A NodeSeq is really just a Seq[Node]. And a List[Node] is also a Seq[Node].
Hence a List[Node] is a NodeSeq.
scala import scala.xml.NodeSeq
import scala.xml.NodeSeq
scala val n: NodeSeq = List(spanA/span, spanB/span, spanC/span)
n: scala.xml.NodeSeq = spanA/spanspanB/spanspanC/span
--j
On Thu,
Sigh... I knew it had to be drop-dead simple. Not sure how I kept
getting List(span...) output instead of span.../span out. Works
now. Thanks.
Chas.
Jorge Ortiz wrote:
A NodeSeq is really just a Seq[Node]. And a List[Node] is also a
Seq[Node]. Hence a List[Node] is a NodeSeq.
scala
On Thu, Nov 13, 2008 at 10:32 AM, Matt Harrington [EMAIL PROTECTED] wrote:
Take a look at List.mkString(). It inherits from Iterable.
---Matt
Erm, I'll retract this. :)
---Matt
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