Did you ever get someone to help you with this?
Simon
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You need to sit down and design a basic application in cakephp and
read all the resources. I don't mean to be rude but I spent a good 3
months learning the conventions and inner workings for cakephp and it
proved to be useful.
You seem as though you don't have the basic understanding of this
for ($i =0 ; $i4;$i++)
{
echo 'Iteration # '.$i;
$this-model-save($distributedImp);
$res = $this-model-findAll();
print_r($res);
}
for($i=0;$i 4 ; $i++) {
$data = $this-Model-create();
$this-Model-save($data);
}
you need to use $data = $this-ModelName-create();
this populates the model with the default data and created the
structure for the data.
For example if you have a table model with the following structure
id int
name varchar(100) defaul 'My Name'
age int(3) default 12
Then using $data =
You can use $this-requestAction('/controller/action') from within a
view is this what you mean.
On Jul 6, 12:48 am, [EMAIL PROTECTED]
[EMAIL PROTECTED] wrote:
Hi again.
Is there anyway to detect from what view a controller action was
called?
Thanks.
Sound like an ideal candidate for reverse AJAX.
I have used JSON for a couple of projects. You need to just google for
JSON
On Jun 22, 2:18 am, [EMAIL PROTECTED]
[EMAIL PROTECTED] wrote:
That's a really good idea, but I have never done this. Can you tell me
a bit more about the { move:[4, 1],
Whatever it is will most likely involve routes. You can do almost any
form of redirect with that.
Like Ian says, a little bit more information would help.
On Jun 21, 2:41 pm, Ian Zepp [EMAIL PROTECTED] wrote:
You are going to have to provide more context than that, sorry.
AbhinavZone wrote:
very strange what is you table structure?
On May 14, 9:21 pm, TracyB [EMAIL PROTECTED] wrote:
I have a model using a table that's been around forever, so it's not a
CakePHP friendly name. My model is set up like so:
class Quote extends AppModel
{
var $name = 'Quote';
var $useTable =
You are most likely running all the sites from the same directory so
the htaccess applies to all websites.
assuming you are using apache you need to create a seperate entry in
your virtualhosts to point to the cakephp webroot.
so your default home page for cake at ~/cake/ this is where your
assuming you model is called User and you have all the validation
rules applied.
in your controller you need to specify
var $helpers = array('Html', 'Form');
This gives you access to the helpers in the view.
To create a form in the view
?php
echo $form-create('User' ,array('action' =
I think in your htaccess file. Something along the lines of
IfModule mod_rewrite.c
RewriteEngine on
RewriteRule ^/foo/(*) webroot/$1 [L]
RewriteRule^$webroot/[L]
RewriteRule(.*) webroot/$1[L]
/IfModule
On May 3, 1:49 pm, MikeK [EMAIL PROTECTED] wrote:
The
You could have a recursive loop. for example you could be redirecting
to an action that requires you to be authenticated. This action itself
needs authenticating and so you get sent back to the original action
thus you end up with an endless loop.
do you have code for the skateparks/index
Assuming you are using 1.2
I have created this snippet in the model. Could be but in app_model if
it is required.
//checks to see if the given fieldname is unique with the model
function checkUnique($data, $fieldName) {
$valid = false;
$this-recursive = -1;
I would like to add to this. I won't mention names but sometimes you
may be asked to do some work and not get the full story about what the
requirements are.
It would be advisable to get some form of contract containing.
1. The specifics of the task itself. what do they want you to do.
2. What
On Apr 19, 5:03 pm, Mech7 [EMAIL PROTECTED] wrote:
I am using sifr, and some other javascripts which call othr files but
then the login does not work anymore correctly for example it goes to:
http://localhost/scms/admin/users/sifr/myriad_pro.swf
Does anybody know a proper way to fix this,
findAll(array('Table.categoryt' A )
Try that.
Not so sure about the second problem I use css to set the width
regarding multiple records use this
?php echo $form-input(Product.{$i}.id, array('value' =
$node['id'], 'label' = false));
echo $form-input(Product.{$i}.qty));?
This is place within
of the array and the value.
To have a condition where you want rows that DON'T match, use
array('Table.categoryt' = 'NOT A'), or '!= A', or ' A'. One of
those should work (it's late, and I can't be bothered to check which
is correct)
Steve
On Apr 19, 5:57 pm, simonb [EMAIL PROTECTED] wrote
Are you sure that you have used the correct selector
for an id it should be
#header{
color: #000;
}
if you have used
.header{
color: #000
}
this declares a class style.
Just a thought!!
On Apr 15, 7:30 pm, Chez17 [EMAIL PROTECTED] wrote:
I am a CakePHP beginner and I am having some
Sorry..
just seen the fact you used #header.
very strange. Have you used the developer tools in firefox?
On Apr 15, 8:22 pm, simonb [EMAIL PROTECTED] wrote:
Are you sure that you have used the correct selector
for an id it should be
#header{
color: #000;
}
if you have used
.header
You need to create a schema in the model. I have done this in a couple
of projects where no tables exists for the model yet I needed to
validate some user input. See the previous thread below.
http://groups.google.com/group/cake-php/browse_thread/thread/3a028fb7f1cc2297
On Mar 29, 10:56 am,
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