Re: [Vo]:Laser Cooling -> Cooling with radiation

[Robin]

In reply to  bobcook39...@hotmail.com's message of Thu, 5 May 2022 05:47:34 
+:
Hi Bob,

I think the standard answer is because of the ZPE. The particles in the nucleus 
are constantly in motion, and
occasionally that motion gives rise to a rearrangement of the particles that 
allows a radionuclide to decay.
IIRC, there is a fairly strong correlation between decay energy and half life 
(for a given type of decay).
Generally, the larger the decay energy, the shorter the half life.

However the point I was trying to make, was that if your method worked, then 
why doesn't it get used by radionuclides,
which instead appear to decay by particle emission &/or gamma radiation?

>Robin--
>
>Why does nuclear decay happen routinely?
>
>The swap of potential energy of a  QM system is not without restrictions os
>regarding conservation of angular momentum and conservation of total energy.  
>In addition the allowable quantum states that are phonic states with  specific 
>non continuous values of kinetic emerge  AND angular momentum.  The angular 
>momentum must b a multiple of h/2 pie.
>
>The proper matching of parameters within a arbitrary QN system does not occur 
>very often in nature.  However it can be engineered in LENR reactors.
>
>Key parameters include startimg material QM enerfy states and  and angular 
>momentum quantum states and  phonic energy states.   Magneticc fields 
>including resonances are also important to modify QM system allowed energy 
>states .
>
>
>Bob Cook
>
>From: Robin
>Sent: Wednesday, May 4, 2022 3:03 PM
>To: vortex-l@eskimo.com
>Subject: Re: [Vo]:Laser Cooling -> Cooling with radiation
>
>In reply to  bobcook39...@hotmail.com's message of Wed, 4 May 2022 16:49:08 
>+:
>Hi Bob,
>[snip]
>>Radiation cooling is how the final process of LENR works.
>>
>>The first step is to swap nuclear potential energy to kinetic spin phonic 
>>energy of a QM atom (including electronic structure) which is classical 
>>thermal energy subject to common radiation cooling in the second step.
>
>...then one wonders why this doesn't apply to the normal decay of 
>radioisotopes?
>If no one clicked on ads companies would stop paying for them. :)
If no one clicked on ads companies would stop paying for them. :)

RE: [Vo]:Laser Cooling -> Cooling with radiation

[Chris Zell]

I have always wondered about what appears to be a breathtaking untidiness about 
radioactive decay. Each isotope has its' own half life, unmoored or untriggered 
by external events.  On the surface, it looks like the worst possible violation 
of any notion of Occams Razor imaginable.  It's crazy arbitrary.

From: bobcook39...@hotmail.com 
Sent: Thursday, May 05, 2022 1:48 AM
To: vortex-l@eskimo.com
Subject: RE: [Vo]:Laser Cooling -> Cooling with radiation

Robin--

Why does nuclear decay happen routinely?

The swap of potential energy of a  QM system is not without restrictions os
regarding conservation of angular momentum and conservation of total energy.  
In addition the allowable quantum states that are phonic states with  specific 
non continuous values of kinetic emerge  AND angular momentum.  The angular 
momentum must b a multiple of h/2 pie.

The proper matching of parameters within a arbitrary QN system does not occur 
very often in nature.  However it can be engineered in LENR reactors.

Key parameters include startimg material QM enerfy states and  and angular 
momentum quantum states and  phonic energy states.   Magneticc fields including 
resonances are also important to modify QM system allowed energy states .


Bob Cook

From: Robin
Sent: Wednesday, May 4, 2022 3:03 PM
To: vortex-l@eskimo.com
Subject: Re: [Vo]:Laser Cooling -> Cooling with radiation

In reply to  bobcook39...@hotmail.com's 
message of Wed, 4 May 2022 16:49:08 +:
Hi Bob,
[snip]
>Radiation cooling is how the final process of LENR works.
>
>The first step is to swap nuclear potential energy to kinetic spin phonic 
>energy of a QM atom (including electronic structure) which is classical 
>thermal energy subject to common radiation cooling in the second step.

...then one wonders why this doesn't apply to the normal decay of radioisotopes?
If no one clicked on ads companies would stop paying for them. :)



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