Re: URL Redirect in Tomcat 6
On 10/12/2009 05:38, bharati wrote: Hi, Iam using Tomcat 6. In my applicaion, when Users entered any url like 'www.google.com' then it will check for the status of the User. If he is Inactive, then it will send a http packet to redirect to the particular URL: like http://192.168.100.125:8080/; . Tomcat is listening to this port 8080. My question is: how do I get the url from tomcat..? If manually user types the url http://192.168.100.125:8080/ then it is displaying proper page to login. But in this case, Internet User does not know the URL. so...i need to get the URL from Tomcat which is listening to 8080 Port. Please help me. Thanks in advance. I'm baffled, I don't know about anyone else... Perhaps you could rephrase your question in a way that might allow us to help you? http://catb.org/~esr/faqs/smart-questions.html p - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org
RE: URL Redirect in Tomcat 6
I guess she wants to display Customizable error responses, when application fails to respond (error code like 404 etc). Though, I agree, the question is not properly framed... With best regards, Nishant Hadole Siemens IT Solutions and Services SIS PRO SI-I Tel.: +91 22 2495 7816 Fax: +91 22 6660 8521 Mailto: nishant.had...@siemens.com www.siemens.co.in -Original Message- From: Pid [mailto:p...@pidster.com] Sent: Thursday, 10 December, 2009 02:29 PM To: users@tomcat.apache.org Subject: Re: URL Redirect in Tomcat 6 On 10/12/2009 05:38, bharati wrote: Hi, Iam using Tomcat 6. In my applicaion, when Users entered any url like 'www.google.com' then it will check for the status of the User. If he is Inactive, then it will send a http packet to redirect to the particular URL: like http://192.168.100.125:8080/; . Tomcat is listening to this port 8080. My question is: how do I get the url from tomcat..? If manually user types the url http://192.168.100.125:8080/ then it is displaying proper page to login. But in this case, Internet User does not know the URL. so...i need to get the URL from Tomcat which is listening to 8080 Port. Please help me. Thanks in advance. I'm baffled, I don't know about anyone else... Perhaps you could rephrase your question in a way that might allow us to help you? http://catb.org/~esr/faqs/smart-questions.html p - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org
Re: URL Redirect in Tomcat 6
-BEGIN PGP SIGNED MESSAGE- Hash: SHA1 To whom it may concern, On 12/10/2009 12:38 AM, bharati wrote: Iam using Tomcat 6. In my applicaion, when Users entered any url like 'www.google.com' then it will check for the status of the User. Where does a user enter such a URL? Into the web browser's address bar? If so, your application is not doing anything in this case (since presumably the request will go to www.google.com). If he is Inactive, then it will send a http packet to redirect to the particular URL: like http://192.168.100.125:8080/; . Tomcat is listening to this port 8080. Okay, sounds good. My question is: how do I get the url from tomcat..? Could it be as simple as request.getRequestURL()? This will return http://192.168.100.125:8080/; in the above example. If you're trying to get the string www.google.com, you'll probably have to try: request.getHeader(Referer) (note the intentional, historic misspelling of referer) This may be NULL if the client has been configured not to send the URL of the referring page, though. Is that what you were looking for? I agree with the other responses that your question was quite unclear. - -chris -BEGIN PGP SIGNATURE- Version: GnuPG v1.4.10 (MingW32) Comment: Using GnuPG with Mozilla - http://enigmail.mozdev.org/ iEYEARECAAYFAkshfyIACgkQ9CaO5/Lv0PAJ8wCeKmg8Gj7/AIZb4FM5pWKyr0uI fY8An1sUIwWWCvsGKZXH2kQUs+oe403w =Qxrl -END PGP SIGNATURE- - To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org
