RE: [Elecraft] K2 dead xmtr

2005-12-12 Thread Don Wilhelm
: [Elecraft] K2 dead xmtr Hi Don. The levels are high everywhere in the chain up through the bases of Q7-8. Requested power is immaterial in this case, since the ALC sees zero detected power, and therefore is pegged at 5v all the time. I measured the levels with a scope, and divided the p-p

Re: [Elecraft] K2 dead xmtr

2005-12-12 Thread Larry Phipps
: Elecraft@mailman.qth.net Subject: Re: [Elecraft] K2 dead xmtr Hi Don. The levels are high everywhere in the chain up through the bases of Q7-8. Requested power is immaterial in this case, since the ALC sees zero detected power, and therefore is pegged at 5v all the time. I measured the levels

Re: [Elecraft] K2 dead xmtr

2005-12-12 Thread Jack Brindle
unlikly because that kind of fault would drag the receiver way down too. 73, Don W3FPR -Original Message- From: Larry Phipps [mailto:[EMAIL PROTECTED] Sent: Sunday, December 11, 2005 10:46 PM To: [EMAIL PROTECTED] Cc: Elecraft@mailman.qth.net Subject: Re: [Elecraft] K2 dead xmtr Hi

Re: [Elecraft] K2 dead xmtr

2005-12-12 Thread Larry Phipps
because that kind of fault would drag the receiver way down too. 73, Don W3FPR -Original Message- From: Larry Phipps [mailto:[EMAIL PROTECTED] Sent: Sunday, December 11, 2005 10:46 PM To: [EMAIL PROTECTED] Cc: Elecraft@mailman.qth.net Subject: Re: [Elecraft] K2 dead xmtr Hi Don

RE: [Elecraft] K2 dead xmtr

2005-12-11 Thread Don Wilhelm
Larry, Exactly where are the RF levels higher than normal? Obviously not at the output of the Low Pass filter or you would have power output (unless you have the tuner and have set it to ANT2 instead of ANT1 or something like that). With the requested power set at 5 watts, send us the RF

Re: [Elecraft] K2 dead xmtr

2005-12-11 Thread Larry Phipps
Hi Don. The levels are high everywhere in the chain up through the bases of Q7-8. Requested power is immaterial in this case, since the ALC sees zero detected power, and therefore is pegged at 5v all the time. I measured the levels with a scope, and divided the p-p values by 2.82 to compare