Re: [Vo]:a longer duration black box test would prove issue without disclosure

2011-01-19 Thread Jed Rothwell

Stephen A. Lawrence wrote:

*/PLEASE!/*  Let's strive for a little more precision in the language 
here!


It was *not* disinformation, which is misinformation that is 
_deliberately_ disseminated in order to influence or confuse rivals 
(WordNet 2.0)


Exactly right. There is no advantage to a device that runs at 1500 deg 
C, and no reason Rossi would want people to think it runs at that 
temperature. On the contrary, that would be dangerous. 400 deg C is much 
better from a commercial standpoint. This is the temperature the uranium 
core is kept at in a conventional reactor. It is relatively mild so it 
reduces wear and tear.


If 1500 deg C was a commercial advantage, this is might be 
disinformation. The only use for such high temperatures would be in 
aerospace apps.


As I said before, there is a major language gap here. Several people 
have told me that Rossi's English is not good, and this has caused 
misunderstandings.


- Jed



Re: [Vo]:a longer duration black box test would prove issue without disclosure

2011-01-19 Thread Stephen A. Lawrence


On 01/19/2011 11:06 AM, Jones Beene wrote:

 Stephen - How can you presume that there has been no deliberate
 attempt to confuse the situation?


OK, my apologies!  I /assumed/ (apparently incorrectly!) that your
choice of words was accidental rather than intentional.

Of course if you meant to imply that Rossi was intentionally trying to
mislead everyone when he said it was 1500 degrees in there, then
'disinformation' was indeed the right word.


  

 After all, there a few skeptics out there who have so much of their
 intellectual net worth tied up in the premise that LENR is
 pathological science - that deliberate sabotage in an early stage
 cannot be ruled out.

  

 IOW -- it is inappropriate for Stephen at this point in time, to
 counter one minor presumption with another one, even though I agree in
 principle that le mot juste is closer mis, not diss. It is too
 early to get to that level of precision.

  

 Since Stephen has chosen to assume a silly role here to be the
 self-appointed nit-picker deluxe,


Hey, I'm a computer programmer.  I pick nits for a living.  Sometimes it
sloshes over into real life (/er, if we can consider Vortex to be real
life...)/

Anyhow sorry about the semantic pickiness.

 lets apply the same standard to his incorrect presumptions, as he
 would apply them to others.


Of course!   :-)


  

 Jones

  

  

 *From:* Stephen A. Lawrence


 On 01/19/2011 10:25 AM, Jones Beene wrote:

 Peter,

  

 Thank you for clearing up the fact that the internal temperature is 400 C.

  

 There was some disinformation circulating about a much higher temperature.


 */PLEASE!/*  Let's strive for a little more precision in the language
 here!

 It was *not* disinformation, which is misinformation that is
 _deliberately_ disseminated in order to influence or confuse rivals
 (WordNet 2.0)

 The assertion that it was 1500 degrees was clearly either true or a
 simple error.  It wasn't anyone's /deliberate/ attempt at clouding the
 issue.



  

 Jones

  

 *From:* Peter Gluck [mailto:peter.gl...@gmail.com]
 *Sent:* Tuesday, January 18, 2011 10:10 PM
 *To:* vortex-l@eskimo.com mailto:vortex-l@eskimo.com
 *Subject:* Re: [Vo]:a longer duration black box test would prove issue
 without disclosure

  

 When used for heating in homes, the device delivers very probably hot
 water. In the case of the experiment, the flow of the water was
 seemingly limited by the pump (we don't know its performance
 characteristics), the connection tube, the cooling space. Cooling
 water moves in pipe with maximum 2-3 meters/second 

 Please do not forget- the temperature inside the generator is
 tipically 400 C so it is easy to deliver steam- and that's in some
 way more convincing than hot water

  

 Peter

 On Tue, Jan 18, 2011 at 11:52 PM, Stephen A. Lawrence sa...@pobox.com
 mailto:sa...@pobox.com wrote:



 On 01/18/2011 02:52 PM, Jed Rothwell wrote:

 Stephen A. Lawrence wrote:



 CLOSE THE LOOP.

 He [Rossi] says he can run without any electrical input.  Ergo he
 /can/  close the loop, without the expense of a Stirling motor and
 generator.


 Actually, that is heat input, from an AC resistance heater. Presumably
 it would work as well with combustion heating. He said he can run
 without heat input, but it is dangerous. I do not think he elaborated
 on that. I gather it means he uses heat to modulate the reaction.

 The Piantelli Ni experiments required high temperature and external
 heating.

 I believe the control factors are heat and pressure. The H2 is at 2
 atm, according to Celani. When you depressurize the cell, the reaction
 soon stops. That's good news. Cold fusion reactions are sometimes
 nearly as difficult to stop as they are to start.

 I assume the Rossi device has some internal self-regulation, or what
 Stan Pons called a memory that keeps electrochemical cells going
 back to the same power level after you refill the cell, tap on it, or
 disturb it some other way. I also assume there is something about the
 Rossi device that acts analogously to a self-quenching CANDU nuclear
 reactor. I am only speculating; I have no knowledge of this. The
 mechanism would be something like the metal degassing at very high
 temperature, cooling down, and then absorbing the gas and reacting
 again. That would explain why it quickly stops when you degas
 manually. I suspect the electric heater is in the core, and the cold
 fusion reaction occurs in the Ni powder surrounding that. I recall
 some of the Piantelli devices had heaters attached directly to the Ni bar.

 I think Rossi claimed the internal temperature of this thing is
 1500°C. Ed Storms pointed out that cannot be right, because the
 melting point of Ni is 1,453°C. Perhaps that is a misunderstanding, or
 a mistranslation. Still, it must be pretty hot in there because the
 device is small and well insulated. Even with 400 W or 1000 W from the
 AC heater it must be quite hot internally. I assume (but I do not
 know) that the heater is the hottest

Re: [Vo]:a longer duration black box test would prove issue without disclosure

2011-01-19 Thread mixent
In reply to  Stephen A. Lawrence's message of Wed, 19 Jan 2011 11:31:25 -0500:
Hi,
[snip]
Of course if you meant to imply that Rossi was intentionally trying to
mislead everyone when he said it was 1500 degrees in there, then
'disinformation' was indeed the right word.
[snip]
You are all making a mountain out of a molehill. Obviously the average
temperature was 400 ºC, while there were hot spots where the temperature
exceeded the melting point of Ni, as it became fused in places.

Regards,

Robin van Spaandonk

http://rvanspaa.freehostia.com/Project.html



Re: [Vo]:a longer duration black box test would prove issue without disclosure

2011-01-19 Thread Jed Rothwell
mix...@bigpond.com wrote:

You are all making a mountain out of a molehill. Obviously the average
 temperature was 400 ºC, while there were hot spots where the temperature
 exceeded the melting point of Ni, as it became fused in places.


Takahashi told me there is a form of low-temperature fusion, similar to
sintering. It happens with pure Pd-black in the presence of hydrogen (or
deuterium) at temperatures well below the melting point of Pd. The hydrogen
plays a role. I do not recall the details . . . I think he mentioned the
spillover effect as playing a role.

He said that some samples of Pd-black were heated in vacuo in pre-treatment.
The particles did not clump together. Later, in the experiment they heated
in the presence of deuterium to lower temperatures, yet they clumped
together. I think that may have happened even with samples that did not
produce anomalous heat.

Anyway, particles clump together differently in different circumstances, and
it does not always mean they melted and fused. In this case, maybe they did
and that can be confirmed in other ways, but clumping alone is not proof.

- Jed


Re: [Vo]:a longer duration black box test would prove issue without disclosure

2011-01-19 Thread noone noone
Jed,

I emailed you. Please respond. 






From: Jed Rothwell jedrothw...@gmail.com
To: vortex-l@eskimo.com
Sent: Wed, January 19, 2011 8:17:19 PM
Subject: Re: [Vo]:a longer duration black box test would prove issue without 
disclosure


mix...@bigpond.com wrote:


You are all making a mountain out of a molehill. Obviously the average
temperature was 400 ºC, while there were hot spots where the temperature
exceeded the melting point of Ni, as it became fused in places.


Takahashi told me there is a form of low-temperature fusion, similar to 
sintering. It happens with pure Pd-black in the presence of hydrogen (or 
deuterium) at temperatures well below the melting point of Pd. The hydrogen 
plays a role. I do not recall the details . . . I think he mentioned the 
spillover effect as playing a role.

He said that some samples of Pd-black were heated in vacuo in pre-treatment. 
The 
particles did not clump together. Later, in the experiment they heated in the 
presence of deuterium to lower temperatures, yet they clumped together. I think 
that may have happened even with samples that did not produce anomalous heat.

Anyway, particles clump together differently in different circumstances, and it 
does not always mean they melted and fused. In this case, maybe they did and 
that can be confirmed in other ways, but clumping alone is not proof.

- Jed




Re: [Vo]:a longer duration black box test would prove issue without disclosure

2011-01-19 Thread Terry Blanton
On Wed, Jan 19, 2011 at 8:33 PM, noone noone thesteornpa...@yahoo.com wrote:
 Jed,

 I emailed you. Please respond.

Is that no one or noonie?  I used to get a nooner occasionally.

eg

T



Re: [Vo]:a longer duration black box test would prove issue without disclosure

2011-01-18 Thread Jed Rothwell
Roarty, Francis X francis.x.roa...@lmco.com wrote:

Rossi could keep his black box method and still prove his claims with a 24
 hour stress test that would produce far more energy than he could possibly

 Conceal inside the black box.


He has done that. People have told me they witnessed that, albeit not at a
national university setting, with professors doing the installation and
running of the calorimetry. I think they did some longer runs in the weeks
leading up to this demo, but I have not heard how long they were. I asked,
but they did not get around to answering.

Despite Rossi's odd nature, he has done a good job of revealing his device.
I think he has done as much as anyone can do without revealing trade
secrets. I am afraid it is futile to try to protect trade secrets, but I
understand why he is trying. It is hard to think of a better way to proceed
given the patent situation.

- Jed


Re: [Vo]:a longer duration black box test would prove issue without disclosure

2011-01-18 Thread Stephen A. Lawrence


On 01/18/2011 11:04 AM, Jed Rothwell wrote:
 Roarty, Francis X francis.x.roa...@lmco.com
 mailto:francis.x.roa...@lmco.com wrote:

 Rossi could keep his black box method and still prove his claims
 with a 24 hour stress test that would produce far more energy than
 he could possibly

 Conceal inside the black box.


 He has done that. People have told me they witnessed that, albeit not
 at a national university setting, with professors doing the
 installation and running of the calorimetry. I think they did some
 longer runs in the weeks leading up to this demo, but I have not heard
 how long they were. I asked, but they did not get around to answering.

 Despite Rossi's odd nature, he has done a good job of revealing his
 device. I think he has done as much as anyone can do without revealing
 trade secrets. I am afraid it is futile to try to protect trade
 secrets, but I understand why he is trying. It is hard to think of a
 better way to proceed given the patent situation.

CLOSE THE LOOP.

He says he can run without any electrical input.  Ergo he /can/  close
the loop, without the expense of a Stirling motor and generator.




 - Jed



Re: [Vo]:a longer duration black box test would prove issue without disclosure

2011-01-18 Thread Stephen A. Lawrence


On 01/18/2011 02:52 PM, Jed Rothwell wrote:
 Stephen A. Lawrence wrote:

 CLOSE THE LOOP.

 He [Rossi] says he can run without any electrical input.  Ergo he
 /can/  close the loop, without the expense of a Stirling motor and
 generator.

 Actually, that is heat input, from an AC resistance heater. Presumably
 it would work as well with combustion heating. He said he can run
 without heat input, but it is dangerous. I do not think he elaborated
 on that. I gather it means he uses heat to modulate the reaction.

 The Piantelli Ni experiments required high temperature and external
 heating.

 I believe the control factors are heat and pressure. The H2 is at 2
 atm, according to Celani. When you depressurize the cell, the reaction
 soon stops. That's good news. Cold fusion reactions are sometimes
 nearly as difficult to stop as they are to start.

 I assume the Rossi device has some internal self-regulation, or what
 Stan Pons called a memory that keeps electrochemical cells going
 back to the same power level after you refill the cell, tap on it, or
 disturb it some other way. I also assume there is something about the
 Rossi device that acts analogously to a self-quenching CANDU nuclear
 reactor. I am only speculating; I have no knowledge of this. The
 mechanism would be something like the metal degassing at very high
 temperature, cooling down, and then absorbing the gas and reacting
 again. That would explain why it quickly stops when you degas
 manually. I suspect the electric heater is in the core, and the cold
 fusion reaction occurs in the Ni powder surrounding that. I recall
 some of the Piantelli devices had heaters attached directly to the Ni bar.

 I think Rossi claimed the internal temperature of this thing is
 1500°C. Ed Storms pointed out that cannot be right, because the
 melting point of Ni is 1,453°C. Perhaps that is a misunderstanding, or
 a mistranslation. Still, it must be pretty hot in there because the
 device is small and well insulated. Even with 400 W or 1000 W from the
 AC heater it must be quite hot internally. I assume (but I do not
 know) that the heater is the hottest part. That's how I imagine it works.

Actually, I'd expect the joule heater to be rather cool relative to the
reactive elements once the thing gets rolling.  The reaction is
contributing 10 kW or more at that point; the joule heater is just
plugging along at 400 watts.

That, also, makes it seem a little surprising that the joule heater
continues to be used *after* ignition.  It's contributing just 4% of
the total heat; you'd think they could just shut it off after the thing
starts up.

Of course, the reacting surface area may be large enough that it stays
cooler than the heater, and perhaps the intense heat near the heater
wire has something to do with the reason they continue to use it after
ignition.

Incidentally, a 1500 degree internal temperature also makes the use of
unpressurized water for a coolant seem to me to be a little iffy. 
Perhaps that has something to do with the reason they boil it all to
steam, rather than running the pump harder and getting out hot water
(which, it has been suggested, might have provided a more rock-solid
output heat measure).



 - Jed



Re: [Vo]:a longer duration black box test would prove issue without disclosure

2011-01-18 Thread Jed Rothwell

Stephen A. Lawrence wrote:

That, also, makes it seem a little surprising that the joule heater 
continues to be used *after* ignition.  It's contributing just 4% of 
the total heat; you'd think they could just shut it off after the 
thing starts up.


Of course, the reacting surface area may be large enough that it stays 
cooler than the heater, and perhaps the intense heat near the heater 
wire has something to do with the reason they continue to use it after 
ignition.


That is my guess. I think the AC heater wire is hotter than the active 
material.


As I said, it is my understanding that heat and hydrogen pressure are 
the two control factors. I do not know how they work. I don't know which 
knob you twist to make the thing go.


Rossi said that removing the AC heat completely is dangerous. That give 
me the willies. If the external electricity cuts off, will the machine 
overheat? Or if it is built in a self sustaining device and the 
generator fails, will it overheat or go out of control? It would be nice 
if the heat triggered the reaction, and removing the heat simply 
quenched it, but based on Rossi's comment that is is dangerous to run 
without the auxiliary heat, that is not the case.


Who knows what to make of it! Rossi is hiding many details.

- Jed



RE: [Vo]:a longer duration black box test would prove issue without disclosure

2011-01-18 Thread Jones Beene
This is not surprising. My guess is that there is strong temperature
inversion, and a prohibitive trigger temperature with instant quench. The
trigger could be say at  800 C, and the inversion 1000 C, giving some room
for error. There are zones and only one of them is externally heated. This
is the insurance.

This amplification of input is why he has named it the way he has.

You cannot EVER let normal fluctuations in the fuel temperature go below the
trigger, or else the whole thing will instantly quench. You spread out the
active material so that once you get over the trigger in one zone, it can
then go over everywhere, and continues up, since the inversion pushes it up
to the limit of heat transfer.

The heater will be placed to heat one a small area in the reactor only - the
failsafe zone, so to speak.

Jones


-Original Message-
From: Jed Rothwell 

Stephen A. Lawrence wrote:

 That, also, makes it seem a little surprising that the joule heater 
 continues to be used *after* ignition.  It's contributing just 4% of 
 the total heat; you'd think they could just shut it off after the 
 thing starts up.

 Of course, the reacting surface area may be large enough that it stays 
 cooler than the heater, and perhaps the intense heat near the heater 
 wire has something to do with the reason they continue to use it after 
 ignition.

That is my guess. I think the AC heater wire is hotter than the active 
material.

As I said, it is my understanding that heat and hydrogen pressure are 
the two control factors. I do not know how they work. I don't know which 
knob you twist to make the thing go.

Rossi said that removing the AC heat completely is dangerous. That give 
me the willies. If the external electricity cuts off, will the machine 
overheat? Or if it is built in a self sustaining device and the 
generator fails, will it overheat or go out of control? It would be nice 
if the heat triggered the reaction, and removing the heat simply 
quenched it, but based on Rossi's comment that is is dangerous to run 
without the auxiliary heat, that is not the case.

Who knows what to make of it! Rossi is hiding many details.

- Jed





Re: [Vo]:a longer duration black box test would prove issue without disclosure

2011-01-18 Thread Terry Blanton
On Tue, Jan 18, 2011 at 5:37 PM, Jones Beene jone...@pacbell.net wrote:

 This amplification of input is why he has named it the way he has.

Although, it would not really be amplification, would it?  The
reaction has a known instability and he uses the 400 W stable source
to mask that instability.

Real time measurements of the core would tell the truth.

T



Re: [Vo]:a longer duration black box test would prove issue without disclosure

2011-01-18 Thread Jed Rothwell

OrionWorks - Steven V Johnson wrote:


Based on what I've read so far, I know I'd prefer the full protection
and experience of a major utility company managing the reactor . . .


Me too!



I would think that only after a considerable amount of experience
combined with a good track record has been built up, plus a theory
that everyone can agree on, would consumer products even be
considered.


I think so too. But here's what I predict: the calendar time it takes to 
generate that considerable track record will be more compressed than 
any industrial development in history, including the development of 
nuclear power and bombs during WWII.


Once it becomes generally known that this is a real nuclear effect that 
is likely to lower the cost of energy by a factor of 10 at first, and 
thousands more later, every industrial corporation on earth will pile 
onto it. Hundreds of thousands of researchers will work frantically to 
understand it, control it, and bring it to market.


So even though it will take billions and probably an act of Congress, I 
am sanguine. It will happen swiftly.


Someone who is talking to investors about Rossi asked me what I thought 
the projected cost per thermal kWh would be. I told him that Rossi 
described the consumables and 6-month maintenance, and estimates about 
$0.01/kWh. But my guess is that first generation machine of that nature 
are far more expensive than anyone anticipates. Then I wrote:



Frankly, I do not think that a conventional analysis such as the cost 
of thermal kWh in the initial implementation does this justice. We are 
talking about the most revolutionary technology in history. Making the 
decision to invest or not based on the initial performance would 
resemble the decisions made by DEC and Data General not to go into the 
personal computer business because the first PCs had lower performance 
per dollar than minicomputers. That was true, but not for long. In 1980, 
any computer company that decided not to pursue the PC market was 
signing its own death warrant. If Rossi is not mistaken, and this thing 
is real, and if even ONE company, anywhere decides to develop it, then 
every other major industrial company will either follow suit and invest 
billions in the technology, or it will go bankrupt in a few decades. GE, 
Toyota or Mitsubishi -- it makes no difference how big or powerful they 
are now. They will either develop this or they will vanish like the 
Pennsylvania Railroad, General Motors, DEC and all the other great 
corporations that went out of business in the 20th century.


Cold fusion will be the core technology to as many different products as 
integrated circuits are today. Can you imagine how long GE would last 
today if they had no expertise in integrated circuits or computers?


That's what I would tell investors . . .


- Jed



Re: [Vo]:a longer duration black box test would prove issue without disclosure

2011-01-18 Thread francis
 

All Catalysts are normally considered accelerators of standard reactions and
skeletal catalysts are based on Casimir geometry / suppression of energy
density which is known to lead

To relativistic effects on the half lives of radioactive gas. Perhaps Rossi
is using sodium or other very slightly radioactive material to make an
accelerator into an amplifier? My premise is that

Both the radioactive gas and the hydrogen reactions are aging relative to us
at a rate related to the Casimir force/geometry turning relatively innocuous
materials into radiation emitters from our perspective but unchanged from
their own local perspective.  I don't know how such seemingly sparse
radiation would be translated back to our frames -  a single emission an
hour might appear a thousand fold faster from our perspective but the
radiation leaves the particle normally from a local perspective . I guess my
question is would time dilation concentrate or dilute radiation during a
space time translation? Could the dimension of time be acting like a
radiation shield?

Fran

 

Terry Blanton
Tue, 18 Jan 2011 14:46:12 -0800

On Tue, Jan 18, 2011 at 5:37 PM, Jones Beene jone...@pacbell.net wrote:

 

 This amplification of input is why he has named it the way he has.

 

Although, it would not really be amplification, would it?  The

reaction has a known instability and he uses the 400 W stable source

to mask that instability.

 

Real time measurements of the core would tell the truth.

 

T

 

 



Re: [Vo]:a longer duration black box test would prove issue without disclosure

2011-01-18 Thread Peter Gluck
When used for heating in homes, the device delivers very probably hot water.
In the case of the experiment, the flow of the water was seemingly limited
by the pump (we don't know its performance characteristics), the connection
tube, the cooling space. Cooling water moves in pipe with maximum 2-3
meters/second
Please do not forget- the temperature inside the generator is tipically 400
C so it is easy to deliver steam- and that's in some way more convincing
than hot water

Peter

On Tue, Jan 18, 2011 at 11:52 PM, Stephen A. Lawrence sa...@pobox.comwrote:



 On 01/18/2011 02:52 PM, Jed Rothwell wrote:

 Stephen A. Lawrence wrote:

 CLOSE THE LOOP.

 He [Rossi] says he can run without any electrical input.  Ergo he *can*
 close the loop, without the expense of a Stirling motor and generator.


 Actually, that is heat input, from an AC resistance heater. Presumably it
 would work as well with combustion heating. He said he can run without heat
 input, but it is dangerous. I do not think he elaborated on that. I gather
 it means he uses heat to modulate the reaction.

 The Piantelli Ni experiments required high temperature and external
 heating.

 I believe the control factors are heat and pressure. The H2 is at 2 atm,
 according to Celani. When you depressurize the cell, the reaction soon
 stops. That's good news. Cold fusion reactions are sometimes nearly as
 difficult to stop as they are to start.

 I assume the Rossi device has some internal self-regulation, or what Stan
 Pons called a memory that keeps electrochemical cells going back to the
 same power level after you refill the cell, tap on it, or disturb it some
 other way. I also assume there is something about the Rossi device that acts
 analogously to a self-quenching CANDU nuclear reactor. I am only
 speculating; I have no knowledge of this. The mechanism would be something
 like the metal degassing at very high temperature, cooling down, and then
 absorbing the gas and reacting again. That would explain why it quickly
 stops when you degas manually. I suspect the electric heater is in the core,
 and the cold fusion reaction occurs in the Ni powder surrounding that. I
 recall some of the Piantelli devices had heaters attached directly to the Ni
 bar.

 I think Rossi claimed the internal temperature of this thing is 1500°C. Ed
 Storms pointed out that cannot be right, because the melting point of Ni is
 1,453°C. Perhaps that is a misunderstanding, or a mistranslation. Still, it
 must be pretty hot in there because the device is small and well insulated.
 Even with 400 W or 1000 W from the AC heater it must be quite hot
 internally. I assume (but I do not know) that the heater is the hottest
 part. That's how I imagine it works.


 Actually, I'd expect the joule heater to be rather cool relative to the
 reactive elements once the thing gets rolling.  The reaction is contributing
 10 kW or more at that point; the joule heater is just plugging along at 400
 watts.

 That, also, makes it seem a little surprising that the joule heater
 continues to be used *after* ignition.  It's contributing just 4% of the
 total heat; you'd think they could just shut it off after the thing starts
 up.

 Of course, the reacting surface area may be large enough that it stays
 cooler than the heater, and perhaps the intense heat near the heater wire
 has something to do with the reason they continue to use it after
 ignition.

 Incidentally, a 1500 degree internal temperature also makes the use of
 unpressurized water for a coolant seem to me to be a little iffy.  Perhaps
 that has something to do with the reason they boil it all to steam, rather
 than running the pump harder and getting out hot water (which, it has been
 suggested, might have provided a more rock-solid output heat measure).



 - Jed