when you want to fetch multiple objects from reverse relation(foriengkey)
On Tue, Sep 6, 2022 at 3:51 PM Justin Kpakpa wrote:
> Hello, pls under what circumstances do you need to defined a related_name
> of a model field?
>
> --
> You received this message because you are su
when you want to fetch multiple objects from that model ( having a foreign
key relation)
On Tue, Sep 6, 2022 at 3:21 PM Justin Kpakpa wrote:
> Hello, pls under what circumstances do you need to defined a related_name
> of a model field?
>
> --
> You received this message
Hello, pls under what circumstances do you need to defined a related_name of a
model field?
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`%(model_name)s` is recommended in the document default_related_name
<https://docs.djangoproject.com/en/3.2/ref/models/options/#default-related-name>
but `%(class)s ` is recommended in the document Be careful with
related_name and related_query_name
<https://docs.djangoproject.c
some option changes.
>
> Are you experiencing this on 2.1 and 2.2 pre release?
>
> Simon
>
> Le vendredi 1 mars 2019 02:40:01 UTC-5, HM a écrit :
>>
>> I added "related_name" to an exiting ForeignKey and checked with
>> "django-admin sqlmigrate" w
Hello HM,
I know that some changes have been made to avoid unnecessary foreign key
rebuilds on some option changes.
Are you experiencing this on 2.1 and 2.2 pre release?
Simon
Le vendredi 1 mars 2019 02:40:01 UTC-5, HM a écrit :
>
> I added "related_name" to an exiting Foreig
I added "related_name" to an exiting ForeignKey and checked with
"django-admin sqlmigrate" what would be done.
It seems that the foreign key constraint is dropped, then the exact
same constraint is added back. Why?
Example: If we have the classes:
class Wall(models.Mo
Hi guys, I've been scratching my head on this one. I want to know if it's
possible to filter the data of models class with related_name in a foor
loop? Basically, I want to show the members info associated to a Team.
models.py
class Team_Region(models.Model):
name = models
Hi:
I am a little confused about this section of django official docs: Be
careful with related_name
<https://docs.djangoproject.com/en/1.9/topics/db/models/#be-careful-with-related-name>
when you are using related_name in an abstract base class (only), part of
> the name shoul
whose target is a 'self' reference, but it
> does not create a related_name "reverse" field.
>
> Here is my model:
>
> class SecurityGroup(models.Model):
> name = models.CharField(max_length=100)
> description = models.TextField()
> subgr
I am using a ManyToManyField whose target is a 'self' reference, but it
does not create a related_name "reverse" field.
Here is my model:
class SecurityGroup(models.Model):
name = models.CharField(max_length=100)
description = models.TextField()
subgroups = mo
I have posted in https://code.djangoproject.com/ticket/25016#ticket .
Tim Graham於 2015年6月23日星期二 UTC+8上午12時30分48秒寫道：
>
> It looks like the check added in ticket #22064 may be too strict (only
> allowing alphanumeric characters in related_name). Would you like to open a
> ticket?
&
It looks like the check added in ticket #22064 may be too strict (only
allowing alphanumeric characters in related_name). Would you like to open a
ticket?
On Monday, June 22, 2015 at 11:28:50 AM UTC-4, Cheng-Hung Hsueh wrote:
>
> This code can run before django 1.7
> But "relate
This code can run before django 1.7
But "related_name" got an error after django 1.8
使用者表.來源: (fields.E306) The name '使用者' is invalid related_name for field
使用者表.來源
class 來源表(models.Model):
名 = models.CharField(max_length=100)
class 使用者表(models.Model):
來源 = mode
On Monday, 28 October 2013 15:11:24 UTC, Joshua Orvis wrote:
> Thank you for responding, that's extremely helpful. I'm still failing to
> query against it though. How would I implement a query for the
> get_children() method in the example above? That is, for any given
> instance of FlowBlue
models.ManyToManyField('self', blank=True, null=True,
>> related_name='children')
>> name = models.CharField( max_length=100 )
>>
>> def __str__(self):
>> return self.name
>>
>> class FlowBlueprint(StepBlueprint):
>>
On Monday, 28 October 2013 07:29:39 UTC, Joshua Orvis wrote:
> I'm using Django 1.6 RC1 and Python 3.3 with the following models:
>
> class StepBlueprint(models.Model):
> parents = models.ManyToManyField('self', blank=True, null=True,
> relat
I'm using Django 1.6 RC1 and Python 3.3 with the following models:
class StepBlueprint(models.Model):
parents = models.ManyToManyField('self', blank=True, null=True,
related_name='children')
name = models.CharField( max_length=100 )
def __str__(self):
t;
>> ### PART B
>>
>> * Things work as intended when the rosword field just contain a simple
>> "FK(Word)".
>> * But when I use the other rosword field instead containing "FK(Word,
>> related_name=&#
__
>
>
>
> ### PART B
>
> * Things work as intended when the rosword field just contain a simple
> "FK(Word)".
> * But when I use the other rosword field instead containing "FK(Word,
> related_name='altword
I use the other rosword field instead containing "FK(Word,
related_name='altword_rosword')", then
my altword_list template file doesn't receive a primary key ID from my
Index template file anymore.
What am I doing wrong when usi
Hiya, thanks for the reply.
So in this case the extra fields are actually denormalized subsets of the
original field, and the reverse relation can use the main field. (At least,
at the moment, that's my plan, but that could change. Which I guess goes to
show how rare this case probably actual
Hello,
I believe you need related_name, for disambiguation at least. Maybe by
setting a db_table you can bypass the related_name but I'm not convinced.
Actually, I'm "parasiting" your post to ask when "[we]'d prefer Django
didn't create a backwards relation
I have a model with more than one (3 in fact) ManyToManyFields which
point to the same other model.
As long as I specify distinct related_names for each, all is well.
But the documentation [1] suggests that if I don't need the backwards
relation, then specifying '+' as the rela
> > But what about 'ForeignKey's? May we pass their 'remote_name's in with
> > the kwargs?
>
> Foreign Keys - yes. Reverse Foreign Keys - no.
Point: All kwargs takes is the fields on this object.
> In the case of a foreign key, just pass in the object instance that
> you want your object to be re
On Tue, May 18, 2010 at 12:45 PM, Phlip wrote:
> Djangoists:
>
> The documentation for Model.objects.create(**kwargs) does not define
> kwargs. It just sez "kwargs".
>
> I think all of our experiences would bear out "kwargs" may at least be
> the model's fields.
Correct.
> But what about 'Foreig
Djangoists:
The documentation for Model.objects.create(**kwargs) does not define
kwargs. It just sez "kwargs".
I think all of our experiences would bear out "kwargs" may at least be
the model's fields.
But what about 'ForeignKey's? May we pass their 'remote_name's in with
the kwargs?
If not, wh
='Cromskey',
blogs=[ b1, b2,
Blog.objects.create(title='yack
yack yack') ] )
In my hypothetical kwargs, the related_name accepts an array of the
target models.
Do the kwargs support this convenience? Or must I simply plug the
items in the
Hi everyone,
I have an abstract base class which has foreign key. Derived classes
should have a related_name="%(class)s..." But, what if I have two or
more derived classes with the same name in different applications?
What is the solution of this issue?
Patch this piece of code in
Hi,
I am relatively new with Django but I like what I have seen so far.
why does this not work?
class Tag(models.Model):
text = models.CharField(max_length=200)
children = models.ManyToManyField('self', blank=True, null=True,
symmetrical=True, related_name='parents
6:23 PM, Asinox wrote:
>
> > Hi guys, first im so sorry with my english, im new with Django, u
> > know ;)
>
> > I have a problem with a related_name, the tables are fine, but the
> > problem is that in the Select (DropDown) the data display is "bad",
On Wed, Jul 29, 2009 at 6:23 PM, Asinox wrote:
>
> Hi guys, first im so sorry with my english, im new with Django, u
> know ;)
>
> I have a problem with a related_name, the tables are fine, but the
> problem is that in the Select (DropDown) the data display is "bad", i
Asinox wrote:
>
>
> Hi guys, first im so sorry with my english, im new with Django, u
> know ;)
>
> I have a problem with a related_name, the tables are fine, but the
> problem is that in the Select (DropDown) the data display is "bad", in
> this w
Hi guys, first im so sorry with my english, im new with Django, u
know ;)
I have a problem with a related_name, the tables are fine, but the
problem is that in the Select (DropDown) the data display is "bad", in
this way: Tarifas_object:
Html code:
Tarifas object
how ill display t
;
> http://dpaste.com/84076/
>
> Thanks in advance!
>
I can't recreate your error because any attempt to use the models.py you
point to produces an error on the declaration of the Edizione ForeignKey
field within model Notizia:
edizione = models.ForeignKey(Edizione, related_n
2008/10/11 Karen Tracey <[EMAIL PROTECTED]>:
> You've got a typo in there somewhere, because there is no 'notizie' in the
> query you posted, you've got 'schede' like above. So I'm not sure exactly
> what you tried nor exactly what error you got. Cut and paste of code and
> error messages is bes
2008/10/11 Karen Tracey <[EMAIL PROTECTED]>:
> You've got a typo in there somewhere, because there is no 'notizie' in the
> query you posted, you've got 'schede' like above. So I'm not sure exactly
> what you tried nor exactly what error you got. Cut and paste of code and
> error messages is bes
On Fri, Oct 10, 2008 at 3:19 PM, Alessandro <[EMAIL PROTECTED]>wrote:
> In a project I have
> class Scheda(models.Model):
>referente = models.ForeignKey(User,related_name="schede",
> editable=False)
>
> and I can use:
> User.objects.distinct().filter(sc
In a project I have
class Scheda(models.Model):
referente = models.ForeignKey(User,related_name="schede", editable=False)
and I can use:
User.objects.distinct().filter(schede__isnull=False):
in another I have
class Notizia(models.Model):
edizione = models.ForeignKe
hi Rajesh
so, implemented it as you told and it works very well.
thanks for your patience and all the explanations.
cheers
André
On Thu, Jul 17, 2008 at 7:22 PM, Rajesh Dhawan <[EMAIL PROTECTED]>
wrote:
>
>
> > > > still, it's not exactly clear to me why the admin does not work the
> same
> >
> > > still, it's not exactly clear to me why the admin does not work the same
> > as
> > > other templates.
>
> > The Admin is not a template. So, I don't know what you mean by that.
>
> admin is not using templates? well, i did not check the implementation.
Sorry, if I wasn't clear. The admin
hi Rajesh
On Thu, Jul 17, 2008 at 6:55 PM, Rajesh Dhawan <[EMAIL PROTECTED]>
wrote:
>
> Hi,
>
> > still, it's not exactly clear to me why the admin does not work the same
> as
> > other templates.
>
> The Admin is not a template. So, I don't know what you mean by that.
admin is not using templa
Hi,
> still, it's not exactly clear to me why the admin does not work the same as
> other templates.
The Admin is not a template. So, I don't know what you mean by that.
>
> in my own template, it is no problem to refer to comments of a post using,
> e.g.
>
> {% for comment in post.comments.all
agine you have a first model class and a second model class with a
> > ForeignKey referring to the first one. for example, a Post model (taken
> from
> > the tutorial blog app) and a Comment model. of course, a post can have
> > multiple comments, so the Post model gets an att
del. of course, a post can have
> multiple comments, so the Post model gets an attribute 'comments' (specified
> using related_name).
>
> how can the comments be displayed in the list view of the posts using
> newforms-admin? i would like to indicate whether there are commen
ments' (specified
using related_name).
how can the comments be displayed in the list view of the posts using
newforms-admin? i would like to indicate whether there are comments and how
many, if any.
but when adding the 'comments' attribute to the list_display of PostOptions,
syncdb
>
> Is there a way to express that I don't need the reverse relation?
No. Even if you don't need them, Django will want to dynamically endow
your Location objects with them. And, as you know, it can't do it if
two reverse relations have the same name.
--~--~-~--~~~--
I'm finding that I have quite a few many-to-one relations that don't
really need the reverse relation to be expressed in the object model.
For example,
class Route(models.Model):
start = models.ForeignKey (Location)
destination = models.ForeignKey (Location)
The default re
right now, I find out how but, anyway, I'll give U an example:
every ForeigmKey have a related_name parameter in its constructor, the
problem is how to change that value once we construct the ForeignKey object.
I did so changing the value of the: foreignkey_object.rel.related_name at
runtime
On Aug 1, 10:07 pm, "Lic. José M. Rodriguez Bacallao"
<[EMAIL PROTECTED]> wrote:
> how can I change the "related_name" value in a ForeignKey field dynamically
> at model creation time?
>
What do you really mean
how can I change the "related_name" value in a ForeignKey field dynamically
at model creation time?
--
Lic. José M. Rodriguez Bacallao
Cupet
-
Todos somos muy ignorantes, lo que ocurre es que no todos ignoramos lo
mismo.
how can I change the "related_name" value in a ForeignKey field dynamically
at model creation time?
--
Lic. José M. Rodriguez Bacallao
Cupet
-
Todos somos muy ignorantes, lo que ocurre es que no todos ignoramos lo
mismo.
=True)
Why it gives you errors..until you change it to this:
class Loan(models.Model):
loan_id = models.AutoField(primary_key=True)
originator =models.ForeignKey(UserInfo,
related_name="originator",null=True)
obligor = models.ForeignKey(UserInfo,
related_name="obligor&quo
:
class Loan(models.Model):
loan_id = models.AutoField(primary_key=True)
originator =models.ForeignKey(UserInfo,
related_name="originator",null=True)
obligor = models.ForeignKey(UserInfo,
related_name="obligor",null=True)
Why doesn't django just just look at th
On 9/10/06, Hawkeye <[EMAIL PROTECTED]> wrote:
>
> Ah ha! Thank you... I now see the error of my ways!
>
> Since I'm using unique=True, is there any way to avoid the [0] mumbo
> jumbo? (I don't see any but I figure it won't hurt to ask).
No. A foreign key is a many-to-one relation. In your case,
Ah ha! Thank you... I now see the error of my ways!
Since I'm using unique=True, is there any way to avoid the [0] mumbo
jumbo? (I don't see any but I figure it won't hurt to ask).
Thanks,
--Ben
--~--~-~--~~~---~--~~
You received this message because you are
On 9/10/06, Hawkeye <[EMAIL PROTECTED]> wrote:
> print "User's Foo: %s" % request.user.foo
>
> ==
request.user.foo is a manager, same as User.objects. The manager
itself isn't a list of objects; you need to use one of the manager
methods (like all(), filter() etc) to get the act
Hi folks,
I'm trying to develop an application that 'extends' the User object.
I'm using the 'related_name' argument for ForeignKey to access the
related objects through request.user
I have a class, similar to this
==
class Foo(models.Model):
d. To avoid confusion, the reverse representation of the relationship (person_set, or whatever related_name specifies) is not added to instances of Person.
Obviously, there are some use cases (such as yours) where this is not the case - to handle these, you need to set symmetrical=False:
insert_into = mo
ield('self', null=True, blank=True, related_name='insert')
The problem is that the model doesn't seem to use the related_name option. PressRun objects have an insert_into property, but no insert property. I'm actually trying
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