This is the project address.
*https://code.google.com/p/cs2103jan2014-f12-5c/*
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I get the following :
*
*
c...*
*
.
On Sun, Apr 13, 2014 at 11:07 AM, Mohamed Ghoneim ghooo.gh...@gmail.comwrote:
What will you output for 5 5 12 ?
--
Mohamed Sayed Ghoneim
On Sun, Apr 13, 2014 at 7:32 AM, Dhruva Sagar dhruva.sa...@gmail.comwrote:
The problem does not
Can you explain why the right most cell not be revealed ?
This is what I get as the weighted game :
235*
002*
0011
So if the first cell with 0 is clicked, I believe it should end up
revealing all...
On Sun, Apr 13, 2014 at 11:26 AM, Tsuyoshi Ito
tsuyoshi.ito.2...@gmail.comwrote:
On Sunday,
Ahh, I see how :/, so the spiral approach isn't correct then.
On Sun, Apr 13, 2014 at 11:53 AM, Dhruva Sagar dhruva.sa...@gmail.comwrote:
Can you explain why the right most cell not be revealed ?
This is what I get as the weighted game :
235*
002*
0011
So if the first cell with 0 is
Here's my approach. It may not be the most elegant, but it passed the test
cases. First, handle 1*c, r*1, and only 1 free space separately. Then,
recognize that you can always always push the free space to one corner. Suppose
that the free spaces are in the top left, then row 12 must have the
Thank you!
On Sun, Apr 13, 2014 at 12:26 PM, Igor Naverniouk abedn...@gmail.comwrote:
Yes, feel free to discuss problems and solutions on your blog after the
round is over.
On Sat, Apr 12, 2014 at 11:12 PM, Amit Thakur he...@amitthakur.orgwrote:
Qualification round is over. Can I write
2014. április 13., vasárnap 7:20:09 UTC+2 időpontban Amber Kulkarni a
következőt írta:
If you have at least 25 points, you qualified.
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This is wrong because of the last empty cell in the first column will never
get filled as there is no 0 surrounding it.
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On Sun, Apr 13, 2014 at 8:18 AM, Dhruva Sagar dhruva.sa...@gmail.comwrote:
I get the following :
*
*
c...*
*
.
On Sun, Apr
On Sunday, April 13, 2014 11:42:23 AM UTC+5:30, Amit Thakur wrote:
Qualification round is over. Can I write about the problems on my blog?
yes
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Thanks!
Alternatively, Noemi could play 0.186 at the very beginning.
My code at
https://github.com/ajlopez/TddRocks/tree/master/Gcj2014
https://github.com/ajlopez/TddRocks/tree/master/Gcj2014/DeceitfulWar
The only minor correction: Noemi cannot say 0.999 every time. Maybe 0.9991,
0.9992 and so
My solution (but still with rejection in small dataset):
- In every solution, the empty cells could be moved to touch a side (that
is, if the empty cells is an internal island, the same solution could be
moved to have an empty cell on a side touching the exterior)
- Find a rectangle r x c, so
My approach was somewhat similar, except I tried to place the mines in a
rectangle instead of the empty squares.
First, I treated and Nx1 grid and any grid with 0,1,2, or 3 empty squares as
special cases. This allowed me to know that I would always have a 2x2
rectangle empty in the corner.
I
Hi,
If in the second arrangement, the cards from the first chosen row are not all
in different rows, then he IS a Bad magician!
I know that the magician may be luck and still be able to find the card
depending on the volunteer choices, but it doesn't change the fact that he IS a
Bad magician!
My solution (but still with rejection in small dataset):
- In every solution, the empty cells could be moved to touch a side (that
is, if the empty cells is an internal island, the same solution could be
moved to have an empty cell on a side touching the exterior)
- Find a rectangle r x c,
For 5 5 4
my algorithm/code gives
Case #1:
c
.
*
*
...**
On Sun, Apr 13, 2014 at 9:07 AM, Richard Braakman gta...@clueonic.netwrote:
My solution (but still with rejection in small dataset):
- In every solution, the empty cells could be moved to touch a side (that
is,
Naomi went to the dark side.
Now she is a corrupted person...
Em 13/04/2014 11:06, Luke Pebody l...@pebody.org escreveu:
Ken is very trusting.
Sent from my iPad
On 13 Apr 2014, at 12:51, Richard Braakman gta...@clueonic.net wrote:
To get 8, Naomi takes 0.300, 0.389, 0.557, 0.832, 0.899,
On Monday, March 24, 2014 10:04:17 PM UTC+2, Shivang Gupta wrote:
Hi,
Are the solutions judged for performance as well, in terms of lines of code,
or execution time, or memory footprint, etc.? Has anybody ever run into a
problem where they had to be careful about this aspect, specially
The problem statement is very clear on when he is a bad magician. From the
problem statement:
If there are multiple cards the volunteer could have chosen, y should be
Bad magician!
So it doesn't matter if in real life that would be a bad magician. In the
problem it's only a bad magician only in
On Sunday, April 13, 2014 3:07:48 AM UTC-7, IdahoJacket wrote:
My approach was somewhat similar, except I tried to place the mines in a
rectangle instead of the empty squares.
IdahoJacket, thank you for the explanation. I've been reading through other
people's code submission to
Amit, care to share your blog with us? ;)
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Sometimes you cannot interpret the problem using your own understanding of
Bad magician
The description is fairly clear.
---
If there is a single card the volunteer could have chosen, y should be the
number on the card. If there are multiple cards the volunteer could have
chosen, y should be
HI,
I could not get this one to pass either, i still don't understand why, it must
be the way i fill the board (I ran the actual recursion algorigthm on both
failures and successes and checked the number of cells left to be revealed and
they were consistent with my results)
If R or C == 1
I'm not new to Code Jam, and flew through the first two questions but got
caught on Minesweeper.
I downloaded another contestants code after the contest and used my small input
set to compare output and find the bug.
There was none! All the 'Impossible' match and all other cases we both give
Actually according to the rules Naomi could always play .999 as long as Ken
didn't have the .999 block.
On Sunday, 13 April 2014 04:55:59 UTC-4, ajlopez wrote:
Thanks!
Alternatively, Noemi could play 0.186 at the very beginning.
My code at
Note that it works exactly the same way in rounds 1A, 1B, and 1C, and in
those rounds it does matter exactly where you come in the scoreboard.
Paul Smith
p...@pollyandpaul.co.uk
On Sat, Apr 12, 2014 at 7:08 AM, Bhawik Jain bhawikonl...@gmail.com wrote:
On Saturday, 12 April 2014 10:15:03
I think even so she could play a 0. block
On Sun, Apr 13, 2014 at 10:16 AM, Christian Wen christian@gmail.comwrote:
Actually according to the rules Naomi could always play .999 as long as
Ken didn't have the .999 block.
On Sunday, 13 April 2014 04:55:59 UTC-4, ajlopez wrote:
25 points and didn't do anything to get disqualified.
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Hi,
I got 25 points exactly and i see many others who got 90 aswell. So would they
stand an advantage in the future rounds compared to me?
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You can't check using diff as configurations produced might be different,
but you can always check your board for inconsistency using a normal dfs.
Also check that you put the required number of mines. See for example my
solution to C-large which contains the checking code, you can use that to
No difference—
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On Mon, Apr 14, 2014 at 12:50 PM, sandeep kumar Mantrala
sandeep@gmail.com wrote:
Hi,
I got 25 points exactly and i see many others who got 90 aswell. So would
they stand an advantage in the future rounds compared to me?
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