Re: How can I pass input value to view function without forms
you mean request.method instead of request.post ?
On Thu, May 27, 2021 at 3:50 PM Bhanu prasad Ch wrote:
> Hello Boris,
> I was thinking of passing number from the input to view function
> *call_me_when_ten()*
> *index.html*
> ...
>
> ...
>
> *views.py*
> def call_me_when_ten(request):
> if request.post == 'POST':
> number = request.POST['numberid']
> if number == 10:
> print('hello world')
> return render(request,'index.html')
>
> I got this code from StackOverflow, but this isn't worked. Please, help me
> in solving out this problem.
>
> On Wednesday, May 26, 2021 at 5:02:04 AM UTC+5:30 Boris Pérez wrote:
>
>> Hi!!! usually HttpResponseRedirects work with reverse
>> function...something like this
>> def myview(request):
>> return HttpResponseRedirect(reverse('arch-summary', args=[1945]))
>> where 'arch-summary' is the path name and args=[1945] the args it
>> expects...
>> You need to modify also your urls.py to add tyhe name argument to your
>> url...
>> Greetings
>>
>> 2021-05-25 0:57 GMT-04:00, Bhanu prasad Ch :
>> > Hello everyone,
>> > Please help me out in understanding how to pass the redirected view
>> > with some arguments like userid to connect the URLs in Django
>> > [image: Screenshot_2.png][image: Screenshot_3.png]
>> > When I am doing this way it is redirecting to the self page that is
>> login.
>> > But I need the
>> > HttpResponseRedirect to redirect to the progress.
>> >
>> > --
>> > You received this message because you are subscribed to the Google
>> Groups
>> > "Django users" group.
>> > To unsubscribe from this group and stop receiving emails from it, send
>> an
>> > email to django-users...@googlegroups.com.
>> > To view this discussion on the web visit
>> >
>> https://groups.google.com/d/msgid/django-users/2ebc28b3-0e99-4ace-9868-aad10564a172n%40googlegroups.com.
>>
>> >
>>
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>
> .
>
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Re: How can I pass input value to view function without forms
You have a typo somehwere; in the HTML you have "numbered", whereas in the code
you have "numberid".
Antonis Christofides
+30-6979924665 (mobile)
On 27/05/2021 13.20, Bhanu prasad Ch wrote:
Hello Boris,
I was thinking of passing number from the input to view function
/call_me_when_ten()/
/_index.html_/
...
...
/_
_/
/_views.py_/
def call_me_when_ten(request):
if request.post == 'POST':
number = request.POST['numberid']
if number == 10:
print('hello world')
return render(request,'index.html')
I got this code from StackOverflow, but this isn't worked. Please, help me in
solving out this problem.
On Wednesday, May 26, 2021 at 5:02:04 AM UTC+5:30 Boris Pérez wrote:
Hi!!! usually HttpResponseRedirects work with reverse
function...something like this
def myview(request):
return HttpResponseRedirect(reverse('arch-summary', args=[1945]))
where 'arch-summary' is the path name and args=[1945] the args it expects...
You need to modify also your urls.py to add tyhe name argument to your
url...
Greetings
2021-05-25 0:57 GMT-04:00, Bhanu prasad Ch :
> Hello everyone,
> Please help me out in understanding how to pass the redirected view
> with some arguments like userid to connect the URLs in Django
> [image: Screenshot_2.png][image: Screenshot_3.png]
> When I am doing this way it is redirecting to the self page that is login.
> But I need the
> HttpResponseRedirect to redirect to the progress.
>
> --
> You received this message because you are subscribed to the Google Groups
> "Django users" group.
> To unsubscribe from this group and stop receiving emails from it, send an
> email to django-users...@googlegroups.com.
> To view this discussion on the web visit
>
https://groups.google.com/d/msgid/django-users/2ebc28b3-0e99-4ace-9868-aad10564a172n%40googlegroups.com
.
>
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.
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Re: How can I pass input value to view function without forms
How are you making the request?
On Thursday, May 27, 2021, 4:20:55 PM GMT+6, Bhanu prasad Ch
wrote:
Hello Boris, I was thinking of passing number from the input to view
function call_me_when_ten()index.html..
views.pydef call_me_when_ten(request): if request.post == 'POST':
number = request.POST['numberid'] if number == 10:
print('hello world') return render(request,'index.html')
I got this code from StackOverflow, but this isn't worked. Please, help me in
solving out this problem.
On Wednesday, May 26, 2021 at 5:02:04 AM UTC+5:30 Boris Pérez wrote:
Hi!!! usually HttpResponseRedirects work with reverse
function...something like this
def myview(request):
return HttpResponseRedirect(reverse('arch-summary', args=[1945]))
where 'arch-summary' is the path name and args=[1945] the args it expects...
You need to modify also your urls.py to add tyhe name argument to your url...
Greetings
2021-05-25 0:57 GMT-04:00, Bhanu prasad Ch :
> Hello everyone,
> Please help me out in understanding how to pass the redirected view
> with some arguments like userid to connect the URLs in Django
> [image: Screenshot_2.png][image: Screenshot_3.png]
> When I am doing this way it is redirecting to the self page that is login.
> But I need the
> HttpResponseRedirect to redirect to the progress.
>
> --
> You received this message because you are subscribed to the Google Groups
> "Django users" group.
> To unsubscribe from this group and stop receiving emails from it, send an
> email to django-users...@googlegroups.com.
> To view this discussion on the web visit
> https://groups.google.com/d/msgid/django-users/2ebc28b3-0e99-4ace-9868-aad10564a172n%40googlegroups.com.
>
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Re: How can I pass input value to view function without forms
Hello Boris,
I was thinking of passing number from the input to view function
*call_me_when_ten()*
*index.html*
...
...
*views.py*
def call_me_when_ten(request):
if request.post == 'POST':
number = request.POST['numberid']
if number == 10:
print('hello world')
return render(request,'index.html')
I got this code from StackOverflow, but this isn't worked. Please, help me
in solving out this problem.
On Wednesday, May 26, 2021 at 5:02:04 AM UTC+5:30 Boris Pérez wrote:
> Hi!!! usually HttpResponseRedirects work with reverse
> function...something like this
> def myview(request):
> return HttpResponseRedirect(reverse('arch-summary', args=[1945]))
> where 'arch-summary' is the path name and args=[1945] the args it
> expects...
> You need to modify also your urls.py to add tyhe name argument to your
> url...
> Greetings
>
> 2021-05-25 0:57 GMT-04:00, Bhanu prasad Ch :
> > Hello everyone,
> > Please help me out in understanding how to pass the redirected view
> > with some arguments like userid to connect the URLs in Django
> > [image: Screenshot_2.png][image: Screenshot_3.png]
> > When I am doing this way it is redirecting to the self page that is
> login.
> > But I need the
> > HttpResponseRedirect to redirect to the progress.
> >
> > --
> > You received this message because you are subscribed to the Google Groups
> > "Django users" group.
> > To unsubscribe from this group and stop receiving emails from it, send an
> > email to django-users...@googlegroups.com.
> > To view this discussion on the web visit
> >
> https://groups.google.com/d/msgid/django-users/2ebc28b3-0e99-4ace-9868-aad10564a172n%40googlegroups.com
> .
> >
>
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