From: IBM Mainframe Discussion List [IBM-MAIN@LISTSERV.UA.EDU] on behalf of
Michael Watkins [032966e74d0f-dmarc-requ...@listserv.ua.edu]
Sent: Friday, January 20, 2023 9:05 AM
To: IBM-MAIN@LISTSERV.UA.EDU
Subject: Re: KMOD1 DS8k box
I understood Jake's question
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From: IBM Mainframe Discussion List On Behalf Of
Allan Staller
Sent: Friday, January 20, 2023 7:33 AM
To: IBM-MAIN@LISTSERV.UA.EDU
Subject: Re: KMOD1 DS8k box
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2023 7:38 AM
To: IBM-MAIN@LISTSERV.UA.EDU
Subject: Re: KMOD1 DS8k box
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From: IBM Mainframe Discussion List On Behalf Of
Jake Anderson
Sent: Thursday, January 19, 2023 11:40 AM
To: IBM-MAIN@LISTSERV.UA.EDU
Subject: Re: KMOD1 DS8k box
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Is there a command or facility within DS8K to generate storage array
utilization report ?
On Thu, Jan 19, 2023, 5:51 PM Paul Gorlinsky wrote:
> This is the theoretical maximum… not realistic… the available usable space
> is 100% determined by the blksize and optional key size… zOS use at most
>
This is the theoretical maximum… not realistic… the available usable space is
100% determined by the blksize and optional key size… zOS use at most 1/2 track
blocking … it you force a 32760 block size you will waste about 12k per track…
safe numbers are about 90% for estimating
as far as configuring and 'lost' space.
-Original Message-
From: IBM Mainframe Discussion List On Behalf Of
Mike Schwab
Sent: Thursday, January 19, 2023 3:59 AM
To: IBM-MAIN@LISTSERV.UA.EDU
Subject: Re: KMOD1 DS8k box
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846,236,160 bytes * 1990 M1s is 1,684,009,958,400 bytes.
On Thu, Jan 19, 2023 at 3:53 AM Mike Schwab wrote:
>
> 3390-1 is 846,236,160 bytes. Divide by 1000 or 1024 three times for a
> Gigabyte factor, or four times for a Terabyte conversion factor.
>
> On Thu, Jan 19, 2023 at 1:29 AM Jake
3390-1 is 846,236,160 bytes. Divide by 1000 or 1024 three times for a
Gigabyte factor, or four times for a Terabyte conversion factor.
On Thu, Jan 19, 2023 at 1:29 AM Jake Anderson wrote:
>
> Hello
>
> I was going through the storage usage in DS8K Gui login And I can see the
> utilization of
