Re: Django REST Framework: How to add prefix in URL for versioning

[Lee Hinde]

Swap the urls:

 url(r'^v1/', include(v1_urls, namespace="v1"))

url(r'^', include(default_urls, namespace="default")),


On Wed, Nov 5, 2014 at 5:01 AM, Shoaib Ijaz  wrote:

> I am trying to create version for REST application. Here is my URL Examle
>
> www.myapi.com/foo [default version]
> www.myapi.com/v1/foo [version one]
>
> This is the project structure
>
> ├── __init__.py├── settings.py├── urls.py├── default_app│ ├── __init__.py│ 
> ├── serializer.py│ ├── models.py│ ├── views.py│ ├── urls.py│ └── v1_app├── 
> __init__.py├── serializer.py├── models.py├── views.py├── urls.py
>
> *default_app urls.py*
>
> from django.conf.urls import *from default_app import views as df_viewsfrom 
> rest_framework import routers
>
> router = routers.DefaultRouter()
> router.register(r'foo', df_views.viewname, "foo")
> urlpatterns = router.urls
>
> *v1_app urls.py*
>
> from django.conf.urls import *from v1_app import views as ver_viewsfrom 
> rest_framework import routers
>
> router = routers.DefaultRouter()
> router.register(r'foo', ver_views.viewname, "foo")
> urlpatterns = router.urls
>
> *main file for urls.py*
>
> from django.conf.urls import patterns, include, urlfrom defualt_app import 
> urls as default_urlsfrom v1_app import urls as v1_urlsfrom 
> django.contrib.staticfiles.urls import staticfiles_urlpatterns
>
>
>
> urlpatterns += patterns('',
> url(r'^', include(default_urls, namespace="default")),
> url(r'^v1/', include(v1_urls, namespace="v1")))
>
> urlpatterns += staticfiles_urlpatterns()
>
> My issue is, when i using simple url without any prefix then it is working
>
> www.myapi.com/foo
>
> and when i used version prefix v1 or v2 then it throws error [Page not
> found (404)]
>
> www.myapi.com/v1/foo
>
> I got this idea from this link http://stackoverflow.com/a/21839842/1558544
>
> If I don't use middleware class then is this possible to get same result?
>
> Thank you
>
>
>

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Django REST Framework: How to add prefix in URL for versioning

[Shoaib Ijaz]

I am trying to create version for REST application. Here is my URL Examle

www.myapi.com/foo [default version]
www.myapi.com/v1/foo [version one]

This is the project structure

├── __init__.py├── settings.py├── urls.py├── default_app│ ├── __init__.py│ ├── 
serializer.py│ ├── models.py│ ├── views.py│ ├── urls.py│ └── v1_app├── 
__init__.py├── serializer.py├── models.py├── views.py├── urls.py

*default_app urls.py*

from django.conf.urls import *from default_app import views as df_viewsfrom 
rest_framework import routers

router = routers.DefaultRouter()
router.register(r'foo', df_views.viewname, "foo")
urlpatterns = router.urls

*v1_app urls.py*

from django.conf.urls import *from v1_app import views as ver_viewsfrom 
rest_framework import routers

router = routers.DefaultRouter()
router.register(r'foo', ver_views.viewname, "foo")
urlpatterns = router.urls

*main file for urls.py*

from django.conf.urls import patterns, include, urlfrom defualt_app import urls 
as default_urlsfrom v1_app import urls as v1_urlsfrom 
django.contrib.staticfiles.urls import staticfiles_urlpatterns



urlpatterns += patterns('',
url(r'^', include(default_urls, namespace="default")),
url(r'^v1/', include(v1_urls, namespace="v1")))

urlpatterns += staticfiles_urlpatterns()

My issue is, when i using simple url without any prefix then it is working

www.myapi.com/foo

and when i used version prefix v1 or v2 then it throws error [Page not 
found (404)]

www.myapi.com/v1/foo

I got this idea from this link http://stackoverflow.com/a/21839842/1558544

If I don't use middleware class then is this possible to get same result?

Thank you

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