On Tue, 27 Sep 2005, Dave Adams wrote:
> What is the purpose of the line "my $msg = shift;"?
In the context of subroutines, it copies the first scalar argument
passed to the routine to the variable $msg. If more than one argument
was passed, the others aren't touched by this statement -- as yo
Mulander wrote:
> If I understood you question properly you want to know why people use
> shift in subrutines and how does shift work.
>
> I will try to make it short:
> shift works on lists, it removes the first element of the list
perldoc -q "What is the difference between a list and an array"
Mulander wrote:
> If I understood you question properly you want to know why people use
> shift in subrutines and how does shift work.
>
> I will try to make it short:
> shift works on lists, it removes the first element of the list ( the 0
> indexed element ) and returns it as a lvalue ( if there
If I understood you question properly you want to know why people use
shift in subrutines and how does shift work.
I will try to make it short:
shift works on lists, it removes the first element of the list ( the 0
indexed element ) and returns it as a lvalue ( if there are no more
elements in a l
> -Original Message-
> From: Ryan Frantz
> Sent: Tuesday, September 27, 2005 5:27 PM
> To: Dave Adams; beginners perl
> Subject: RE: Shift Question
>
>
>
> > -Original Message-
> > From: Dave Adams [mailto:[EMAIL PROTECTED]
> > Sent:
> -Original Message-
> From: Dave Adams [mailto:[EMAIL PROTECTED]
> Sent: Tuesday, September 27, 2005 5:17 PM
> To: beginners perl
> Subject: Shift Question
>
> QUESTION: What is the purpose of the line "my $msg = shift;"? I am
> guessing it is for the
QUESTION: What is the purpose of the line "my $msg = shift;"? I am
guessing it is for the @_ array but what list element is there to be
shifted off? It seems that the shift function is in a lot of
subroutines and I am confused as to their purpose.
#!/bin/perl -w
(my $PROGNAME = $0) =~ s/^.*\///;
[EMAIL PROTECTED] wrote:
I found this in a template for creating subroutines, this is the base
that is created when you use the template to create the subroutine.
So now the newbie part, why would you place "my $par1 = shift;" in the
subroutine template, and what does it do??
Basically I am trying
Subject: RE: shift question
[EMAIL PROTECTED] wrote:
> Ok fantastic, I totally understand that, and if there were going to be
> more than one thing passed, just insert $par2 = shift; on the next
> line and then the second argument is in $par2, I assume.right??
Yes.
You might al
> [EMAIL PROTECTED] wrote:
> > Ok fantastic, I totally understand that, and if there were going to be
> > more than one thing passed, just insert $par2 = shift; on the next
> > line and then the second argument is in $par2, I assume.right??
>
> Yes.
>
> You might also see it this way:
>
>
[EMAIL PROTECTED] wrote:
> Ok fantastic, I totally understand that, and if there were going to be
> more than one thing passed, just insert $par2 = shift; on the next
> line and then the second argument is in $par2, I assume.right??
Yes.
You might also see it this way:
my ($par1, $par2) =
please
notify the sender immediately and delete the message.
-Original Message-
From: Bob Showalter [mailto:[EMAIL PROTECTED]
Sent: Monday, August 30, 2004 2:41 PM
To: Christopher L. Hood; [EMAIL PROTECTED]
Subject: RE: shift question
[EMAIL PROTECTED] wrote:
> OK here comes the new
[EMAIL PROTECTED] wrote:
> OK here comes the newbie question.
>
> I found this in a template for creating subroutines, this is the base
> that is created when you use the template to create the subroutine.
>
> So now the newbie part, why would you place "my $par1 = shift;" in
> the subroutine te
OK here comes the newbie question.
I found this in a template for creating subroutines, this is the base
that is created when you use the template to create the subroutine.
So now the newbie part, why would you place "my $par1 = shift;" in the
subroutine template, and what does it do??
Basicall
Wim De Hul <[EMAIL PROTECTED]> writes:
> my $var = shift;
>
> I thought that shift puts a variable in an array? What does this mean?
Did you check the documentation on "shift" *before* posting
the question?
>From "Programming Perl":
3.2.143 shift
shift ARRAY
shift
This fu
> -Original Message-
> From: Wim De Hul [mailto:[EMAIL PROTECTED]]
> Sent: Thursday, December 20, 2001 10:48 AM
> To: [EMAIL PROTECTED]
> Subject: Shift question...
>
>
> Hello guys ( and girls),
>
> While I was reading a script, I saw the lines:
>
;From: Wim De Hul <[EMAIL PROTECTED]>
>To: [EMAIL PROTECTED]
>Subject: Shift question...
>Date: Thu, 20 Dec 2001 16:48:16 +0100
>
>Hello guys ( and girls),
>
>While I was reading a script, I saw the lines:
>
>my $var = shift;
>
>I thought that shift puts a
om: Wim De Hul [mailto:[EMAIL PROTECTED]]
Sent: 20 December 2001 15:48
To: [EMAIL PROTECTED]
Subject: Shift question...
Hello guys ( and girls),
While I was reading a script, I saw the lines:
my $var = shift;
I thought that shift puts a variable in an array? What does this mean?
Thanks,
Wim.
Hello guys ( and girls),
While I was reading a script, I saw the lines:
my $var = shift;
I thought that shift puts a variable in an array? What does this mean?
Thanks,
Wim.
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