Re: Validator Can't Find Form Submitting Component
Please upgrade to 1.4.22 first and recheck the problem. Sven On 06/13/2013 05:49 PM, Richard W. Adams wrote: [Re-sending, as I noticed my previous send was an accidental forward, so probably ended up in the wrong thread. Also adding some more info] I have a form inside a panel. The form is nested inside another form that includes the panel. The panel form has a validator which is supposed to validate only conditionally, depending on how the form was submitted. When I submit the panel form via an AjaxSubmitLink, the call to findSubmittingButton() inside the validator returns null, even though I called panelForm.add(theLiink). Is this expected behavior? I know the findSubmittingButton() method says button, but it returns an IFormSubmittingComponent, so I would expect it could return either a button or a submitting link. I need to distinguish between the various links/buttons that can submit the form. Is this not possible with an AjaxSubmitLink? I'm using Wicket 1.4.17. ** This email and any attachments may contain information that is confidential and/or privileged for the sole use of the intended recipient. Any use, review, disclosure, copying, distribution or reliance by others, and any forwarding of this email or its contents, without the express permission of the sender is strictly prohibited by law. If you are not the intended recipient, please contact the sender immediately, delete the e-mail and destroy all copies. ** - To unsubscribe, e-mail: users-unsubscr...@wicket.apache.org For additional commands, e-mail: users-h...@wicket.apache.org
Form Submitting Component
When I submit a form via an AjaxSubmitLink, form.findSubmittingButton()
returns null, even though I called form.add(theLlink). Is this expected
behavior? I know the findSubmittingButton() method says button, but it
returns an IFormSubmittingComponent, so I would expect it could return
either a button or a submitting link.
I need to distinguish between the various links/buttons that can submit
the form. Is this not possible with an AjaxSubmitLink? I'm using Wicket
1.4.17.
From: Sven Meier s...@meiers.net
To: users@wicket.apache.org
Date: 06/13/2013 07:53 AM
Subject:Re: wicket and JPA
Please read 9.6 Detachable models of the Wicket Free Guide and come
back with your questions.
Sven
On 06/13/2013 01:20 PM, Boris Brinza wrote:
Hello to all,
I have some fundamental issues with integration of jpa into wicket.
I develop web application using wicket 6 and JPA (eclipselink). Maybe
next question is more JPA oriented, but nevertheless:
Lets say i have
class BaseDetailPageT extens BaseDO extends WebPage {
protected T dbEntity;
}
where dbEntity is instance of jpa persisted object.
BaseDetail page contains form for editing db entity using
CompoundPropertyModel.
After i open detail page, entity is read from DB and page is displayed
(if edit button is pressed) or i create new instance of object (if add
button is pressed).
After submit, if i want to add new record, everything is clear, i call
beginTX(), entityManager.persist(dbEntity), commitTX().
But what about updating existing record?
Every example for JPA shows some basic code like this:
beginTX()
dbObject.setXXX();
dbObject.setYYY();
commitTX()
But how to integrate this into wicket form using compound property
model?
There is no such code for setting properties of db object, and jpa
does not have anything like entityManager.update().
Now i use hack (by my opinion it';s a hack)
beginTX()
entityManaget.detach(dbObject);
entityManager.merge(dbObject)
commitTX()
but i am not sure, if it's right solution (or i'm almost sure it's not
right attitude)
Is there any tutorial how to integrate these frameworks, or some
simple opensource project to check how it's solved?
Thanks for any advice,
Boris
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Validator Can't Find Form Submitting Component
[Re-sending, as I noticed my previous send was an accidental forward, so probably ended up in the wrong thread. Also adding some more info] I have a form inside a panel. The form is nested inside another form that includes the panel. The panel form has a validator which is supposed to validate only conditionally, depending on how the form was submitted. When I submit the panel form via an AjaxSubmitLink, the call to findSubmittingButton() inside the validator returns null, even though I called panelForm.add(theLiink). Is this expected behavior? I know the findSubmittingButton() method says button, but it returns an IFormSubmittingComponent, so I would expect it could return either a button or a submitting link. I need to distinguish between the various links/buttons that can submit the form. Is this not possible with an AjaxSubmitLink? I'm using Wicket 1.4.17. ** This email and any attachments may contain information that is confidential and/or privileged for the sole use of the intended recipient. Any use, review, disclosure, copying, distribution or reliance by others, and any forwarding of this email or its contents, without the express permission of the sender is strictly prohibited by law. If you are not the intended recipient, please contact the sender immediately, delete the e-mail and destroy all copies. **
