Hi Chao,
I spent some time to figure out why I cannot replace ax1.hist() with
ax1.scatter().
It seems hist() returns list of 'Rectangle' (sadly if there is just one, it
does return
just the 'Rectangle' (not wrapped in a list) ... somewhere a trick
a = [a, ]
is likely needed.
Anyway, my
Hi Martin,
I am not sure that I understand your question very well.
For a single scatter() plot, I guess I agree with you, you need to put it
in [] because
legend() function must receive iterable as far as I understand.
I don't think scatter() allows you to pass a series of group of (x,y) data
Hi Chao,
ChaoYue wrote:
Dear Martin,
I worked out a similar example for your reference as I don't catch your
example very well.
I think you got the idea quite well.
fig = plt.figure()
ax1 = fig.add_subplot(211)
Hi Martin,
I don't know tight_layout quite well. Probably you could also split the
handlers of the barplot into
and 2 or 3 or 4 parts depending on the number, and then show them in
sperate axes?
then you create n+1 subplots for the whole figure?
probably this is quite stupid.
cheers,
Chao
On
ChaoYue wrote:
Hi Martin,
I don't know tight_layout quite well. Probably you could also split the
handlers of the barplot into
and 2 or 3 or 4 parts depending on the number, and then show them in sperate
axes?
then you create n+1 subplots for the whole figure?
No, the reason why I use
Dear Martin,
I worked out a similar example for your reference as I don't catch your
example very well.
fig =
plt.figure()
ax1 =
fig.add_subplot(211)
ax2 =
fig.add_subplot(212)
arrlist = [np.random.normal(size=100) for i in
range(50)]
ret =
ax1.hist(arrlist,histtype='barstacked')
reclist =
On Mon, May 20, 2013 at 12:02 PM, Martin Mokrejs
mmokr...@fold.natur.cuni.cz wrote:
Hi,
I am having trouble to get space allocated for a long legend text,
lets say spanning 2/3 - 3/4 of the whole output. I would like to have
stacked barchart as 1st subplot and the place of remaining 3
