Tzafrir Cohen wrote:
On Sun, Dec 21, 2008 at 04:45:21PM -0600, Ron Johnson wrote:
On 12/21/08 15:58, Jörg-Volker Peetz wrote:
$ seq -w 1 1 10 | xargs -i -n1 cp file.jpg file{}.jpg
What's with the {}? An implied variable?
$ LANG=C man xargs | grep -C 2 '{}'
-i[replace-str]
Osamu Aoki wrote:
On Sat, Dec 13, 2008 at 09:13:07PM +, Tzafrir Cohen wrote:
On Sun, Dec 14, 2008 at 03:50:31AM +0900, Osamu Aoki wrote:
On Sat, Dec 13, 2008 at 07:12:32PM +, Rodolfo Medina wrote:
I need the right syntax to copy file.jpg 100 times with one command so to
get
100
On 12/21/08 15:58, Jörg-Volker Peetz wrote:
Osamu Aoki wrote:
On Sat, Dec 13, 2008 at 09:13:07PM +, Tzafrir Cohen wrote:
On Sun, Dec 14, 2008 at 03:50:31AM +0900, Osamu Aoki wrote:
On Sat, Dec 13, 2008 at 07:12:32PM +, Rodolfo Medina wrote:
I need the right syntax to copy file.jpg
On Sun, Dec 21, 2008 at 04:45:21PM -0600, Ron Johnson wrote:
On 12/21/08 15:58, Jörg-Volker Peetz wrote:
$ seq -w 1 1 10 | xargs -i -n1 cp file.jpg file{}.jpg
What's with the {}? An implied variable?
$ LANG=C man xargs | grep -C 2 '{}'
-i[replace-str]
This option is a
2008/12/14, Rodolfo Medina rodolfo.med...@gmail.com:
I need the right syntax to copy file.jpg 100 times with one command so to
get
100 files named file1.jpg, file2.jpg, ..., file100.jpg.
Can anybody suggest how to achieve that?
You could try something like:
cat file.pdf | tee `seq -w 0 100
I need the right syntax to copy file.jpg 100 times with one command so to get
100 files named file1.jpg, file2.jpg, ..., file100.jpg.
Can anybody suggest how to achieve that?
Thanks for any reply
Rodolfo
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On Sat, Dec 13, 2008 at 07:12:32PM +, Rodolfo Medina wrote:
I need the right syntax to copy file.jpg 100 times with one command so to get
100 files named file1.jpg, file2.jpg, ..., file100.jpg.
Can anybody suggest how to achieve that?
c=0; while [ $c -lt 100 ]; do c=$[c + 1]; n='000'$c;
Hi Rodolfo
On Sat, Dec 13, 2008 at 8:12 PM, Rodolfo Medina
rodolfo.med...@gmail.com wrote:
I need the right syntax to copy file.jpg 100 times with one command so to get
100 files named file1.jpg, file2.jpg, ..., file100.jpg.
#!/bin/bash
for x in `seq 1 100`; do
if [[ x -lt 10 ]]; then
On Sat, Dec 13, 2008 at 07:35:44PM +0100, Manon Metten wrote:
Hi Rodolfo
On Sat, Dec 13, 2008 at 8:12 PM, Rodolfo Medina
rodolfo.med...@gmail.com wrote:
I need the right syntax to copy file.jpg 100 times with one command so to
get
100 files named file1.jpg, file2.jpg, ...,
Rodolfo writes:
I need the right syntax to copy file.jpg 100 times with one command so to
get 100 files named file1.jpg, file2.jpg, ..., file100.jpg.
for I in {1..100}; do cp file.jpg file$I.jpg ; done
But what are you actually trying to achieve?
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John Hasler
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On Sat, Dec 13, 2008 at 07:12:32PM +, Rodolfo Medina wrote:
I need the right syntax to copy file.jpg 100 times with one command so to get
100 files named file1.jpg, file2.jpg, ..., file100.jpg.
Can anybody suggest how to achieve that?
ere is one without looping :-)
$ seq 1 100 | sed
The Saturday 13 December 2008 20:12:32 Rodolfo Medina, you wrote :
I need the right syntax to copy file.jpg 100 times with one command so to
get 100 files named file1.jpg, file2.jpg, ..., file100.jpg.
Can anybody suggest how to achieve that?
Thanks for any reply
Rodolfo
filevar=file.jpg
On Sun, Dec 14, 2008 at 03:50:31AM +0900, Osamu Aoki wrote:
On Sat, Dec 13, 2008 at 07:12:32PM +, Rodolfo Medina wrote:
I need the right syntax to copy file.jpg 100 times with one command so to
get
100 files named file1.jpg, file2.jpg, ..., file100.jpg.
Can anybody suggest how to
On Sat, Dec 13, 2008 at 09:13:07PM +, Tzafrir Cohen wrote:
On Sun, Dec 14, 2008 at 03:50:31AM +0900, Osamu Aoki wrote:
On Sat, Dec 13, 2008 at 07:12:32PM +, Rodolfo Medina wrote:
I need the right syntax to copy file.jpg 100 times with one command so to
get
100 files named
Hi Rick,
On Sat, Dec 13, 2008 at 7:41 PM, Rick Pasotto r...@niof.net wrote:
I forgot about seq. This is even better (the -w left pads with zero for
equal width):
for x in $(seq -w 1 100); do cp file.jpg file${c}.jpg; done
Waw! Great one-liner.
BTW: Guess you meant file${x}.jpg;
On Sat, Dec 13, 2008 at 09:13:07PM +, Tzafrir Cohen wrote:
On Sun, Dec 14, 2008 at 03:50:31AM +0900, Osamu Aoki wrote:
On Sat, Dec 13, 2008 at 07:12:32PM +, Rodolfo Medina wrote:
I need the right syntax to copy file.jpg 100 times with one command so to
get
100 files named
Rick Pasotto wrote:
I forgot about seq. This is even better (the -w left pads with zero for
equal width):
for x in $(seq -w 1 100); do cp file.jpg file${x}.jpg; done
correction^
Nice! Something I have been looking for quite some time. I was using
Thomas Preud'homme wrote:
The Saturday 13 December 2008 20:12:32 Rodolfo Medina, you wrote :
I need the right syntax to copy file.jpg 100 times with one command so to
get 100 files named file1.jpg, file2.jpg, ..., file100.jpg.
Can anybody suggest how to achieve that?
Thanks for any reply
Thomas Preud'homme wrote:
filevar=$1 # The file to copy a hundred time
basefile=${filevar%.[^.]*} # We delete all the end from the last dot (eg
a dot followed by any others caracters)
extension=${filevar##^.*.} # We delete all the beginning until the last
Just for
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