Re: [Matplotlib-users] precision of drange

2008-06-02 Thread Eric Firing
Brian McLaughlin wrote: > If I do: > t1=datetime.datetime(2008,06,02,01,0,0) > t1=datetime.datetime(2008,06,02,02,0,0) > tVec1=drange(t1,t2,datetime.timedelta(seconds=1)) > tVec2=drange(t1,t2,datetime.timedelta(seconds=5)) > tVec3=nan*ones(tVec1.shape) > > I cannot do something like: > for i in tV

[Matplotlib-users] precision of drange

2008-06-02 Thread Brian McLaughlin
If I do: t1=datetime.datetime(2008,06,02,01,0,0) t1=datetime.datetime(2008,06,02,02,0,0) tVec1=drange(t1,t2,datetime.timedelta(seconds=1)) tVec2=drange(t1,t2,datetime.timedelta(seconds=5)) tVec3=nan*ones(tVec1.shape) I cannot do something like: for i in tVec2: tVec3[where(tVec1==i)]=i tVec3[0]