Re: Unable to call each on a lockstep range containing 2 or more ranges
On Wednesday, 18 November 2015 at 17:22:52 UTC, Meta wrote: On Wednesday, 18 November 2015 at 12:20:42 UTC, maik klein wrote: [...] Which version of the compiler are you using? Linux - DMD64 D Compiler v2.069.0
Re: Unable to call each on a lockstep range containing 2 or more ranges
On Wednesday, 18 November 2015 at 12:20:42 UTC, maik klein wrote:
https://stackoverflow.com/questions/33779822/unable-to-call-each-on-a-lockstep-range-containing-2-or-more-ranges
http://dpaste.dzfl.pl/76c79f1f12ab
void main(){
import std.container;
import std.stdio;
import std.algorithm.iteration;
import std.range;
Array!int ai = [1,2,3,4];
Array!int ai1 = [1,2,3,4];
Array!int ai2 = [1,2,3,4];
auto arange = lockstep(ai[],ai1[]);
arange.each!((a,b) => writeln(a, b));
auto arange2 = lockstep(ai[],ai1[],ai2[]);
arange2.each!((a,b,c) => writeln(a, b, c));
}
Error: template std.algorithm.iteration.each cannot deduce
function from argument types !((a, b, c) => writeln(a, b,
c))(Lockstep!(RangeT!(Array!int), RangeT!(Array!int),
RangeT!(Array!int))), candidates are:
/opt/compilers/dmd2/include/std/algorithm/iteration.d(820):
std.algorithm.iteration.each(alias pred = "a")
"arange" works but "arange2" doesn't because the compiler is
unable to deduce the the function. The error even appears if I
explicitly add the argument types.
Which version of the compiler are you using?
Re: Unable to call each on a lockstep range containing 2 or more ranges
On Wednesday, 18 November 2015 at 17:40:21 UTC, maik klein wrote: On Wednesday, 18 November 2015 at 17:22:52 UTC, Meta wrote: Which version of the compiler are you using? Linux - DMD64 D Compiler v2.069.0 https://issues.dlang.org/show_bug.cgi?id=15357 https://issues.dlang.org/show_bug.cgi?id=15358
Unable to call each on a lockstep range containing 2 or more ranges
https://stackoverflow.com/questions/33779822/unable-to-call-each-on-a-lockstep-range-containing-2-or-more-ranges
http://dpaste.dzfl.pl/76c79f1f12ab
void main(){
import std.container;
import std.stdio;
import std.algorithm.iteration;
import std.range;
Array!int ai = [1,2,3,4];
Array!int ai1 = [1,2,3,4];
Array!int ai2 = [1,2,3,4];
auto arange = lockstep(ai[],ai1[]);
arange.each!((a,b) => writeln(a, b));
auto arange2 = lockstep(ai[],ai1[],ai2[]);
arange2.each!((a,b,c) => writeln(a, b, c));
}
Error: template std.algorithm.iteration.each cannot deduce
function from argument types !((a, b, c) => writeln(a, b,
c))(Lockstep!(RangeT!(Array!int), RangeT!(Array!int),
RangeT!(Array!int))), candidates are:
/opt/compilers/dmd2/include/std/algorithm/iteration.d(820):
std.algorithm.iteration.each(alias pred = "a")
"arange" works but "arange2" doesn't because the compiler is
unable to deduce the the function. The error even appears if I
explicitly add the argument types.
Re: Unable to call each on a lockstep range containing 2 or more ranges
On Wednesday, 18 November 2015 at 13:51:59 UTC, John Colvin wrote:
On Wednesday, 18 November 2015 at 12:20:42 UTC, maik klein
wrote:
[...]
I think this is a bug, please report it at issues.dlang.org and
perhaps there will be an explanation or it will be fixed.
In the mean time, something like this should work:
auto arange2 = zip(ai[],ai1[],ai2[]);
arange2.each!((t) => writeln(t[0], t[1], t[2]));
// or if you really must have the names:
arange2.each!((t) => (a,b,c){ writeln(a, b, c); }(t.expand));
Thanks, but the problem I have with zip is that it doesn't work
with "ref".
for example
auto arange3 = zip(ai[],ai1[],ai2[]);
foreach(ref a; arange3){
a[0] = 42;
}
Won't change anything. Is this another bug?
Re: Unable to call each on a lockstep range containing 2 or more ranges
On Wednesday, 18 November 2015 at 14:11:45 UTC, maik klein wrote:
On Wednesday, 18 November 2015 at 13:51:59 UTC, John Colvin
wrote:
On Wednesday, 18 November 2015 at 12:20:42 UTC, maik klein
wrote:
[...]
I think this is a bug, please report it at issues.dlang.org
and perhaps there will be an explanation or it will be fixed.
In the mean time, something like this should work:
auto arange2 = zip(ai[],ai1[],ai2[]);
arange2.each!((t) => writeln(t[0], t[1], t[2]));
// or if you really must have the names:
arange2.each!((t) => (a,b,c){ writeln(a, b, c); }(t.expand));
Thanks, but the problem I have with zip is that it doesn't work
with "ref".
for example
auto arange3 = zip(ai[],ai1[],ai2[]);
foreach(ref a; arange3){
a[0] = 42;
}
Won't change anything. Is this another bug?
Unfortunately, yes: https://issues.dlang.org/show_bug.cgi?id=10541
Note that
while(!arange3.empty)
{
arange3.front[0] = 42;
arange3.popFront();
}
should work as expected.
Re: Unable to call each on a lockstep range containing 2 or more ranges
On Wednesday, 18 November 2015 at 12:20:42 UTC, maik klein wrote:
https://stackoverflow.com/questions/33779822/unable-to-call-each-on-a-lockstep-range-containing-2-or-more-ranges
http://dpaste.dzfl.pl/76c79f1f12ab
void main(){
import std.container;
import std.stdio;
import std.algorithm.iteration;
import std.range;
Array!int ai = [1,2,3,4];
Array!int ai1 = [1,2,3,4];
Array!int ai2 = [1,2,3,4];
auto arange = lockstep(ai[],ai1[]);
arange.each!((a,b) => writeln(a, b));
auto arange2 = lockstep(ai[],ai1[],ai2[]);
arange2.each!((a,b,c) => writeln(a, b, c));
}
Error: template std.algorithm.iteration.each cannot deduce
function from argument types !((a, b, c) => writeln(a, b,
c))(Lockstep!(RangeT!(Array!int), RangeT!(Array!int),
RangeT!(Array!int))), candidates are:
/opt/compilers/dmd2/include/std/algorithm/iteration.d(820):
std.algorithm.iteration.each(alias pred = "a")
"arange" works but "arange2" doesn't because the compiler is
unable to deduce the the function. The error even appears if I
explicitly add the argument types.
I think this is a bug, please report it at issues.dlang.org and
perhaps there will be an explanation or it will be fixed.
In the mean time, something like this should work:
auto arange2 = zip(ai[],ai1[],ai2[]);
arange2.each!((t) => writeln(t[0], t[1], t[2]));
// or if you really must have the names:
arange2.each!((t) => (a,b,c){ writeln(a, b, c); }(t.expand));
