This posting contains:
1. The python script file used to input the data and produce the contour
and color map plots
2. The input data
3. JPG files containing screen snaps of the actual contour and color map
plots
Hope this helps.
solution.txt
Per request my question is being resubmitted here.
I'm attempting to generate contour and a color map in Matplotlib ver. 1.4.3
on a MacBook Pro under Mac OS X ver. 10.10.2 in Python 2.7.3 with the
Anaconda environment.
A zip file has been attached to this note. Two sub-directories,
Eric,
I took your suggestion and it worked. Thank you.
To all the others who responded so quickly, thank you as well.
P.S. - I'm still wondering what other differences between vers. 1.1.1rc and
1.4.3 I'll run into. I'll worry about those when I run into them.
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I'm attempting to generate contour and a color map in Matplotlib ver. 1.4.3
on a MacBook Pro under Mac OS X ver. 10.10.2 in Python 2.7.3 with the
Anaconda environment. Now the messages from Matplotlib I get
are:users-MacBook-Pro:lecture1 user$ python plot_solution.pySaved
pseudocolor plot as
On 2015/02/21 5:32 PM, Starfighter wrote:
Per request my question is being resubmitted here.
I'm attempting to generate contour and a color map in Matplotlib ver. 1.4.3
on a MacBook Pro under Mac OS X ver. 10.10.2 in Python 2.7.3 with the
Anaconda environment.
A zip file has been attached
Can you re-send this with that error message formatted a bit better (It is
really hard to make any sense of it all squashed into one line like that).
From what I can make it out looks like it is mostly warnings, not errors.
Does it correctly save the figure? Can you show us the two outputs?
Hey Starfighter,
I want to help, but I also don't like unzipping files from strangers. Can you
make a simple script that generates some fake with numoy and the handful of
matplotib commands you need to make the figure.
-p
—
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On Sat, Feb 21, 2015 at 7:34 PM,
In the Ticker API docs http://matplotlib.org/api/ticker_api.html the
following is listed as a valid rc parameter:
axes.formatter.useoffset=False
Is there a way to put this in my matplotlibrc?
I have tried the obvious choice:
axes.formatter.useoffset : False
but that give the error
