[julia-users] Re: Getting sequence of time and subset it

2016-06-01 Thread Evan Fields
Of course there's a way :) You can use the isna function to check if a value is NA or not. There's also the dropna function which takes a DataArray as input and returns a regular Vector with the NA elements removed. You could try something like the following: firstbreakcol = 4 lastbreakcol =

[julia-users] Re: Getting sequence of time and subset it

2016-05-31 Thread akrun
Many thanks for the solution and it works well with the example posted. But, if I have missing values in one of the columns, it throws an error. sdt2 = DataFrame(ID = 1:2, StartTime = DateTime(["4/13/2016 07:00", "4/13/2016 07:15"], "m/d/y H:M"), EndTime =

[julia-users] Re: Getting sequence of time and subset it

2016-05-30 Thread Evan Fields
I'm not 100% sure I understand your question, but let me give it a shot. First thing is to note why you're getting that MethodError. It's from the line println(si in sdt1[i, [:BreakTime1, :BreakTime2]]) Define sdt1 as you do (I just copied into a Julia REPL) and set i = 1 to for the first