Hi!. I continue with this :) One of the problems is already solved.
I have a table called "clientsproducts" with 3 keys:
cli_id(Client)
cat_id (Category)
pro_id (Product)
In this example, the pro_id and cat_id are a complex key from the table
"products", because every product has a
Thanks Ugo!
I know I have a really big problem, I am newbie in Java, XML, XSL and Cocoon
at the same time:
1-XML dont make me problem because is very easy.
2-Cocoon I think is very logical, but have some dark sides to me (I think).
3-For Java I need to have the API Docs in a browser to write so
Antonio Gallardo Rivera wrote:
>if (i > 0)
>{
> a.concat("WHERE cat_id=");
> a.concat(Integer.toString(i));
>}
Strings in Java are immutable! The concat(String) method returns a *NEW*
String [1].
a = a.concat("WHERE cat_id=");
a = a.concat(Integer.toStri
Hi!
I have a table called "clientsproducts" with 3 keys:
cli_id Client
pro_id (Product)
cat_id (Category)
In this example, the pro_id and cat_id are a complex key from the table
"products", because every product has a category. And one category can have
many products.
When I need
