On Wed, 21 Dec 2022 at 04:18, Lee wrote:
> On 12/20/22, David wrote:
> > $ echo -e '100:CD001\nXXX\n200:CD001' | awk 'BEGIN { FS=":" ; done=0 }
> > /CD001/ && done==0 { print $1 - 50 ; done=1 }'
> > 50
>
> You can do it without flags:
>
> $ echo -e '100:CD001\nXXX\n200:CD001' | awk -F: '/CD001/
On 12/20/22, David wrote:
> On Tue, 20 Dec 2022 at 22:04, David wrote:
>> On Tue, 20 Dec 2022 at 22:02, David wrote:
>
>> > $ echo -e '100:CD001\n200:CD001' | awk 'BEGIN { FS=":" } /CD001/ &&
>> > NR==1 { print $1 - 50 }'
>> > 50
>>
>> Oops, my mistake, that's not the solution. Give me another
> Not that that is always important. But I just commented today
> because so often 'awk' is ignored as if its only capability is 'print $1'
> when in fact it is actually very powerful but neglected.
FWIW, `sed` can also do that job. Tho the subtraction part would take
a lot more work (`sed`
On Tue, 20 Dec 2022 at 22:04, David wrote:
> On Tue, 20 Dec 2022 at 22:02, David wrote:
> > $ echo -e '100:CD001\n200:CD001' | awk 'BEGIN { FS=":" } /CD001/ &&
> > NR==1 { print $1 - 50 }'
> > 50
>
> Oops, my mistake, that's not the solution. Give me another minute and I
> will post a better
On Tue, 20 Dec 2022 at 22:02, David wrote:
> $ echo -e '100:CD001\n200:CD001' | awk 'BEGIN { FS=":" } /CD001/ &&
> NR==1 { print $1 - 50 }'
> 50
Oops, my mistake, that's not the solution. Give me another minute and I
will post a better one one.
On Tue, 20 Dec 2022 at 21:53, The Wanderer wrote:
> On 2022-12-20 at 05:37, David wrote:
> > On Tue, 20 Dec 2022 at 21:10, The Wanderer wrote:
> >> On 2022-12-20 at 02:51, Thomas Schmitt wrote:
> >>> This contradicts the promises of man grep about option -m.
> >> It does seem to, at least at a
On 2022-12-20 at 05:37, David wrote:
> On Tue, 20 Dec 2022 at 21:10, The Wanderer
> wrote:
>
>> On 2022-12-20 at 02:51, Thomas Schmitt wrote:
>>> This contradicts the promises of man grep about option -m.
>>
>> It does seem to, at least at a glance - but I think I've figured
>> out what's
7 matches
Mail list logo
