Re: [Matplotlib-users] polar() is not equal to ax.plot (where ax is a PolarAxes)?

2009-08-03 Thread Michael Droettboom
I'm not able to see a difference between the two methods here: from pylab import * import numpy as np r = np.arange(0, 3.0, 0.01) theta = 2*np.pi*r fig = figure() ax = fig.add_axes([0.1, 0.1, 0.8, 0.8], polar=True) ax.plot(theta, r) show() polar(theta, r) show() Can you provide a standalone

[Matplotlib-users] polar() is not equal to ax.plot (where ax is a PolarAxes)?

2009-08-02 Thread plaf
Hi all, I have been trying both ways of plotting polar and found that they behave differently? Is it just me? I have sets of theta and R to plot, and when I plotted in console using polar() it produces different plot (!) than when I used ax.plot() from my application. I compared this with the