_ _ _(_)_ | A fresh approach to technical computing
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| | |_| | | | (_| | | Version 0.3.3 (2014-10-21 20:18 UTC)
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one vector 10^9 it is about 16 GB,
Paul
W dniu 2015-01-07 o 13:13, Tim Holy pisze:
Did you try calculating how much memory the right hand side of that assignment
requires? (Remember that sizeof(Float64) == 8).
--Tim
On Wednesday, January 07, 2015 03:25:54 AM paul analyst wrote:
_ _
On Wednesday, January 07, 2015 01:42:24 PM Paul Analyst wrote:
one vector 10^9 it is about 16 GB,
...and that explains it. (Compare against your RAM size.)
--Tim
Paul
W dniu 2015-01-07 o 13:13, Tim Holy pisze:
Did you try calculating how much memory the right hand side of that
Did you try calculating how much memory the right hand side of that assignment
requires? (Remember that sizeof(Float64) == 8).
--Tim
On Wednesday, January 07, 2015 03:25:54 AM paul analyst wrote:
_ _ _(_)_ | A fresh approach to technical computing
(_) | (_) (_)|
2.if sum k and l 9 Julia cant work. Is it to big size for hdf5 or for
system (Win7 64 Home Premium) ?
Not sure. It works for me (Kubuntu Linux 14.04).
I checked on Ubuntu :
If sum of k or/and l is more then 7 I have problem with reading
vectors (cols)
samsung2@samsung2:~$ julia
On Monday, January 05, 2015 03:17:12 PM Paul Analyst wrote:
Thx, Tim,
I have solution but is 2 questions:
1. Whay must be line: /fid[mygroup/A]=rand(2)/ ?
That line just means 'create a variable called A inside a group called
mygroup, and assign it a value of rand(2)'. If you don't need that
On Monday, January 05, 2015 09:52:28 PM Paul Analyst wrote:
dset = d_create( F, datatype(Float64), dataspace(10,10))/
You're missing the `fid`. You have to tell it where (which file, or which
group)
you want to create that dataset.
--Tim
Tim , thx for hints, but do not work without this line
#fid[mygroup/A]=rand(2)
becouse I vave not g , and nothing to declare in this line /dset =
d_create(g, F, datatype(Float64), dataspace(10,10))/
/
dset = d_create( F, datatype(Float64), dataspace(10,10))/
do not work ...
Paul
using
How to overwrite to an existing file, only range of data?
In HDF5 can do this?
I have an array of zeros 10 x 10
I need an existing file owerwrite range rand (5x5), for example.
Existingfile [2: 7.3: 8]
Paul
If I understand correctly, then yes, that's possible. See the HDF5 docs.
--Tim
On Sunday, January 04, 2015 04:25:13 AM paul analyst wrote:
How to overwrite to an existing file, only range of data?
In HDF5 can do this?
I have an array of zeros 10 x 10
I need an existing file owerwrite range
Of course, first I read :)
Is there about reading range array. I need to save a range of In analogy to.
A = reshape (1: 120, 15, 8)
h5write (/ tmp / test2.h5, mygroup2 / A, A)
data = h5read (/ tmp / test2.h5, mygroup2 / A (2: 3: 15: 3: 5))
Paul
W dniu niedziela, 4 stycznia 2015 14:14:03 UTC+1
You can also work directly with the HDF5 file as an array object...
using HDF5
hfi=h5open(myfile.h5,w); # create the file
close(hfi)
A = reshape(1: 120, 15, 8);
hfi = h5open(myfile.h5,r+) # read/write access
hfi[mygroup/A] = A
15x8 Array{Int64,2}:
1 16 31 46 61 76 91 106
...
14
See the part about ...incrementally save to very large ...
--Tim
On Sunday, January 04, 2015 06:59:53 AM paul analyst wrote:
Of course, first I read :)
Is there about reading range array. I need to save a range of In analogy to.
A = reshape (1: 120, 15, 8)
h5write (/ tmp / test2.h5,
Do note there are two additional pages of documentation in the doc/ folder.
--Tim
On Sunday, January 04, 2015 06:59:53 AM paul analyst wrote:
Of course, first I read :)
Is there about reading range array. I need to save a range of In analogy to.
A = reshape (1: 120, 15, 8)
h5write (/ tmp /
Thx, form me this moment
*hfi[mygroup/A] = A*
was not too clear
Paul
W dniu niedziela, 4 stycznia 2015 18:37:30 UTC+1 użytkownik Tim Holy
napisał:
See the part about ...incrementally save to very large ...
--Tim
On Sunday, January 04, 2015 06:59:53 AM paul analyst wrote:
Of
Big Thx for big lesson, is no too dark now
Paul
W dniu niedziela, 4 stycznia 2015 17:58:28 UTC+1 użytkownik Adrian
Cuthbertson napisał:
You can also work directly with the HDF5 file as an array object...
using HDF5
hfi=h5open(myfile.h5,w); # create the file
close(hfi)
A = reshape(1:
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