Re: How to delete an item from List view.
Hi
I have got a refreshingView with a delete link in each row and only one
AddLink,AddLink adds the
row properly but deleteRow everytime deletes the last row,its driving me
crazy,I have posted my
code also.I will apprecaite if any one can help me in this.
Honestly its not that easy the way it seams.
Thanks
Prati
prati wrote:
Hi,
I am also having similar issue, it all the time removes last row.
I have attached code.
OptionGroupPageForm(String id) {
super(id);
final MarkupContainer rowPanel = new
WebMarkupContainer(rowPanel);
rowPanel.setOutputMarkupId(true);
add(rowPanel);
// List all rows
rows.add(new String());
RefreshingView lv = new RefreshingView(rows) {
@Override
protected IteratorIModel getItemModels()
{
List models = new ArrayList();
for(int i=0;irows.size();i++){
models.add(new Model( (String)
rows.get(i)));
}
return models.iterator();
//return rows.iterator();
}
@Override
protected void populateItem(final Item item) {
int index = item.getIndex() + 1;
item.add(new Label(index,
Option+index + .));
TextField text = new TextField(text,
item.getModel());
RadioChoice rc = new
RadioChoice(status, STATUS);
item.add(text);
item.add(rc);
item.add(new AjaxLink(removeRow) {
@Override
public void
onClick(AjaxRequestTarget target) {
if (target != null) {
target.addComponent(rowPanel);
}
}
} );
}
};
lv.setItemReuseStrategy(ReuseIfModelsEqualStrategy.getInstance());
rowPanel.add(lv);
AjaxSubmitLink addLink = new AjaxSubmitLink(addRow,
this) {
@Override
public void onSubmit(AjaxRequestTarget target,
Form form) {
rows.add(new String());
if (target != null)
target.addComponent(rowPanel);
}
};
addLink.setDefaultFormProcessing(false);
add(addLink);
}
Thanks
Prati
Johan Compagner wrote:
You do use a delete button, so i guess the values are submitted.
Then if you store those first in the model objects you won't loose
anything
johan
On Feb 4, 2008 2:35 PM, pnerkar pner...@gmail.com wrote:
Hi Johan,
Yes that will be quickest solution ,
But this will clear the fields of all vehicles.
-Pnerkar
Johan Compagner wrote:
wasn't the quickest solution:
public void onSubmit() {
List vehicles = (List)
getParent().getParent().getModelObject();
vehicles.remove(index);
listView.removeAll();
}
Then if the list itself is stable on the server side (if other persons
can
also delete or add stuff to that list you really should do it
differently)
that should work fine. After you alter the listviews model you have to
remove all the items so that it will rebuild
johan
On Feb 1, 2008 12:49 AM, pnerkar pner...@gmail.com wrote:
Hi All,
I have rendered a list view on a Web Page.
vehicle1X
vehicle2X
vehicle3X
when a person click on 'X', that item should be deleted.
But I'm facing an issue, when i click on 'X', last item get deleted.
Actually when I delete vehicle2 from my list, it deletes vehicle2 but
that
component is still there.
So while rendering it render vehicle1 vehicle2.
public void onSubmit() {
List vehicles = (List)
getParent().getParent().getModelObject();
vehicles.remove(index);
}
can please
Re: How to delete an item from List view.
Hi Team,
Also i dont want to remove values , i want to remove the entire row.
My row contains(TextBox and option group)
Thanks
Prati
prati wrote:
Hi
I have got a refreshingView with a delete link in each row and only one
AddLink,AddLink adds the
row properly but deleteRow everytime deletes the last row,its driving me
crazy,I have posted my
code also.I will apprecaite if any one can help me in this.
Honestly its not that easy the way it seams.
Thanks
Prati
prati wrote:
Hi,
I am also having similar issue, it all the time removes last row.
I have attached code.
OptionGroupPageForm(String id) {
super(id);
final MarkupContainer rowPanel = new
WebMarkupContainer(rowPanel);
rowPanel.setOutputMarkupId(true);
add(rowPanel);
// List all rows
rows.add(new String());
RefreshingView lv = new RefreshingView(rows) {
@Override
protected IteratorIModel getItemModels()
{
List models = new ArrayList();
for(int i=0;irows.size();i++){
models.add(new Model( (String)
rows.get(i)));
}
return models.iterator();
//return rows.iterator();
}
@Override
protected void populateItem(final Item item) {
int index = item.getIndex() + 1;
item.add(new Label(index,
Option+index + .));
TextField text = new TextField(text,
item.getModel());
RadioChoice rc = new
RadioChoice(status, STATUS);
item.add(text);
item.add(rc);
item.add(new AjaxLink(removeRow) {
@Override
public void
onClick(AjaxRequestTarget target) {
if (target != null) {
target.addComponent(rowPanel);
}
}
} );
}
};
lv.setItemReuseStrategy(ReuseIfModelsEqualStrategy.getInstance());
rowPanel.add(lv);
AjaxSubmitLink addLink = new AjaxSubmitLink(addRow,
this) {
@Override
public void onSubmit(AjaxRequestTarget target,
Form form) {
rows.add(new String());
if (target != null)
target.addComponent(rowPanel);
}
};
addLink.setDefaultFormProcessing(false);
add(addLink);
}
Thanks
Prati
Johan Compagner wrote:
You do use a delete button, so i guess the values are submitted.
Then if you store those first in the model objects you won't loose
anything
johan
On Feb 4, 2008 2:35 PM, pnerkar pner...@gmail.com wrote:
Hi Johan,
Yes that will be quickest solution ,
But this will clear the fields of all vehicles.
-Pnerkar
Johan Compagner wrote:
wasn't the quickest solution:
public void onSubmit() {
List vehicles = (List)
getParent().getParent().getModelObject();
vehicles.remove(index);
listView.removeAll();
}
Then if the list itself is stable on the server side (if other
persons
can
also delete or add stuff to that list you really should do it
differently)
that should work fine. After you alter the listviews model you have
to
remove all the items so that it will rebuild
johan
On Feb 1, 2008 12:49 AM, pnerkar pner...@gmail.com wrote:
Hi All,
I have rendered a list view on a Web Page.
vehicle1X
vehicle2X
vehicle3X
when a person click on 'X', that item should be deleted.
But I'm facing an issue, when i click on 'X', last item get deleted.
Actually when I delete vehicle2 from my list, it deletes vehicle2
but
that
component is still there.
So while rendering it render vehicle1 vehicle2.
public void onSubmit
Re: How to delete an item from List view.
Hi ListView/Refreshing View any willd o
but dont know how to solve this.
Thanks
P
prati wrote:
Hi Team,
Also i dont want to remove values , i want to remove the entire row.
My row contains(TextBox and option group)
Thanks
Prati
prati wrote:
Hi
I have got a refreshingView with a delete link in each row and only one
AddLink,AddLink adds the
row properly but deleteRow everytime deletes the last row,its driving me
crazy,I have posted my
code also.I will apprecaite if any one can help me in this.
Honestly its not that easy the way it seams.
Thanks
Prati
prati wrote:
Hi,
I am also having similar issue, it all the time removes last row.
I have attached code.
OptionGroupPageForm(String id) {
super(id);
final MarkupContainer rowPanel = new
WebMarkupContainer(rowPanel);
rowPanel.setOutputMarkupId(true);
add(rowPanel);
// List all rows
rows.add(new String());
RefreshingView lv = new RefreshingView(rows) {
@Override
protected IteratorIModel getItemModels()
{
List models = new ArrayList();
for(int i=0;irows.size();i++){
models.add(new Model( (String)
rows.get(i)));
}
return models.iterator();
//return rows.iterator();
}
@Override
protected void populateItem(final Item item) {
int index = item.getIndex() + 1;
item.add(new Label(index,
Option+index + .));
TextField text = new TextField(text,
item.getModel());
RadioChoice rc = new
RadioChoice(status, STATUS);
item.add(text);
item.add(rc);
item.add(new AjaxLink(removeRow) {
@Override
public void
onClick(AjaxRequestTarget target) {
if (target != null) {
target.addComponent(rowPanel);
}
}
} );
}
};
lv.setItemReuseStrategy(ReuseIfModelsEqualStrategy.getInstance());
rowPanel.add(lv);
AjaxSubmitLink addLink = new AjaxSubmitLink(addRow,
this) {
@Override
public void onSubmit(AjaxRequestTarget target,
Form form) {
rows.add(new String());
if (target != null)
target.addComponent(rowPanel);
}
};
addLink.setDefaultFormProcessing(false);
add(addLink);
}
Thanks
Prati
Johan Compagner wrote:
You do use a delete button, so i guess the values are submitted.
Then if you store those first in the model objects you won't loose
anything
johan
On Feb 4, 2008 2:35 PM, pnerkar pner...@gmail.com wrote:
Hi Johan,
Yes that will be quickest solution ,
But this will clear the fields of all vehicles.
-Pnerkar
Johan Compagner wrote:
wasn't the quickest solution:
public void onSubmit() {
List vehicles = (List)
getParent().getParent().getModelObject();
vehicles.remove(index);
listView.removeAll();
}
Then if the list itself is stable on the server side (if other
persons
can
also delete or add stuff to that list you really should do it
differently)
that should work fine. After you alter the listviews model you have
to
remove all the items so that it will rebuild
johan
On Feb 1, 2008 12:49 AM, pnerkar pner...@gmail.com wrote:
Hi All,
I have rendered a list view on a Web Page.
vehicle1X
vehicle2X
vehicle3X
when a person click on 'X', that item should be deleted.
But I'm facing an issue, when i click on 'X', last item get
deleted.
Actually when I delete vehicle2 from my list, it deletes vehicle2
but
that
component is still there.
So while
Re: How to delete an item from List view.
Hi,
I am also having similar issue, it all the time removes last row.
I have attached code.
OptionGroupPageForm(String id) {
super(id);
final MarkupContainer rowPanel = new
WebMarkupContainer(rowPanel);
rowPanel.setOutputMarkupId(true);
add(rowPanel);
// List all rows
rows.add(new String());
RefreshingView lv = new RefreshingView(rows) {
@Override
protected IteratorIModel getItemModels()
{
List models = new ArrayList();
for(int i=0;irows.size();i++){
models.add(new Model( (String)
rows.get(i)));
}
return models.iterator();
//return rows.iterator();
}
@Override
protected void populateItem(final Item item) {
int index = item.getIndex() + 1;
item.add(new Label(index,
Option+index + .));
TextField text = new TextField(text,
item.getModel());
RadioChoice rc = new
RadioChoice(status, STATUS);
item.add(text);
item.add(rc);
item.add(new AjaxLink(removeRow) {
@Override
public void
onClick(AjaxRequestTarget target) {
if (target != null) {
target.addComponent(rowPanel);
}
}
} );
}
};
lv.setItemReuseStrategy(ReuseIfModelsEqualStrategy.getInstance());
rowPanel.add(lv);
AjaxSubmitLink addLink = new AjaxSubmitLink(addRow,
this) {
@Override
public void onSubmit(AjaxRequestTarget target,
Form form) {
rows.add(new String());
if (target != null)
target.addComponent(rowPanel);
}
};
addLink.setDefaultFormProcessing(false);
add(addLink);
}
Thanks
Prati
Johan Compagner wrote:
You do use a delete button, so i guess the values are submitted.
Then if you store those first in the model objects you won't loose
anything
johan
On Feb 4, 2008 2:35 PM, pnerkar pner...@gmail.com wrote:
Hi Johan,
Yes that will be quickest solution ,
But this will clear the fields of all vehicles.
-Pnerkar
Johan Compagner wrote:
wasn't the quickest solution:
public void onSubmit() {
List vehicles = (List) getParent().getParent().getModelObject();
vehicles.remove(index);
listView.removeAll();
}
Then if the list itself is stable on the server side (if other persons
can
also delete or add stuff to that list you really should do it
differently)
that should work fine. After you alter the listviews model you have to
remove all the items so that it will rebuild
johan
On Feb 1, 2008 12:49 AM, pnerkar pner...@gmail.com wrote:
Hi All,
I have rendered a list view on a Web Page.
vehicle1X
vehicle2X
vehicle3X
when a person click on 'X', that item should be deleted.
But I'm facing an issue, when i click on 'X', last item get deleted.
Actually when I delete vehicle2 from my list, it deletes vehicle2 but
that
component is still there.
So while rendering it render vehicle1 vehicle2.
public void onSubmit() {
List vehicles = (List)
getParent().getParent().getModelObject();
vehicles.remove(index);
}
can please help out ??
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Re: How to access ListItem from ListView from AjaxLink?
Hi
I have got a refreshing view ,it contains list of links.I need to highlight
the link when i click on that link.
It works properly but if i click the next item in the list,the previous text
remains highlighted.
wicket:extend
table cellspacing=0 class=dataview
tr
thFirst Name/th
/tr
tr wicket:id=view
td # /td
/tr
/table
/wicket:extend
public class RefreshingPage extends BasePage {
public RefreshingPage()
{
final ListIModel contacts = new ArrayListIModel(10);
// populate list of contacts to be displayed
IteratorContact it = rgetContacts().iterator();
while (it.hasNext())
{
contacts.add(new Model(it.next()));
}
// create the refreshing view
RefreshingView view = new RefreshingView(view)
{
/**
* Return an iterator over models for items in the view
*/
@Override
protected IteratorIModel getItemModels()
{
return contacts.iterator();
}
@Override
protected void populateItem(final Item item)
{
Contact contact = (Contact)
item.getModelObject();
final Label contacteLabel = new
Label(aname,contact.getName());
contacteLabel.setOutputMarkupId(true);
item.add(new AjaxLink(name) {
private static final long
serialVersionUID = 1L;
@Override
public void onClick(AjaxRequestTarget
target) {
if(target!= null) {
contacteLabel.add(new
AttributeModifier(style, true, new AbstractReadOnlyModel() {
@Override
public String getObject() {
return background-color:#80b6ed;;
}
}));
target.addComponent(contacteLabel);
}
}
}.add(contacteLabel));
}
};
add(view);
}
}
Regards
P
moontz wrote:
i tried that before. did not work. no compile or runtime errors, but the
source did not show the change.
im thinking, since its an ajax link and because only the target panel
refreshes, the change to the link is not applied because the actual link
is not refreshed. only the other panel is. in which case i would need to
append javascript. i was hping there was a pure wicket solutioin though
without using JS.
igor.vaynberg wrote:
final ListItem item
-igor
On Fri, Feb 13, 2009 at 7:36 AM, moontz bmun...@yahoo.com wrote:
I would like to add an attribute to the ListItem element in the markup
(basically change the class style) on click of the link. Below is my
snippet. Any insight on how I can accomplish this? Thanks in advance!
ListView lv = new ListView(tabListView, tabList) {
protected void populateItem(ListItem item) {
AjaxLink ajaxLink = new AjaxLink(tabLink,
item.getModel()) {
public void onClick(AjaxRequestTarget target)
{
item.add(new
SimpleAttributeModifier(class, on)); //
want to do this but do not have access to item object from inner class
--
ideas for this?
.
.
.
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Re: How to access ListItem from ListView from AjaxLink?
Hi Cemal,
Thanks for replying me,but the list gets rendered only once,and i am able to
capture previous value on click but then how to move further.
Regards
P
jWeekend wrote:
Prati,
This is because you are only re-rendering the most recently selected
label.
One solution is keep track of the previous current selection
(probably in your RefreshingView implementation - eg declare
Component currentSelection;), which you update in your Link's
onClick (ie currentSelecton = contactLabel;) _after_ you remove the
style attribute (that you previously set) on currentSelection and add
currrentSelection to the AjaxRequestTarget so it too gets refreshed.
Make sense?
Regards - Cemal
jWeekend
OO Java Technologies, Wicket
Consulting, Development, Training
http://jWeekend.com
On 11 March 2010 18:09, prati pratibha.pari...@gmail.com wrote:
Hi
I have got a refreshing view ,it contains list of links.I need to
highlight
the link when i click on that link.
It works properly but if i click the next item in the list,the previous
text
remains highlighted.
wicket:extend
table cellspacing=0 class=dataview
tr
thFirst Name/th
/tr
tr wicket:id=view
td # /td
/tr
/table
/wicket:extend
public class RefreshingPage extends BasePage {
public RefreshingPage()
{
final ListIModel contacts = new ArrayListIModel(10);
// populate list of contacts to be displayed
IteratorContact it = rgetContacts().iterator();
while (it.hasNext())
{
contacts.add(new Model(it.next()));
}
// create the refreshing view
RefreshingView view = new RefreshingView(view)
{
/**
* Return an iterator over models for items in the
view
*/
�...@override
protected IteratorIModel getItemModels()
{
return contacts.iterator();
}
�...@override
protected void populateItem(final Item item)
{
Contact contact = (Contact)
item.getModelObject();
final Label contacteLabel = new
Label(aname,contact.getName());
contacteLabel.setOutputMarkupId(true);
item.add(new AjaxLink(name) {
private static final long
serialVersionUID = 1L;
�...@override
public void
onClick(AjaxRequestTarget target) {
if(target!= null) {
contacteLabel.add(new
AttributeModifier(style, true, new AbstractReadOnlyModel() {
�...@override
public String getObject() {
return background-color:#80b6ed;;
}
}));
target.addComponent(contacteLabel);
}
}
}.add(contacteLabel));
}
};
add(view);
}
}
Regards
P
moontz wrote:
i tried that before. did not work. no compile or runtime errors, but
the
source did not show the change.
im thinking, since its an ajax link and because only the target panel
refreshes, the change to the link is not applied because the actual link
is not refreshed. only the other panel is. in which case i would need
to
append javascript. i was hping there was a pure wicket solutioin though
without using JS.
igor.vaynberg wrote:
final ListItem item
-igor
On Fri, Feb 13, 2009 at 7:36 AM, moontz bmun...@yahoo.com wrote:
I would like to add an attribute to the ListItem element in the markup
(basically change the class style) on click of the link. Below is my
snippet. Any insight on how I can accomplish this? Thanks in
advance!
ListView lv = new ListView(tabListView, tabList) {
protected void populateItem(ListItem item) {
AjaxLink ajaxLink = new AjaxLink(tabLink,
item.getModel()) {
public void onClick
Re: Integrating Hibernate Validator with Wicket
Hi
I integrated Hibernate Validator given in Wicket stuff with my application
I am getting this error
org.hibernate.PropertyValueException: not-null property references a null or
transient value:
Any ideas?
Thanks
P
Carlos Vara wrote:
Hi,
if you prefer to use JSR 303 Bean Validation (it's very similar to
Hibernate
Validator, in fact, it is the reference implementation), I made a blog
post
about how to integrate it with Wicket:
http://carinae.net/2009/12/integration-of-jsr-303-bean-validation-standard-and-wicket-1-4/
On Mon, Jan 4, 2010 at 11:28 AM, ayman elwany aymanelw...@gmail.com
wrote:
thanks Martin for the link , I used it but I had a problem;
public class CarPage extends WebPage {
* ..*
* ..*
UserModel user=
((LoginSession)getSession()).getUserBean();
* ..*
*..*
* ..*
private void fillPersonalInfoComponents(Form personalForm) {
* ..*
* .. *
PropertyModel fullnamepropertyModel =new
PropertyModelString(user, fullNameValue);
fullName = new TextField(fullName, fullnamepropertyModel);
personalForm.add(fullName);
//System.out.println(Model =
+fullnamepropertyModel.getChainedModel().getClass().getName());
fullName.add(new HibernateValidatorString(fullnamepropertyModel,
fullNameValue));
}
}
And the user model is
public class UserModel implements Serializable {
/**
*
*/
private static final long serialVersionUID = 1011452297289823651L;
* ..*
* ..*
* ..*
@NotNull
@NotEmpty
private String fullNameValue;
* ..*
* ..*
* ..*
}
but it always fails and gives me that my model is null . but the strange
behaviour that when I changed HibernateValidator constructor
*from*
public HibernateValidator(I*Model entityModel*, String property) {
this.property = property;
if (entityModel != null)
hibernateValidator = new
ClassValidator(*entityModel.getObject().getClass()*
);
}
*TO*
public HibernateValidator(*Object bean, *String property) {
this.property = property;
//if (entityModel != null)
hibernateValidator = new ClassValidator(*bean.getClass()*);
}
and did this
fullName.add(new HibernateValidatorString(user, fullNameValue));
the validation worked *fine *!!!
so is there is any problem in the propertymodel with hibernate
validator???
On Mon, Jan 4, 2010 at 8:37 AM, Martin Makundi
martin.maku...@koodaripalvelut.com wrote:
http://42lines.net/content/integrating-hibernate-validator-and-wicket
2010/1/4 ayman elwany aymanelw...@gmail.com:
Hi,
Is there any common practice to integrate wicket with hibernate
validator
?
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Re: Checkbox tree component
Hi i also am having same kind of problem. I got checkboxes in tree panel ,how to iterate over the selected nodes on checkbox click. Thanks Partibha Edi wrote: I am not able to configure the above example Doug. Could you give me .war file. please thanks and regards, edi Doug Leeper wrote: If the tree is pre-loaded, it is easier. When the checkbox is selected, iterate through the children nodes and set its state to selected. The dynamically loaded is alot trickier...as you would have to load the tree from the selected node and then iterate and set the children notes to selected. Are you sure you want to select the children nodes or is it the parent nodes you want to select? -- View this message in context: http://old.nabble.com/Checkbox-tree-component-tp13433102p27250675.html Sent from the Wicket - User mailing list archive at Nabble.com. - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org
Re: Dynamically update TreeTable model
Hi i too am facing this problem. When i refresh the page the tree collapses to its original state. Please guide me how to solve this Thanks Prati CrocodileShoes wrote: I've finally got this working by extending DefaultTreeState and overriding the isNodeSelected to calculate the selection based upon the wicket model containing the data. This makes more sense since the tree's state is representative of the actual data now! -- View this message in context: http://old.nabble.com/Dynamically-update-TreeTable-model-tp21056846p27234506.html Sent from the Wicket - User mailing list archive at Nabble.com. - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org
Re: Tree table with check box
Hey it worked,i wanted checkbox in other column
Above apparoach works perfectly.
Thanks
prati wrote:
Hi Peter,
Many thanks for your reply.My problem is exactly same as second one
discussed in the post.
I need checkbox in other column .
Code is
TreeTable.html
/tr
trtd wicket:id=treeTable class=my-tree/td
td /td
/tr
TreeTable.java
public TreeTablePage()
{
IColumn columns[] = new IColumn[] { col1(), col2() };
tree = new TreeTable(treeTable, createTreeModel(), columns);
tree.getTreeState().setAllowSelectMultiple(true);
add(tree);
tree.getTreeState().collapseAll();
}
private PropertyTreeColumn col1() {
return new PropertyTreeColumn(new
ColumnLocation(Alignment.MIDDLE, 5,
Unit.PROPORTIONAL), Check,
userObject.name);
}
private PropertyTreeColumn col2() {
return new PropertyTreeColumn(new
ColumnLocation(Alignment.LEFT,
7, Unit.EM), L2,
userObject.name) {
@Override
public Component newCell(MarkupContainer parent, String
id, TreeNode
node, int level) {
DefaultMutableTreeNode n =
(DefaultMutableTreeNode) node;
CheckBoxPanel boxPanel = new
CheckBoxPanel(mypanel);
return boxPanel;
}
};
}
I am getting no getter methods defined for ModelBean.
Am i doing it in a right way particularly HTML
Thanks
Prati
aldaris wrote:
Hi,
check out wicket-tree (http://code.google.com/p/wicket-tree/) and see
the example app, I think it will solve your problem.
Regards,
Peter
prati írta:
Hi,
I am also stuck in similar problem.If you can share your code snippets
of
how u did that will be of great help.
Thanks
Pratibha
vela wrote:
Hello again,
The links and nodes are added in the TreeFragment class. But the
TreeFragment is a private inner class in Treetable, could you tell how
to
use the TreeFragment to acheive this functionality
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Re: Tree table with check box
Hi, I am also stuck in similar problem.If you can share your code snippets of how u did that will be of great help. Thanks Pratibha vela wrote: Hello again, The links and nodes are added in the TreeFragment class. But the TreeFragment is a private inner class in Treetable, could you tell how to use the TreeFragment to acheive this functionality -- View this message in context: http://old.nabble.com/Tree-table-with-check-box-tp26080852p27164039.html Sent from the Wicket - User mailing list archive at Nabble.com. - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org
