I have recently changed my django project (using A2 hosting) from fcgi to
wsgi. I have successfully gotten the project to work, but I am
experiencing a minor caveat I am trying to solve. Now, when I use the {%
url %} tag in the templates to form a link, I get the absolute path of the
server
Hi Richard,
Am 27.02.2017 um 04:01 schrieb Richard Belew:
{%url 'djggApp/guest'guest.guestId 'update'%}
but this generates a /NoReverseMatch/ error
/Reverse for 'djggApp/guest' with arguments '(1, u'update')' and keyword
arguments '{}' not found. 0 pattern(s) tried: []/
In the {% url %}, yo
i should also probably say that the url spec is in the djggApp's specific
urls.py file, included in the project's urls.py
my primary reference is the url tag reference doc
<https://docs.djangoproject.com/en/1.10/ref/templates/builtins/#url> but i
must not be composing its arg
ate code with a more modern reverse
lookup via a url tag:
{% url 'djggApp/guest' guest.guestId 'update'%}
but this generates a *NoReverseMatch* error
*Reverse for 'djggApp/guest' with arguments '(1, u'update')' and keyword
arguments '{}' no
Hi,
You have to use a form of keyword arguments to provide parameters in {% url
%} tag.
For example,
{% url post_view post_id=post_id %}
the former post_id is the argument name in your view function, the latter
post_id is the variable name in your template context.
If you have more than
>
> {%url url_name url_params%}
>
> where url_params as 'pk=object.id' or 'page=page.number'
>
Here have an example
https://docs.djangoproject.com/en/1.10/topics/http/urls/#reverse-resolution-of-urls
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,= ,-_-. =. [] Alessandro Madruga Correia
((_/)o o(\_)) [http://counter.li.org]
Hou to send parameters in url as string?
{%url url_name url_params%}
where url_params as 'pk=object.id' or 'page=page.number'
Please, help me, if you can
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rey
On Thu, Oct 30, 2014, at 03:23 PM, Daniel Grace wrote:
> Hi, I am trying to use the url tag on some parameters, one of which
> needs to come from a function. For example as follows: {% with
> state_url=encode_url flow.state.description %} advance
>
> encode_url is defined a
Hi,
I am trying to use the url tag on some parameters, one of which needs to
come from a function.
For example as follows:
{% with state_url=encode_url flow.state.description %}
advance
encode_url is defined as follows:
@register.simple_tag
def encode_url(link_text):
return link_text.replace
emove the
> last comma in the patterns()
> )
>
> Hope this helps
>
> On Friday, May 18, 2012 5:58:28 AM UTC+8, refreegrata wrote:
>>
>> Hello list
>>
>> I know, this question has been posted and resolved before, but the
>> solutions don't wo
:
>
> Hello list
>
> I know, this question has been posted and resolved before, but the
> solutions don't work in my situation. I don't know why.
>
> When I try to use the "url" tag in any template an exception is raised:
> "
;> >> Exception Type: NoReverseMatch
>> >> Exception Value:
>> >>
>> >> Reverse for 'django.contrib.auth.views.login' with arguments '()' and
>> >> keyword arguments '{}' not found.
>> >>
>> >>
>> &g
blog/urls.py:
> > urlpatterns = patterns('',
> >url(r'^accounts/login/$',
> > 'django.contrib.auth.views.login', name='login1'),
> > url(r'^accounts/logout/$',
> > 'd
#x27; not found.
> >>
> >>
> >> blog/urls.py:
> >> urlpatterns = patterns('',
> >>url(r'^accounts/login/$',
> >> 'django.contrib.auth.views.login', name='login1'),
> >>
t/$',
'django.contrib.auth.views.logout'),
)
blog/templates/registration/login.html:
I try without quotes, but I receive another error (I know, in django
1.5 are a some changes in url tag):
'url' requires a non-empty first argument. The syntax changed in
Django 1.5,
;,
>> 'django.contrib.auth.views.login', name='login1'),
>>url(r'^accounts/logout/$',
>> 'django.contrib.auth.views.logout'),
>> )
>>
>> blog/templates/registration/login.html:
>>
>>
>&
/$',
> 'django.contrib.auth.views.login', name='login1'),
>url(r'^accounts/logout/$',
> 'django.contrib.auth.views.logout'),
> )
>
> blog/templates/registration/login.html:
>
>
> I try without quot
; not found.
>
>
> blog/urls.py:
> urlpatterns = patterns('',
>url(r'^accounts/login/$',
> 'django.contrib.auth.views.login', name='login1'),
>url(r'^accounts/logout/$',
> 'django.c
'django.contrib.auth.views.login', name='login1'),
url(r'^accounts/logout/$',
'django.contrib.auth.views.logout'),
)
blog/templates/registration/login.html:
I try without quotes, but I receive another error (I know, in django 1.5
are a s
2012/8/31 Amyth Arora
> Paste the code to your urls.py and highlight which urls are not working.
>
>
> On Thu, Aug 30, 2012 at 8:07 PM, Nikolas Stevenson-Molnar <
> nik.mol...@consbio.org> wrote:
>
>> Also, your URL patters should start with "^" like your first one does.
>> And unless you need th
Paste the code to your urls.py and highlight which urls are not working.
On Thu, Aug 30, 2012 at 8:07 PM, Nikolas Stevenson-Molnar <
nik.mol...@consbio.org> wrote:
> Also, your URL patters should start with "^" like your first one does.
> And unless you need the older version, I would upgrade to
Also, your URL patters should start with "^" like your first one does.
And unless you need the older version, I would upgrade to the latest
stable version of Django (1.4.1) before doing anything else.
_Nik
On 8/29/2012 7:37 PM, Scarl wrote:
> My python version is 2.7.2 , and django version is 1.2
It should still work... the problem may be elsewhere. Would you please
provide the full contents of both url files?
_Nik
On 8/29/2012 7:37 PM, Scarl wrote:
> My python version is 2.7.2 , and django version is 1.2.7
> I have a test just now.
> If i put the name parameter in mysite.urls like url(r'
I am so sorry……I didn't provide the render params...
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My python version is 2.7.2 , and django version is 1.2.7
I have a test just now.
If i put the name parameter in mysite.urls like url(r'^test/$', 'testpage',
name='www'), the {% url www %} can work...
But when I put the name parameter in mysite.myapp.urls like url(r'help/$',
'testpage', name='www'
Hello list
I know, this question has been posted and resolved before, but the
solutions don't work in my situation. I don't know why.
When I try to use the "url" tag in any template an exception is raised:
"'str' object has no attribute 'regex&#
On Thu, Aug 11, 2011 at 9:52 AM, Tom Evans wrote:
> On Wed, Aug 10, 2011 at 7:06 PM, bruno desthuilliers
> wrote:
> > On 10 août, 16:35, Reinout van Rees wrote:
> >>
> >> Best solution: calculate that url in your python view code and just pass
> >> it along in the context.
> >
> > Definitly not
On Wed, Aug 10, 2011 at 10:37 PM, bruno desthuilliers <
bruno.desthuilli...@gmail.com> wrote:
> On 10 août, 21:52, Kayode Odeyemi wrote:
>
> You don't pass anything from "one view to another". You eventually
> pass data from a request to another, using either request params
> (querystring, post..
On Wed, Aug 10, 2011 at 7:06 PM, bruno desthuilliers
wrote:
> On 10 août, 16:35, Reinout van Rees wrote:
>>
>> Best solution: calculate that url in your python view code and just pass
>> it along in the context.
>
> Definitly not the best solution if this has to work for more than
> exactly ONE v
On 10 août, 21:52, Kayode Odeyemi wrote:
> On Wed, Aug 10, 2011 at 6:57 PM, bruno desthuilliers <
>
> bruno.desthuilli...@gmail.com> wrote:
> > On 10 août, 16:30, Tom Evans wrote:
>
> > Now for the third solution: write your own template tag. Not
> > necessarily required, but that's often the bes
On Wed, Aug 10, 2011 at 6:57 PM, bruno desthuilliers <
bruno.desthuilli...@gmail.com> wrote:
> On 10 août, 16:30, Tom Evans wrote:
>
>
> Now for the third solution: write your own template tag. Not
> necessarily required, but that's often the best solution wrt/
> decoupling / flexibility / mainta
On 10 août, 16:35, Reinout van Rees wrote:
>
> Best solution: calculate that url in your python view code and just pass
> it along in the context.
Definitly not the best solution if this has to work for more than
exactly ONE view.
> The generic rule is that most processing should happen in pytho
On 10 août, 16:30, Tom Evans wrote:
>
> You have two options:
Actually, three.
> you can extract the value in the view, and put it into the context
> that is used to render the template.
Simple but totally unpractical for most projects, as it requires
making ALL views duplicating this behavior.
On 10-08-11 16:17, Kayode Odeyemi wrote:
I need some help on how to pass url parameters to template url tag.
Something like this:
my page
page is the url parameter I want to get
Best solution: calculate that url in your python view code and just pass
it along in the context.
The generic
On Wed, Aug 10, 2011 at 3:17 PM, Kayode Odeyemi wrote:
> Hello friends,
> I need some help on how to pass url parameters to template url tag.
> Something like this:
> my page
> page is the url parameter I want to get
> Thank you
You have two options:
you can extract the valu
Hello friends,
I need some help on how to pass url parameters to template url tag.
Something like this:
my page
page is the url parameter I want to get
Thank you
--
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http://www.sinati.com. t: @charyorde
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ok, thanks everyone
2011/3/31 Łukasz Rekucki :
> On 31 March 2011 18:50, Lic. José M. Rodriguez Bacallao
> wrote:
>> well, I don't know if this is ok, but I solved the problem adding a
>> name='help_subject' tu the urlconf line
>
> Sorry, I couldn't answer earlier, but yes - that is exactly what
On 31 March 2011 18:50, Lic. José M. Rodriguez Bacallao
wrote:
> well, I don't know if this is ok, but I solved the problem adding a
> name='help_subject' tu the urlconf line
Sorry, I couldn't answer earlier, but yes - that is exactly what you
should do. Class-based views can't be referenced by u
apps.help.views.HelpSubject.as_view()' with arguments '()' and
> >> keyword arguments '{'slug': u'gdsgdgdg'}' not found.
> >>
> >> On Thu, Mar 31, 2011 at 12:33 PM, Lic. José M. Rodriguez Bacallao
> >> wrote:
> &
ws.HelpSubject.as_view()' with arguments '()' and
>> keyword arguments '{'slug': u'gdsgdgdg'}' not found.
>>
>> On Thu, Mar 31, 2011 at 12:33 PM, Lic. José M. Rodriguez Bacallao
>> wrote:
>>> I mean url tag: {% url ..
ile rendering: Reverse for
> 'apps.help.views.HelpSubject.as_view()' with arguments '()' and
> keyword arguments '{'slug': u'gdsgdgdg'}' not found.
>
> On Thu, Mar 31, 2011 at 12:33 PM, Lic. José M. Rodriguez Bacallao
> wrote:
>>
2011 at 12:33 PM, Lic. José M. Rodriguez Bacallao
wrote:
> I mean url tag: {% url ... %}
>
> this is what I am using: Leer
> mas...
>
> directory structure:
>
> site
> |--> url.py
> |--> apps (included in the python path)
> |--> help
>
I mean url tag: {% url ... %}
this is what I am using: Leer
mas...
directory structure:
site
|--> url.py
|--> apps (included in the python path)
|--> help
|--> models.py
|--> views.py
|--> urls.py
where:
"apps&q
On 31 March 2011 17:16, Lic. José M. Rodriguez Bacallao
wrote:
> use the tag:
> url
What do you mean by that ? Do you mean the {% url %} template tag, or
the `url` function commonly used in urls.py module. Give us some
examples of what you want to achieve and what problems you have.
--
Łukasz Re
hi folks, I was using django 1.2.5 and generic views to some simple
things, now, I upgrade to django 1.3 and I am trying to use the tag:
url but it doesn't seems to work with django class based generic
views. How to use this tag correctly?
--
Lic. José M. Rodriguez Bacallao
Centro de Biofisica Me
After accumulating a large number of apps over the years in a single
web project, I would say that the time it takes to reverse urls has
become quite significant, especially if we have multiple links on
screen using the reverse function.
Would there be a noticeable difference if we go back to usin
> In other words, if you designed the URL regex to handle a certain sort
> of string, and the view it points to handle a certain sort of string,
> and now in your template you're running that string through iriencode
> first, then the URL definition and the view it points to is receiving
> somethin
On Aug 15, 9:34 am, aa56280 wrote:
> > Does the view code in app.views.blah know what to do with the
> > iriencode'd values?
>
> What does that have to do with anything?
More accurately, I should have asked "Does the URL definition and view
for app.views.blah know what to do with the
iriencode'd
ning.
> Remember there are two ways to generate URLs in your templates -
> either with the {% url ... %} tag as you're doing now or with a
> get_absolute_url() method on the model (you then refer to href="{{ instancename.get_absolute_url }}"> in your template).
I'
On Aug 12, 9:22 am, aa56280 wrote:
> I'm using the url tag like so: {% url app.views.blah var1, var2 %}
>
> var1 and var2 need to be encoded, using the iriencode filter, so I
> tried this: {% url app.views.blah var1|iriencode, var2|iriencode %}
>
> That doesn't do a
I'm using the url tag like so: {% url app.views.blah var1, var2 %}
var1 and var2 need to be encoded, using the iriencode filter, so I
tried this: {% url app.views.blah var1|iriencode, var2|iriencode %}
That doesn't do anything though. I can't find any examples anywhere to
figure
› Entries
› Entry detail
{% endblock %}
... and here the url tag fetches the wrong URL. Instead of rendering
entry_archive.html as I expected, it renders entry_detail.html with
exactly the same detail as the link in 2 above.
I have tried closing down the dev server and browser and starting again
b
t ...
3. I have a problem in breadcrumbs in coltrane/entry_detail.html ...
{% block breadcrumbs %}{{ block.super }}
› Entries
› Entry detail
{% endblock %}
... and here the url tag fetches the wrong URL. Instead of rendering
entry_archive.html as I expected, it renders entry_detail.html wi
Yes, that's it exactly. Thanks!
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For mo
On Mon, Mar 15, 2010 at 11:28 PM, saxon75 wrote:
> I'm trying to generate a link where the URL of the current page gets
> passed in the querystring of the link. Like so: .
>
> I would have thought that I could do this relatively easily with
> template tags, so I've tried this:
>
> <% url arg1, ar
I'm trying to generate a link where the URL of the current page gets
passed in the querystring of the link. Like so: .
I would have thought that I could do this relatively easily with
template tags, so I've tried this:
<% url arg1, arg2 as the_url %>
http://www.example.com?variable={{ the_url|ur
On Fri, Dec 11, 2009 at 3:37 PM, Stodge wrote:
> Thanks. Bear with me - I'm new to javascript. I have this, rather this
> is what I want to do:
>
> function view_document() {
> id = get_document_id();
> if (id != -1) {
> url = "/document/
Thanks. Bear with me - I'm new to javascript. I have this, rather this
is what I want to do:
function view_document() {
id = get_document_id();
if (id != -1) {
url = "/document/view/" + id + "/";
window.open(ur
On Fri, Dec 11, 2009 at 3:25 PM, Stodge wrote:
> I'm writing some javascript for my django app and I need to use 'url'
> to lookup an... url! But I can't see how to do it for urls that
> require parameters. It works for urls without parameters, otherwise I
> get syntax errors. Any pointers? I'm se
I'm writing some javascript for my django app and I need to use 'url'
to lookup an... url! But I can't see how to do it for urls that
require parameters. It works for urls without parameters, otherwise I
get syntax errors. Any pointers? I'm searching the groups and Google
but nothing jumps out so a
If i want to create a URL tag for feeds then where should the
path.to.view point to?
Should it point to urls.py or feeds.py?
or do i need to do something else entirely?
This is using the standard sydication framwork.
Thanks,
Andrew
--~--~-~--~~~---~--~~
You
ct.myapp.views.blog'),
> > (r'^myposts/(?P.+)/$', 'myproject.myapp.views.title_view'),
>
> > On 24 Sep, 20:17, When ideas fail wrote:
> >> Hello, I was wondering if somebody could tell me what i'm doing
> >> wrong.
>
> >> I keep gett
Hello, I was wondering if somebody could tell me what i'm doing
>> wrong.
>>
>> I keep getting this error relating to a url tag:
>>
>> Traceback:
>> File "C:\Python26\lib\site-packages\django\core\handlers\base.py" in
>> get_response
>>
ong.
>
> I keep getting this error relating to a url tag:
>
> Traceback:
> File "C:\Python26\lib\site-packages\django\core\handlers\base.py" in
> get_response
> 92. response = callback(request, *callback_args,
>
Hello, I was wondering if somebody could tell me what i'm doing wrong.
I keep getting this error relating to a url tag:
Traceback:
File "C:\Python26\lib\site-packages\django\core\handlers\base.py" in
get_response
92. response = callback(request,
Hi, i resolved the problem by creating a custom url tag named
app1_url. I copied the code from URLNode and related url method (of
defaulttags.py) and modified the calls to reverse so that it gets the
argument urlconf.
On Aug 29, 9:06 pm, selcukcihan wrote:
> (Django release 1.1)
> Hi, i h
(Django release 1.1)
Hi, i have an application within my project, call it app1. It has
urls.py within its directory. That project.app1.urls does not get
included within ROOT_URLCONF(which points to 'project.urls'). I needed
project.app1.urls be isolated from other urls. Then i wrote a
middleware i
On Mon, Jul 27, 2009 at 7:58 AM, Kenneth Gonsalves
wrote:
>
> On Monday 27 Jul 2009 5:21:46 pm Kenneth Gonsalves wrote:
> > > can't handle anything except the outermost capturing groups in a
> > > reg-exp.
> > >
> > > I suspect you intend your pattern to be
> > >
> > > r'^addlandmark/(?:(?
On Monday 27 Jul 2009 5:21:46 pm Kenneth Gonsalves wrote:
> > can't handle anything except the outermost capturing groups in a
> > reg-exp.
> >
> > I suspect you intend your pattern to be
> >
> > r'^addlandmark/(?:(?P\d+)/)?$'
> >
> > changing the optional portion to be a non-captu
On Monday 27 Jul 2009 4:55:42 pm Malcolm Tredinnick wrote:
> > url(r'^addlandmark/((?P\d+)/)?$', 'addlandmark',
> > name='add_landmark'),
>
> You have nested capturing groups here, which is almost always an error.
> You have also mixed positional and named arguments, for bonus confusion
> (if they
On Mon, 2009-07-27 at 16:30 +0530, Kenneth Gonsalves wrote:
> hi
> latest trunk.
> in my urls.py I have a url:
>
> url(r'^addlandmark/((?P\d+)/)?$', 'addlandmark', name='add_landmark'),
You have nested capturing groups here, which is almost always an error.
You have also mixed positional and nam
hi
latest trunk.
in my urls.py I have a url:
url(r'^addlandmark/((?P\d+)/)?$', 'addlandmark', name='add_landmark'),
as can be seen, the id part is optional. In my template I have:
Edit this entry
this does not work as it says Reverse not found. How does one use this tag
when the argument is op
I have a a list that I generate using this code in a template:
{% extends "base.html" %}
{% block title %}Lobbyist by Country {% endblock %}
{% block content %}
Browse by County
Click on one of the items below to get information about the firms
{% for county in county_list %}
{{ coun
normal?
>
> Probably you should try setting `FORCE_SCRIPT_NAME`:
> http://docs.djangoproject.com/en/dev/ref/settings/#force-script-name.
>
> I had similar issue with `url` tag giving awkward path.
To be accurate, this isn't a problem with the URL tag. The URL tag is
providing a complet
> `FORCE_SCRIPT_NAME`:http://docs.djangoproject.com/en/dev/ref/settings/#force-script-name.
>
> I had similar issue with `url` tag giving awkward path.
>
>
>
>
> >
>
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o teh location of the
>> view.py (/var/opt/django/projects/ilayer/intranet/)
>>
>> Anyone seen this before - is it normal?
>>
>
> Probably you should try setting `FORCE_SCRIPT_NAME`:
> http://docs.djangoproject.com
gt; the absolute path on my apache mail server to teh location of the
> view.py (/var/opt/django/projects/ilayer/intranet/)
>
> Anyone seen this before - is it normal?
Probably you should try setting `FORCE_SCRIPT_NAME`:
http://docs.djangoproject.com/en/dev/ref/settings/#force-script-name
Hi,
I have a url tag as follows in my template:
{{username.name}}
I would expect the url to show as: http://intranet/MV_Edit_Employee/1/
But, it shows up as:
http://intranet/var/opt/django/projects/ilayer/MV_Edit_Employee/1/
Everything still workds, but it just looks strange to have a url
Thankyou Malcom. I understood the bottom line.
On Dec 12, 6:09 am, Malcolm Tredinnick
wrote:
> On Thu, 2008-12-11 at 04:01 -0800, madhav wrote:
> > I am facing a strage error while using 'url' tag. I am using {%url
> > logout%} for getting the logout url in th
Resolved, if I could say so :)
the problem was that I can't use reverse in forms.py 'cause is to
early for doing that :(
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Almost resolved :)
I tried everything to find the error and finally I did, but I don't
know how to resolve :(
the error is casued by this line in a imported script:
CITY_URL = reverse('get_city_list')
if I remove that line the project works fine, but I need that line :(
Ps. the url get_city_l
This is really boring :(
I've restarted the server, and it doens't work again :/
also I've noticed that no urls in reparations.urls can't be called
with the template tag url...
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What a strangeness!
I edit the template removing the extend tag, and it worked, next I
readded the extend and it still worked :O
this is really strange :/
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s:
>
> In [3]: from django.template import Template, Context
>
> In [4]: t = Template("{% url show_worksheet 5537 %}")
>
> In [5]: t.render(Context())
> Out[5]: u'/foglio/5537/'
>
> That shows the url tag is working in my setup when I
de. That's going to be a little tougher to
debug.
Oh ... other idea. Try some experiments like this:
In [3]: from django.template import Template, Context
In [4]: t = Template("{% url show_worksheet 5537 %}")
In [5]: t.render(Context())
Out[5]:
On 22 Dic, 02:17, Malcolm Tredinnick wrote:
> Certainly a bit unexpected. Can you paste the relevant lines from your
> URL Conf file, please?
>
> Regards,
> Malcolm
Sure :)
here it is:
url(r'foglio/(?P[0-9]+)/$', views.show_worksheet,
name='show_worksheet'),
Thanks for the reply
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On Sun, 2008-12-21 at 11:45 -0800, patrick91 wrote:
> Hi, I've a problem with the url tag, when I call this template:
> Visualizza
> I get this error:
> Caught an exception while rendering: Reverse for
> 'catsnc.show_worksheet' with arguments '(5537,)'
Hi, I've a problem with the url tag, when I call this template:
Visualizza
I get this error:
Caught an exception while rendering: Reverse for
'catsnc.show_worksheet' with arguments '(5537,)' and keyword arguments
'{}' not found.
But when I call
On Thu, 2008-12-11 at 04:01 -0800, madhav wrote:
> I am facing a strage error while using 'url' tag. I am using {%url
> logout%} for getting the logout url in the template. It is telling
> "Reverse for 'PROD_settings.logout' with arguments '()' and ke
I am facing a strage error while using 'url' tag. I am using {%url
logout%} for getting the logout url in the template. It is telling
"Reverse for 'PROD_settings.logout' with arguments '()' and keyword
arguments '{}' not found". Why is it referrin
I had the same problem recently in a template that was created for use
in an inclusion_tag. My workaround was to the perform the reverse call
in the templatetag and pass in the resulting url.
If that is not an appropriate workaround for you, perhaps a "with"
will do the trick. If that doesn't wor
On Nov 27, 10:43 pm, bruno desthuilliers
<[EMAIL PROTECTED]> wrote:
> On 27 nov, 14:19, dash86no <[EMAIL PROTECTED]> wrote:
> (snip)
>
> > However, when I do :
>
> > delete
>
> > I get the error:
>
> > Caught an exception while rendering: Reverse for 'sam_project.delete-
> > quote-page,' with arg
On 27 nov, 14:19, dash86no <[EMAIL PROTECTED]> wrote:
(snip)
> However, when I do :
>
> delete
>
> I get the error:
>
> Caught an exception while rendering: Reverse for 'sam_project.delete-
> quote-page,' with arguments '('',)' and keyword arguments '{}' not
> found.
>
> If anyone has any hints th
Why don't write {% url delete-quote-page object.id %} ?
HTH
//Thomas
On Nov 27, 2:19 pm, dash86no <[EMAIL PROTECTED]> wrote:
> I'm trying to use a URL tag as following:
>
> delete
>
> my named url is here:
>
> url(r'^quote/delete/(?P\d+)/$',
>
I'm trying to use a URL tag as following:
delete
my named url is here:
url(r'^quote/delete/(?P\d+)/$',
'django.views.generic.create_update.delete_object', dict(quote_info,
post_delete_redirect='/sam/'), name="delete-quote-page"),
If I change the co
Thanks for the reply. I just submitted it as bug 9315.
http://code.djangoproject.com/ticket/9315
Regards.
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> And the view is defined like this:
>
> def search(request, words):
>
> Now I'd like to print a link to the search page with certain words
> from a template and used the url tag like this:
>
> {% url search_page words="someword" %}
>
> When viewing on
t a link to the search page with certain words
from a template and used the url tag like this:
{% url search_page words="someword" %}
When viewing on the browser I get something like '/search/someword',
which is good.
My question is how do I pass more than one word in the
Brian Neal wrote:
>
>
> On Sep 19, 12:45 pm, Steve Holden <[EMAIL PROTECTED]> wrote:
>> That's annoying: now *I* have a (named) pattern that won't reverse with
>> the URL tag: specifically, the edit profile URL from the Google code
>> profiles ap
On Sep 19, 12:45 pm, Steve Holden <[EMAIL PROTECTED]> wrote:
> That's annoying: now *I* have a (named) pattern that won't reverse with
> the URL tag: specifically, the edit profile URL from the Google code
> profiles app:
>
>
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