Re: [Matplotlib-users] x axis non-uniform labeling (KURT PETERS)
On Mon, Sep 30, 2013 at 4:50 PM, KURT PETERS petersk...@msn.com wrote: That doesn't seem to fix it. What I'm expecting is at the top, 28 should correspond to the value -2. Instead it puts a 30 there. Kurt It's not really clear to me what you're trying to do. But the rounding of the axes limits is an expected behavior of matplotlib. You can set them manually if you like. Also, I think this achieves what you want and is much simpler. import numpy as np import matplotlib.pyplot as plt xdat=np.arange(1,11) simtimedata = np.array([0, 1, 5, 9, 13, 18, 21, 24, 25, 28]) idatanp = np.array([-1,0, 1, 2, 3, 2, 1, 0, -1, -2]) fig, (ax1, ax2) = plt.subplots(nrows=2, sharey=True) ax1.plot(xdat,idatanp) ax2.plot(simtimedata, idatanp,'k--') ax2.set_xlim([simtimedata.min(), simtimedata.max()]) fig.tight_layout() -- October Webinars: Code for Performance Free Intel webinars can help you accelerate application performance. Explore tips for MPI, OpenMP, advanced profiling, and more. Get the most from the latest Intel processors and coprocessors. See abstracts and register http://pubads.g.doubleclick.net/gampad/clk?id=60134791iu=/4140/ostg.clktrk___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] x axis non-uniform labeling (KURT PETERS)
It's not really clear to me what you're trying to do. But the rounding of the axes limits is an expected behavior of matplotlib. You can set them manually if you like. Also, I think this achieves what you want and is much simpler. import numpy as npimport matplotlib.pyplot as pltxdat=np.arange(1,11)simtimedata = np.array([0, 1, 5, 9, 13, 18, 21, 24, 25, 28]) idatanp = np.array([-1,0, 1, 2, 3, 2, 1, 0, -1, -2]) fig, (ax1, ax2) = plt.subplots(nrows=2, sharey=True) ax1.plot(xdat,idatanp)ax2.plot(simtimedata, idatanp,'k--') ax2.set_xlim([simtimedata.min(), simtimedata.max()]) REPLY: here's what SHOULD be happening | 0 1 5 9 13 18 21 24 25 28 3 | x|x x| xx| x x-1|_x__x_ 12 3 4 56 7 8 9 10 How can I make that happen? Instead, MPL is autoranging the top axis. I don't want that I just want the actual labels to occur up there. Kurt -- October Webinars: Code for Performance Free Intel webinars can help you accelerate application performance. Explore tips for MPI, OpenMP, advanced profiling, and more. Get the most from the latest Intel processors and coprocessors. See abstracts and register http://pubads.g.doubleclick.net/gampad/clk?id=60134791iu=/4140/ostg.clktrk___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] x axis non-uniform labeling (KURT PETERS)
2013/10/1 KURT PETERS petersk...@msn.com: here's what SHOULD be happening | 0 1 5 9 13 18 21 24 25 28 3 | x |x x | xx | x x -1|_x__x_ 12 3 4 56 7 8 9 10 How can I make that happen? Instead, MPL is autoranging the top axis. I don't want that I just want the actual labels to occur up there. Then just set the ticks and the tick labels of the axis: import numpy as np import matplotlib.pyplot as plt xdat=np.arange(1,11) simtimedata = np.array([0, 1, 5, 9, 13, 18, 21, 24, 25, 28]) idatanp = np.array([-1,0, 1, 2, 3, 2, 1, 0, -1, -2]) ax1 = plt.subplot(111) ax1.plot(xdat,idatanp) ax2 = ax1.twiny() ax2.set_xticks(range(len(xdat))) ax2.set_xticklabels(simtimedata) plt.show() Goyo -- October Webinars: Code for Performance Free Intel webinars can help you accelerate application performance. Explore tips for MPI, OpenMP, advanced profiling, and more. Get the most from the latest Intel processors and coprocessors. See abstracts and register http://pubads.g.doubleclick.net/gampad/clk?id=60134791iu=/4140/ostg.clktrk ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] x axis non-uniform labeling (KURT PETERS)
Date: Tue, 1 Oct 2013 19:35:39 +0200 Subject: Re: [Matplotlib-users] x axis non-uniform labeling (KURT PETERS) From: goyod...@gmail.com To: petersk...@msn.com CC: pmhob...@gmail.com; matplotlib-users@lists.sourceforge.net 2013/10/1 KURT PETERS petersk...@msn.com: here's what SHOULD be happening | 0 1 5 9 13 18 21 24 25 28 3 | x |x x | xx | x x -1|_x__x_ 12 3 4 56 7 8 9 10 How can I make that happen? Instead, MPL is autoranging the top axis. I don't want that I just want the actual labels to occur up there. Then just set the ticks and the tick labels of the axis: import numpy as np import matplotlib.pyplot as plt xdat=np.arange(1,11) simtimedata = np.array([0, 1, 5, 9, 13, 18, 21, 24, 25, 28]) idatanp = np.array([-1,0, 1, 2, 3, 2, 1, 0, -1, -2]) ax1 = plt.subplot(111) ax1.plot(xdat,idatanp) ax2 = ax1.twiny() ax2.set_xticks(range(len(xdat))) ax2.set_xticklabels(simtimedata) plt.show() Goyo Goyo, Thanks, the code below seems to work. The problem is that with REAL/actual data, I have SO many data points that each point is now labeled and it takes forever to render. And when it does render, I cannot read the axis because there are too many there. Is there a way to judiciously have it only display a certain number of values? Such as every 100th value?Kurtxdat=np.arange(1,11) simtimedata = np.array([0, 1, 5, 9, 13, 18, 21, 24, 25, 28]) idatanp = np.array([-1,0, 1, 2, 3, 2, 1, 0, -1, -2]) print idatanp.shape print simtimedata.shape print xdat.shape fig = plt.figure() ax1 = fig.add_subplot(211) ax1.plot(xdat,idatanp) ax1.grid(True) ax2 = fig.add_subplot(212) ax2.plot(xdat, idatanp.real,'k-o') ax2.set_xticks(xdat) ax2.set_xticklabels(simtimedata) #ax2.set_title(time domain) ax2.grid(True) plt.show()-- October Webinars: Code for Performance Free Intel webinars can help you accelerate application performance. Explore tips for MPI, OpenMP, advanced profiling, and more. Get the most from the latest Intel processors and coprocessors. See abstracts and register http://pubads.g.doubleclick.net/gampad/clk?id=60134791iu=/4140/ostg.clktrk___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] x axis non-uniform labeling (KURT PETERS)
On Oct 1, 2013, at 10:55 AM, KURT PETERS petersk...@msn.com wrote: Goyo, Thanks, the code below seems to work. The problem is that with REAL/actual data, I have SO many data points that each point is now labeled and it takes forever to render. And when it does render, I cannot read the axis because there are too many there. Is there a way to judiciously have it only display a certain number of values? Such as every 100th value? Kurt ax2.set_xticks(xdat) ax2.set_xticklabels(simtimedata) ax2.set_xticks(xdat[::100]) ax2.set_xticklabels(simtimedata[::100]) Cheers, Jody -- Jody Klymak http://web.uvic.ca/~jklymak/ -- October Webinars: Code for Performance Free Intel webinars can help you accelerate application performance. Explore tips for MPI, OpenMP, advanced profiling, and more. Get the most from the latest Intel processors and coprocessors. See abstracts and register http://pubads.g.doubleclick.net/gampad/clk?id=60134791iu=/4140/ostg.clktrk___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] x axis non-uniform labeling (KURT PETERS)
On Oct 1, 2013, at 11:01AM, Jody Klymak wrote: On Oct 1, 2013, at 10:55 AM, KURT PETERS petersk...@msn.com wrote: Goyo, Thanks, the code below seems to work. The problem is that with REAL/actual data, I have SO many data points that each point is now labeled and it takes forever to render. And when it does render, I cannot read the axis because there are too many there. Is there a way to judiciously have it only display a certain number of values? Such as every 100th value? Kurt ax2.set_xticks(xdat) ax2.set_xticklabels(simtimedata) ax2.set_xticks(xdat[::100]) ax2.set_xticklabels(simtimedata[::100]) Cheers, Jody I thought that, too, but then he used the word 'judiciously'. I think that you want to change the xaxis major formatter so that it returns the indexed element of simtimedata as the label. Example to come in a moment. -Sterling -- October Webinars: Code for Performance Free Intel webinars can help you accelerate application performance. Explore tips for MPI, OpenMP, advanced profiling, and more. Get the most from the latest Intel processors and coprocessors. See abstracts and register http://pubads.g.doubleclick.net/gampad/clk?id=60134791iu=/4140/ostg.clktrk ___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] x axis non-uniform labeling (KURT PETERS)
On Tue, Oct 1, 2013 at 1:55 PM, KURT PETERS petersk...@msn.com wrote: Date: Tue, 1 Oct 2013 19:35:39 +0200 Subject: Re: [Matplotlib-users] x axis non-uniform labeling (KURT PETERS) From: goyod...@gmail.com To: petersk...@msn.com CC: pmhob...@gmail.com; matplotlib-users@lists.sourceforge.net 2013/10/1 KURT PETERS petersk...@msn.com: here's what SHOULD be happening | 0 1 5 9 13 18 21 24 25 28 3 | x | x x | x x | x x -1|_x__x_ 1 2 3 4 5 6 7 8 9 10 How can I make that happen? Instead, MPL is autoranging the top axis. I don't want that I just want the actual labels to occur up there. Then just set the ticks and the tick labels of the axis: import numpy as np import matplotlib.pyplot as plt xdat=np.arange(1,11) simtimedata = np.array([0, 1, 5, 9, 13, 18, 21, 24, 25, 28]) idatanp = np.array([-1,0, 1, 2, 3, 2, 1, 0, -1, -2]) ax1 = plt.subplot(111) ax1.plot(xdat,idatanp) ax2 = ax1.twiny() ax2.set_xticks(range(len(xdat))) ax2.set_xticklabels(simtimedata) plt.show() Goyo Goyo, Thanks, the code below seems to work. The problem is that with REAL/actual data, I have SO many data points that each point is now labeled and it takes forever to render. And when it does render, I cannot read the axis because there are too many there. Is there a way to judiciously have it only display a certain number of values? Such as every 100th value? Kurt xdat=np.arange(1,11) simtimedata = np.array([0, 1, 5, 9, 13, 18, 21, 24, 25, 28]) idatanp = np.array([-1,0, 1, 2, 3, 2, 1, 0, -1, -2]) print idatanp.shape print simtimedata.shape print xdat.shape fig = plt.figure() ax1 = fig.add_subplot(211) ax1.plot(xdat,idatanp) ax1.grid(True) ax2 = fig.add_subplot(212) ax2.plot(xdat, idatanp.real,'k-o') ax2.set_xticks(xdat) ax2.set_xticklabels(simtimedata) #ax2.set_title(time domain) ax2.grid(True) plt.show() The philosophy of matplotlib is to have smart defaults, but always allow the user to override. Perhaps you are looking for a particular ticker? http://matplotlib.org/api/ticker_api.html I hope this helps! Ben Root -- October Webinars: Code for Performance Free Intel webinars can help you accelerate application performance. Explore tips for MPI, OpenMP, advanced profiling, and more. Get the most from the latest Intel processors and coprocessors. See abstracts and register http://pubads.g.doubleclick.net/gampad/clk?id=60134791iu=/4140/ostg.clktrk___ Matplotlib-users mailing list Matplotlib-users@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/matplotlib-users
Re: [Matplotlib-users] x axis non-uniform labeling (KURT PETERS)
On Oct 1, 2013, at 8:59AM, KURT PETERS wrote:
REPLY:
here's what SHOULD be happening
| 0 1 5 9 13 18 21 24 25 28
3 | x
|x x
| xx
| x x
-1|_x__x_
12 3 4 56 7 8 9 10
How can I make that happen? Instead, MPL is autoranging the top axis. I
don't want that I just want the actual labels to occur up there.
Kurt
Kurt,
Here is a self-contained example of what I think you are asking for:
{{{
import matplotlib.pyplot as plt
import numpy as np
from matplotlib.ticker import FuncFormatter, MaxNLocator
simtimedata = np.array([0, 1, 5, 9, 13, 18, 21, 24, 25, 28, 31, 32, 41, 55, 56,
57])
idatanp = np.array([-1,0, 1, 2, 3, 2, 1, 0, -1, -2, -3, -2, -1, 0, -1, -2])
xdat = range(len(simtimedata))
fig = plt.figure()
ax1 = fig.add_subplot(211)
ax1.plot(xdat,idatanp)
ax1.grid(True)
ax2 = fig.add_subplot(212)
ax2.plot(xdat, idatanp.real,'k-o')
def index_to_label(i,dummy):
if i = 0 and i len(simtimedata):
return str(simtimedata[i])
else:
return ''
form = FuncFormatter(index_to_label)
ax2.xaxis.set_major_formatter(form)
#ax2.set_title(time domain)
ax2.grid(True)
plt.show()
}}}
You may also be interested in this question and answer on stackoverflow:
http://stackoverflow.com/questions/3918028/how-do-i-plot-multiple-x-or-y-axes-in-matplotlib
-Sterling
--
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Re: [Matplotlib-users] x axis non-uniform labeling (KURT PETERS)
Subject: Re: [Matplotlib-users] x axis non-uniform labeling (KURT PETERS)
From: smit...@fusion.gat.com
Date: Tue, 1 Oct 2013 11:34:39 -0700
CC: pmhob...@gmail.com; matplotlib-users@lists.sourceforge.net
To: petersk...@msn.com
On Oct 1, 2013, at 8:59AM, KURT PETERS wrote:
REPLY:
here's what SHOULD be happening
| 0 1 5 9 13 18 21 24 25 28
3 | x
|x x
| xx
| x x
-1|_x__x_
12 3 4 56 7 8 9 10
How can I make that happen? Instead, MPL is autoranging the top axis. I
don't want that I just want the actual labels to occur up there.
Kurt
Kurt,
Here is a self-contained example of what I think you are asking for:
{{{
import matplotlib.pyplot as plt
import numpy as np
from matplotlib.ticker import FuncFormatter, MaxNLocator
simtimedata = np.array([0, 1, 5, 9, 13, 18, 21, 24, 25, 28, 31, 32, 41, 55,
56, 57])
idatanp = np.array([-1,0, 1, 2, 3, 2, 1, 0, -1, -2, -3, -2, -1, 0, -1, -2])
xdat = range(len(simtimedata))
fig = plt.figure()
ax1 = fig.add_subplot(211)
ax1.plot(xdat,idatanp)
ax1.grid(True)
ax2 = fig.add_subplot(212)
ax2.plot(xdat, idatanp.real,'k-o')
def index_to_label(i,dummy):
if i = 0 and i len(simtimedata):
return str(simtimedata[i])
else:
return ''
form = FuncFormatter(index_to_label)
ax2.xaxis.set_major_formatter(form)
#ax2.set_title(time domain)
ax2.grid(True)
plt.show()
}}}
You may also be interested in this question and answer on stackoverflow:
http://stackoverflow.com/questions/3918028/how-do-i-plot-multiple-x-or-y-axes-in-matplotlib
-Sterling
Thanks Sterling,
That's exactly what I was looking for. I ended up creating a class because I
wasn't comfortable using either a lambda function or simtimedata as a global
variable (just a style issue). In case someone's been following along and
wants the final code:
...
from matplotlib.ticker import Formatter
class MyFormatter(Formatter):
def __init__(self, simtime):
self.simtime = simtime
def __call__(self,val,pos=0):
if val = 0 and val len(self.simtime):
return str(self.simtime[val])
else:
return ''
xdat=np.arange(0,10)
simtimedata = np.array([ 0, 1, 5, 9, 13, 18, 21, 24, 25, 28])
idatanp = np.array([-1,0, 1, 2, 3, 2, 1, 0, -1, -2])
print idatanp.shape
print simtimedata.shape
print xdat.shape
fig = plt.figure()
intformatter = MyFormatter(simtimedata)
ax1 = fig.add_subplot(211)
ax1.plot(xdat,idatanp)
ax1.grid(True)
ax2 = fig.add_subplot(212)
ax2.plot(xdat, idatanp.real,'k-o')
ax2.xaxis.set_major_formatter(intformatter)
ax2.set_title(time domain)
ax2.grid(True)
plt.show()
--
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