On 10/12/2009 05:38, bharati wrote:

Hi,
  Iam using Tomcat 6. In my applicaion, when Users entered any url like
'www.google.com'  then it will check for the status of the User.
>
If he is Inactive, then it will send a http packet to redirect to the 
particular URL:
like "http://192.168.100.125:8080/";  . Tomcat is listening to this port
8080.
>
  My question is: how do I get the url from tomcat..? If manually user types
the url http://192.168.100.125:8080/  then it is displaying proper page to
login.
>
But in this case, Internet User does not know the URL. so...i need to get
the URL from Tomcat which is listening to 8080 Port.

Please help me.
Thanks in advance.

I'm baffled, I don't know about anyone else... Perhaps you could rephrase your question in a way that might allow us to help you?

 http://catb.org/~esr/faqs/smart-questions.html


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