hi,
the basic is the same with full html site, except in ajax you only render part
of your html output.
so in ajax you can use ajax call the target url, and the output from the html
output is display in the div specified.
use jquery or prototype for easy manipulation.
hope help
Sent from my
Hi,
Javascript does not understand django template syntax. In your case you can
return a template rendered with django, and replace the html.
Thannks,
On Sunday, February 10, 2013 3:12:47 PM UTC+5:30, doniyor wrote:
>
> hey guys, i am stuck in this problem. i posted the problem on
>
hey guys, i am stuck in this problem. i posted the problem on
stackoverflow.com
also,
http://stackoverflow.com/questions/14787772/sorting-queryset-of-search-result-and-render-back-thru-ajax
but till now no one could answer there, so i am asking here again. anyone
can help me? :(
--
You
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