlet.java:266) javax.servlet.http.HttpServlet.service(HttpServlet.java:803) On 7/23/07, David Smith [EMAIL PROTECTED] wrote: A few things to consider: 1. Either place your Resource definition in server.xml as a GlobalResource *OR* in your webapp's context.xml file. 2. If you have the Resource defined in the GlobalResources, that's the only time you need to use a ResourceLink element in context.xml. 3. Drop the autoReconnect parameter in your mysql URL. It has it's uses, but not in a pooled environment. 4. You should probably be attempting to use the path java:comp/env/jdbc/TestMySQL (note the lack of a '/' before comp) as described in the JNDI howto on tomcat's website. I think I saw you using java:/comp/env/jdbc/TestMySQL in one of your posts. 5. Please post relevant messages from your logs if this isn't working. --David Mohammed Zabin wrote: Would you please be more specific? which file you mean? I have created Oracel connection Pool as the stated way above, and it's worked fine, shall i put resource defeninitoin in context.xml only? On 7/22/07, Pid [EMAIL PROTECTED] wrote: You only need one resource definition. You only need a resource link definition if your resource is a global one. Simplify your configuration and then post the error message from the logs so we can see Tomcat says is wrong. p Mohammed Zabin wrote: Hi All I have confiured oracle connection pool on my tomacat 6, and it worked fine. When i came to configure MySql, I repeated the same steps for Oracle databse, with considering the specfication of MySql database. But it's didn't work. Any Help please about configuring
Bean and Servlet
Hi All What is the best way to pass a list collection from a Bean to a Servlet? Thank you
Tags and Servlets
Hi all I am trying to pass an object from a tag to a servlet. i did the following, 1. In the tag class, i put: pageContext.getRequest().setAttribute(QList, list); The above Tag will go to a servlet, i need to read the above request attribute in the servlet, how can i do this?, i tried ListInteger list = (ListInteger)request.getAttribute(QList); , but when i tried to access the read list, it gave me NullPointerException, any help please Jotnarta
Re: Bean and Servlet
Thank you Johnny, To be specific this is my question Hi all I am trying to pass an object from a tag to a servlet. i did the following, 1. In the tag class, i put: pageContext.getRequest().setAttribute(QList, list); The above Tag will go to a servlet, i need to read the above request attribute in the servlet, how can i do this?, i tried ListInteger list = (ListInteger)request.getAttribute(QList); , but when i tried to access the read list, it gave me NullPointerException...What do u think? On 7/23/07, Johnny Kewl [EMAIL PROTECTED] wrote: Hi Mohammed, Cant say I really understand the question In general this is what the Session Objects are for So say you have a servlet and a JSP page and say the servlet makes the bean with the Array List in it then if you session.setAttribute(MyBean, MyBean); you can get it (MyBean) back when the next call comes into say the JSP page Now if you read up on this you will see you can also set 'request' objects and these are good for when you say dispatch a request to a JSP page from the servlet and want to pass a bean across. Anyway... if you just google for servlet session and setAttribute you will be on your way... I think ;) This area of servlet programming is one of the things that make it such a powerful technology. Have fun... - Original Message - From: Mohammed Zabin [EMAIL PROTECTED] To: Tomcat Users List users@tomcat.apache.org Sent: Monday, July 23, 2007 11:18 AM Subject: Bean and Servlet Hi All What is the best way to pass a list collection from a Bean to a Servlet? Thank you - To start a new topic, e-mail: users@tomcat.apache.org To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
MySql Connector
Hi All I have confiured oracle connection pool on my tomacat 6, and it worked fine. When i came to configure MySql, I repeated the same steps for Oracle databse, with considering the specfication of MySql database. But it's didn't work. Any Help please about configuring MySql, I downloaded MySql connector from mysql website and place it in CATALINA_HOME/lib directory, and i put the following: 1. in server.xml file: Resource name=jdbc/TestMySql auth=Container type=javax.sql.DataSource maxActive=100 maxIdle=30 maxWait=1 username=root password=exam driverClassName= com.mysql.jdbc.Driver url=jdbc:mysql://localhost:3306/exam?autoReconnect=true/ 2. in web.xml file resource-ref descriptionOracle Datasource example/description res-ref-namejdbc/TestMySql/res-ref-name res-typejavax.sql.DataSource/res-type res-authContainer/res-auth /resource-ref 3. in context.xml file (on server's context.xml file): Resource name=jdbc/TestMySql auth=Container type=javax.sql.DataSource maxActive=100 maxIdle=30 maxWait=1 username=root password=exam driverClassName= com.mysql.jdbc.Driver url=jdbc:mysql://localhost:3306/exam/ 4. in cotext.xml file ( In my web application's context.xml file): ResourceLink global=jdbc/TestMySql name=jdbc/TestMySql type= javax.sql.DataSource/ Any Help please?
Re: MySql Connector
Would you please be more specific? which file you mean? I have created Oracel connection Pool as the stated way above, and it's worked fine, shall i put resource defeninitoin in context.xml only? On 7/22/07, Pid [EMAIL PROTECTED] wrote: You only need one resource definition. You only need a resource link definition if your resource is a global one. Simplify your configuration and then post the error message from the logs so we can see Tomcat says is wrong. p Mohammed Zabin wrote: Hi All I have confiured oracle connection pool on my tomacat 6, and it worked fine. When i came to configure MySql, I repeated the same steps for Oracle databse, with considering the specfication of MySql database. But it's didn't work. Any Help please about configuring MySql, I downloaded MySql connector from mysql website and place it in CATALINA_HOME/lib directory, and i put the following: 1. in server.xml file: Resource name=jdbc/TestMySql auth=Container type=javax.sql.DataSource maxActive=100 maxIdle=30 maxWait=1 username=* password=* driverClassName= com.mysql.jdbc.Driver url=jdbc:mysql://localhost:3306/exam?autoReconnect=true/ 2. in web.xml file resource-ref descriptionOracle Datasource example/description res-ref-namejdbc/TestMySql/res-ref-name res-typejavax.sql.DataSource/res-type res-authContainer/res-auth /resource-ref 3. in context.xml file (on server's context.xml file): Resource name=jdbc/TestMySql auth=Container type=javax.sql.DataSource maxActive=100 maxIdle=30 maxWait=1 username=* password=* driverClassName= com.mysql.jdbc.Driver url=jdbc:mysql://localhost:3306/exam/ 4. in cotext.xml file ( In my web application's context.xml file): ResourceLink global=jdbc/TestMySql name=jdbc/TestMySql type= javax.sql.DataSource/ Any Help please?
Re: MySql Connector
Thank you, what about testing the connection, i am afraid that the test code is the reason: Context initContext = new InitialContext(); Context envContext = (Context)initContext.lookup(java:/comp/env); DataSource ds = (DataSource)envContext.lookup(jdbc/TestMySql); Connection conn = ds.getConnection(); out.println(Connection Established); what is java:/comp/env?? On 7/22/07, Pid [EMAIL PROTECTED] wrote: You can define either: a) Resource inside a Context - either in META-INF/context.xml or host/appname.xml b) ResourceLink inside a Context (as above) referring to a global Resource defined in server.xml. You're doing both at the moment, so one of them isn't being used, depending on where you placed the Resource in server.xml. Just defining a Resource inside your META-INF/context.xml and the corresponding WEB-INF/web.xml reference should be sufficient. p Mohammed Zabin wrote: Would you please be more specific? which file you mean? I have created Oracel connection Pool as the stated way above, and it's worked fine, shall i put resource defeninitoin in context.xml only? On 7/22/07, Pid [EMAIL PROTECTED] wrote: You only need one resource definition. You only need a resource link definition if your resource is a global one. Simplify your configuration and then post the error message from the logs so we can see Tomcat says is wrong. p Mohammed Zabin wrote: Hi All I have confiured oracle connection pool on my tomacat 6, and it worked fine. When i came to configure MySql, I repeated the same steps for Oracle databse, with considering the specfication of MySql database. But it's didn't work. Any Help please about configuring MySql, I downloaded MySql connector from mysql website and place it in CATALINA_HOME/lib directory, and i put the following: 1. in server.xml file: Resource name=jdbc/TestMySql auth=Container type=javax.sql.DataSource maxActive=100 maxIdle=30 maxWait=1 username=* password=* driverClassName= com.mysql.jdbc.Driver url=jdbc:mysql://localhost:3306/exam?autoReconnect=true/ 2. in web.xml file resource-ref descriptionOracle Datasource example/description res-ref-namejdbc/TestMySql/res-ref-name res-typejavax.sql.DataSource/res-type res-authContainer/res-auth /resource-ref 3. in context.xml file (on server's context.xml file): Resource name=jdbc/TestMySql auth=Container type=javax.sql.DataSource maxActive=100 maxIdle=30 maxWait=1 username=* password=* driverClassName= com.mysql.jdbc.Driver url=jdbc:mysql://localhost:3306/exam/ 4. in cotext.xml file ( In my web application's context.xml file): ResourceLink global=jdbc/TestMySql name=jdbc/TestMySql type= javax.sql.DataSource/ Any Help please?
Paging
Hi All I want to ask about ResultSet paging. I mean, displaying your records on multiple of pages instead of dumping them all in one page. In ASP using ADO 2, there is a property called page size, when you set the property, your recordset will determine how many page your recordset will be displayed. My questiion is, how could i implement paging using JDBC, is there such property in JDBC? Thank You
Redirection
Hi Everybody I have a servlet that renders some database related values, at the botton of the page, i want to add a hyberlink to a jsp page, and i want pass to this jsp page, and i want to pass some values from servlet to jsp??? How could i do this, any help please? Jotnarta
Re: Redirection
Thanks, seems spanish ;), I live Spain, am learning spanish language now, Gratias, EL java es Aburrido On 7/4/07, David Delbecq [EMAIL PROTECTED] wrote: String url = response.encodeURL (/path/to/jsp.jsp?paramX=someValueparamY=someOtherValue); En l'instant précis du 04/07/07 09:20, Mohammed Zabin s'exprimait en ces termes: Hi Everybody I have a servlet that renders some database related values, at the botton of the page, i want to add a hyberlink to a jsp page, and i want pass to this jsp page, and i want to pass some values from servlet to jsp??? How could i do this, any help please? Jotnarta - To start a new topic, e-mail: users@tomcat.apache.org To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Re: Redirection
Thank you again, But I want to add a hyber link, that when clicked will transfer the user to a jsp page, like this: Click Here for example. how could i do this?? On 7/4/07, David Delbecq [EMAIL PROTECTED] wrote: String url = response.encodeURL (/path/to/jsp.jsp?paramX=someValueparamY=someOtherValue); En l'instant précis du 04/07/07 09:20, Mohammed Zabin s'exprimait en ces termes: Hi Everybody I have a servlet that renders some database related values, at the botton of the page, i want to add a hyberlink to a jsp page, and i want pass to this jsp page, and i want to pass some values from servlet to jsp??? How could i do this, any help please? Jotnarta - To start a new topic, e-mail: users@tomcat.apache.org To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Re: Redirection
No, it's not what i wanted :) I have a servlet page with the following address http://localhost:8080/Exam/servlets/results in this servlet page, results, i have a hyperlink: *Click Here To view your Results* This link is designated to navigate to a jsp page with the following address: http://localhost:80808/Exam/jsp/results.jsp my question is, how could this hyperlink go correctly from within the servlet page (results) to a jsp page (results.jsp) Thank you On 7/4/07, David Delbecq [EMAIL PROTECTED] wrote: Sorry, it's not spanish but french, totally unrelated languages as for how to create an hyperlink, just open an html book and look for tag a href=../a En l'instant précis du 04/07/07 11:58, Mohammed Zabin s'exprimait en ces termes: Thanks, seems spanish ;), I live Spain, am learning spanish language now, Gratias, EL java es Aburrido On 7/4/07, David Delbecq [EMAIL PROTECTED] wrote: String url = response.encodeURL (/path/to/jsp.jsp?paramX=someValueparamY=someOtherValue); En l'instant précis du 04/07/07 09:20, Mohammed Zabin s'exprimait en ces termes: Hi Everybody I have a servlet that renders some database related values, at the botton of the page, i want to add a hyberlink to a jsp page, and i want pass to this jsp page, and i want to pass some values from servlet to jsp??? How could i do this, any help please? Jotnarta - To start a new topic, e-mail: users@tomcat.apache.org To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] - To start a new topic, e-mail: users@tomcat.apache.org To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Re: Redirection
Yes Thank you, I found it from your first response, *response.encodeURL*, Thank you Buddy, my greetings for Sarkoozi ;) On 7/4/07, Mohammed Zabin [EMAIL PROTECTED] wrote: No, it's not what i wanted :) I have a servlet page with the following address http://localhost:8080/Exam/servlets/results in this servlet page, results, i have a hyperlink: *Click Here To view your Results* This link is designated to navigate to a jsp page with the following address: http://localhost:80808/Exam/jsp/results.jsp my question is, how could this hyperlink go correctly from within the servlet page (results) to a jsp page (results.jsp) Thank you On 7/4/07, David Delbecq [EMAIL PROTECTED] wrote: Sorry, it's not spanish but french, totally unrelated languages as for how to create an hyperlink, just open an html book and look for tag a href=../a En l'instant précis du 04/07/07 11:58, Mohammed Zabin s'exprimait en ces termes: Thanks, seems spanish ;), I live Spain, am learning spanish language now, Gratias, EL java es Aburrido On 7/4/07, David Delbecq [EMAIL PROTECTED] wrote: String url = response.encodeURL (/path/to/jsp.jsp?paramX=someValueparamY=someOtherValue); En l'instant précis du 04/07/07 09:20, Mohammed Zabin s'exprimait en ces termes: Hi Everybody I have a servlet that renders some database related values, at the botton of the page, i want to add a hyberlink to a jsp page, and i want pass to this jsp page, and i want to pass some values from servlet to jsp??? How could i do this, any help please? Jotnarta - To start a new topic, e-mail: users@tomcat.apache.org To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] - To start a new topic, e-mail: users@tomcat.apache.org To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Performance
Hi All
I have developed a web site that opens a recordset at start, and while
looping through records of the main ResultSet i Open a new ResultSet for
each record, to get a specific information, then close it. like this:
while( rs.next() ) {
Statement stmt = dbConn.createStatement();
ResultSet newRs = stmt.executeQuery(SOME QUERY);
..
.
*Some Code Here*
.
.
stmt.close();
newRs.close();
}
I feel that this way is resource-consuming, is it or not, and if it is, what
is the best way to code this code??
Thanks
Re: Null
Thank you very much for your detailed illustration. But the compiler
complies that there is no such methods isNull() and wasNull()
???
On 6/21/07, Reinhardt Christiansen [EMAIL PROTECTED] wrote:
- Original Message -
From: Mohammed Zabin [EMAIL PROTECTED]
To: Tomcat Users List users@tomcat.apache.org
Sent: Thursday, June 21, 2007 6:45 AM
Subject: Null
Hi All
Anyone knows how to deal with null values in JDBC ResultSet??
I am trying to render a table in jsp page that read its value from the
database, sometimes, the database returns null values, and so, the whole
table couldn't be rendered. Is there any way to deal with null values.
The correct way to detect nulls in a JDBC ResultSet is rather different
from
the replies you've had so far. You should detect the presence of nulls in
a
given result set row by using the ResultSet.isNull() method.
So, let's say that we have a result set called 'rs' (you will probably
have
used a Statement or PreparedStatement or some other technique to get your
result set from the database):
Statement stmt = ; //an arbitrary Statement object
ResultSet rs = stmt.executeQuery(select employee_number, last_name,
first_name, middle_initial from employee_table);
Now, on to the matter of nulls. Let's say that you are working your way
through your ResultSet. As you know, you get the rows of the ResultSet one
row at a time, using the next() method, as follows:
while (rs.next()) { //as long as there are rows in the result set
//handle one row of the result set
}
Within the while loop, each iteration of the loop will handle one complete
row of the result set.
Let's assume you don't know which columns of the result set are null and
you
want to display the values in each column of the result set exactly as
they
appear in the result set, except that when the value is null, you want to
display the word unknown. Here's what you would need to do:
String empno = null;
String lastname = null;
String firstname = null;
String midinit = null;
while (rs.next()) {
empno = rs.getString(employee_number); //get the employee number
from this row of the result set
if (rs.wasNull()) { //if the employee number is null
System.out.println(Employee Number is unknown);
}
else {
System.out.println(Employee Number is + empno);
}
lastname = rs.getString(last_name); //get the last name from this
row of the result set
if (rs.wasNull()) { //if the last name is null
System.out.println(Last Name is unknown);
}
else {
System.out.println(Last Name is + lastname);
}
firstname = rs.getString(first_name); //get the first name from
this row of the result set
if (rs.wasNull()) { //if the first name is null
System.out.println(First Name is unknown);
}
else {
System.out.println(First Name is + firstname);
}
midinit = rs.getString(middle_initial); //get the middle initial
from this row of the result set
if (rs.wasNull()) { //if the middle initial is null
System.out.println(Middle Initial is unknown);
}
else {
System.out.println(Middle Initial is + midinit);
}
}
Although this example uses only result set columns that are being stored
in
Strings, the technique differs very little for non-text data. Let's say
that
we had a column called annual_salary in our result set, where the
annual_salary was an integer containing the number of dollars that the
person earned per year. Let's assume that some people are still
negotiating
their salaries so that the salary is stored as null for those people until
the salary has been fully agreed.. The technique to handle the salary
would
look like this:
int salary = null;
while (rs.next()) {
salary = getInt(annual_salary); //get the salary from this row of
the result set
if (rs.isNull()) { //if the salary is null
System.out.println(Annual Salary is unknown);
}
else {
System.out.println(Annual Salary is + salary);
}
I hope this helps you with your null handling!
--
Rhino
-
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Null
Hi All Anyone knows how to deal with null values in JDBC ResultSet?? I am trying to render a table in jsp page that read its value from the database, sometimes, the database returns null values, and so, the whole table couldn't be rendered. Is there any way to deal with null values. Thanks
Re: Null
I tried it the other way, if( rs.getString(field) == null ) but the
compiler plames that null can't be compared to string
On 6/21/07, Tim Funk [EMAIL PROTECTED] wrote:
if (null == rs.getString(col_foo)) {
out.println(tdnbsp;/td);
} else {
// Evil since this doesn't escape the xml - for edutainment only
out.println(td + rs.getString(col_foo) + /td);
}
-Tim
Mohammed Zabin wrote:
Hi All
Anyone knows how to deal with null values in JDBC ResultSet??
I am trying to render a table in jsp page that read its value from the
database, sometimes, the database returns null values, and so, the whole
table couldn't be rendered. Is there any way to deal with null values.
Thanks
-
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To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
Design
Hi All I am developing an online exam site as a graduation project. I have some questions regardsing the design: 1. In such a program which is a web site that introduce some multiple choice questions, and shows the result of user answers, DO I HAVE TO USE EJB??
Re: Design
I am using a Tag that render the whole questions, can i create another tag that deals with user request? On 6/19/07, Kevin Wilhelm [EMAIL PROTECTED] wrote: No! This sounds like a simple webapp to me. Just use some Servlet Container (Tomcat) and have all of the presentation (JSP), business and persistence things handled in ONE engine. - Original Message - From: Mohammed Zabin [EMAIL PROTECTED] To: Tomcat Users List users@tomcat.apache.org Sent: Tuesday, June 19, 2007 9:26 AM Subject: Design Hi All I am developing an online exam site as a graduation project. I have some questions regardsing the design: 1. In such a program which is a web site that introduce some multiple choice questions, and shows the result of user answers, DO I HAVE TO USE EJB?? - To start a new topic, e-mail: users@tomcat.apache.org To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Re: Design
What learning curve? On 6/19/07, ben short [EMAIL PROTECTED] wrote: Id suggest having a look at the spring web mvc stuff it can help you simplify form submissions by mapping request params to objects so you don't have to do, although there will be a slight learning curve. Just my 2 pence :) On 6/19/07, Kevin Wilhelm [EMAIL PROTECTED] wrote: I'd take the approach with Servlets/JSP that handle user inputs. You could in deed use tags for the inputs and process them with suitable controllers in the logic tier. May be there are simpler ways to proceed with questionaires. - Original Message - From: Mohammed Zabin [EMAIL PROTECTED] To: Tomcat Users List users@tomcat.apache.org Sent: Tuesday, June 19, 2007 9:42 AM Subject: Re: Design I am using a Tag that render the whole questions, can i create another tag that deals with user request? On 6/19/07, Kevin Wilhelm [EMAIL PROTECTED] wrote: No! This sounds like a simple webapp to me. Just use some Servlet Container (Tomcat) and have all of the presentation (JSP), business and persistence things handled in ONE engine. - Original Message - From: Mohammed Zabin [EMAIL PROTECTED] To: Tomcat Users List users@tomcat.apache.org Sent: Tuesday, June 19, 2007 9:26 AM Subject: Design Hi All I am developing an online exam site as a graduation project. I have some questions regardsing the design: 1. In such a program which is a web site that introduce some multiple choice questions, and shows the result of user answers, DO I HAVE TO USE EJB?? - To start a new topic, e-mail: users@tomcat.apache.org To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] - To start a new topic, e-mail: users@tomcat.apache.org To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] - To start a new topic, e-mail: users@tomcat.apache.org To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Re: DBCP
Thank you You know what, all that advises made me somewhat confused, i have reread Tomcat Documentation, now, am not sure about the following: 1. Which is best, servlet.xml or context.xml? 2. If it is servlet.xml, which servlet.xml, is it the config file for the container, or my web application servlet.xml file. 3. Where shall i put jdbc driver class file, in my web application META-INF or in Tomcat lib folder. I susbect with jdbc driver, if you look at otn.oracle, you will find many drivers for all jdks, but there is no one for JDK 6. On 5/26/07, Pid [EMAIL PROTECTED] wrote: Mohammed Zabin wrote: Thank you Christ For instance, I usually see oracle.jdbc.driver.OracleDriver instead of what you have above. It's as you stated above. But with Oracle 9i and onwards, the driver must be oracle.jdbc.OracleDriver, anyways, i am looking for a solution, and I am sure that i'll find one, thank you If you've not found it yet you need to carefully re-read the advice we've offered. I think we've identified the problem and advised a solution each time, I also think you're changing more than just what we've recommended you change, and thus introducing more problems. Your last issue was that you have moved the Resource definition to GlobalResources, then failed to add the ResourceLink that makes it available to the Context. Your previous issue was that you hadn't added the driver jar to the correct place for Tomcat's classloaders to find it. The issue before that* was that your Resource config definition was incorrect, as were the previous two attempts. Before that your JSP was faulty as you hadn't imported any of the classes you needed. p * Hopefully I've got these in the right order. server.xml : GlobalResource def yourapp.xml : Context def, ResourceLink web.xml : web app deployment desc, Resource Ref your.jsp: imports, active code On 5/25/07, Christopher Schultz [EMAIL PROTECTED] wrote: -BEGIN PGP SIGNED MESSAGE- Hash: SHA1 Mohammed, Mohammed Zabin wrote: I put the jar file in my WEB-INF/lib and CATALINA_HOME/lib and CLASSPATH, but nothing changed, I got the same error No, you are getting a different error. The first one was ClassNotFoundException. Now, you are getting: org.apache.tomcat.dbcp.dbcp.SQLNestedException: Cannot create JDBC driver of class '' for connect URL 'null' Those are not the same. Search the archives for Cannot create JDBC driver of class '' and I'm sure you'll find this question answered hundreds of times over. It usually turns out to be an incorrect JDBC URL or an incorrect driver class name. Please check these over /carefully/: driverClassName=oracle.jdbc.OracleDriver url=jdbc:oracle:thin:@127.0.0.1:1521:orcldb For instance, I usually see oracle.jdbc.driver.OracleDriver instead of what you have above. - -chris -BEGIN PGP SIGNATURE- Version: GnuPG v1.4.7 (MingW32) Comment: Using GnuPG with Mozilla - http://enigmail.mozdev.org iD8DBQFGVvxA9CaO5/Lv0PARArmAAJsEdBWX6X0TcjTLZ30hFYNjACEAZQCgr9+d 7ag9qjj7Q+Uxg23E0P21XyU= =EAkm -END PGP SIGNATURE- - To start a new topic, e-mail: users@tomcat.apache.org To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Re: DBCP
Thank you Pid for your patience with me, Thank you all guys, the problem finally sovled, and the connection established. The problem was because of i didn't state the ResourceLink, I put it like this: ResourceLink name=jdbc/myoracle type=javax.sql.DataSource global=jdbc/myoracle/ in Context.xml, and i removed all occurences of jdbc class drivers but in CATALINA_HOME/lib. By the way, it is the advice of David Smith and Pid. Thank you guys, Thank you ver much :). Jotnarta On 5/26/07, Pid [EMAIL PROTECTED] wrote: Mohammed Zabin wrote: Thank you (Please just reply to the list, not 'all') You know what, all that advises made me somewhat confused, i have reread Tomcat Documentation, now, am not sure about the following: 1. Which is best, servlet.xml or context.xml? You must add information to all of config files, it's not optional, I think the documentation is pretty clear on what needs to be added to each file. (Below, ... is a location or name of something on your system). 2. If it is servlet.xml, which servlet.xml, is it the config file for the container, or my web application servlet.xml file. I'm not aware of a Tomcat configuration file called servlet.xml. Tomcat uses the following files (in addition to your web app's files): tomcat/conf/server.xml - main config tomcat/conf/context.xml - default/all contexts tomcat/conf/web.xml - main config You can configure the Context by placing the definition in - EITHER: tomcat/conf/hostname/contextname.xml OR: webapp/META-INF/context.xml You should also configure your servlet definitions and the remainder of your application as per the spec in: webapp/WEB-INF/web.xml 3. Where shall i put jdbc driver class file, in my web application META-INF or in Tomcat lib folder. Not META-INF, WEB-INF and META-INF are different locations, with different purposes. You can place the oracle jar file in - EITHER: tomcat/lib OR: webapp/WEB-INF/lib I susbect with jdbc driver, if you look at otn.oracle, you will find many drivers for all jdks, but there is no one for JDK 6. It's not the driver, it's your config. Tomcat+Oracle is successfully deployed by many people all over the world. So, in summary, as an *example* to demonstrate some possible locations for various bits of config, you might have: Resource def in GlobalResources, 'testhost' Host def: /path/to/tomcat6/conf/server.xml ResourceLink in Context: /path/to/tomcat6/conf/testhost/ROOT.xml oracle-XXX.jar in /path/to/tomcat6/lib Resource ref, servlets in: /path/to/testhost/webapps/ROOT/WEB-INF/web.xml JSP in: /path/to/testhost/webapps/ROOT/test.jsp p p.s. Chuck, if you read this, I'm betting that you'll need to get your path attribute standard response ready. On 5/26/07, Pid [EMAIL PROTECTED] wrote: Mohammed Zabin wrote: Thank you Christ For instance, I usually see oracle.jdbc.driver.OracleDriver instead of what you have above. It's as you stated above. But with Oracle 9i and onwards, the driver must be oracle.jdbc.OracleDriver, anyways, i am looking for a solution, and I am sure that i'll find one, thank you If you've not found it yet you need to carefully re-read the advice we've offered. I think we've identified the problem and advised a solution each time, I also think you're changing more than just what we've recommended you change, and thus introducing more problems. Your last issue was that you have moved the Resource definition to GlobalResources, then failed to add the ResourceLink that makes it available to the Context. Your previous issue was that you hadn't added the driver jar to the correct place for Tomcat's classloaders to find it. The issue before that* was that your Resource config definition was incorrect, as were the previous two attempts. Before that your JSP was faulty as you hadn't imported any of the classes you needed. p * Hopefully I've got these in the right order. server.xml : GlobalResource def yourapp.xml : Context def, ResourceLink web.xml : web app deployment desc, Resource Ref your.jsp: imports, active code On 5/25/07, Christopher Schultz [EMAIL PROTECTED] wrote: -BEGIN PGP SIGNED MESSAGE- Hash: SHA1 Mohammed, Mohammed Zabin wrote: I put the jar file in my WEB-INF/lib and CATALINA_HOME/lib and CLASSPATH, but nothing changed, I got the same error No, you are getting a different error. The first one was ClassNotFoundException. Now, you are getting: org.apache.tomcat.dbcp.dbcp.SQLNestedException: Cannot create JDBC driver of class '' for connect URL 'null' Those are not the same. Search the archives for Cannot create JDBC driver of class '' and I'm sure you'll find this question answered hundreds of times over. It usually turns out to be an incorrect JDBC URL or an incorrect driver class name. Please check these over /carefully/: driverClassName=oracle.jdbc.OracleDriver url
Re: DBCP
It didn't work, I put the following in Context.xml:
Resource name=jdbc/mydb
auth=Container
type=oracle.jdbc.pool.OracleDataSource
factory=oracle.jdbc.pool.OracleDataSourceFactory
user=hr
password=hr
driverClassName=oracle.jdbc.driver.OracleDriver
url=jdbc:oracle:thin:@localhost:1521:orcldb
maxActive=20 maxIdle=10 maxwait=-1/
and i got the following exception:
javax.servlet.ServletException: javax.naming.NamingException: Could
not load resource factory class [Root exception is
java.lang.ClassNotFoundException:
oracle.jdbc.pool.OracleDataSourceFactory]
org.apache.jasper.runtime.PageContextImpl.doHandlePageException(PageContextImpl.java:855)
org.apache.jasper.runtime.PageContextImpl.handlePageException(PageContextImpl.java:784)
org.apache.jsp.jsp.testDBCP_jsp._jspService(testDBCP_jsp.java:75)
org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:70)
javax.servlet.http.HttpServlet.service(HttpServlet.java:803)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:384)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:320)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:266)
javax.servlet.http.HttpServlet.service(HttpServlet.java:803)
is there any jar file that should be in lib???
On 5/24/07, Christopher Schultz [EMAIL PROTECTED] wrote:
-BEGIN PGP SIGNED MESSAGE-
Hash: SHA1
Mohammed,
Mohammed Zabin wrote:
You know what? I am confusing with this. Shall i put the following code
in
web.xml in my web application or web.xml on config folder, shall i use
server.xml or context.xml
Use META-INF/context.xml in your WAR file or deployment directory. Don't
use ${TOMCAT_HOME}/conf/Catalina/[host]/[app].xml unless there's a
really good reason to do so.
Put your Resource in context.xml and remove all Resource
configuration from server.xml.
Remove any resource-ref you have in your web.xml.
- -chris
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Version: GnuPG v1.4.7 (MingW32)
Comment: Using GnuPG with Mozilla - http://enigmail.mozdev.org
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3EScAagRpgYlErF8uPLvF9E=
=MAx6
-END PGP SIGNATURE-
-
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Re: DBCP
I did, in Tomcat 6 documentation, it's mentioned that classes12.jar must be placed in CATALINA_HOME/lib, and i put the jar file there, but still, it's don't work On 5/25/07, Caldarale, Charles R [EMAIL PROTECTED] wrote: From: Mohammed Zabin [mailto:[EMAIL PROTECTED] Subject: Re: DBCP i have downloaded JDBC driver from otn.oracle classes12.zip and i changed it to classes12.jar, and put it in CLASSPATH. The CLASSPATH environment variable should not be used for Tomcat (or for any other Java application, for that matter); the standard Tomcat startup mechanisms rightly ignore it. The JDBC driver jar must be placed in the Tomcat 6 lib directory in order to use connection pooling. - Chuck THIS COMMUNICATION MAY CONTAIN CONFIDENTIAL AND/OR OTHERWISE PROPRIETARY MATERIAL and is thus for use only by the intended recipient. If you received this in error, please contact the sender and delete the e-mail and its attachments from all computers. - To start a new topic, e-mail: users@tomcat.apache.org To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Re: DBCP
anyways, i put the jar file in my classpath, and this will override the lib folder i think, isn't it? On 5/25/07, Javier Ortiz [EMAIL PROTECTED] wrote: Yes but not in the same path as in previous versions. On 5/25/07, Mohammed Zabin [EMAIL PROTECTED] wrote: Thank you Lib folder in CATALINA_HOME, as mentioned in Tomact 6, isn't it? On 5/25/07, Javier Ortiz [EMAIL PROTECTED] wrote: Are you aware of the new placing of files in 6.x? There's a new lib folder. Put the file there and try again. On 5/25/07, Mohammed Zabin [EMAIL PROTECTED] wrote: Hello Geeks Following is my problem, I am trying to configure my Tomcat 6 to connect to my localhost Oracle 10g Database, following is my server.xml file : Resource name=jdbc/myoracle auth=Container type=javax.sql.DataSource driverClassName= oracle.jdbc.OracleDriver url=jdbc:oracle:thin:@127.0.0.1:1521:orcldb username=hr password=hr maxActive=20 maxIdle=10 maxWait=-1/ and i put the following in web.xml: resource-ref descriptionOracle Datasource example/description res-ref-namejdbc/myoracle/res-ref-name res-typejavax.sql.DataSource/res-type res-authContainer/res-auth /resource-ref and the following is code is the JSP code: %@ page import=javax.naming.Context,javax.naming.InitialContext, javax.naming.NamingException,javax.sql.DataSource, java.sql.* % % Context initContext = new InitialContext(); Context envContext = (Context)initContext.lookup(java:/comp/env); DataSource ds = (DataSource)envContext.lookup(jdbc/myoracle); Connection conn = ds.getConnection(); out.println( Connection Established ); % After running the jsp page, i got the following error: org.apache.jasper.JasperException: javax.servlet.ServletException: org.apache.tomcat.dbcp.dbcp.SQLNestedException: Cannot create JDBC driver of class '' for connect URL 'null' org.apache.jasper.servlet.JspServletWrapper.handleJspException ( JspServletWrapper.java:532) org.apache.jasper.servlet.JspServletWrapper.service( JspServletWrapper.java:408) org.apache.jasper.servlet.JspServlet.serviceJspFile( JspServlet.java:320) org.apache.jasper.servlet.JspServlet.service(JspServlet.java :266) javax.servlet.http.HttpServlet.service(HttpServlet.java:803) i have downloaded JDBC driver from otn.oracle classes12.zip and i changed it to classes12.jar, and put it in CLASSPATH. I am working on this problem almost from 2 weeks, i didn't know what the problem is, any help plzz
DBCP
Hello Geeks Following is my problem, I am trying to configure my Tomcat 6 to connect to my localhost Oracle 10g Database, following is my server.xml file : Resource name=jdbc/myoracle auth=Container type=javax.sql.DataSource driverClassName= oracle.jdbc.OracleDriver url=jdbc:oracle:thin:@127.0.0.1:1521:orcldb username=hr password=hr maxActive=20 maxIdle=10 maxWait=-1/ and i put the following in web.xml: resource-ref descriptionOracle Datasource example/description res-ref-namejdbc/myoracle/res-ref-name res-typejavax.sql.DataSource/res-type res-authContainer/res-auth /resource-ref and the following is code is the JSP code: %@ page import=javax.naming.Context,javax.naming.InitialContext, javax.naming.NamingException,javax.sql.DataSource, java.sql.* % % Context initContext = new InitialContext(); Context envContext = (Context)initContext.lookup(java:/comp/env); DataSource ds = (DataSource)envContext.lookup(jdbc/myoracle); Connection conn = ds.getConnection(); out.println( Connection Established ); % After running the jsp page, i got the following error: org.apache.jasper.JasperException: javax.servlet.ServletException: org.apache.tomcat.dbcp.dbcp.SQLNestedException: Cannot create JDBC driver of class '' for connect URL 'null' org.apache.jasper.servlet.JspServletWrapper.handleJspException(JspServletWrapper.java:532) org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:408) org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:320) org.apache.jasper.servlet.JspServlet.service(JspServlet.java:266) javax.servlet.http.HttpServlet.service(HttpServlet.java:803) i have downloaded JDBC driver from otn.oracle classes12.zip and i changed it to classes12.jar, and put it in CLASSPATH. I am working on this problem almost from 2 weeks, i didn't know what the problem is, any help plzz
Re: DBCP
Thank you Pid Yeah, where exactly in the server.xml did you put this? I put it in GlobalNamingResources tag in server.xml On 5/25/07, Pid [EMAIL PROTECTED] wrote: Mohammed Zabin wrote: Hello Geeks I'm not sure what the appropriate response is but I'll try to sneak something passed my language filter: Hello X, Following is my problem, I am trying to configure my Tomcat 6 to connect to my localhost Oracle 10g Database, following is my server.xml file : Resource name=jdbc/myoracle auth=Container type=javax.sql.DataSource driverClassName= oracle.jdbc.OracleDriver url=jdbc:oracle:thin:@127.0.0.1:1521:orcldb username=hr password=hr maxActive=20 maxIdle=10 maxWait=-1/ Yeah, where exactly in the server.xml did you put this? Tomcat is now telling you that it can't even find the name of the driver, which I think you told us in your previous thread it could, but couldn't find the class. All you had to do was add the oracle driver to CATALINA_HOME/lib or your WEB-INF/lib and you should have been done... p and i put the following in web.xml: resource-ref descriptionOracle Datasource example/description res-ref-namejdbc/myoracle/res-ref-name res-typejavax.sql.DataSource/res-type res-authContainer/res-auth /resource-ref and the following is code is the JSP code: %@ page import=javax.naming.Context,javax.naming.InitialContext, javax.naming.NamingException,javax.sql.DataSource, java.sql.* % % Context initContext = new InitialContext(); Context envContext = (Context)initContext.lookup(java:/comp/env); DataSource ds = (DataSource)envContext.lookup(jdbc/myoracle); Connection conn = ds.getConnection(); out.println( Connection Established ); % After running the jsp page, i got the following error: org.apache.jasper.JasperException: javax.servlet.ServletException: org.apache.tomcat.dbcp.dbcp.SQLNestedException: Cannot create JDBC driver of class '' for connect URL 'null' org.apache.jasper.servlet.JspServletWrapper.handleJspException( JspServletWrapper.java:532) org.apache.jasper.servlet.JspServletWrapper.service( JspServletWrapper.java:408) org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java :320) org.apache.jasper.servlet.JspServlet.service(JspServlet.java:266) javax.servlet.http.HttpServlet.service(HttpServlet.java:803) i have downloaded JDBC driver from otn.oracle classes12.zip and i changed it to classes12.jar, and put it in CLASSPATH. I am working on this problem almost from 2 weeks, i didn't know what the problem is, any help plzz
Re: DBCP
Thank you Lib folder in CATALINA_HOME, as mentioned in Tomact 6, isn't it? On 5/25/07, Javier Ortiz [EMAIL PROTECTED] wrote: Are you aware of the new placing of files in 6.x? There's a new lib folder. Put the file there and try again. On 5/25/07, Mohammed Zabin [EMAIL PROTECTED] wrote: Hello Geeks Following is my problem, I am trying to configure my Tomcat 6 to connect to my localhost Oracle 10g Database, following is my server.xml file : Resource name=jdbc/myoracle auth=Container type=javax.sql.DataSource driverClassName= oracle.jdbc.OracleDriver url=jdbc:oracle:thin:@127.0.0.1:1521:orcldb username=hr password=hr maxActive=20 maxIdle=10 maxWait=-1/ and i put the following in web.xml: resource-ref descriptionOracle Datasource example/description res-ref-namejdbc/myoracle/res-ref-name res-typejavax.sql.DataSource/res-type res-authContainer/res-auth /resource-ref and the following is code is the JSP code: %@ page import=javax.naming.Context,javax.naming.InitialContext, javax.naming.NamingException,javax.sql.DataSource, java.sql.* % % Context initContext = new InitialContext(); Context envContext = (Context)initContext.lookup(java:/comp/env); DataSource ds = (DataSource)envContext.lookup(jdbc/myoracle); Connection conn = ds.getConnection(); out.println( Connection Established ); % After running the jsp page, i got the following error: org.apache.jasper.JasperException: javax.servlet.ServletException: org.apache.tomcat.dbcp.dbcp.SQLNestedException: Cannot create JDBC driver of class '' for connect URL 'null' org.apache.jasper.servlet.JspServletWrapper.handleJspException( JspServletWrapper.java:532) org.apache.jasper.servlet.JspServletWrapper.service( JspServletWrapper.java:408) org.apache.jasper.servlet.JspServlet.serviceJspFile( JspServlet.java:320) org.apache.jasper.servlet.JspServlet.service(JspServlet.java :266) javax.servlet.http.HttpServlet.service(HttpServlet.java:803) i have downloaded JDBC driver from otn.oracle classes12.zip and i changed it to classes12.jar, and put it in CLASSPATH. I am working on this problem almost from 2 weeks, i didn't know what the problem is, any help plzz
Re: DBCP
I put the jar file in my WEB-INF/lib and CATALINA_HOME/lib and CLASSPATH, but nothing changed, I got the same error On 5/25/07, Mohammed Zabin [EMAIL PROTECTED] wrote: Thank you Pid Yeah, where exactly in the server.xml did you put this? I put it in GlobalNamingResources tag in server.xml On 5/25/07, Pid [EMAIL PROTECTED] wrote: Mohammed Zabin wrote: Hello Geeks I'm not sure what the appropriate response is but I'll try to sneak something passed my language filter: Hello X, Following is my problem, I am trying to configure my Tomcat 6 to connect to my localhost Oracle 10g Database, following is my server.xml file : Resource name=jdbc/myoracle auth=Container type=javax.sql.DataSource driverClassName= oracle.jdbc.OracleDriver url= jdbc:oracle:thin:@127.0.0.1:1521:orcldb username=hr password=hr maxActive=20 maxIdle=10 maxWait=-1/ Yeah, where exactly in the server.xml did you put this? Tomcat is now telling you that it can't even find the name of the driver, which I think you told us in your previous thread it could, but couldn't find the class. All you had to do was add the oracle driver to CATALINA_HOME/lib or your WEB-INF/lib and you should have been done... p and i put the following in web.xml: resource-ref descriptionOracle Datasource example/description res-ref-namejdbc/myoracle/res-ref-name res-typejavax.sql.DataSource/res-type res-authContainer/res-auth /resource-ref and the following is code is the JSP code: %@ page import=javax.naming.Context,javax.naming.InitialContext, javax.naming.NamingException,javax.sql.DataSource , java.sql.* % % Context initContext = new InitialContext(); Context envContext = (Context)initContext.lookup(java:/comp/env); DataSource ds = (DataSource)envContext.lookup(jdbc/myoracle); Connection conn = ds.getConnection(); out.println( Connection Established ); % After running the jsp page, i got the following error: org.apache.jasper.JasperException : javax.servlet.ServletException: org.apache.tomcat.dbcp.dbcp.SQLNestedException: Cannot create JDBC driver of class '' for connect URL 'null' org.apache.jasper.servlet.JspServletWrapper.handleJspException ( JspServletWrapper.java:532) org.apache.jasper.servlet.JspServletWrapper.service( JspServletWrapper.java:408) org.apache.jasper.servlet.JspServlet.serviceJspFile( JspServlet.java:320) org.apache.jasper.servlet.JspServlet.service(JspServlet.java:266) javax.servlet.http.HttpServlet.service(HttpServlet.java:803) i have downloaded JDBC driver from otn.oracle classes12.zip and i changed it to classes12.jar, and put it in CLASSPATH. I am working on this problem almost from 2 weeks, i didn't know what the problem is, any help plzz
DBCP
*Hi All* ** *I want to use DBCP to connect my localhost Oracle Database, I have write the following in servlet.xml file:* Resource name=jdbc/myoracledb auth=Container type=javax.sql.DataSource / ResourceParams name=jdbc/myoracledb parameter namefactory/name valueorg.apache.commons.dbcp.BasicDataSourceFactory/value /parameter parameter namedriverClassName/name valueoracle.jdbc.OracleDriver/value /parameter parameter nameurl/name valuejdbc:oracle:thin:@127.0.0.1:1521:mine/value /parameter parameter nameusername/name valuehr/value /parameter parameter namepassword/name valuehr/value /parameter parameter namemaxActive/name value20/value /parameter parameter namemaxIdle/name value10/value /parameter parameter namemaxWait/name value-1/value /parameter /ResourceParams /GlobalNamingResources *and the following in web.xml file:* resource-ref descriptionOracle Datasource example/description res-ref-namejdbc/myoracledb/res-ref-name res-typejavax.sql.DataSource/res-type res-authContainer/res-auth /resource-ref *and following is my JSP code:* %@ page import=javax.sql.*, javax.naming.*, java.sql.* % % Context initContext = new InitialContext(); Context envContext = (Context)initContext.lookup(java:/comp/env); DataSource ds = (DataSource)envContext.lookup(jdbc/myoracledb); Connection conn = ds.getConnection(); out.println( Connection Established ); % *When running the above jsp page, i got the following exception:* *org.apache.jasper.JasperException: javax.servlet.ServletException: org.apache.tomcat.dbcp.dbcp.SQLNestedException: Cannot create JDBC driver of class '' for connect URL 'null' org.apache.jasper.servlet.JspServletWrapper.handleJspException(JspServletWrapper.java:532) org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:408) org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:320) org.apache.jasper.servlet.JspServlet.service(JspServlet.java:266) javax.servlet.http.HttpServlet.service(HttpServlet.java:803)* Any Help Please, I am working to solving this problem from one week, I am lost, what is the reason for this exception, any help will be apprecieated Jotnarta
Re: DBCP
I am using tomcat 6, and another thing, i have changed my configuration parameters to the following: Resource name=jdbc/myoracle auth=Container type=javax.sql.DataSource driverClassName=oracle.jdbc.OracleDriver url=jdbc:oracle:thin:@127.0.0.1:1521:mysid username=scott password=tiger maxActive=20 maxIdle=10 maxWait=-1/ On 5/24/07, David Rodríguez Fernández [EMAIL PROTECTED] wrote: What tomcat version do you have? -Mensaje original- De: Mohammed Zabin [mailto:[EMAIL PROTECTED] Enviado el: jueves, 24 de mayo de 2007 12:03 Para: users@tomcat.apache.org Asunto: DBCP *Hi All* ** *I want to use DBCP to connect my localhost Oracle Database, I have write the following in servlet.xml file:* Resource name=jdbc/myoracledb auth=Container type=javax.sql.DataSource / ResourceParams name=jdbc/myoracledb parameter namefactory/name valueorg.apache.commons.dbcp.BasicDataSourceFactory/value /parameter parameter namedriverClassName/name valueoracle.jdbc.OracleDriver/value /parameter parameter nameurl/name valuejdbc:oracle:thin:@127.0.0.1:1521:mine/value /parameter parameter nameusername/name valuehr/value /parameter parameter namepassword/name valuehr/value /parameter parameter namemaxActive/name value20/value /parameter parameter namemaxIdle/name value10/value /parameter parameter namemaxWait/name value-1/value /parameter /ResourceParams /GlobalNamingResources *and the following in web.xml file:* resource-ref descriptionOracle Datasource example/description res-ref-namejdbc/myoracledb/res-ref-name res-typejavax.sql.DataSource/res-type res-authContainer/res-auth /resource-ref *and following is my JSP code:* %@ page import=javax.sql.*, javax.naming.*, java.sql.* % % Context initContext = new InitialContext(); Context envContext = (Context)initContext.lookup(java:/comp/env); DataSource ds = (DataSource)envContext.lookup(jdbc/myoracledb); Connection conn = ds.getConnection(); out.println( Connection Established ); % *When running the above jsp page, i got the following exception:* *org.apache.jasper.JasperException: javax.servlet.ServletException: org.apache.tomcat.dbcp.dbcp.SQLNestedException: Cannot create JDBC driver of class '' for connect URL 'null' org.apache.jasper.servlet.JspServletWrapper.handleJspException (JspServletWra pper.java:532) org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java :4 08) org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:320) org.apache.jasper.servlet.JspServlet.service(JspServlet.java:266) javax.servlet.http.HttpServlet.service(HttpServlet.java:803)* Any Help Please, I am working to solving this problem from one week, I am lost, what is the reason for this exception, any help will be apprecieated Jotnarta -- La Información incluida en el presente correo electrónico es SECRETO PROFESIONAL Y CONFIDENCIAL, siendo para el uso exclusivo del destinatario arriba mencionado. Si usted lee este mensaje y no es el destinatario señalado, el empleado o el agente responsable de entregar el mensaje al destinatario, o ha recibido esta comunicación por error, le informamos que esta totalmente prohibida cualquier divulgación, distribución o reproducción de esta comunicación, y le rogamos que nos lo notifique inmediatamente y nos devuelva el mensaje original a la dirección arriba mencionada. Gracias. The information contained in this e-mail is LEGALLY PRIVILEDGED AND CONFIDENTIAL and is intended only for the use of the addressee named above. If the reader of this message is not the intended recipient or the employee or agent responsible for delivering the message to the intended recipient, or you have received this communication in error, please be aware that any dissemination, distribution or duplication of this communication is strictly prohibited, and please notify us immediately and return the original message to us at the address above. Thank you. - To start a new topic, e-mail: users@tomcat.apache.org To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Re: DBCP
You know what? I am confusing with this. Shall i put the following code in
web.xml in my web application or web.xml on config folder, shall i use
server.xml or context.xml
On 5/24/07, David Rodríguez Fernández [EMAIL PROTECTED] wrote:
I'm using tomcat 5.5, and for this kind of things i'm creating a xml file
in
the {TOMCATHOME}/conf/Catalina/localhost/AppName.xml
With a content like this:
# cat /etc/tomcat-5.5/Catalina/localhost/AppName.xml
Context path=/AppName docBase=AppName debug=5 reloadable=true
crossContext=true
Resource name=jdbc/conexion auth=Container
type=javax.sql.DataSource
driverClassName=oracle.jdbc.driver.OracleDriver
url=jdbc:oracle:thin:@192.168.1.1:1521:SIDBD username=scott
password=tiger
maxActiVe=3 maxIdle=1 maxWait=-1 /
/Context
-Mensaje original-
De: Mohammed Zabin [mailto:[EMAIL PROTECTED]
Enviado el: jueves, 24 de mayo de 2007 12:24
Para: Tomcat Users List
Asunto: Re: DBCP
I am using tomcat 6, and another thing, i have changed my configuration
parameters to the following:
Resource name=jdbc/myoracle auth=Container
type=javax.sql.DataSource
driverClassName=oracle.jdbc.OracleDriver
url=jdbc:oracle:thin:@127.0.0.1:1521:mysid
username=scott password=tiger maxActive=20 maxIdle=10
maxWait=-1/
On 5/24/07, David Rodríguez Fernández [EMAIL PROTECTED]
wrote:
What tomcat version do you have?
-Mensaje original-
De: Mohammed Zabin [mailto:[EMAIL PROTECTED] Enviado el: jueves, 24
de mayo de 2007 12:03
Para: users@tomcat.apache.org
Asunto: DBCP
*Hi All*
**
*I want to use DBCP to connect my localhost Oracle Database, I have
write the following in servlet.xml file:*
Resource name=jdbc/myoracledb auth=Container
type=javax.sql.DataSource /
ResourceParams name=jdbc/myoracledb
parameter
namefactory/name
valueorg.apache.commons.dbcp.BasicDataSourceFactory/value
/parameter
parameter
namedriverClassName/name
valueoracle.jdbc.OracleDriver/value
/parameter
parameter
nameurl/name
valuejdbc:oracle:thin:@127.0.0.1:1521:mine/value
/parameter
parameter
nameusername/name
valuehr/value
/parameter
parameter
namepassword/name
valuehr/value
/parameter
parameter
namemaxActive/name
value20/value
/parameter
parameter
namemaxIdle/name
value10/value
/parameter
parameter
namemaxWait/name
value-1/value
/parameter
/ResourceParams
/GlobalNamingResources
*and the following in web.xml file:*
resource-ref
descriptionOracle Datasource example/description
res-ref-namejdbc/myoracledb/res-ref-name
res-typejavax.sql.DataSource/res-type
res-authContainer/res-auth
/resource-ref
*and following is my JSP code:*
%@ page import=javax.sql.*, javax.naming.*, java.sql.* %
%
Context initContext = new InitialContext(); Context envContext =
(Context)initContext.lookup(java:/comp/env);
DataSource ds = (DataSource)envContext.lookup(jdbc/myoracledb);
Connection conn = ds.getConnection();
out.println( Connection Established ); %
*When running the above jsp page, i got the following exception:*
*org.apache.jasper.JasperException: javax.servlet.ServletException:
org.apache.tomcat.dbcp.dbcp.SQLNestedException: Cannot create JDBC
driver of class '' for connect URL 'null'
org.apache.jasper.servlet.JspServletWrapper.handleJspException
(JspServletWra
pper.java:532)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.
java
:4
08)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:320)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:266)
javax.servlet.http.HttpServlet.service(HttpServlet.java:803)*
Any Help Please, I am working to solving this problem from one week, I
am lost, what is the reason for this exception, any help will be
apprecieated
Jotnarta
--
La Información incluida en el presente correo electrónico es SECRETO
PROFESIONAL Y CONFIDENCIAL, siendo para el uso exclusivo del
destinatario arriba mencionado. Si usted lee este mensaje y no es el
destinatario señalado, el empleado o el agente responsable de entregar
el mensaje al destinatario, o ha recibido esta comunicación por error,
le informamos que esta totalmente prohibida cualquier divulgación,
distribución o reproducción de esta comunicación, y le rogamos que nos
lo notifique inmediatamente y nos devuelva el mensaje original a la
dirección arriba mencionada.
Gracias.
The information contained in this e-mail is LEGALLY PRIVILEDGED AND
CONFIDENTIAL and is intended only for the use of the addressee named
above. If the reader of this message is not the intended
Re: JDBC
Thank you buddy, I have another confusing question for me, I have two web.xml files, one in conf/web.xml and one in my application under WEB-INF, When configuring connection pool, which one shall i use? or shall i put the configuration parameters in both of them?? Thank you On 5/22/07, ben short [EMAIL PROTECTED] wrote: Have a look here.. http://tomcat.apache.org/tomcat-6.0-doc/jndi-datasource-examples-howto.html On 5/22/07, Mohammed Zabin [EMAIL PROTECTED] wrote: Hi All Am new on this, i want to know how to configure Database Connection Pooling to use Oracle Database?? anyhelp will be appreciated. Jotnarta - To start a new topic, e-mail: users@tomcat.apache.org To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Re: JDBC
with your example, i don't have to put extra parameters in web.xml or servlet.xml? just in context.xml??? On 5/22/07, Zdeněk Vráblík [EMAIL PROTECTED] wrote: Hi, here is example of Resource configration. Put it in context.xml file. Resource name=Name auth=Container type=oracle.jdbc.pool.OracleDataSource factory=oracle.jdbc.pool.OracleDataSourceFactory user=oraUserName password=oraUserPass driverClassName=oracle.jdbc.driver.OracleDriver url=jdbc:oracle:thin:@IPAddress:1521:orcl maxActive=20 maxIdle=10 maxwait=-1/ java code to get connection: DataSource ds = (DataSource) ctxt.lookup(java:/comp/env/ + poolName); OracleConnection conn = ds.getConnection(); There is used another datasource type in OC4J http://www.oracle.com/technology/sample_code/tech/java/codesnippet/j2ee/jdbc/JDBC_in_J2EE.html Regards, Zdenek On 5/22/07, Mohammed Zabin [EMAIL PROTECTED] wrote: Hi All Am new on this, i want to know how to configure Database Connection Pooling to use Oracle Database?? anyhelp will be appreciated. Jotnarta - To start a new topic, e-mail: users@tomcat.apache.org To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Re: JDBC
Thank you Foo, I but the following in the context.xml: *Resource name=Name auth=Container type=oracle.jdbc.pool.OracleDataSource factory=oracle.jdbc.pool.OracleDataSourceFactory user=hr password=hr driverClassName=oracle.jdbc.driver.OracleDriver url=jdbc:oracle:thin:@localhost:1521:orcldb maxActive=20 maxIdle=10 maxwait=-1/* ** and I have this jsp code: *%@ page import=javax.sql.DataSource %* *% Context initContext = new InitialContext(); Context envContext = (Context)initContext.lookup(java:/comp/env); DataSource ds = (DataSource)envContext.lookup(jdbc/myoracledb); Connection conn = ds.getConnection(); out.println( Got the connection ); %* but, i got the following error: *org.apache.jasper.JasperException: Unable to compile class for JSP: An error occurred at line: 4 in the jsp file: /jsp/testDBCP.jsp Context cannot be resolved to a type 1: %@ page import=javax.sql.DataSource % 2: 3: % 4: Context initContext = new InitialContext(); 5: Context envContext = (Context)initContext.lookup(java:/comp/env); 6: DataSource ds = (DataSource)envContext.lookup(jdbc/myoracledb); 7: Connection conn = ds.getConnection(); An error occurred at line: 4 in the jsp file: /jsp/testDBCP.jsp InitialContext cannot be resolved to a type 1: %@ page import=javax.sql.DataSource % * On 5/22/07, Foo Shyn [EMAIL PROTECTED] wrote: Not both of them. It's context.xml if u're using Tomcat 5.0 or above, or server.xml if u're using Tomcat 4.1 or below, which is located in the conf folder in Tomcat root path. check this link out : http://forums.oracle.com/forums/thread.jspa?messageID=1489914 Hope that helps. FooShyn Mohammed Zabin wrote: Thank you buddy, I have another confusing question for me, I have two web.xml files, one in conf/web.xml and one in my application under WEB-INF, When configuring connection pool, which one shall i use? or shall i put the configuration parameters in both of them?? Thank you On 5/22/07, ben short [EMAIL PROTECTED] wrote: Have a look here.. http://tomcat.apache.org/tomcat-6.0-doc/jndi-datasource-examples-howto.html On 5/22/07, Mohammed Zabin [EMAIL PROTECTED] wrote: Hi All Am new on this, i want to know how to configure Database Connection Pooling to use Oracle Database?? anyhelp will be appreciated. Jotnarta - To start a new topic, e-mail: users@tomcat.apache.org To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] No virus found in this incoming message. Checked by AVG Free Edition. Version: 7.5.467 / Virus Database: 269.7.6/814 - Release Date: 5/21/2007 2:01 PM - To start a new topic, e-mail: users@tomcat.apache.org To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
Re: JDBC
Thank you Foo for your patience with me, I did imported all the needed classes, but i got the following exception: *exception * *org.apache.jasper.JasperException: An exception occurred processing JSP page /jsp/testDBCP.jsp at line 7 4: Context initContext = new InitialContext(); 5: Context envContext = (Context)initContext.lookup(java:/comp/env); 6: DataSource ds = (DataSource)envContext.lookup(jdbc/myoracledb); 7: Connection conn = ds.getConnection(); 8: 9: out.println( The Connection Gotted Fine ); 10: % Stacktrace: org.apache.jasper.servlet.JspServletWrapper.handleJspException(JspServletWrapper.java:515) org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:408) org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:320) org.apache.jasper.servlet.JspServlet.service(JspServlet.java:266) javax.servlet.http.HttpServlet.service(HttpServlet.java:803)* ** *root cause * *javax.servlet.ServletException: org.apache.tomcat.dbcp.dbcp.SQLNestedException: Cannot create JDBC driver of class '' for connect URL 'null' org.apache.jasper.runtime.PageContextImpl.doHandlePageException(PageContextImpl.java:855) org.apache.jasper.runtime.PageContextImpl.handlePageException(PageContextImpl.java:784) org.apache.jsp.jsp.testDBCP_jsp._jspService(testDBCP_jsp.java:73) org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:70) javax.servlet.http.HttpServlet.service(HttpServlet.java:803) org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:384) org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:320) org.apache.jasper.servlet.JspServlet.service(JspServlet.java:266) javax.servlet.http.HttpServlet.service(HttpServlet.java:803)* ** *root cause* org.apache.tomcat.dbcp.dbcp.SQLNestedException: Cannot create JDBC driver of class '' for connect URL 'null' org.apache.tomcat.dbcp.dbcp.BasicDataSource.createDataSource(BasicDataSource.java:780) org.apache.tomcat.dbcp.dbcp.BasicDataSource.getConnection(BasicDataSource.java:540) org.apache.jsp.jsp.testDBCP_jsp._jspService(testDBCP_jsp.java:62) org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:70) javax.servlet.http.HttpServlet.service(HttpServlet.java:803) org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:384) org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:320) org.apache.jasper.servlet.JspServlet.service(JspServlet.java:266) javax.servlet.http.HttpServlet.service(HttpServlet.java:803) *root cause* java.lang.NullPointerException sun.jdbc.odbc.JdbcOdbcDriver.getProtocol(JdbcOdbcDriver.java:507) sun.jdbc.odbc.JdbcOdbcDriver.knownURL(JdbcOdbcDriver.java:476) sun.jdbc.odbc.JdbcOdbcDriver.acceptsURL(JdbcOdbcDriver.java:307) java.sql.DriverManager.getDriver(DriverManager.java:253) org.apache.tomcat.dbcp.dbcp.BasicDataSource.createDataSource(BasicDataSource.java:773) org.apache.tomcat.dbcp.dbcp.BasicDataSource.getConnection(BasicDataSource.java:540) org.apache.jsp.jsp.testDBCP_jsp._jspService(testDBCP_jsp.java:62) org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:70) javax.servlet.http.HttpServlet.service(HttpServlet.java:803) org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:384) org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:320) org.apache.jasper.servlet.JspServlet.service(JspServlet.java:266) javax.servlet.http.HttpServlet.service(HttpServlet.java:803) On 5/22/07, Foo Shyn [EMAIL PROTECTED] wrote: The jsp doesn't import the class for Context and Initial Context. Put them in as how u inport the Datasource would do. HTH FooShyn Mohammed Zabin wrote: Thank you Foo, I but the following in the context.xml: *Resource name=Name auth=Container type=oracle.jdbc.pool.OracleDataSource factory=oracle.jdbc.pool.OracleDataSourceFactory user=hr password=hr driverClassName=oracle.jdbc.driver.OracleDriver url=jdbc:oracle:thin:@localhost:1521:orcldb maxActive=20 maxIdle=10 maxwait=-1/* ** and I have this jsp code: *%@ page import=javax.sql.DataSource %* *% Context initContext = new InitialContext(); Context envContext = (Context)initContext.lookup(java:/comp/env); DataSource ds = (DataSource)envContext.lookup(jdbc/myoracledb); Connection conn = ds.getConnection(); out.println( Got the connection ); %* but, i got the following error: *org.apache.jasper.JasperException: Unable to compile class for JSP: An error occurred at line: 4 in the jsp file: /jsp/testDBCP.jsp Context cannot be resolved to a type 1: %@ page import=javax.sql.DataSource % 2: 3: % 4: Context initContext = new
Re: JDBC
When searching on Tomcat documentation, i found that it uses both server.xmland web.xml, again, I got the same error, *org.apache.jasper.JasperException: An exception occurred processing JSP page /jsp/testDBCP.jsp at line 7 4: Context initContext = new InitialContext(); 5: Context envContext = (Context)initContext.lookup(java:/comp/env); 6: DataSource ds = (DataSource)envContext.lookup(jdbc/myoracledb); 7: Connection conn = ds.getConnection(); 8: 9: out.println( The Connection Gotted Fine ); 10: % Stacktrace: org.apache.jasper.servlet.JspServletWrapper.handleJspException(JspServletWrapper.java:515) org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:408) org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:320) org.apache.jasper.servlet.JspServlet.service(JspServlet.java:266) javax.servlet.http.HttpServlet.service(HttpServlet.java:803)* ** *root cause * *javax.servlet.ServletException: org.apache.tomcat.dbcp.dbcp.SQLNestedException: Cannot create JDBC driver of class '' for connect URL 'null' org.apache.jasper.runtime.PageContextImpl.doHandlePageException(PageContextImpl.java:855) org.apache.jasper.runtime.PageContextImpl.handlePageException(PageContextImpl.java:784) org.apache.jsp.jsp.testDBCP_jsp._jspService(testDBCP_jsp.java:73) org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:70) javax.servlet.http.HttpServlet.service(HttpServlet.java:803) org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:384) org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:320) org.apache.jasper.servlet.JspServlet.service(JspServlet.java:266) javax.servlet.http.HttpServlet.service(HttpServlet.java:803)* On 5/22/07, Foo Shyn [EMAIL PROTECTED] wrote: Check out ur resource name, it is different from the one u use to get ur connection pooling. The resource name must be the same as your lookup name. HTH FooShyn Mohammed Zabin wrote: Thank you Foo for your patience with me, I did imported all the needed classes, but i got the following exception: *exception * *org.apache.jasper.JasperException: An exception occurred processing JSP page /jsp/testDBCP.jsp at line 7 4: Context initContext = new InitialContext(); 5: Context envContext = (Context)initContext.lookup(java:/comp/env); 6: DataSource ds = (DataSource)envContext.lookup(jdbc/myoracledb); 7: Connection conn = ds.getConnection(); 8: 9: out.println( The Connection Gotted Fine ); 10: % Stacktrace: org.apache.jasper.servlet.JspServletWrapper.handleJspException( JspServletWrapper.java:515) org.apache.jasper.servlet.JspServletWrapper.service( JspServletWrapper.java:408) org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java :320) org.apache.jasper.servlet.JspServlet.service(JspServlet.java:266) javax.servlet.http.HttpServlet.service(HttpServlet.java:803)* ** *root cause * *javax.servlet.ServletException: org.apache.tomcat.dbcp.dbcp.SQLNestedException: Cannot create JDBC driver of class '' for connect URL 'null' org.apache.jasper.runtime.PageContextImpl.doHandlePageException( PageContextImpl.java:855) org.apache.jasper.runtime.PageContextImpl.handlePageException( PageContextImpl.java:784) org.apache.jsp.jsp.testDBCP_jsp._jspService(testDBCP_jsp.java:73) org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:70) javax.servlet.http.HttpServlet.service(HttpServlet.java:803) org.apache.jasper.servlet.JspServletWrapper.service( JspServletWrapper.java:384) org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java :320) org.apache.jasper.servlet.JspServlet.service(JspServlet.java:266) javax.servlet.http.HttpServlet.service(HttpServlet.java:803)* ** *root cause* org.apache.tomcat.dbcp.dbcp.SQLNestedException: Cannot create JDBC driver of class '' for connect URL 'null' org.apache.tomcat.dbcp.dbcp.BasicDataSource.createDataSource( BasicDataSource.java:780) org.apache.tomcat.dbcp.dbcp.BasicDataSource.getConnection( BasicDataSource.java:540) org.apache.jsp.jsp.testDBCP_jsp._jspService(testDBCP_jsp.java:62) org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:70) javax.servlet.http.HttpServlet.service(HttpServlet.java:803) org.apache.jasper.servlet.JspServletWrapper.service( JspServletWrapper.java:384) org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java :320) org.apache.jasper.servlet.JspServlet.service(JspServlet.java:266) javax.servlet.http.HttpServlet.service(HttpServlet.java:803) *root cause* java.lang.NullPointerException sun.jdbc.odbc.JdbcOdbcDriver.getProtocol(JdbcOdbcDriver.java:507) sun.jdbc.odbc.JdbcOdbcDriver.knownURL(JdbcOdbcDriver.java:476) sun.jdbc.odbc.JdbcOdbcDriver.acceptsURL(JdbcOdbcDriver.java:307
Oracle 10g with Tomcat 6
Hi All I want to conigure DBCP to connect to Oracle 10g on my localhost on Tomcat6. I did the following error, I don't know how to solve it, is there is a third-party jar file that must be added to classpath??? *1. I put the following in server.xml* *Resource name=jbdc/myoracledb auth=Container type=javax.sql.DataSource / ResourceParams name=jdbc/myoracledb parameter namefactory/name valueorg.apache.commons.dbcp.BasicDataSourceFactory/value /parameter parameter namedriverClassName/name valueoracle.jdbc.OracleDriver/value /parameter parameter nameurl/name valuejdbc:oracle:thin:@127.0.0.1:1521:orcldb/value /parameter parameter nameusername/name valuehr/value /parameter parameter namepassword/name valuehr/value /parameter parameter namemaxActive/name value20/value /parameter parameter namemaxIdle/name value10/value /parameter parameter namemaxWait/name value-1/value /parameter /ResourceParams* *2. The following in web.xml:* *resource-ref descriptionOracle Datasource example/description res-ref-namejdbc/myoracledb/res-ref-name res-typejavax.sql.DataSource/res-type res-authContainer/res-auth /resource-ref* 3. And here is my JSP Code: %@ page import=javax.sql.*, javax.naming.*, java.sql.* % % Context initContext = new InitialContext(); Context envContext = (Context)initContext.lookup(java:/comp/env); DataSource ds = (DataSource)envContext.lookup(jdbc/myoracledb); Connection conn = ds.getConnection(); out.println( Connection Established ); % When running the page, i got the following error: *org.apache.jasper.JasperException: An exception occurred processing JSP page /jsp/testDBCP.jsp at line 7 4: Context initContext = new InitialContext(); 5: Context envContext = (Context)initContext.lookup(java:/comp/env); 6: DataSource ds = (DataSource)envContext.lookup(jdbc/myoracledb); 7: Connection conn = ds.getConnection(); 8: 9: out.println( Connection Established ); 10: % Stacktrace: org.apache.jasper.servlet.JspServletWrapper.handleJspException(JspServletWrapper.java:515) org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:408) org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:320) org.apache.jasper.servlet.JspServlet.service(JspServlet.java:266) javax.servlet.http.HttpServlet.service(HttpServlet.java:803)* ** *root cause * *javax.servlet.ServletException: org.apache.tomcat.dbcp.dbcp.SQLNestedException: Cannot create JDBC driver of class '' for connect URL 'null' org.apache.jasper.runtime.PageContextImpl.doHandlePageException(PageContextImpl.java:855) org.apache.jasper.runtime.PageContextImpl.handlePageException(PageContextImpl.java:784) org.apache.jsp.jsp.testDBCP_jsp._jspService(testDBCP_jsp.java:73) org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:70) javax.servlet.http.HttpServlet.service(HttpServlet.java:803) org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:384) org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:320) org.apache.jasper.servlet.JspServlet.service(JspServlet.java:266) javax.servlet.http.HttpServlet.service(HttpServlet.java:803)*
Configuring PoolMan for MySQL
Hi All I am wondering what is the steps to configure poolman to run with MYSQL Database over tomcat Apache? Regards
