Hi, we have found a very strange problem with our firebird database, a
record on a table of firebird databes is not always beeing returned:
1 - Using flamerobin we are never fetching record 1648 of our datble.
2 - Using an application we are developing (with vb.net on vs2010)
Hello Paul,
do you have an idea, when the packager will be supported El Capitan or is any
other way manually to install firebird?
Thanks for you help
Bernd Frei
Hi Norbert,
Sorry to say, but the below SQL you shared doesn't givbe the sub nodes in the
base node, it just gives the first level of nodes and not the enitre node
structure i.e. all other nodes below the nodes (i.e. nodes which I get from you
SQL as a result ) are missing.
Would you please
Sorry, forgot to put SQL for reference.
if I understand the request, something like select b.description from(select
a.* from mygroup awhere a.linked_to_group is not nulland(exists(select 1 from
mygroup b where b.linked_to_group = a.pk_group )or a.linked_to_group !=
(select first 1 pk_group
Hi Norbert,
The SQL you have shared without CTE, gives me other group details as well if
they exists. If you create another base group like 'Vishal Group', then this
SQL gives that group details as well. I tried but putting group name in
condition but getting only one record, could you show me
On Mon, Oct 5, 2015 at 12:59 PM, 'Alexis (PROINTER)' ale...@prointersl.com
[firebird-support] wrote:
> Hi, we have found a very strange problem with our firebird database, a
> record on a table of firebird databes is not always beeing returned:
>
> 1 - Using
Hi All
Is there a query structure available I can use to identify where records
have been change or are missing between two table with the exact table
structure?
i.e.
I store a backup of financial data annually in separate tables.
JOURNAL2013
JOURNAL2015
JOURNAL2015 etc.
where
if I understand the request, something like
select b.description from
(
select a.* from mygroup a
where a.linked_to_group is not null
and
(
exists(select 1 from mygroup b where b.linked_to_group = a.pk_group )
or a.linked_to_group != (select first 1 pk_group from mygroup where
Hi Norbert,
Thank You So Much, I got exactly the same result what I was expecting.
Thank You So much.
Are you aware of any documents which are avaialble in english, so I could learn
this recirsive SQL ?
With Best Regards.
Vishal
On Monday, 5 October 2015 3:55 PM, "'Norbert Saint Georges'