,
Paul Ivanov
John Hunter, on 2008-11-23 07:36, wrote:
On Sun, Nov 23, 2008 at 2:01 AM, Paul Ivanov [EMAIL PROTECTED] wrote:
I took a stab at it, how does this look?
I also took the liberty of adding alpha to LinearSegmentedColormap and
updated its docstring changing two somewhat ambiguous
Hi Jesper,
confirming the problem over here, as well. both numpy and mpl from svn
(also on an Ubuntu 8.04 machine).
good luck,
Paul
Jesper Larsen, on 2008-11-27 02:10, wrote:
Hi Eric and Mauro,
Thanks for your answers.
2008/11/27 Eric Firing [EMAIL PROTECTED]:
It looks OK to me with
Try something like this:
from os import sys
from matplotlib import *
from numpy.random import rand
fig= pyplot.figure(figsize=(8,8), dpi=120)
pyplot.show()
while True:
z= rand(20,20)
pyplot.imshow(z)
pyplot.draw()
chr= sys.stdin.read(1)
if chr=='q':
break
appologies - sys.stdin.read(1) blocks until you give it a new line
(Enter) that' s probably what you were having problems with.
Paul Ivanov, on 2009-08-23 01:14, wrote:
Try something like this:
from os import sys
from matplotlib import *
from numpy.random import rand
fig
/blog/2010/06/07/ca-prop/
best,
Paul Ivanov
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left', borderaxespad=0,
bbox_to_anchor=(.85,.85))
thanks in advance,
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Paul Ivanov, on 2010-09-06 18:01, wrote:
I want to have two legends (from different axes) positioned right up
against on another.
Here's a static example, except I want the second legend to be defined
relative to the first (if leg is moved, I want leg2 to move as well). I
can't seem
crashes. Am I missing something?
I'm using 1.0.0 with WXAgg
thanks,
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Alan G Isaac, on 2010-10-28 21:29, wrote:
On 10/27/2010 8:21 PM, Paul Ivanov wrote:
def onelegend_twinaxes(axis,twin):
#make a joint axis legend
lines = twin.get_lines()
lines.extend(axis.get_lines())
labels = [l.get_label() for l in lines
something like
bbox2 = bbox.transformed(l.axes.transAxes.inverted())
bbox2.width,bbox2.height
The bboxes have other handy attributes like p0,p1,x0,x1,y0,y1
etc, as well as methods like bbox.padded(), etc.
best,
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Paul Ivanov
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for your purposes, the code will be something like:
from mpl_toolkits.mplot3d import Axes3D
import matplotlib.pyplot as plt
fig = plt.figure()
ax = fig.add_subplot(111, projection='3d')
ax.scatter(x,y,z)
best,
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to 10.10).
me too, and I kept forgetting to report it.
PS. what's wrong with the sf.net bugzilla? I was not able to post the
issue there --
this I do not know.
best,
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as plt
x,y = rand(2,100)
z = randint(1,6,100)
for i,c,m in zip(range(1,6),'rgbmk', 'odp*s'):
mask = z==i
plt.plot(x[mask],y[mask], color=c, marker=m)
hope that helps,
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instead of bars
plt.step(edges[1:]+10,h) # same as above, with an offset
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solution. For more on
transformations see:
http://matplotlib.sourceforge.net/users/transforms_tutorial.html
And you can wrap my hand-rolled solution nicely using something
like:
http://matplotlib.sourceforge.net/examples/api/line_with_text.html
best,
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Paul Ivanov
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blocking. Can you try starting ipython
-pylab -gthread and ipython -pylab -wthread to see if that fixes
the issue? Make sure that you change the backend accordingly - and use
plt.get_backend() to ensure the appropriate one is being used.
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/pylab_examples/spine_placement_demo.html
best
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Gf B, on 2011-01-04 12:31, wrote:
On Mon, Jan 3, 2011 at 3:53 PM, Paul Ivanov pivanov...@gmail.com wrote:
Gf B, on 2011-01-03 15:23, wrote:
Can such a grid of grids be done with matplotlib? If so, could someone
show me how?
You'll be able to group the inner grids visually
the right thing, let's adjust
the xlim on that original plot.
In [221]: ax2.set_xlim(norm(14),norm(40))
Out[221]: (0.34998, 1.0)
In [222]: plt.draw()
Hope this clears things up,
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the major ticks to be solid lines, and minor ticks
to be dashed. I got all dashed.
In [3]: plt.grid(which='major', linestyle='solid')
In [4]: plt.grid(which='minor', linestyle='dashed')
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)
plt.subplots_adjust(hspace=.7, bottom=.2)
#comment out the next line to see the original (0-40 colormap)
ax1.set_xlim(rawlins_norm((14,40)))
plt.show()
best,
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that helps,
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Gaining the trust of online
, there's just not room left between the
indexes that you're using. Just change your ind assignment line
to this:
ind = np.arange(0, 2*N, 2)
this spaces your indexes out more.
hope that helps,
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from locator to locator,
but you can quickly figure it out in ipython using tab completion
in IPython once you grab a given locator object.
best,
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.
lines = plot_date([2000.10,2000.20,2000.30],[1,2,3])
[l.set_visible(False) for l in lines]
or something like this to toggle visibility on and off
[l.set_visible(not l.get_visible()) for l in lines]
best,
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http
will be placed at the minor tick
locations. That would be a reasonable way to proceed - set the
major ticks to be non-overlapping, and put the minor ones
everywhere else.
You've probably already found it, but just in case:
http://matplotlib.sourceforge.net/api/ticker_api.html
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.
http://matplotlib.sourceforge.net/api/colors_api.html#matplotlib.colors.LogNorm
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/gridspec.html
2.
http://matplotlib.sourceforge.net/mpl_toolkits/axes_grid/index.html#toolkit-axes
best,
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,
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From: Paul Ivanov pivanov...@gmail.com
To: Larry Evans cppljev...@suddenlink.net
Cc:
Bcc:
Subject: Re: [Matplotlib-users] what does numRows, numCols in subplot docs
mean?
Reply-To:
In-Reply-To: 4d32e05d.4090...@suddenlink.net
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Larry Evans
?
Can you try deleting ../site-packages/matplotlib, and the build/
directory for your sources of mpl1.0.1 and reinstall? Please
report back either way so we get a handle on this.
best,
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may want a higher resolution, or to make the figure
# background white
#savefig.dpi : 100 # figure dots per inch
So try playing around with that parameter (which is what you're
doing if you call plt.savefig('name', dpi=300)
best,
--
Paul Ivanov
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a collections attribute which holds the actual lines.
hope that helps,
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,
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Daryl Herzmann, on 2011-01-21 16:41, wrote:
On Fri, Jan 21, 2011 at 4:15 PM, Paul Ivanov pivanov...@gmail.com wrote:
I guess I'm not sure what you meant by the fonts looking 'nasty',
so if font.size doesn't address your issue, could you post a
small example that does the wrong thing
etc for producing images at various scales)
Reply-To:
In-Reply-To: 20110121232036.GA26739@ykcyc
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Paul Ivanov, on 2011-01-21 15:20, wrote:
I'm almost certain that one *can* write a function to do this
pro grammatically (without having
://matplotlib.sourceforge.net/devel/add_new_projection.html
Yet another way would be to re-label the tick lines (e.g. make .6
label be 1.0 and subtract that offset from your two outliers.
best,
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Paul Ivanov, on 2011-01-22 18:28, wrote:
Ilya Shlyakhter, on 2011-01-22 19:06, wrote:
Is it possible to create a break in the y-axis so that it has ticks
for value 0-.2, then ticks for values .8-1.0, but devotes only a token
amount of space to the area 0.2-0.8?
I have a dataset
Eric Firing, on 2011-01-22 17:49, wrote:
Paul Ivanov, on 2011-01-22 18:28, wrote:
Paul,
Your example below is nice, and this question comes up quite often. If
we don't already have a gallery example of this, you might want to add
one. (Probably better to use deterministic fake data
('right')
grid2[0].yaxis.set_label_text('foo')
grid2[1].yaxis.set_label_position('right')
grid2[1].yaxis.set_label_text('bar')
plt.show()
#---
best,
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?
# prevent the automatic rotation caused by view changes
ax.yaxis.set_rotate_label(False)
ax.yaxis.label.set_rotation(45)
Beware that you'll have to adjust that angle on a per-view basis
to get things to look right.
best,
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Paul Ivanov
314 address only used for lists, off-list direct email at:
http
the 'bottom' keyword argument to bar. Note that the
second parameter is height of the bar, *not* the top of the bar
plt.bar([1,2,3,4], [2,2.5,5,3], bottom=[0,-1,1,2])
best,
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=350)
cbar = plt.colorbar()
cbar.ax.set_ylim(cbar.norm((300,350)))
cbar.ax.set_xlim(cbar.norm((300,350))) # maintain aspect ratio
cbar.set_ticks(np.linspace(300,350,6))
# didn't see a quick way to fix the outline
cbar.outline.set_visible(False)
cbar.ax.set_frame_on(True)
plt.draw()
best,
--
Paul
, times-bot, bottom=bot, align='center')
ax.yaxis_date()
fig.autofmt_xdate()
plt.show()
best,
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On the other hand, if you just want the contour to not show up,
you can pass it alpha=0.0 to make it completely transparent and
invisible (but it's still there)
contourset = pyplot.contour(.., alpha=0.0)
# later call contourset.set_alpha(1.0) to make visible again
best,
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314 address
).
Che,
just make a numpy array out of your two lists, and you'll be able
to subtract one from the other.
import numpy as np
top = np.array(top)
bot = np.array(bot)
best,
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, z should be, and then
create a contour using
C = matplotlib.contour._cntr.Cntr(x,y,z)
and then for each level, do something like what
QuadContourSet._get_allsegs_and_allkinds does
C.trace(..)
best,
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=err, color='g',linestyle='None',xuplims=True)
plt.show()
Hi Francesco,
plt.errorbar(x,y, yerr=err, color='g',linestyle='None',xuplims=True)
I'm not sure what you're hoping to see, but you should either use
xerr with xuplims, or yerr with uplims.
best,
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would be to set the ylim after the call to yticks,
like this:
plt.ylim(3.5, -0.5)
best,
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Jeremy Conlin, on 2011-02-01 16:48, wrote:
I'm trying to create a custom colormap used with pcolormesh, but the
results seem inconsistent to me. I want the following colors
-3 x = -2 - Black
-2 x = -1 - Blue
-1 x = 0 - Yellow
0 x = 1 - Green
1 x = inf - Red
-for-tick-labels
best,
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Paul Ivanov, on 2011-02-01 17:14, wrote:
Kris Kuhlman, on 2011-02-01 18:03, wrote:
I am trying to plot a large number of locations that need to be labeled.
Often the locations are quite clustered and the resulting text is
unreadable. I have been looking through the API and examples
From: Paul Ivanov pivanov...@gmail.com
To: Francois Maltey fmal...@nerim.fr
Cc:
cc:
Subject: Re: [Matplotlib-users] Is it possible to plot axes with arrows ?
Reply-To:
In-Reply-To: 4d496f84.7070...@nerim.fr
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Francois Maltey, on 2011-02-02
)
#shown_lab[-1].set_visible(False)
plt.show()
best,
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, .set_linewidth
To hide the tickmarks that are right next to the spines, you can
do:
ax1.xaxis.tick_bottom()
ax1.yaxis.tick_left()
and finally, to color the ticks in red as well, do:
ax1.tick_params(color='red')
best,
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with step's where parameter for
slightly different behavior of where the transition between the
steps occurs.
best,
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there are python2.7 64 bit version for OS X at this time)
more on how to do that in the comments of the top reply here:
http://stackoverflow.com/questions/3606964/no-matching-architecture-in-universal-wrapper-problem-in-wxpython
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participants,
etc. Our collective involvement in whatever capacity is what
makes projects like matplotlib thrive!
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The ultimate all-in-one performance toolkit: Intel
that.
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ax.figure.canvas.mpl_disconnect(%d) %cid
print #run the line above to 'flatline' (stop heartbeat)
plt.show()
best,
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]),
a list of 20 Patch objects)
In [11]: ax.hist(a) # the default bins=10
(array([4, 2, 3, 1, 0, 2, 1, 2, 0, 5]),
array([ 0. , 1.9, 3.8, 5.7, 7.6, 9.5, 11.4, 13.3,
15.2,
17.1, 19. ]),
a list of 10 Patch objects)
best,
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, there is no need to send duplicates of
mailing list questions directly to me.
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= mpl.ticker.FuncFormatter(lambda x,pos: %.2f%np.exp(x))
ax2.yaxis.set_major_formatter(fmtr)
plt.draw()
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# pyplot (matlab-like) interface
plt.errorbar?
As Daniel pointed out, the question mark will pull up the
docstring if you're using IPython, but if you aren't, you
can always call python's help.
help(plt.errorbar)
which will print the docstring for you.
hope that helps,
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], which
I believe were addressed in [3], and are waiting to be merged.
1. https://github.com/ipython/ipython/issues/#issue/202
2. https://github.com/ipython/ipython/issues/#issue/185
3. https://github.com/ipython/ipython/pull/237
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run into building
matplotlib for your 64-bit python.
best,
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, the line chart's y-axis on the
left. Can this be controlled?
ax1.yaxis.tick_right()
ax2.yaxis.tick_left()
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have an even number of subplot figures so the
grid is filled and this situation does not occur.
Hi Jim,
how's this:
import matplotlib.pyplot as plt
from mpl_toolkits.axes_grid1 import AxesGrid
ag = AxesGrid(plt.figure(),(0,0,1,1),(2,3))
ag.axes_all[-1].set_visible(False)
best,
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.
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, on 2011-03-01 12:58, wrote:
Paul Ivanov pivanov...@gmail.com writes:
You can do this with:
ax = plt.subplot(111)
ax.plot(range(10))
ax.set_ymargin(.2)
ax.set_xmargin(.1)
# or ax.margins(.1,.2)
ax.autoscale()
plt.draw()
see also the docstring for ax.autoscale_view for more
with
newlines
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be to make a polar subplot and transform your
rectangular data to polar coordinates for the purposes of
plotting (rather than transforming the grid to polar). This way
you'll get your clipping for free.
best,
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http
rcParam to affect all plots. You might also play
with using different fontsize parameters when calling .text(...)
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= ...' line inside the for-loop, and you'll
be all set.
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in enumerate(labels):
x_loc = data1[i]
y_loc = data2[i]
txt = ax.annotate(label, xy=(x_loc, y_loc), size=8,
xytext=(-10, 10), textcoords='offset points',
arrowprops=None)
plt.axis('equal')
plt.show()
best,
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= np.random.rand(npts)
d = np.random.rand(npts)
plt.scatter(a,b,c=c,s=c*100, marker='o')
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)
plt.xlim(0,30)
# for the next line to work in ipython you'll need to
# paste/or cpaste this entire script, or just pause before
# changing the xlim again to verify that it works as intended
raw_input(press return for to rescale)
plt.xlim(0,55)
best,
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in January, 2011 at [1] or [2]:
1. http://old.nabble.com/How-to-make-a-grid-of-%28plot%29-grids--td30581281.html
2.
http://www.mail-archive.com/matplotlib-users@lists.sourceforge.net/msg19710.html
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in
progress, what's been completed, and what's left to do here:
https://github.com/matplotlib/matplotlib-py3/wiki
(Also, this is more of a matplotlib-users question, so I'm replying
to that list)
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just that these tests
weren't running before.
Any developers want to chime in on this?
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Paul Ivanov
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Michael Droettboom, on 2010-07-27 11:19, wrote:
Hmm... surprisingly, I am actually able to reproduce this sort of=20
behaviour here
that these tests
weren't running before.
Any developers want to chime in on this?
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Paul Ivanov
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Michael Droettboom, on 2010-07-27 11:19, wrote:
Hmm... surprisingly, I am actually able to reproduce this sort of
behaviour here. I'll
or slider of the zipper (since it's at the top, you'll be
pulling it down, or unzipping): see
http://docs.python.org/library/functions.html#zip
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Paul Ivanov
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():
ax.spines['left'].set_visible(True)
if ax.is_last_col():
ax.spines['right'].set_visible(True)
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Paul Ivanov
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,
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Paul Ivanov
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Xperia(TM) PLAY
It's a major breakthrough
, we'd be able to much more definitively track down the
problem and find a solution.
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Paul Ivanov
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matplotlib more consistent.
best,
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Paul Ivanov
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Xperia(TM) PLAY
It's
that functionality.
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Paul Ivanov
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Xperia(TM) PLAY
It's a major
? what is the error
message?
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Paul Ivanov
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Forrester
in one dimension,
something like twinx() or twiny() would work to create new axes
on top of another one, sharing the one of the dimension, while
being independent in the other.
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Paul Ivanov
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you'll have.
len(set(zip(n_x,n_y))) will tell you how many points you should
see.
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Paul Ivanov
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do:
figure.subplotpars.right=.8 # make smaller if still crashes
or if it's an option, use gtkagg, which doesn't suffer from the crash.
from matplotlib.backends.backend_gtkagg import FigureCanvasGTKAgg
as FigureCanvasGTK
best,
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Paul Ivanov
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Jason Heeris, on 2011-04-23 00:29, wrote:
On 22 April 2011 03:56, Paul Ivanov pivanov...@gmail.com wrote:
Thanks for the report, Jason. It's a bug - could you please file
a bug report, so we can keep track of it?
Will do, thanks for the workarounds :)
or if it's an option, use gtkagg
()
ax.add_artist(r)
plt.draw()
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Paul Ivanov
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Fulfilling the Lean
to you).A
best,
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Paul Ivanov
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All of the data generated
, but is this an application that you built and
compiled? Is recompiling matplotlib an option?
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Paul Ivanov
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://matplotlib.sourceforge.net/examples/pylab_examples/contour_image.html
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Paul Ivanov
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instead of subplot(211) you use
plt.axes(...) to create them (I guess there may be a nicer
method, not sure).
I belive the plt.subplots() command is what Sebastian was
referring to.
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Paul Ivanov
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/matplotlib/matplotlib-0.98.5/matplotlib-0.98.5.3.tar.gz
The error which causes both to fail is:
Hi Bogdan,
are you specifically trying to install that old version of
matplotlib? If not, add the -U flag to easy_install to try to
grab a newer version
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Paul Ivanov
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in the figure.
best,
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Paul Ivanov
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