Re: How to split a string to a 2D array
On Saturday, 24 February 2018 at 09:06:09 UTC, Domain wrote:
On Saturday, 24 February 2018 at 08:59:46 UTC, Domain wrote:
On Saturday, 24 February 2018 at 07:51:27 UTC, Domain wrote:
[...]
And why this not compile:
rows.each!(a => data ~= a.split(",").map!(b =>
b.strip).padRight("", 2));
Error: cannot deduce function from argument types
!()(string[]), candidates are:
C:\D\dmd2\windows\bin\..\..\src\phobos\std\algorithm\iteration.d(899):
C:\D\dmd2\windows\bin\..\..\src\phobos\std\algorithm\iteration.d(934):
OK, this compile:
rows.each!(a => data ~= a.split(",").map!(b =>
b.strip).padRight("", 2).array);
FYI: Idiomatic D would be to avoid allocations (faster!).
An example:
```
auto html = " a,b1, 23 ";
auto rows =
html.strip.splitter("").filter!(not!empty).map!(a =>
a.splitter(","));
rows.writeln;
```
https://run.dlang.io/is/LC7Sog
If you really, really need a 2d array you can always do so if
required at the end:
```
auto arr2d = rows.map!array.array;
```
But please keep in mind that you ideally avoid the allocations in
the first place.
Re: How to split a string to a 2D array
On Saturday, 24 February 2018 at 08:59:46 UTC, Domain wrote:
On Saturday, 24 February 2018 at 07:51:27 UTC, Domain wrote:
[...]
And why this not compile:
rows.each!(a => data ~= a.split(",").map!(b =>
b.strip).padRight("", 2));
Error: cannot deduce function from argument types
!()(string[]), candidates are:
C:\D\dmd2\windows\bin\..\..\src\phobos\std\algorithm\iteration.d(899):
C:\D\dmd2\windows\bin\..\..\src\phobos\std\algorithm\iteration.d(934):
OK, this compile:
rows.each!(a => data ~= a.split(",").map!(b =>
b.strip).padRight("", 2).array);
Re: How to split a string to a 2D array
On Saturday, 24 February 2018 at 07:51:27 UTC, Domain wrote:
I want to convert a string like " a,b1, 23 " to
a 2D array like:
[["a", "b"],
["1", "2"],
["3", "" ]]
auto html = " a,b1, 23 ";
auto rows = html.strip.chomp("").split("");
string[][] data;
rows.each!(a => data ~= a.split(","));
string[][] result = data.map!(a => a.padRight("",
data[0].length).map!(b => b.strip)).array;
but the result is not a string[][]:
Error: cannot implicitly convert expression `array(map(data))`
of type `MapResult!(__lambda2, Result)[]` to `string[][]`
And why this not compile:
rows.each!(a => data ~= a.split(",").map!(b =>
b.strip).padRight("", 2));
Error: cannot deduce function from argument types !()(string[]),
candidates are:
C:\D\dmd2\windows\bin\..\..\src\phobos\std\algorithm\iteration.d(899):
C:\D\dmd2\windows\bin\..\..\src\phobos\std\algorithm\iteration.d(934):
