Le mardi 01 février 2005 à 11:49, José Castro écrivait:
Hi, guys.
Apart from the secret eskimo greeting and the goatse operator, can
anyone tell me about other secret operators?
Examples:
eskimo: }{
goatse: =()=
eskimo usage: perl -ne '}{print $.'
goatse usage: perl -e
On Tue, 1 Feb 2005 11:49:57 +
Jos_ Castro [EMAIL PROTECTED] wrote:
Hi, guys.
Apart from the secret eskimo greeting and the goatse operator, can
anyone tell me about other secret operators?
Examples:
eskimo: }{
goatse: =()=
eskimo usage: perl -ne '}{print $.'
perl
Le mardi 01 février 2005 à 18:57, Vladi Belperchinov-Shabanski écrivait:
On Tue, 1 Feb 2005 15:57:33 +0100
[EMAIL PROTECTED] (Philippe 'BooK' Bruhat) wrote:
There's also @{[]} but I don't know f it has a name.
Usage: print splatt @{[ ... ]} pow
where ... is any valid expression,
Can I get that just a little slower?
$b = () = /u/g;
is the same as:
@a = /u/g;
$b = @a;
I understand what happens, but it appears to be assigning to an empty list
- is that filling up the list, so to speak? Or is it just that it makes
the 'result' of /u/g assign in array/list
From the keyboard of [EMAIL PROTECTED] [01.02.05,11:15]:
Can I get that just a little slower?
$b = () = /u/g;
is the same as:
@a = /u/g;
$b = @a;
it's not the same.
perl -le '$_=foo; print $b =()= /o/g'
2
perl -le '$_=foo; print @b =()= /o/g'
perl -le '$_=foo; print /o/g'
oo
* Ronald J Kimball ([EMAIL PROTECTED]) wrote:
You can assign two elements to a one-element list:
($foo) = (1, 2);
You can even assign two elements to an empty list:
() = (1, 2);
In each case, any extra elements are simply discarded, but the result of
the assignment in scalar
On Tue, 2005-02-01 at 03:49, Jos Castro wrote:
Hi, guys.
Apart from the secret eskimo greeting and the goatse operator, can
anyone tell me about other secret operators?
Examples:
eskimo: }{
goatse: =()=
eskimo usage: perl -ne '}{print $.'
This is wonderfully deranged. I
* Jeff Yoak ([EMAIL PROTECTED]) wrote:
eskimo usage: perl -ne '}{print $.'
This is wonderfully deranged. I haven't seen it before, but it was
immediately clear what it does.
goatse usage: perl -e '$_=zbrughau;$b=()=/u/g;print $b'
This is probably even more wonderfully deranged as
--- José Castro [EMAIL PROTECTED] wrote:
* Quantum Mechanic ([EMAIL PROTECTED])
wrote:
$foo = ($bar) = (9,8,7);
RHS list
($bar) array
$bar - 7 (rest discarded)
No, no, no.
$bar - 9
Yes, that was a typo -- thanks.
It's the same as
$foo = ($bar,
José Castro wrote:
Apart from the secret eskimo greeting and the goatse operator,
can anyone tell me about other secret operators?
Let's not forget the Ton Hospel high-precedence decrement
operator ~- invented during a golf tournament (anyone remember
which one?).
IIRC, Ton's ~- invention
Philippe 'BooK' Bruhat wrote:
So we have :
symbolnicknameRole
--
= spaceship documented operator
0+venus numification
}{eskimo greeting END{} in
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