[web2py] Re: Find name of user with a given id: Auth table issues
hi Anthony, i apologise for the late response, i had no access to the internet the whole weekend. Maybe i should clarify. I am customising this from one of your tutorials Web development with python and web2py part 1 and 2 The 'user' in this case is the person that posted a post. Hence if i use auth.user it makes all posts be written by the currently logged in user. I guess my challenge is extracting the value of 'usealiasname' If its true or not for that user that posted. i tried the 'user.usealiasname' but it says that user has no attribute 'usealiasname' But thank you for all the help. On Friday, 12 June 2015 17:55:03 UTC+2, Anthony wrote: If you have: user = db.auth_user(id) Then there is no need for the me variable -- just use user.usealiasname. However, if id is the same as auth.user_id, then you don't even need the above line -- just use auth.user (which holds the whole user record). If it still isn't working, then there is likely a problem elsewhere in your code. Anthony On Friday, June 12, 2015 at 9:20:00 AM UTC-4, zimani wrote: Its supposed to be the same. But this does not work. All i am doing is checking if this user: db.auth_user(id) wants to use an aliasname or not. Of which aliasname is a field in auth_user table On Friday, 12 June 2015 15:11:19 UTC+2, zimani wrote: I apologise, i have been trying too many things: me=db(db.auth_user.id == id).select(db.auth_user.usealiasname).first().usealiasname This is what i currently have. On Friday, 12 June 2015 14:54:57 UTC+2, Anthony wrote: On Friday, June 12, 2015 at 8:36:43 AM UTC-4, zimani wrote: I have this code: def author(id): if id is None: return Unknown else: user = db.auth_user(id) me=db(db.auth_user.id == id).select(db.auth_user.usealiasname).first().usealiasname if me==False: return '%(first_name)s %(last_name)s' % user if user else '' else: return '%(aliasname)s' % user if user else '' I want to check if the user with a particular 'id' wants to use an aliasname or real names. However it wont work. i know for sure this line is the one that is wrong because without the condition it prints properly. can somebody help. i am sure its simple but i cannot seem to figure it out. me=db(db.auth_user.id == auth.user_id).select(db.auth_user.usealiasname).first().usealiasname In the function code you showed above, you have db.auth_user.id == id, but here you have db.auth_user.id == auth.user_id. Which code are you actually using? Is id supposed to be the same value as auth.user_id? If so, your me variable is unnecessary, as you are simply fetching the same record that you have already stored in the user variable. Anthony -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups web2py-users group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.
[web2py] Re: Find name of user with a given id: Auth table issues
Ok, i have dropped me and am now using just user. I will try to find a solution and update what the error is. Thanks a lot for all your prompt help. On Monday, 15 June 2015 14:45:15 UTC+2, Anthony wrote: On Monday, June 15, 2015 at 4:57:51 AM UTC-4, zimani wrote: hi Anthony, i apologise for the late response, i had no access to the internet the whole weekend. Maybe i should clarify. I am customising this from one of your tutorials Web development with python and web2py part 1 and 2 The 'user' in this case is the person that posted a post. Hence if i use auth.user it makes all posts be written by the currently logged in user. I guess my challenge is extracting the value of 'usealiasname' If its true or not for that user that posted. i tried the 'user.usealiasname' but it says that user has no attribute 'usealiasname' But thank you for all the help. In your original code, both me and user refer to the same record, so there is no need for both. Anyway, if you have a record from db.auth_user and it says there is no usealiasname attribute, then there is a problem elsewhere in your code. Hard to say where without seeing all the code. Anthony -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups web2py-users group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.
[web2py] Re: Find name of user with a given id: Auth table issues
On Monday, June 15, 2015 at 4:57:51 AM UTC-4, zimani wrote: hi Anthony, i apologise for the late response, i had no access to the internet the whole weekend. Maybe i should clarify. I am customising this from one of your tutorials Web development with python and web2py part 1 and 2 The 'user' in this case is the person that posted a post. Hence if i use auth.user it makes all posts be written by the currently logged in user. I guess my challenge is extracting the value of 'usealiasname' If its true or not for that user that posted. i tried the 'user.usealiasname' but it says that user has no attribute 'usealiasname' But thank you for all the help. In your original code, both me and user refer to the same record, so there is no need for both. Anyway, if you have a record from db.auth_user and it says there is no usealiasname attribute, then there is a problem elsewhere in your code. Hard to say where without seeing all the code. Anthony -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups web2py-users group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.
[web2py] Re: Find name of user with a given id: Auth table issues
On Friday, June 12, 2015 at 8:36:43 AM UTC-4, zimani wrote: I have this code: def author(id): if id is None: return Unknown else: user = db.auth_user(id) me=db(db.auth_user.id == id).select(db.auth_user.usealiasname).first().usealiasname if me==False: return '%(first_name)s %(last_name)s' % user if user else '' else: return '%(aliasname)s' % user if user else '' I want to check if the user with a particular 'id' wants to use an aliasname or real names. However it wont work. i know for sure this line is the one that is wrong because without the condition it prints properly. can somebody help. i am sure its simple but i cannot seem to figure it out. me=db(db.auth_user.id == auth.user_id).select(db.auth_user.usealiasname).first().usealiasname In the function code you showed above, you have db.auth_user.id == id, but here you have db.auth_user.id == auth.user_id. Which code are you actually using? Is id supposed to be the same value as auth.user_id? If so, your me variable is unnecessary, as you are simply fetching the same record that you have already stored in the user variable. Anthony -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups web2py-users group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.
[web2py] Re: Find name of user with a given id: Auth table issues
I apologise, i have been trying too many things: me=db(db.auth_user.id == id).select(db.auth_user.usealiasname).first().usealiasname This is what i currently have. On Friday, 12 June 2015 14:54:57 UTC+2, Anthony wrote: On Friday, June 12, 2015 at 8:36:43 AM UTC-4, zimani wrote: I have this code: def author(id): if id is None: return Unknown else: user = db.auth_user(id) me=db(db.auth_user.id == id).select(db.auth_user.usealiasname).first().usealiasname if me==False: return '%(first_name)s %(last_name)s' % user if user else '' else: return '%(aliasname)s' % user if user else '' I want to check if the user with a particular 'id' wants to use an aliasname or real names. However it wont work. i know for sure this line is the one that is wrong because without the condition it prints properly. can somebody help. i am sure its simple but i cannot seem to figure it out. me=db(db.auth_user.id == auth.user_id).select(db.auth_user.usealiasname).first().usealiasname In the function code you showed above, you have db.auth_user.id == id, but here you have db.auth_user.id == auth.user_id. Which code are you actually using? Is id supposed to be the same value as auth.user_id? If so, your me variable is unnecessary, as you are simply fetching the same record that you have already stored in the user variable. Anthony -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups web2py-users group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.
[web2py] Re: Find name of user with a given id: Auth table issues
Its supposed to be the same. But this does not work. All i am doing is checking if this user: db.auth_user(id) wants to use an aliasname or not. Of which aliasname is a field in auth_user table On Friday, 12 June 2015 15:11:19 UTC+2, zimani wrote: I apologise, i have been trying too many things: me=db(db.auth_user.id == id).select(db.auth_user.usealiasname).first().usealiasname This is what i currently have. On Friday, 12 June 2015 14:54:57 UTC+2, Anthony wrote: On Friday, June 12, 2015 at 8:36:43 AM UTC-4, zimani wrote: I have this code: def author(id): if id is None: return Unknown else: user = db.auth_user(id) me=db(db.auth_user.id == id).select(db.auth_user.usealiasname).first().usealiasname if me==False: return '%(first_name)s %(last_name)s' % user if user else '' else: return '%(aliasname)s' % user if user else '' I want to check if the user with a particular 'id' wants to use an aliasname or real names. However it wont work. i know for sure this line is the one that is wrong because without the condition it prints properly. can somebody help. i am sure its simple but i cannot seem to figure it out. me=db(db.auth_user.id == auth.user_id).select(db.auth_user.usealiasname).first().usealiasname In the function code you showed above, you have db.auth_user.id == id, but here you have db.auth_user.id == auth.user_id. Which code are you actually using? Is id supposed to be the same value as auth.user_id? If so, your me variable is unnecessary, as you are simply fetching the same record that you have already stored in the user variable. Anthony -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups web2py-users group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.
[web2py] Re: Find name of user with a given id: Auth table issues
If you have: user = db.auth_user(id) Then there is no need for the me variable -- just use user.usealiasname. However, if id is the same as auth.user_id, then you don't even need the above line -- just use auth.user (which holds the whole user record). If it still isn't working, then there is likely a problem elsewhere in your code. Anthony On Friday, June 12, 2015 at 9:20:00 AM UTC-4, zimani wrote: Its supposed to be the same. But this does not work. All i am doing is checking if this user: db.auth_user(id) wants to use an aliasname or not. Of which aliasname is a field in auth_user table On Friday, 12 June 2015 15:11:19 UTC+2, zimani wrote: I apologise, i have been trying too many things: me=db(db.auth_user.id == id).select(db.auth_user.usealiasname).first().usealiasname This is what i currently have. On Friday, 12 June 2015 14:54:57 UTC+2, Anthony wrote: On Friday, June 12, 2015 at 8:36:43 AM UTC-4, zimani wrote: I have this code: def author(id): if id is None: return Unknown else: user = db.auth_user(id) me=db(db.auth_user.id == id).select(db.auth_user.usealiasname).first().usealiasname if me==False: return '%(first_name)s %(last_name)s' % user if user else '' else: return '%(aliasname)s' % user if user else '' I want to check if the user with a particular 'id' wants to use an aliasname or real names. However it wont work. i know for sure this line is the one that is wrong because without the condition it prints properly. can somebody help. i am sure its simple but i cannot seem to figure it out. me=db(db.auth_user.id == auth.user_id).select(db.auth_user.usealiasname).first().usealiasname In the function code you showed above, you have db.auth_user.id == id, but here you have db.auth_user.id == auth.user_id. Which code are you actually using? Is id supposed to be the same value as auth.user_id? If so, your me variable is unnecessary, as you are simply fetching the same record that you have already stored in the user variable. Anthony -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups web2py-users group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.
