Hi Vijay,
On Wed, Jan 9, 2013 at 1:25 PM, vijay vnbang2...@yahoo.com wrote:
i want to use only list compression to get solution like the way you see i
share solutions.
Basically one line solution .
I think you are referring to list comprehension here.
I want to know if there is any
On Wed, Jan 9, 2013 at 1:25 PM, vijay vnbang2...@yahoo.com wrote:
i want to use only list compression to get solution like the way you see i
share solutions.
Basically one line solution .
Start reading from here.
http://www.catb.org/esr/faqs/smart-questions.html
Kushal
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On 9 January 2013 13:25, vijay vnbang2...@yahoo.com wrote:
i want to use only list compression to get solution like the way you see i
share solutions.
Basically one line solution .
Do you mean list comprehension? Even so, it is not clear how
the resulting list is to be derived from the
On Wed, Jan 9, 2013 at 1:11 PM, vijay vnbang2...@yahoo.com wrote:
Hi,
I want to know if there is any other better way for improving below list
compression. I have to use list compression only to achieve it.
say i have list a=[1, 4, 9, 12, 15, 21] expected result (4, 12), (9, 12,
On Wed, Jan 9, 2013 at 1:43 PM, Anand Chitipothu anandol...@gmail.comwrote:
[[x for x in a if x%i == 0] for i in [2, 3]]
oh thats smart.
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On Wed, Jan 9, 2013 at 1:11 PM, vijay vnbang2...@yahoo.com wrote:
2) [y for y in a if bool(y%2==0)],[y for y in a if bool(y%3==0)]
You don't have to do if bool(y%2==0), just if y % 2 == 0 is enough.
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Jeffrey Jose jeffjosej...@gmail.com writes:
On Wed, Jan 9, 2013 at 1:43 PM, Anand Chitipothu anandol...@gmail.comwrote:
[[x for x in a if x%i == 0] for i in [2, 3]]
oh thats smart.
Yup. Very.
[...]
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Cordially,
Noufal
http://nibrahim.net.in
First of all,it is list comprehension. Second, i don't know what elegant
method you want to look, as list in itself is fast. The only thing which
you can look out is TUPLE, which are immutable list.
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To: Bangalore Python Users Group - India bangpypers@python.org
Sent: Wednesday, 9 January 2013 1:31 PM
Subject: Re: [BangPypers] List compression imrpovement
Let me guess. You want the first tuple with elements that are divisible by
2 and second divisible by 3. Beats me still as to why
Thanks Anand. This look good to me.
From: Anand Chitipothu anandol...@gmail.com
To: vijay vnbang2...@yahoo.com; Bangalore Python Users Group - India
bangpypers@python.org
Sent: Wednesday, 9 January 2013 1:43 PM
Subject: Re: [BangPypers] List compression
Hi,
I want to know if there is any other better way for improving below list
compression. I have to use list compression only to achieve it.
say i have list a=[1, 4, 9, 12, 15, 21] expected result (4, 12), (9, 12,
15, 21)
few solutions are
1) [filter(None, l) for l in zip(*[(x if x
On 9 January 2013 13:11, vijay vnbang2...@yahoo.com wrote:
Hi,
I want to know if there is any other better way for improving below list
compression. I have to use list compression only to achieve it.
say i have list a=[1, 4, 9, 12, 15, 21] expected result (4, 12), (9, 12,
15, 21)
12 matches
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