Re: [Matplotlib-users] passing multiple path arguments to make_compound_path

2014-11-27 Thread Francesco Montesano
Hi,

put all them into a list

ps = [p1, p2, ..., pn]

and then unpack them

path.Path.make_compound_path(*ps)

Cheers,

Fra

ps: this is standard python unpacking


2014-11-27 18:12 GMT+01:00 Evan Mason evanma...@gmail.com:

 Hi, I have several path objects that I want to join together with
 make_compound_path.

 For example, with p1 and p2:

 In [136]: p1
 Out[136]:
 Path(array([[-29.85721973, -30.],
[-29.84752676, -29.77715877],
[-29.88734508, -29.55431755],
[-29.97470553, -29.33147632],
[-30., -29.28831083]]), None)

 In [138]: p2
 Out[138]:
 Path(array([[-30.,  45.166 ],
[-29.94756898,  45.09749304],
[-29.87227011,  45.32033426],
[-29.84525888,  45.54317549],
[-29.86787108,  45.76601671],
[-29.93898847,  45.98885794],
[-30.,  46.10595725]]), None)

 I can do path.Path.make_compound_path(p1, p2) which joins them
 successfully.
 If I have a another path, p3, I can do:
 path.Path.make_compound_path(p1, p2,p3), and so on.

 However, in my script I never know how many paths I will have, so I'd like
  to put them into some sort of container, and pass that to
  make_compound_path.  I've tried lists:


 In [140]: p1p2 = [p1, p2]

 In [141]: path.Path.make_compound_path(p1p2)
 ---
 AttributeErrorTraceback (most recent call last)
 ipython-input-141-eb62de9fcada in module()
  1 path.Path.make_compound_path(p1p2)

 /usr/lib64/python2.7/site-packages/matplotlib-1.4.2-py2.7-linux-x86_64.egg
 /matplotlib/path.py
 in make_compound_path(cls, *args)
 330 total_length = sum(lengths)
 331
 -- 332 vertices = np.vstack([x.vertices for x in args])
 333 vertices.reshape((total_length, 2))
 334

 AttributeError: 'list' object has no attribute 'vertices'


 without success.  Can anybody suggest a way to do this?

 Thanks, Evan



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Re: [Matplotlib-users] Defaults?

2014-11-07 Thread Francesco Montesano
Hi Sebastian,

If you want to set the defaults only once and use them forever, there is
the matplotlibrc file (http://matplotlib.org/users/customizing.html)

If you want to easily change the defaults according to the context of the
plot mpltools by Tony S. Yu can help you (
https://github.com/tonysyu/mpltools)

Cheers,
Fra

2014-11-07 16:15 GMT+01:00 Sebastian Berg sebast...@sipsolutions.net:

 Hey,

 just something I was wondering about today. I commonly want to change
 certain things about my plots. For example I like a serif/larger fonts,
 and everyone knows that jet is an awful default colour map almost
 always...

 It could be neat to have some more default rc's or so that can be
 loaded easily. I mean I could just create one for myself, but having
 some examples of what can be done and being able to switch that could be
 neat. Such as some defaults that are better for printing, maybe in
 matplotlib or really just on a website which shows some example plot for
 uploaded RCs.

 Anyway, just rambling :), I am not planning to really think about it
 much. And maybe some things even exist and I am not aware of it.

 Regards,

 Sebastian


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Re: [Matplotlib-users] a possible bug report

2014-06-12 Thread Francesco Montesano
Hi Michael,

I don't have an answer about your bug. But the official place to report
possible bugs is github.
https://github.com/matplotlib/matplotlib/issues?state=open

Cheers,
Fra



2014-06-12 18:07 GMT+02:00 M.Rule mrule7...@gmail.com:

 Hi all,

 I haven't been able to find a more official place to report potential
 Matplotlib bugs, so I'm going to describe the issue I'm seeing here. Sorry
 if this is the wrong forum.

 On my system, it takes matplotlib a very very long time to close plots.
 Sometimes, up to 20 minutes to close a simple figure. Creating new figures
 remains fast. The problem seems to occur only when I've loaded a large
 amount of data in to python ( on the order of 1GB ). I am using the current
 version of Ubuntu and running ipython --pylab. To reproduce on my system,
 it is sufficient to load a large amount of data, create a plot.. any plot,
 and then try to close it using the little x at the top right corner of
 the window. The whole session will freeze for an extended period of time.
 The plot does not have to be complex: a hundred datapoints, a thousand, it
 makes no difference. Since the problem only occurs when a large amount of
 data has been loaded, my guess is that there is a problem with how
 Matplotlib/Pylab/Python is trying to free the memory associated with the
 figure?

 So... I just though I'd put this out there in case anyone else sees the
 same issue, or in case a developer who knows why this might be happening
 reads this. The workaround for me is... to simply wait for the figures to
 close, however long that may take, or restart the whole session.

 Best,
 michael.


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Re: [Matplotlib-users] video without black bands

2014-03-13 Thread Francesco Montesano
Dear Diego,


2014-03-13 14:49 GMT+01:00 diedro diego.aves...@gmail.com:

 Dear B.,
 thanks a lot for your replay. I get it.
 What do you think is the measure for w and h. Is the unit of measure
 in pixels?.

yes


 What does fps stand for?

frames per second


Cheers,
Francesco


 Thanks a lot

 Diego



 On 12 March 2014 16:05, Benjamin Root-2 [via matplotlib] [hidden 
 email]http://user/SendEmail.jtp?type=nodenode=43059i=0
  wrote:

 In your options to mencoder, you are specifying the width/height as:

  'type=png:w=9800:h=600:fps=0.6',

 But your PNGs have size of 704x538 pixels. That's why you have black bars
 on either side of your animation.

 Cheers!
 Ben Root



 On Wed, Mar 12, 2014 at 7:16 AM, diedro [hidden 
 email]http://user/SendEmail.jtp?type=nodenode=43050i=0
  wrote:

 sorry for that,
 I supposed that I was not more in the the first mailing list. When I
 post the second one, I realized that I was still in the mailing list

 Regarding the post:
 Image Type: png (The PNG image format)
 Width: 704 pixels
 Height: 538 pixels

 Thanks a lot

 Diego



 On 12 March 2014 12:10, Oliver [via matplotlib] [hidden 
 email]http://user/SendEmail.jtp?type=nodenode=43047i=0
  wrote:

 Please don't double post. Also, this post is much more informative than
 the first, it's much clearer now where the problem is, and it is not
 related to matplotlib at all, but with the options you're passing to
 *mencoder*.

 What's the size of your orginal pngs?



 2014-03-12 11:58 GMT+01:00 diedro [hidden 
 email]http://user/SendEmail.jtp?type=nodenode=43046i=0
 :

 Dear all,
 I have created a video from *.png files. The problem is that my video
 has
 black bands on the left and on the right. I have used the following
 commands:

 command = ('mencoder',
'mf://*.png',
'-mf',
'type=png:w=9800:h=600:fps=0.6',
'-ovc',
'lavc',
'-lavcopts',
'vcodec=mpeg4',
'-oac',
'copy',
'-o',
'output.avi')

 How could I create a video without the black bands.

 Thank you all,



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Re: [Matplotlib-users] savefig - legend only

2014-01-31 Thread Francesco Montesano
Hi Peter,

just get the legend handlers and labels with

handles,labels = ax.get_legend_handles_labels()

then create an empty plot with axes `axe` and do

axe.legend(handles, labels, loc=loc)

If you want to hide the axis:

axe.xaxis.set_visible(False)
axe.yaxis.set_visible(False)

and/or

for v in axe.spines.values():
v.set_visible(False)

Enjoy,

Fra


2014-01-31 Peter Van Wieren p...@sbcglobal.net


 I would like to ask if there is a way to print only the legend box of a
 figure.

 The motiviation for wanting to do this is a work around to the problem of
 having the legend box obscuring data without resorting to outside
 placement of the legend.   The idea here is that matplotlib would provide
 two images:

 1. PNG file of figure without legend.
 2. PNG file of legend only.

 The end user would import both images into another tool (e.g. microsoft
 power point) and arrange figure and legend interactively for the final
 product.

 Example follows:

 import numpy as np
 import matplotlib.pyplot as plt

 x = np.linspace(0, 1)
 fig, (ax)  = plt.subplots(nrows=1)
 ax.plot( x , np.sin(2*np.pi*x) , label='Curve1')
 ax.plot( x , np.sin(2*np.pi*x+0.2) , label='Curve2')
 ax.set_title('Set default color cycle to rgby')
 plt.savefig('without_legend.png',dpi=75)

 if True: # Difficult to automatically make a location choice robust
   ax.legend(loc='upper left') # in this particular case, a poor choice for
 placement
 else:
   ax.legend(loc='upper right') # in this particular case, a good choice
 for placement

 plt.savefig('with_legend.png',dpi=75)

 # worst case solution could be post processing these files with imagemagick
 #   begin with composite without_legend.png with_legend.png -compose
 difference alpha_channel.png
 #... then filter with alpha_channel.png against with_legend.png
 #... finally crop this to get legend_only.png



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Re: [Matplotlib-users] how do I set the order of layers?

2013-08-24 Thread Francesco Montesano
use the zorder keyword. higher zorder stay above lower values.

cheers
Francesco
Il giorno 24/ago/2013 11:27, vwf v...@vulkor.net ha scritto:

 Hello,

 In the attached example I would like to have the wedges under the
 arrows. Can someone tell me how do this? I tried to follow the tutorial
 from http://matplotlib.org/users/artists.html  but I didn't really get
 it all.

 Thank you


 from pylab import *
 from numpy import ma
 import math
 import matplotlib.pyplot as plt
 from matplotlib.patches import Wedge

 X,Y = meshgrid( arange(0,2*pi,1),arange(0,2*pi,1) )
 U = cos(X)
 V = sin(Y)

 def draw_w(x, y, p1, v, ax=None, **kwargs):
 if ax is None:
 ax = plt.gca()
 p1*=180/math.pi
 t1= (p1-v)
 t2= (p1+v)
 c=(x,y)
 radius=0.5
 w1 = Wedge(c, radius, t1, t2, fc='0.0', ec='None', alpha=1.0, **kwargs)
 ax.add_artist(w1)

 fig, ax = plt.subplots()
 Q = plt.quiver( U, V, color='LightSalmon', edgecolors='LightSalmon')
 (a,b)=shape(X)
 for i in range(a):
 for j in range(b):
 draw_w(X[i,j],Y[i,j],X[i,j], 25, ax=ax)
 plt.show()



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Re: [Matplotlib-users] Individual custom markers and colorbar

2013-04-26 Thread Francesco Montesano
Il giorno 26/apr/2013 13:16, Hackstein news.hackst...@gmx.net ha
scritto:

 Thanks, Ryan, this is (amost) exactly what I was looking  for. Now, I get
the markers and their colors right, but I still have two problems:
 The markers have a black edges, that I cannot get rid of. I've tried

 rect = Rectangle(..., ec=None)

 and also

 col.set=edgecolor(None)

I think that you have to use the string 'none' instead of None type. The
latter is used to use the default value for the variable (in you case
black).

cheers
Francesco

 and 'None', respectively, both with no effect whatsoever.

 The second problem is, that I cannot get the colorbar to work.
 I tried

 sc = ax.add_collection(col)
 plt.colorbar(sc)

 and

 plt.colobar(col)

 both do not work.
 Any Ideas how to fix those two issues?

 Thanks,

 -Hackstein


  Message: 4
  Date: Thu, 25 Apr 2013 19:44:23 -0400
  From: Ryan Nelson rnelsonc...@gmail.com
  Subject: Re: [Matplotlib-users] Individual custom markers and colorbar
  To: matplotlib-users@lists.sourceforge.net
  Message-ID: 5179bfd7.7060...@gmail.com
  Content-Type: text/plain; charset=iso-8859-1
 
  Hackstein,
 
  Unfortunately, I'm not sure of an 'elegant' way to do what your asking
  with a single call to scatter. Others may know a better way. However,
  you can use rectangle patches and patch collections. (Requires a bit
  more code than scatter but is ultimately more flexible.)
 
  I think the example below does what you need, but with random numbers.
 
  Hope it helps a little.
 
  Ryan
 
  ###
  import numpy as np
  import matplotlib.pyplot as plt
  from matplotlib.patches import Rectangle
  from matplotlib.collections import PatchCollection
 
  n = 100
 
  # Get your xy data points, which are the centers of the rectangles.
  xy = np.random.rand(n,2)
 
  # Set a fixed height
  height = 0.02
  # The variable widths of the rectangles
  widths = np.random.rand(n)*0.1
 
  # Get a color map and color values (normalized between 0 and 1)
  cmap = plt.cm.jet
  colors = np.random.rand(n)
 
  rects = []
  for p, w, c in zip(xy, widths, colors):
  xpos = p[0] - w/2 # The x position will be half the width from the
  center
  ypos = p[1] - height/2 # same for the y position, but with height
  rect = Rectangle( (xpos, ypos), w, height ) # Create a rectangle
  rects.append(rect) # Add the rectangle patch to our list
 
  # Create a collection from the rectangles
  col = PatchCollection(rects)
  # set the alpha for all rectangles
  col.set_alpha(0.3)
  # Set the colors using the colormap
  col.set_facecolor( cmap(colors) )
 
  # Make a figure and add the collection to the axis.
  ax = plt.subplot(111)
  ax.add_collection(col)
  plt.show()
 
  ###
 
 
  On 4/24/2013 5:35 PM, Hackstein wrote:
 
  Hi all,
 
  I am trying to get a scatter plot using a colormap. Additionally, I
  need to define every marker for every data point individually -- each
  being a rectangle with fixed height but varying width as a function of
  the y-value. X and y being the data coordinates, z being a number to
  be color coded with the colormap.
 
  Ideally, I would like to create a list of width and height values for
  each data point and tell the scatter plot to use those.
 
  So far I got colormapped data with custom markers (simplified):
 
  [code]
 
  import numpy as np
 
  import matplotlib.pyplot as plt
 
  from pylab import *
 
  x = y = [1,2,3,4,5]
 
  z = [2,4,6,8,10]
 
  colors = cm.gnuplot2
 
  verts_vec = list(zip([-10.,10.,10.,-10.],[-5.,-5.,5.,5.]))
 
  fig = plt.figure(1, figsize=(14.40, 9.00))
 
  ax = fig.add_subplot(1,1,1)
 
  sc = ax.scatter(x, y, c=np.asarray(z), marker=None, edgecolor='None',
  verts=verts_vec, cmap=colors, alpha=1.)
 
  plt.colorbar(sc, orientation='horizontal')
 
  plt.savefig('test.png', dpi=200)
 
  plt.close(1)
 
  [/code]
 
  But I need to define a marker size for each point, and I also need to
  do that in axis scale values, not in points.
 
  I imagine giving verts a list of N*2 tuples instead of 2 tuples, N
  being len(x), to define N individual markers.
 
  But when doing that I get the error that vertices.ndim==2.
 
  A less elegant way would be to plot every data point in an individual
  scatter plot function, using a for-loop iterating over all data
  points. Then, however, I see no way to apply a colormap and colorbar.
 
  What is the best way to accomplish that then?
 
  Thanks,
 
  -Hackstein
 
 
 
 
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Re: [Matplotlib-users] Trying to migrate to Python 3.2, Matplotlib 1.2.1

2013-04-19 Thread Francesco Montesano
Hi John,

on Kubuntu Precise the standard repo has at least:

python3-pyqt4
python3-pyside
python3-tk

The first two should enable Qt4Agg backend, the last TkAgg

Fra


2013/4/19 Sterling Smith smit...@fusion.gat.com

 I have used the TkAgg backend in python2, installing the dependencies by
 hand.  Is this backend not available for python3?

 -Sterling

 On Apr 18, 2013, at 8:03PM, John Ladasky wrote:

  Thanks to both Francesco Montesano and Benjamin Root.  I have done some
  reading.  And I have made some progress, though I am not quite where I
  want to be yet.
 
  So the problem appears to be that the only backend for which I had
  suitable Python 3 libraries was agg.  It only requires libpng, which I
  have.  I can render a Matplotlib canvas, but it appears that the only
  output that agg offers is in the form of PNG files to disk.  I cannot
  create a live window on the screen.
 
  Reading more, I realize that the way I was getting GUI output previously
  (with Python 2.7 and Matplotlib 1.1) was through wxPython.
  Unfortunately, it appears that wxPython's star is fading, and a Python
  3-compatible version will not be written.  In fact, wxPython hasn't
  released a new version in nine months.
 
  The other choices for Matplotlib GUI output on Linux appear to be
  through GTK, PySide, and PyQt.  I am not familiar with GTK, but I know
  that it is widely-used.  Also, GTK appears to be Python 3-compatible,
  and so that is where I need to go.
 
  I'm going through a trial and error process.  Unfortunately, the names
  of the repositories in Ubuntu are not very helpful.  I installed a few
  GTK and python-gtk related packages that I thought were relevant.  On my
  first build attempt I got no errors, but also, I didn't get a GTKAgg
  backend.  Upon re-reading, I saw that I should modify matplotlib's
  setup.cfg file to force a GTK build attempt, and to report errors if it
  fails. That's what it does.  In the optional backend dependencies
  section I am not seeing any GTK libraries listed, even though I have
  installed python-gtk2-dev (2.24.0), python-gobject-2-dev (2.28.6),
  libgtk2.0-dev (2.24.10), libglib2.0-dev (2.32.3), python-gi-dev (3.2.2),
  python-gobject-dev (3.2.2), python3-gi (3.2.2), and a few DOZEN packages
  on which these depend.
 
  If anyone knows the way forward from here, I would appreciate your
  advice.  Thanks again.
 
 
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Re: [Matplotlib-users] zig-zag to represent suppressed 0 on axis?

2013-04-08 Thread Francesco Montesano
Il giorno 08/apr/2013 21:05, Kevin Hunter Kesling kmhun...@ncsu.edu ha
scritto:

 At 4:20pm -0400 Sun, 07 Apr 2013, Francesco Montesano wrote:

 Il giorno 07/apr/2013 21:03, Kevin Hunter Kesling ha scritto:

 On the other hand, I'm still such a noob at Matplotlib ... is there
 a way to have one of the subplots take up more than its default 50%
 allotment?


 you can give a look at the last two plots in this example
 http://matplotlib.org/examples/pylab_examples/demo_tight_layout.html or
use
 plot.axes providing the rectangle that you want


 That is closer to what I want, but still not there.  I was finally able
to find something that fit the bill to 95% of what I want:


http://matplotlib.1069221.n5.nabble.com/Proposal-for-Broken-Axes-td38050.html

 The first post by 'klukas' does exactly what I asked for.  It's a zig-zag
on the Y-axis to show that what is graphed is not continuous, and unlike
the various official examples, the zig-zag placement is user-specifiable,
as opposed to exactly halfway between the top and bottom.

 The only thing I have yet to figure out how to do is to simultaneously
have a zig-zag on the X axis as well -- an artifact of how these zig-zags
must be created via multiple axes on the same figure, rather than as built
in to the axis artist.

 For googleability:

 The above linked graph code enables for matplotlib:

  - suppressed zeros on the Y-axis of an XY plot
  - showing suppressed data on the Y-axis
  - lightning bolt symbol on the Y-axis
  - zig-zag on the Y-axis
  - a broken Y-axis

 Thanks for your pointers, Francesco, as they helped me to fine-tune my
Google search terms.  And thank you, Klukas, whoever you are.


I'm half that you found the solution for your problem and to have been
useful just providing links. This has been one of the easiest answer I have
ever given :)

And mostly thanks for sharing your findings.

cheers and good night,
Fra

 Cheers,

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Re: [Matplotlib-users] zig-zag to represent suppressed 0 on axis?

2013-04-07 Thread Francesco Montesano
2013/4/7 Kevin Hunter Kesling kmhun...@ncsu.edu

 Hullo Matplotlib List,

 I'm looking for a way to represent on an X-Y graph the fact that an axis
 does not start from the origin.  When drawing by hand, I'll use a little
 zig-zag, lightning bolt, or slight space on the axis in question to
 represent this fact, just off from where the X and Y axis lines meet.
 How would I go about telling Matplotlib to do this?  After two hours of
 perusing the Axes documentation, and tooling around in an IPython shell,
 I appear to be striking out.

 If you are using a monospaced font to view this email, this may
 illustrate the functionality for which I'm looking:


   150 ||  * *
   145 ||  *  *
   140 || **
   135 || *
   130 ||
   /
/   zig zag I want
   ||
 0   
0   1   2   3   4   5   6   7   8


 Many thanks for any help,

 Kevin


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Hi Kevin,

Have you given a look at this example:
http://matplotlib.org/examples/pylab_examples/broken_axis.html

Francesco
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Re: [Matplotlib-users] real time plotting

2013-03-11 Thread Francesco Montesano
Dear Neal,

2013/3/11 Neal Becker ndbeck...@gmail.com

 I want to update a plot in real time.  I did some goog search, and saw
 various
 answers.  Trouble is, they aren't working.

 Here's a typical example:

 import matplotlib.pyplot as plt
 import numpy as np
 fig=plt.figure()
 plt.axis([0,1000,0,1])

 i=0
 x=list()
 y=list()

 while i 1000:
 temp_y=np.random.random()
 x.append(i)
 y.append(temp_y)
 plt.scatter(i,temp_y)
 i+=1
 plt.draw()

 If I run this, it draws nothing.

 This is my matplotlibrc:
 backend : Qt4Agg
 mathtext.fontset: stix


do you use interactive mode? (plt.ion() before creating the figure)
Francesco








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Re: [Matplotlib-users] Newbie help with subplots

2013-02-01 Thread Francesco Montesano
2013/2/1 Benjamin Root ben.r...@ou.edu



 On Fri, Feb 1, 2013 at 11:04 AM, Jeff Layton layto...@att.net wrote:

 Good morning,

 I'm been using matplotlib for a while but it's always been very
 simple plots (hey - I'm a simple person). I have a need for some
 fancier plots using subplots.

 I want to have 3 charts one above the other with a single set of
 x-axis labels on the bottom subplot that works for all three charts.
 I'd also like to put a legend outside the set of three charts - either
 to the top right or horizontally along the bottom.

 I've been reading a number of links and nothing really works.
 Most everything is around pylab and I'm using just straight
 matploblib. I hate to say it, but I need to have the solution and
 I'm looking for some newbie help. One of the frustrating aspects
 is I need to make sure it works for version 0.91 :(

 I'm attaching a simple example script that shows the plots
 as I currently have achieved them. Apologies for any bad coding.
 Just in case the attachment doesn't make it through the code is
 below.

 Thanks!

 Jeff



 I don't know when it was introduced, but ax.label_outer() (called on each
 axes object) can help you with the axis labeling.  If that works, we can
 then tackle legend placement.


if it does not work should be possible to do for ax1 and ax2

[t.set_visible(False) for t in ax.get_xticklabels()]

Francesco



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[Matplotlib-users] subplots: common x and y labels

2012-11-13 Thread Francesco Montesano
Dear matplolibers,

when dealing with multi-axes plot sometimes would be nice to use
figure-wide x and y labels.
On the web I've found some suggestion on how to do this, but I found
no solution valid in the general case and that integrate in the
matplotlib ecosystem.
The ideal would be to have a set_xlabel and set_ylabel method in the
Figure class, with the same api of the corresponding Axes methods.

As a proof of concept I've written a class derived from Figure , which
implements the two methods simply adding a horizontal (vertical) text below
(left of) the lowest (leftmost) axes.
The class together with a short example is attached.
I'm aware that the current implementation is really poor (no integration
with tight_layout, the padding must be adjusted by hand, a problem in
particular for the y label).

The best is to use self.xaxis.set_label_text(xlabel, fontdict, **kwargs)
as in the Axis set_xlabel (as I gather this create a label that is rendered
in the correct position accounting for ticklabels, ticks, tight_layout,
etc). To do this one would have to create:

   - a figure-wide invisible axes that encloses all the other
   axes/subplots, and whose dimension has to be updated every time a new
   axis/subplot is added (this should be easily done) with only the label
   visible. This could also allow to use axis features, like twin axis.
   - just the required axis (invisible) that hosts the labels. I think that
   this approach is less demanding computationally, but I don't know how much
   sense have two axis not attached to axes.

Any suggestions/hints on how to implement these methods in a better way is
very welcome.

If there is no opposition, later in the day I'll submit PR on github with
the two new method and see if we can get something out of this idea.

Cheers,
Francesco


test_set_label_fig.py
Description: Binary data
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[Matplotlib-users] default backend on 1.2.0rc1 and master

2012-10-17 Thread Francesco Montesano
Dear list,

I've see a difference between the default backend between

v1.1.1 (shipped with kubuntu 12.10dev) and v1.2.0.rc1, 1.2.0rc2 and master
(1.3.x).


My set up is to call ipython with pylab and turn on interactive mode. I
still haven't copied over my matplotlibrc file from my work computer (there
I use qtagg, if I remember well)


On v1.1.1 the default is [backend: TkAgg], while in the other two cases it
is  [backend: agg]. Is there some reason for this difference?


cheers,

Francesco
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Re: [Matplotlib-users] default backend on 1.2.0rc1 and master

2012-10-17 Thread Francesco Montesano
2012/10/17 Eric Firing efir...@hawaii.edu

 On 2012/10/16 9:22 PM, Francesco Montesano wrote:
  Dear list,
 
  I've see a difference between the default backend between
 
  v1.1.1 (shipped with kubuntu 12.10dev) and v1.2.0.rc1, 1.2.0rc2 and
  master (1.3.x).
 
 
  My set up is to call ipython with pylab and turn on interactive mode. I
  still haven't copied over my matplotlibrc file from my work computer
  (there I use qtagg, if I remember well)
 
 
  On v1.1.1 the default is [backend: TkAgg], while in the other two cases
  it is  [backend: agg]. Is there some reason for this difference?

 The default should be based on what is found when mpl is built, so it
 sounds like when you are building v1.2.x, none of the supported gui
 toolkits is being found.  I don't know why that is.  Are you installing
 on a system that has gui toolkits already installed?

I think so, as the v1.1.1 shipped with my OS is using TkAgg as backend and
I can plot interactively.

When I build from source I get
OPTIONAL BACKEND DEPENDENCIES
libpng: found, but unknown version (no pkg-config)
   Tkinter: no
* Using default library and include directories for
* Tcl and Tk because a Tk window failed to open.
* You may need to define DISPLAY for Tk to work so
* that setup can determine where your libraries are
* located. Tkinter present, but header files are not
* found. You may need to install development
* packages.
* You may need to install 'dev' package(s) to
* provide header files.
  Gtk+: no
* Could not find Gtk+ headers in any of
* '/usr/local/include', '/usr/include',
* '/usr/local/include', '/usr/include', '.'
   Mac OS X native: no
Qt: no
   Qt4: Qt: 4.8.2, PyQt4: 4.9.3
PySide: no
 Cairo: 1.8.8

Could be a problem with Tkinter and dev packages.




 One useful
 technique with ubuntu derivatives is to do

sudo apt-get build-dep python-matplotlib

 probably it's easier if I just switch to qtagg, as I already have it


 It might pull in more than you really want, but it will certainly
 include gui toolkits.

 Eric

Thanks,
Francesco



 
 
  cheers,
 
  Francesco
 
 
 
 
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Re: [Matplotlib-users] default backend on 1.2.0rc1 and master

2012-10-17 Thread Francesco Montesano
2012/10/17 Damon McDougall damon.mcdoug...@gmail.com

 On Wed, Oct 17, 2012 at 9:12 AM, Francesco Montesano
 franz.berges...@gmail.com wrote:
 
 
  2012/10/17 Eric Firing efir...@hawaii.edu
 
  On 2012/10/16 9:22 PM, Francesco Montesano wrote:
   Dear list,
  
   I've see a difference between the default backend between
  
   v1.1.1 (shipped with kubuntu 12.10dev) and v1.2.0.rc1, 1.2.0rc2 and
   master (1.3.x).
  
  
   My set up is to call ipython with pylab and turn on interactive mode.
 I
   still haven't copied over my matplotlibrc file from my work computer
   (there I use qtagg, if I remember well)
  
  
   On v1.1.1 the default is [backend: TkAgg], while in the other two
 cases
   it is  [backend: agg]. Is there some reason for this difference?
 
  The default should be based on what is found when mpl is built, so it
  sounds like when you are building v1.2.x, none of the supported gui
  toolkits is being found.  I don't know why that is.  Are you installing
  on a system that has gui toolkits already installed?
 
  I think so, as the v1.1.1 shipped with my OS is using TkAgg as backend
 and I
  can plot interactively.
 
  When I build from source I get
  OPTIONAL BACKEND DEPENDENCIES
  libpng: found, but unknown version (no pkg-config)
 Tkinter: no
  * Using default library and include directories
 for
  * Tcl and Tk because a Tk window failed to open.
  * You may need to define DISPLAY for Tk to work
 so
  * that setup can determine where your libraries
 are
  * located. Tkinter present, but header files are
 not
  * found. You may need to install development
  * packages.
  * You may need to install 'dev' package(s) to
  * provide header files.
Gtk+: no
  * Could not find Gtk+ headers in any of
  * '/usr/local/include', '/usr/include',
  * '/usr/local/include', '/usr/include', '.'
 Mac OS X native: no
  Qt: no
 Qt4: Qt: 4.8.2, PyQt4: 4.9.3
  PySide: no
   Cairo: 1.8.8
 
  Could be a problem with Tkinter and dev packages.
 
 
 
 
  One useful
  technique with ubuntu derivatives is to do
 
  sudo apt-get build-dep python-matplotlib
 
  probably it's easier if I just switch to qtagg, as I already have it
 
 
  It might pull in more than you really want, but it will certainly
  include gui toolkits.
 
  Eric
 
  Thanks,
  Francesco
 
 
 
  
  
   cheers,
  
   Francesco

 Packages have whatever default backend the maintainer decided to build
 them with. For example, the macports packaged version of matplotlib is
 maintained by someone who specifies the macosx backend to be the
 default. When building from source, I think the TkAgg backend is the
 default, because most platforms have tkinter installed out of the box.
 Since it appears you don't have Tkinter installed, Agg is the default.

 Agg is a non-gui backend (but it produces awesome output).


Thanks for the explanation.

Fra



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Re: [Matplotlib-users] Matplotlib produced plots in academic journal articles

2012-10-05 Thread Francesco Montesano
2012/10/5 Gökhan Sever gokhanse...@gmail.com



 On Fri, Oct 5, 2012 at 1:23 PM, Damon McDougall damon.mcdoug...@gmail.com
  wrote:

 On Fri, Oct 5, 2012 at 8:11 PM, Gökhan Sever gokhanse...@gmail.com
 wrote:
  Seeing mpl produced plots would be only 1 or 2 clicks away, plus this
 would

 This is not true. A lot of articles are unavailable to certain
 institutions due to a lack of subscription. A major sticking point.


 I was only thinking open-access journals, which open-source users (i.e.
 users of python tools) tend to publish their articles in open-journals. Of
 course, there are subscription required articles but those are secondary
 concerns. Sometimes authors make their articles publicly available even the
 article is on a paid journal.





  provide context to the use of plots rather that extracting figures and
  putting them separately (dealing with copyright issues and such) on an
  alternative gallery page. The figures you linked look shinny but not
 much
  practical use in my field.

 Point taken on the context argument. I'll take that. To resolve it,
 make the figure/html image link to the underlying publication?


 Citation listing is easier for me, we can go both ways, a page listing
 only citations, another one a more experimental figure/citation if
 copyright issues can be resolved easily. In anyways, we will have to gather
 citations. Let's start doing that?


I think that an official acknowledgment that people can copy and paste (and
adapt) in their paper would be a great idea.

Francesco



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Re: [Matplotlib-users] sharex with different tick labels

2012-09-13 Thread Francesco Montesano
Hi Daniel,

2012/9/13 Daniel Welling dantwell...@gmail.com

 Greetings, all.

 I have an issue: I have several axes stacked in a column with a common time 
 vector on each x-axis.  Each plot is a contour, so overplotting is not an 
 option.  In a perfect world, I want the following:
 1) The subplots are tightly spaced such that with ax.grid() activated, the 
 grid lines appear continuous.  This makes comparing simultaneous 
 characteristics between subplots very easy.
 2) The subplots are linked via the sharex keyword so I can move them all in 
 unison.
 3) Only the bottommost subplot has x tick labels; on other plots, the long 
 time-formatted labels stick out of the left and right of the plots.

 Items 2 and 3 are contradictory: if I turn off tick labels (e.g. 
 ax.set_xticklabels('')) on one axes, the others turn off as well, including 
 the bottom axes.  That is bad.
 Does anyone know of a good workaround for this?

To obtain what you want you have to set the tick labels invisible is
the axes where you don't want them to show up.
From http://matplotlib.org/examples/pylab_examples/shared_axis_demo.html:
setp( ax.get_xticklabels(), visible=False)

As the axis are shared, the ticklabels are also shared, so setting
them to , erase them from all the axes.
I hope that this helps.

Cheers,
Francesco



 Thanks for your help.

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Re: [Matplotlib-users] strange behaviour with fill_between

2012-09-04 Thread Francesco Montesano
Dear Eric,

sorry for the delay in replying, and thanking: I forgot the mail after
reading it.

2012/8/30 Eric Firing efir...@hawaii.edu:
 On 2012/08/27 5:10 AM, Francesco Montesano wrote:
 Dear matplotlibers,

 I encountered a bug (?) in fill_between when using logarithmic scales and
 the last part of y and yerr arrays as set to zero: a diagonal stripe going 
 from
 the rightmost non zero value to the first value is drawn.
 It's visible in the right panel of the attached figure, while is not
 present if the plot is linear (left panel).
 If xaxis is log and yaxis is linear the plot is correctly drawn.

 I'm using mpl.__version__ = '1.1.1rc' under Kubuntu 12.04 with Python 2.7.3

 The plot has been created with the script below.

 Is this a bug or am I missing something?

 I don't think it is exactly a bug, but I don't know why the fill region
 is appearing as it does.  The underlying problem is that fill_between is
 doing what it is told to do without knowing that it is going to be
 plotted on a log axis.
I think that also most of the other plotting functions (e.g. errorbar)
do not know about the scale used on the axis, but they behave
correctly. Am I right?


 A good workaround is to change your call to fill_between to look like this:
 positive = y - yerr  0
 ax2.fill_between( x,y-yerr,y+yerr, where=positive, color='b', alpha=0.4)

 Alternatively, you could use np.clip to put a floor under y - yerr and y
 + yerr.

The workaround works fine, but I dare say that it's not THE solution.
I think that the problem lies in the way PolyCollection is drawn when
y=yerr=0 (and probably also if y+- yerr =0) if the yaxis is log. I
have no clue where to look in the source to go deeper in the problem.

cheers,
Fra

 Eric


 Cheers
 Francesco


 # error_fill_between.py ##
 import matplotlib.pyplot as plt
 import numpy as np

 #values to plot
 x = np.linspace( 1, 10, num=100 )
 y = np.exp( -x**2 )
 y[50:] = 0
 yerr = y* np.random.rand(100)

 #figure
 fig = plt.figure()

 ax1 = fig.add_subplot(121)  #first axes: linear
 ax1.errorbar( x,y,yerr, c='r' )
 ax1.fill_between( x,y-yerr,y+yerr, color='b', alpha=0.4 )

 ax2 = fig.add_subplot(122)  #second axes: logarithmic
 ax2.errorbar( x,y,yerr, c='r' )
 ax2.fill_between( x,y-yerr,y+yerr, color='b', alpha=0.4 )
 ax2.set_xscale( log )
 ax2.set_yscale( log )

 plt.show()
 ## end script  #



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[Matplotlib-users] strange behaviour with fill_between

2012-08-27 Thread Francesco Montesano
Dear matplotlibers,

I encountered a bug (?) in fill_between when using logarithmic scales and
the last part of y and yerr arrays as set to zero: a diagonal stripe going from
the rightmost non zero value to the first value is drawn.
It's visible in the right panel of the attached figure, while is not
present if the plot is linear (left panel).
If xaxis is log and yaxis is linear the plot is correctly drawn.

I'm using mpl.__version__ = '1.1.1rc' under Kubuntu 12.04 with Python 2.7.3

The plot has been created with the script below.

Is this a bug or am I missing something?

Cheers
Francesco


# error_fill_between.py ##
import matplotlib.pyplot as plt
import numpy as np

#values to plot
x = np.linspace( 1, 10, num=100 )
y = np.exp( -x**2 )
y[50:] = 0
yerr = y* np.random.rand(100)

#figure
fig = plt.figure()

ax1 = fig.add_subplot(121)  #first axes: linear
ax1.errorbar( x,y,yerr, c='r' )
ax1.fill_between( x,y-yerr,y+yerr, color='b', alpha=0.4 )

ax2 = fig.add_subplot(122)  #second axes: logarithmic
ax2.errorbar( x,y,yerr, c='r' )
ax2.fill_between( x,y-yerr,y+yerr, color='b', alpha=0.4 )
ax2.set_xscale( log )
ax2.set_yscale( log )

plt.show()
## end script  #


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Re: [Matplotlib-users] basemap via macports

2012-08-24 Thread Francesco Montesano
2012/8/24 Carlos Grohmann carlos.grohm...@gmail.com:
 Hello all,

 I just did a fresh macports install, and installed py27-matplotlib-basemap,
 so all dependencies were installed as well.

 After installing python, I did run port-select (or something like it) to
 make sure I'm using macports python.

 My problem is that I can't run it:


 GuanoMac:~ guano$ python
 Python 2.7.2 (v2.7.2:8527427914a2, Jun 11 2011, 15:22:34)
 [GCC 4.2.1 (Apple Inc. build 5666) (dot 3)] on darwin
 Type help, copyright, credits or license for more information.
 from mpl_toolkits.basemap import Basemap
 Traceback (most recent call last):
   File stdin, line 1, in module
 ImportError: No module named basemap


 Anyone experienced in this kind of installation could share hints?

if you do
import sys
print sys.path

you can check if the directory of basemap is in your path

if not, you can add it both in the scritp/session
appending/inserting/extending sys.path (which is a list):
e.g.: sys.path.append( dir/to/basemap )
or in the .profile, .bash_profile or .bash_rc files (in this way is
loaded in every session)
export PYTHONPATH=$PYTHONPATH:dir/to/basemap


cheers,
Francesco


 tks

 Carlos

 --
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 Institute of Geosciences - Univ. of São Paulo, Brazil
 - Digital Terrain Analysis | GIS | Remote Sensing -

 http://carlosgrohmann.com
 
 Can’t stop the signal.


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Re: [Matplotlib-users] Axis ticks 'zorder'

2012-07-30 Thread Francesco Montesano
Hi,

2012/7/30 oc-spam65 oc-spa...@laposte.net:
 Hello,

 Can the 'zorder' of the ticks be set? This minimal example shows a
 hard-coded value of 2.5

 This may come from file matplotlib/axes.py, function draw(). Can it
 be adjusted? Shall it be bug-reported?

 ###
 import matplotlib.pyplot as pyplot

 fig = pyplot.figure()
 ax = fig.add_subplot(111)

 ax.add_patch(pyplot.Rectangle((0,0), 1, 1, zorder=3))
 ax.xaxis.set_zorder(4)
 # Expected behavior: the ticks should be drawn after the Rectangle,
 # because 4  3. They should therefore be visible.

 pyplot.show()
 # Problem: The ticks are hidden by the rectangle, contrary to the
 # expected behavior.

 print(ax.xaxis.get_zorder())
 # Prints 2.5 instead of 4!

 ###

I confirm the bug on matplotlib v: 1.1.0, Kubuntu 11.04, Python 2.7.1+

 ax.xaxis.set_zorder(4)
 ax.xaxis.get_zorder()
 4
 plt.draw()
 ax.xaxis.get_zorder()

It seems that the call to draw or show sets the zorder to default,
instead of updating it.

@Mr Spam (can you sign your mail, please)
In one of my scripts managed to set zorder to the spines as, e.g.,
ax.spines['left'].set_zorder(101).
This puts the axis spine well on top, but ax.xaxis.set_zorder does
nothing. I've also found a method ax.tick_params,
that has a zorder keyword, but it does nothing too.

Cheers,
Francesco


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Re: [Matplotlib-users] Placing a 'title' inside a legend

2012-07-27 Thread Francesco Montesano
Hi Andreas,

2012/7/27 Andreas Hilboll li...@hilboll.de:
 Hi,

 I'd like to place something like a 'title' inside a legend's box. In my
 specific case, I have a legend with 5 entries, arranged in 5 columns, so
 they're horizontally next to each other in one row. Now what I'd like to
 have is inside the legend's box a first row (above the legend entries),
 where I can write some text.

 Any ideas?

The keyword 'title' in legend
(http://matplotlib.sourceforge.net/api/pyplot_api.html#matplotlib.pyplot.legend)
should work.

Francesco


 Cheers, Andreas.


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Re: [Matplotlib-users] Placing a 'title' inside a legend

2012-07-27 Thread Francesco Montesano
Hi Andreas,

2012/7/27 Andreas Hilboll li...@hilboll.de:
 Hi Andreas,

 2012/7/27 Andreas Hilboll li...@hilboll.de:
 Hi,

 I'd like to place something like a 'title' inside a legend's box. In my
 specific case, I have a legend with 5 entries, arranged in 5 columns, so
 they're horizontally next to each other in one row. Now what I'd like to
 have is inside the legend's box a first row (above the legend entries),
 where I can write some text.

 Any ideas?

 The keyword 'title' in legend
 (http://matplotlib.sourceforge.net/api/pyplot_api.html#matplotlib.pyplot.legend)
 should work.

 Almost embarassingly simple ... however: It looks like the title is in a
 smaller font size than the other legend texts. Do I have some control
 about the font size of the legend's title? Couldn't find anything in the
 plt.legend docstring (I'm on 1.1.1).

try:
l = ax.legend( patches, labels, ..., title=legend title)
t = l.get_title()  #get the text object containing the title
t.set_fontsize(30)  #set the font size

you can merge the last two lines together l.get_title().set_fontsize(30)

Francesco


 Cheers, A.


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Re: [Matplotlib-users] How to plot only a legend?

2012-07-26 Thread Francesco Montesano
Hi Andreas,

2012/7/26 Andreas Hilboll li...@hilboll.de:
 Hi,

 I would like to create a figure which only contains a legend, and no axes
 at all. I would like to manually assign the colors. I found this here:

http://stackoverflow.com/a/3302666

 but from there on, I'd like to remove the axes, and put the legend into
 three columns.

If the plot attached it's fine for you it's easy:

import matplotlib.pyplot as plt
ax = plt.subplot()  #create the axes
ax.set_axis_off()  #turn off the axis
  #do patches and labels
ax.legend(patches, labels, ...)  #legend alone in the figure
plt.show()

Cheers,
Francesco


 Any help is greatly appreciated :)
 Andreas.


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test.pdf
Description: Adobe PDF document
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Re: [Matplotlib-users] How to plot only a legend?

2012-07-26 Thread Francesco Montesano
Hi,

you should be also able to create the axes as:

ax = plt.figure( figsize=(x,y) ).add_subplot(111)
with figsize big enough to fit just the legend

Cheers
Francesco

2012/7/26 Damon McDougall damon.mcdoug...@gmail.com:
 On Thu, Jul 26, 2012 at 06:05:39PM +0200, Andreas Hilboll wrote:
  Hi Andreas,
 
  2012/7/26 Andreas Hilboll li...@hilboll.de:
  Hi,
 
  I would like to create a figure which only contains a legend, and no
  axes
  at all. I would like to manually assign the colors. I found this here:
 
 http://stackoverflow.com/a/3302666
 
  but from there on, I'd like to remove the axes, and put the legend into
  three columns.
 
  If the plot attached it's fine for you it's easy:
 
  import matplotlib.pyplot as plt
  ax = plt.subplot()  #create the axes
  ax.set_axis_off()  #turn off the axis
    #do patches and labels
  ax.legend(patches, labels, ...)  #legend alone in the figure
  plt.show()
 
  Cheers,
  Francesco

 That's really easy :) I could live with this solution, applying some
 external tool like pdfcrop to the result. Of course, it would be nicer if
 the PDF's page size would be exactly that of the legend (plus some
 margin), so that I wouldn't have to resort to external tools ...

 Any ideas?


 How about

 plt.savefig('roflcakes.png', bbox_inches='tight', pad_inches=0.1)

 Since the other artists are invisible, that should crop to just your
 legend. I'm assuming matplotlib updates the BoundingBox such that it
 doesn't include invisible artists.


 Cheers, A.


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 B2.39
 Mathematics Institute
 University of Warwick
 Coventry
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 CV4 7AL
 United Kingdom

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Re: [Matplotlib-users] Combining 4 plots into one figure

2012-07-19 Thread Francesco Montesano
Hi Brad,

2012/7/19 Alexander Eberspaecher alexander.eberspaec...@ovgu.de:
 On Wed, 18 Jul 2012 15:50:50 -0700
 Brad Malone brad.mal...@gmail.com wrote:

 Hi, I have a collection of 4 plots that I spent some time in
 constructing. They themselves include modifications of the axes
 labels, have rotated subplots next to them, etc. I need to be able to
 take these 4 plots and consolidate them into a single plot (referee
 suggestion to save space).

 Assuming you are using LaTeX to write your paper, you could use a LaTeX
 solution. Here are some links:

 http://en.wikibooks.org/wiki/LaTeX/Floats,_Figures_and_Captions#Subfloats
 ftp://ctan.tug.org/tex-archive/macros/latex/contrib/subfig/subfig.pdf

 This might be easier - and would also make your figures more reusable
 (for e.g. presentations).

The solution from Alex might work, but not being optimal in saving
space, in particular if you can share axis.

The labels (a),(b),... can be inserted in the figures with
a.text(x,y,'(a)', ... ). I know that some journals want them in the
figure and not made with latex, so you probably have to rerun your
script with the text added.

If you want to make a unique figure you can try to declare the axis
directly, insead of using subplot, and play with the rect keyword:
http://matplotlib.sourceforge.net/api/pyplot_api.html#matplotlib.pyplot.axes
.
You can also play with gridspec
(http://matplotlib.sourceforge.net/users/gridspec.html), but I've
never used myself

Cheers,
Francesco

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[Matplotlib-users] gallery link broken/not working

2012-07-19 Thread Francesco Montesano
Hi,

roaming through the gallery I've found that in
http://matplotlib.sourceforge.net/examples/pylab_examples/demo_tight_layout_00.html
http://matplotlib.sourceforge.net/examples/pylab_examples/demo_tight_layout_01.html
http://matplotlib.sourceforge.net/examples/axes_grid/demo_axes_divider_01.html
and maybe others do not work

error:
1. Server: matplotlib.sourceforge.net
2. URL path: /examples/pylab_examples/demo_tight_layout_00.html
3. Error notes: NONE
4. Error type: 404
5. Request method: GET
6. Request query string: NONE
7. Time: 2012-07-19 09:12:32 UTC (1342689152)

http://matplotlib.sourceforge.net/examples/pylab_examples/demo_tight_layout.html
works fine

Cheers,

Francesco

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Re: [Matplotlib-users] need an icon for a new featureH

2012-07-19 Thread Francesco Montesano
2012/7/19 Nicolas Rougier nicolas.roug...@inria.fr:


 What size/format do you need and would that be an option to transform/use 
 Tango icons ?

 http://tango.freedesktop.org/
 http://commons.wikimedia.org/wiki/Tango_icons


 Tango (for fullscreen but might suit tight-layout)

















 Nicolas


 On Jul 19, 2012, at 0:47 , Benjamin Root wrote:

 Hello all!

 I have just about completed a PR that would add a new button to the 
 navigation toolbar for the tight_layout() action.  I am hardly an artist and 
 have no clue how to graphically represent the tight_layout action in a tiny 
 icon.  I would greatly welcome any graphics artist out there who could 
 provide such an icon for matplotlib.

 Thanks!
 Ben Root
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Hi
What about modify the icon suggested by Nicolas with a small square
inside the arrows?
Francesco

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Re: [Matplotlib-users] gallery link broken/not working

2012-07-19 Thread Francesco Montesano
done: https://github.com/matplotlib/matplotlib/issues/1024
Fra

2012/7/19 Phil Elson pelson@gmail.com:
 I can confirm the bad link.
 Would you mind opening a new issue on github for this?

 github.com/matplotlib/matplotlib/issues/new

 Thanks,

 On 19 July 2012 10:15, Francesco Montesano franz.berges...@gmail.com wrote:
 Hi,

 roaming through the gallery I've found that in
 http://matplotlib.sourceforge.net/examples/pylab_examples/demo_tight_layout_00.html
 http://matplotlib.sourceforge.net/examples/pylab_examples/demo_tight_layout_01.html
 http://matplotlib.sourceforge.net/examples/axes_grid/demo_axes_divider_01.html
 and maybe others do not work

 error:
 1. Server: matplotlib.sourceforge.net
 2. URL path: /examples/pylab_examples/demo_tight_layout_00.html
 3. Error notes: NONE
 4. Error type: 404
 5. Request method: GET
 6. Request query string: NONE
 7. Time: 2012-07-19 09:12:32 UTC (1342689152)

 http://matplotlib.sourceforge.net/examples/pylab_examples/demo_tight_layout.html
 works fine

 Cheers,

 Francesco

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Re: [Matplotlib-users] mimic alpha (channel) v0.1

2012-07-19 Thread Francesco Montesano
2012/7/18 Francesco Montesano franz.berges...@gmail.com:
 2012/7/18 Jonathan Slavin jsla...@cfa.harvard.edu:
 Ben,

 Yes, you're right, but I doubt any solution that involves mimicking an
 alpha channel will work for one case that I've been using.  That is,
 making the legend box partially transparent.  I use that to allow the
 box to fit in the plot without blocking the data and without the need to
 make the upper y limit too large.
 My solution would probably work if you could, pixel by pixel (or patch
 by patch), mimic alpha in each layer using as background the resulting
 color of the previous layer.

 Do anyone know if it is possible to implement something like this in
 matplotlib when saving a eps or in a backend?


 I don't notice any problems with blockiness in the text or lines in the
 raster image.  I'll find out soon if the editors of the Astrophysical
 Journal are okay with the figures.
 I guess that you produce the figures roughly of the right size (about
 8 or 16 cms wide for single or double column figures)  and then
 convert. So probably you see that the figure is a raster if you zoom
 in.

 Fra


 Jon

 On Tue, 2012-07-17 at 15:34 -0500, Benjamin Root wrote:


 On Tue, Jul 17, 2012 at 3:01 PM, Jonathan Slavin
 jsla...@cfa.harvard.edu wrote:
 Francesco,

 While I like your solution, there is an alternative that is
 simpler and
 works for me.  That is 1) save matplotlib plot as a png, 2)
 convert to
 eps using either ImageMagick or GraphicsMagick.  You do end up
 with
 relatively large files, but they look identical to the
 original plots.

 Regards,
 Jon

 No, it is not the same thing.  Text in a vector-based format such as
 eps is scalable.  ImageMagick and GraphicsMagick are inherently
 raster-based, and before that, PNGs are raster-based.  Therefore, the
 text is not scaled and anti-aliased according to the display size.

 I will be looking over the proposed solution this evening.

 Cheers!
 Ben Root



Dear matplotlibers,
I've uploaded a new version which accepts also lists/tuple/numpy
arrays of colors and/or alphas and returns a list of RGB colors.
https://github.com/montefra/mimic_alpha
https://github.com/montefra/mimic_alpha/downloads

Cheers,
Francesco

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Re: [Matplotlib-users] mimic alpha (channel) v0.1

2012-07-18 Thread Francesco Montesano
2012/7/18 Jonathan Slavin jsla...@cfa.harvard.edu:
 Ben,

 Yes, you're right, but I doubt any solution that involves mimicking an
 alpha channel will work for one case that I've been using.  That is,
 making the legend box partially transparent.  I use that to allow the
 box to fit in the plot without blocking the data and without the need to
 make the upper y limit too large.
My solution would probably work if you could, pixel by pixel (or patch
by patch), mimic alpha in each layer using as background the resulting
color of the previous layer.

Do anyone know if it is possible to implement something like this in
matplotlib when saving a eps or in a backend?


 I don't notice any problems with blockiness in the text or lines in the
 raster image.  I'll find out soon if the editors of the Astrophysical
 Journal are okay with the figures.
I guess that you produce the figures roughly of the right size (about
8 or 16 cms wide for single or double column figures)  and then
convert. So probably you see that the figure is a raster if you zoom
in.

Fra


 Jon

 On Tue, 2012-07-17 at 15:34 -0500, Benjamin Root wrote:


 On Tue, Jul 17, 2012 at 3:01 PM, Jonathan Slavin
 jsla...@cfa.harvard.edu wrote:
 Francesco,

 While I like your solution, there is an alternative that is
 simpler and
 works for me.  That is 1) save matplotlib plot as a png, 2)
 convert to
 eps using either ImageMagick or GraphicsMagick.  You do end up
 with
 relatively large files, but they look identical to the
 original plots.

 Regards,
 Jon

 No, it is not the same thing.  Text in a vector-based format such as
 eps is scalable.  ImageMagick and GraphicsMagick are inherently
 raster-based, and before that, PNGs are raster-based.  Therefore, the
 text is not scaled and anti-aliased according to the display size.

 I will be looking over the proposed solution this evening.

 Cheers!
 Ben Root


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Re: [Matplotlib-users] emulate transparency in eps

2012-07-16 Thread Francesco Montesano
2012/6/20 Michael Droettboom md...@stsci.edu:
 The postscript output of the Cairo backend supports transparency
 emulation, though it hasn't been tested in some time.  Eric's suggestion
 (to output PDF and then convert to EPS) is also a reasonable one.

 Mike

 On 06/20/2012 10:38 AM, Francesco Montesano wrote:
 Dear list,

 it might be that this is not the best place to ask, but I guess that
 there are enough people with experience with colors.

 I think plots with nice colors and shaded areas are very nice, but for
 my publication I have to use eps files, that do not support
 transparency.
 The script below produce a figure like the one that I would like to
 make. If I save it as eps all the shaded areas are not transparent and
 the plot look ugly and unreadable.

 A way to emulate transparency that I've applied some time ago was to
 get the RGB value of the transparent color (with DigitalColor Meter on
 Mac) and to insert it by hand in fill_between, with a low value for
 the zorder option. The results was fine, but I don't like too much
 this approach, as any change in color or alpha value would require to
 go, get the new color, insert it and redo the figure.

 Is anyone aware of a way to obtain automatically a RGB color that on
 screen or printed looks similar to the corresponding RGBA?

 Thanks in advance,
 Francesco

 Sample code*

 plot with errors done with fill_between. Emulation of alpha in eps

 import itertools as it
 import matplotlib.pyplot as plt
 import numpy as np

 col = it.cycle([ 'm', 'r', 'g', 'b', 'c', 'y', 'k', ])
 ls = it.cycle( [ '-', '--', '-.', ':' ][::-1])

 #figure
 fig = plt.figure()
 ax = fig.add_subplot(111)

 x= np.linspace(0.5,5,100)
 for i in range(3):
c = col.next()
l = ls.next()
ax.plot( x, np.sin(x)**i, color=c, ls=l,
 label='$sin^{0}(x)$'.format(i), zorder=10+i )
ax.fill_between( x, np.sin(x)**i + 1./x, np.sin(x)**i - 1./x,
 color=c, linestyle=l, alpha=0.5, zorder=i+1)

 ax.legend(frameon=False)

 plt.savefig(test_alpha.pdf)
 plt.savefig(test_alpha.eps)
 plt.show()

 exit()
 End sample code*


Hi,

I was doing again some search on the topic when I realised that I just
replied to Eric.
This is my reply (Eric sorry for sending this mail twice to you)


I remember trying to convert pdf to eps in different ways with usually
ugly results and/or very large files.

Now I've tried the following commands on test_alpha.pdf (from
http://tex.stackexchange.com/questions/20883/how-to-convert-pdf-to-eps):
i) pdf2ps -eps test_alpha.pdf test_alpha.conv.eps
ii) gs -q -dNOCACHE -dNOPAUSE -dBATCH -dSAFER -sDEVICE=epswrite
-sOutputFile=test_alpha.gs.eps test_alpha.pdf

the results are:

39K 2012-06-19 17:37 test_alpha.eps   (original eps: no transparency)
23K 2012-06-19 17:37 test_alpha.pdf   (original pdf: transparency)
90M 2012-06-20 20:20 test_alpha.gs.eps  (converted with gs: transparency)
613K 2012-06-20 20:14 test_alpha.pdf2ps.eps   (converted with pdf2ps:
transparency [from my understanding it uses gs])
In both the converted cases the texts (tick labels, legend) are badly
rendered. The lines and contours of the filled areas look noisier than
in the original pdf.

It might be that increasing the resolution the situation improves, but
the file size increases, which is not an option.

Michael, I've tried Cairo (import matplotlib as mpl; mpl.use(Cairo)
 before importing pyplot), but the eps is not transparent.

Cheers,
Francesco

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[Matplotlib-users] emulate transparency in eps

2012-06-20 Thread Francesco Montesano
Dear list,

it might be that this is not the best place to ask, but I guess that
there are enough people with experience with colors.

I think plots with nice colors and shaded areas are very nice, but for
my publication I have to use eps files, that do not support
transparency.
The script below produce a figure like the one that I would like to
make. If I save it as eps all the shaded areas are not transparent and
the plot look ugly and unreadable.

A way to emulate transparency that I've applied some time ago was to
get the RGB value of the transparent color (with DigitalColor Meter on
Mac) and to insert it by hand in fill_between, with a low value for
the zorder option. The results was fine, but I don't like too much
this approach, as any change in color or alpha value would require to
go, get the new color, insert it and redo the figure.

Is anyone aware of a way to obtain automatically a RGB color that on
screen or printed looks similar to the corresponding RGBA?

Thanks in advance,
Francesco

Sample code*

plot with errors done with fill_between. Emulation of alpha in eps

import itertools as it
import matplotlib.pyplot as plt
import numpy as np

col = it.cycle([ 'm', 'r', 'g', 'b', 'c', 'y', 'k', ])
ls = it.cycle( [ '-', '--', '-.', ':' ][::-1])

#figure
fig = plt.figure()
ax = fig.add_subplot(111)

x= np.linspace(0.5,5,100)
for i in range(3):
  c = col.next()
  l = ls.next()
  ax.plot( x, np.sin(x)**i, color=c, ls=l,
label='$sin^{0}(x)$'.format(i), zorder=10+i )
  ax.fill_between( x, np.sin(x)**i + 1./x, np.sin(x)**i - 1./x,
color=c, linestyle=l, alpha=0.5, zorder=i+1)

ax.legend(frameon=False)

plt.savefig(test_alpha.pdf)
plt.savefig(test_alpha.eps)
plt.show()

exit()
End sample code*

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Re: [Matplotlib-users] [matplotlib-users] definition to show quikly a plot

2012-05-29 Thread Francesco Montesano
Dear Fabien

2012/5/29 Fabien Lafont lafont.fab...@gmail.com:
 Hello everyone,

 I have a problem. I have to look at many plots. Usely I do it like that:

 from pylab import*

 X1 = genfromtxt(Myfile.dat, usecols =(0))
 Y1 = genfromtxt(Myfile.dat, usecols =(1))
 plot(X1,Y1, label =My curve)

 show()


 But the problem is when I have many plots I have to copy paste and
 change manually all the name of the variables X1, X2, X3...etc. It's
 not really convenient.
 I want to create a def with the name of my file as argument which do
 something like that:

 from pylab import*

 def plotgraph(name):
    X_name = genfromtxt(name, usecols =(0))
    Y_name = genfromtxt(name, usecols =(1))
    plot(X_name,Y_name, label =name)

 plotgraph(MyFile)

 show()


Try this:

def plotgraph(name):
   Plot stuff:
   name: string
 file name
   
   X_name, Y_name = genfromtxt(name, usecols =(0,1)).T
   plot(X_name,Y_name, label =name)

'name' should contain already a string, so you have to pass it to
genfromtxt. I you pass name, the file name is name and not the
what is in the variable.
Just a note: if you read the file as 'X_name, Y_name =
genfromtxt(name, usecols =(0,1)).T'  you open, read and close the file
only once.

Cheers,
Francesco


 But it doesn't work. Do you know why? Do you have a smarter idea?

 Thanks!

 Fab

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Re: [Matplotlib-users] [matplotlib-users] definition to show quikly a plot

2012-05-29 Thread Francesco Montesano
2012/5/29 Fabien Lafont lafont.fab...@gmail.com:
 Thx Francesco, it works great!

 What for the .T at the end of genfromtxt?

genfromtxt with usecols=(0,1) return an array with 2 columns. with .T
you transpose it so that you can save it in two variables. For more
info, e.g., 
http://docs.scipy.org/doc/numpy/reference/generated/numpy.ndarray.T.html#numpy-ndarray-t

Cheers,
Francesco




 2012/5/29 Francesco Montesano franz.berges...@googlemail.com:
 Dear Fabien

 2012/5/29 Fabien Lafont lafont.fab...@gmail.com:
 Hello everyone,

 I have a problem. I have to look at many plots. Usely I do it like that:

 from pylab import*

 X1 = genfromtxt(Myfile.dat, usecols =(0))
 Y1 = genfromtxt(Myfile.dat, usecols =(1))
 plot(X1,Y1, label =My curve)

 show()


 But the problem is when I have many plots I have to copy paste and
 change manually all the name of the variables X1, X2, X3...etc. It's
 not really convenient.
 I want to create a def with the name of my file as argument which do
 something like that:

 from pylab import*

 def plotgraph(name):
    X_name = genfromtxt(name, usecols =(0))
    Y_name = genfromtxt(name, usecols =(1))
    plot(X_name,Y_name, label =name)

 plotgraph(MyFile)

 show()


 Try this:

 def plotgraph(name):
   Plot stuff:
   name: string
     file name
   
   X_name, Y_name = genfromtxt(name, usecols =(0,1)).T
   plot(X_name,Y_name, label =name)

 'name' should contain already a string, so you have to pass it to
 genfromtxt. I you pass name, the file name is name and not the
 what is in the variable.
 Just a note: if you read the file as 'X_name, Y_name =
 genfromtxt(name, usecols =(0,1)).T'  you open, read and close the file
 only once.

 Cheers,
 Francesco


 But it doesn't work. Do you know why? Do you have a smarter idea?

 Thanks!

 Fab

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Re: [Matplotlib-users] position of xtick labels

2012-04-27 Thread Francesco Montesano
Dear Nils,

you can try to play with
i) ax.axis[right, top, bottom, left] and their methods (see
setup_axis3 here
http://matplotlib.sourceforge.net/examples/axes_grid/demo_floating_axes.html
for an example)
ii) twinx and twiny axes (example
http://matplotlib.sourceforge.net/examples/api/two_scales.html )

The first one can be a bit confusing with orientations. Once I found
an explanation about it on matplotlib website, but I cannot find it
right now.
The second way creates a second axis that you probably don't need.

Cheers,
Francesco

Il 27 aprile 2012 11:48, Nils Wagner nwag...@iam.uni-stuttgart.de ha scritto:
 Hi all,

 I would like to add different xtick labels on the top and
 bottom of a figure. The number and position of the xticks
 is the same.
 How can I do that ?

 An example would be appreciated.

 Nils

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Re: [Matplotlib-users] position of xtick labels

2012-04-27 Thread Francesco Montesano
Dear Nils,

I think that I've found what you need (example adapted from
http://notes.brooks.nu/2008/03/plotting-on-left-and-right-axis-simulateously-using-matplotlib-and-numpy/
)

import matplotlib.pyplot as plt
import numpy as np

#data to plot
x = np.linspace(0,5,num=100)
y = np.sinc(x)

fig   = plt.figure(figsize=(16,10))  #figure
ax= fig.add_subplot(111)#axis containing the figure
ax1 = fig.add_subplot(111, sharex=ax, sharey=ax, frameon=False)
#axis that shares both x and y and without frame (so ax is visible)

ax.plot(x, y)   #plot the data

ax1.xaxis.tick_top()  #show ticks on top
ax1.yaxis.tick_right()  #show ticks on the right

Now if you do any modification on the ax limits should reflect on ax1.

Might be that there is some smarter way of doing it, but if the
project is not too long and efficiency is not a problem, I think that
this example will suffice

Cheers,
Francesco

Il 27 aprile 2012 14:50, Nils Wagner nils...@googlemail.com ha scritto:
 Dear Francesco,

 Thank you for your prompt reply !
 My incomplete example is below.

 import matplotlib.pyplot as plt
 fig   = plt.figure(figsize=(16,10))
 ax    = fig.add_subplot(111)
 ind = np.arange(nfreq)
 yoff = np.array([0.0]*nfreq)
 for row in range(nsets):

    ax.bar(ind,A[row,:],width,bottom=yoff, 
 color=colours[row],label=elabel[row])
    yoff = yoff + A[row,:]

 plt.legend(loc=upper left, bbox_to_anchor=(1,1))
 plt.xticks(ind+0.5*width,np.arange(nfreq)+1,rotation=90)
 ax.set_xlim(0.,nfreq)
 ax.set_ylim(0.,102.)
 plt.subplots_adjust(left=0.075, right=0.85, top=0.9, bottom=0.05)
 plt.show()

 How can I add xtick labels on the top of my figure ?

 Cheers,
               Nils


 On 4/27/12, Francesco Montesano franz.berges...@googlemail.com wrote:
 Dear Nils,

 you can try to play with
 i) ax.axis[right, top, bottom, left] and their methods (see
 setup_axis3 here
 http://matplotlib.sourceforge.net/examples/axes_grid/demo_floating_axes.html
 for an example)
 ii) twinx and twiny axes (example
 http://matplotlib.sourceforge.net/examples/api/two_scales.html )

 The first one can be a bit confusing with orientations. Once I found
 an explanation about it on matplotlib website, but I cannot find it
 right now.
 The second way creates a second axis that you probably don't need.

 Cheers,
 Francesco

 Il 27 aprile 2012 11:48, Nils Wagner nwag...@iam.uni-stuttgart.de ha
 scritto:
 Hi all,

 I would like to add different xtick labels on the top and
 bottom of a figure. The number and position of the xticks
 is the same.
 How can I do that ?

 An example would be appreciated.

 Nils

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[Matplotlib-users] mpl_toolkits.axisartist.floating_axes.FloatingSubplot required option

2012-04-27 Thread Francesco Montesano
Dear matplotlibers,

I know almost nothing about mpl_toolkits (matplolib.__version__ = 1.1.0).
From the help of
mpl_toolkits.axisartist.floating_axes.FloatingSubplot, the init
function reads
__init__(self, fig, *args, **kwargs)

In the example here
(http://matplotlib.sourceforge.net/examples/axes_grid/demo_floating_axes.html)
the object is initialised as
 FloatingSubplot(fig, rect, grid_helper=grid_helper)

If I take out 'grid_helper' I get this error:
ValueError: FloatingAxes requires grid_helper argument

In my understanding, **kwargs (like grid_helper) are optional
arguments and I think that 'required' options do not make much sense.
Besides its not documented in the help of the class.

Could grid_helper be upgraded to *args?

Cheers,
Francesco

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Re: [Matplotlib-users] (no subject)

2012-03-30 Thread Francesco Montesano
 
 From: Francesco Montesano franz.berges...@googlemail.com
 To: Dorm Eight dormei...@yahoo.com
 Cc: matplotlib-users@lists.sourceforge.net
 matplotlib-users@lists.sourceforge.net
 Sent: Tuesday, March 27, 2012 3:38 PM
 Subject: Re: [Matplotlib-users] (no subject)

 Il 27 marzo 2012 05:08, Dorm Eight dormei...@yahoo.com ha scritto:
 hi, everybody!

 when I run my script, why there is no figure show up? I downloaded the
 demos
 from matplotlib gallery and it didn't work either.

 x=np.arange(100)
 y=x**2+3*x-1
 pl.plot(x,y)
 [matplotlib.lines.Line2D object at 0x2581050]
 pl.show()

 there is no error, no figure pop-up!

 Thank you for any answer!


 Hi Dorm
 If you can send more info about the operating system and matplotlib
 version, it's easier to help you
 (for the latter do
 import matplotlib
 print matplotlib.__version__
 )

 Cheers,
 Francesco


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Il 30 marzo 2012 13:23, Dorm Eight dormei...@yahoo.com ha scritto:

Dear Dorm,

please reply to all the list.
  My system is Fedora 3.3.0-4.fc16.x86_64, after I recently updated the
 system with 'yum update', the problem appeared.
 the Matplotlib version is 1.10. I have no idea at all now.

I've tested your small example on python 2.6, matplotlib 1.0.0 with
MacOSX backend and on Kubuntu 11.04, python 2.7, matplotlib 1.1, with
TkAgg and Qt4Agg backends and the small code works for me. In all
cases I have set plt.ion()

If you save the figure instead of showing, does it work?
Which backend are you using: the name is stored in matplotlib.backends.backend

Cheers
Francesco

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Re: [Matplotlib-users] (no subject)

2012-03-30 Thread Francesco Montesano
Dear Dorm,

Il 30 marzo 2012 14:17, Dorm Eight dormei...@yahoo.com ha scritto:
 Dear Francesco,
 Yes, I just tried it, it can be save perfectly.

so might be a problem with the backend.
Give a look to this page:
http://stackoverflow.com/questions/2512225/matplotlib-not-showing-up-in-mac-osx
and try to change the backend.
I think that I cannot help much more here. Does anyone else has an
idea if there might be any other problem?

Cheers,
Francesco


 
 From: Francesco Montesano franz.berges...@googlemail.com
 To: Dorm Eight dormei...@yahoo.com; matplotlib-users@lists.sourceforge.net
 Sent: Friday, March 30, 2012 8:01 PM

 Subject: Re: [Matplotlib-users] (no subject)

 
 From: Francesco Montesano franz.berges...@googlemail.com
 To: Dorm Eight dormei...@yahoo.com
 Cc: matplotlib-users@lists.sourceforge.net
 matplotlib-users@lists.sourceforge.net
 Sent: Tuesday, March 27, 2012 3:38 PM
 Subject: Re: [Matplotlib-users] (no subject)

 Il 27 marzo 2012 05:08, Dorm Eight dormei...@yahoo.com ha scritto:
 hi, everybody!

 when I run my script, why there is no figure show up? I downloaded the
 demos
 from matplotlib gallery and it didn't work either.

 x=np.arange(100)
 y=x**2+3*x-1
 pl.plot(x,y)
 [matplotlib.lines.Line2D object at 0x2581050]
 pl.show()

 there is no error, no figure pop-up!

 Thank you for any answer!


 Hi Dorm
 If you can send more info about the operating system and matplotlib
 version, it's easier to help you
 (for the latter do
 import matplotlib
 print matplotlib.__version__
 )

 Cheers,
 Francesco



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Il 30 marzo 2012 13:23, Dorm Eight dormei...@yahoo.com ha scritto:

 Dear Dorm,

 please reply to all the list.
  My system is Fedora 3.3.0-4.fc16.x86_64, after I recently updated the
 system with 'yum update', the problem appeared.
 the Matplotlib version is 1.10. I have no idea at all now.

 I've tested your small example on python 2.6, matplotlib 1.0.0 with
 MacOSX backend and on Kubuntu 11.04, python 2.7, matplotlib 1.1, with
 TkAgg and Qt4Agg backends and the small code works for me. In all
 cases I have set plt.ion()

 If you save the figure instead of showing, does it work?
 Which backend are you using: the name is stored in
 matplotlib.backends.backend

 Cheers
 Francesco



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Re: [Matplotlib-users] (no subject)

2012-03-27 Thread Francesco Montesano
Il 27 marzo 2012 05:08, Dorm Eight dormei...@yahoo.com ha scritto:
 hi, everybody!

 when I run my script, why there is no figure show up? I downloaded the demos
 from matplotlib gallery and it didn't work either.

 x=np.arange(100)
 y=x**2+3*x-1
 pl.plot(x,y)
 [matplotlib.lines.Line2D object at 0x2581050]
 pl.show()

 there is no error, no figure pop-up!

 Thank you for any answer!


Hi Dorm
If you can send more info about the operating system and matplotlib
version, it's easier to help you
(for the latter do
import matplotlib
print matplotlib.__version__
)

Cheers,
Francesco

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Re: [Matplotlib-users] Looking for a good color map that works both for color and bw

2012-01-16 Thread Francesco Montesano
2012/1/16 Michael Cracraft michael.cracr...@gmail.com:
 I prepared some plots for a conference paper using pcolormesh.  The plots
 need to work both for color and for a bw print copy.  Does anyone have a
 goto color map for that sort of occassion?  I was using YlGrBu, but I'm just
 not happy with it.

 Thanks,
 Michael


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Dear Michael,

Recently I've used 'hot' which I think is very clear in color and
works perfectly in grayscale.

Cheers,
Francesco

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Re: [Matplotlib-users] legend border, frameon keyword

2011-11-11 Thread Francesco Montesano
Hi,

I usually do like this

l = ax.legend( (rects1[0], rects2[0]), ('set1', 'set2'))
l.draw_frame(False)

Cheers,

Francesco

2011/11/9 magurling magurl...@gmail.com:

 I want a legend without the black border. I've tried a few things that have
 been suggested on this forum and elsewhere to no avail. According to what
 I've seen, it should be as simple as:

 import matplotlib.pyplot as plt
 import numpy as np

 N = 5
 Means1 = (20, 35, 30, 35, 27)
 Means2 = (25, 32, 34, 20, 25)

 ind = np.arange(N)  # the x locations for the groups
 width = 0.20       # the width of the bars

 fig = plt.figure()
 ax = fig.add_subplot(111)
 rects1 = ax.bar(ind, Means1, width, color='k')
 rects2 = ax.bar(ind+width, Means2, width, color='w')

 ax.legend( (rects1[0], rects2[0]), ('set1', 'set2'), frameon=False )

 plt.show()


 It all works except for frameon=False

 I get this:

 /usr/lib/pymodules/python2.7/matplotlib/axes.pyc in legend(self, *args,
 **kwargs)
   4042
   4043         handles = cbook.flatten(handles)
 - 4044         self.legend_ = mlegend.Legend(self, handles, labels,
 **kwargs)
   4045         return self.legend_
   4046

 TypeError: __init__() got an unexpected keyword argument 'frameon'

 I've also checked my matplotlibrc under the Legend section and I don't see
 a legend.frameon line.

 It must be something simple that I am doing wrong. Any ideas?
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Re: [Matplotlib-users] fill with a semilogy axis?

2011-05-06 Thread Francesco Montesano
Hi Michael,

I use fill_between() and log axis without problems in the following way (it's 
by memory, I hope the sintax is correct)

fig = plt.figure()
spl = fig.add_subplot(111)

spl.fill_between(x,y1,y2)

spl.set_yscale(log)

plt.show()

Cheers,

Fra

Il giorno 06/mag/2011, alle ore 01.34, Benjamin Root ha scritto:

 
 
 On Tue, May 3, 2011 at 3:40 AM, K.-Michael Aye kmichael@gmail.com wrote:
 A colleague posed an interesting challenge:
 How to do a filled plot having the y-axis in logarithm?
 I think I can do it with creating patches myself an adding it to the
 axis, but isn't there anything built-in?
 
 Best regards,
 Michael
 
 
 
 Does fill_between() not work for you?  Note, I have never tried it on a log 
 scale plot.
 
 Ben Root
 
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[Matplotlib-users] multiline legend tags

2011-03-17 Thread Francesco Montesano
Dear all,

I have a rather complex code that takes a list of file names and of
legend tags from command line and compute contour plots

./contour_plots.py [options] filename1 ... filename2 tag1 ... tagn

The codes make filled contours at required levels, then line contours.
From the latter I extract one line from each file and create a legend

spl.legend(lines, [tag1...tagn], other options)

All it works fine. The only problem is that sometimes I have tags that
are long and I would like to be able to break between multiple lines.
In examples/legend_demo3.py is shown that 'ax1.plot([1],
label=multi\nline)' the \n is interpreted (correctly) as new line.

Normaly I have something like
./contour_plots.py [options] filename1 \(long\)tag\$_\{very long\}\$
that gives me a legend with the correct formatting. If I try to add a
'\n' after 'tag', I get out the tag as before plus a 'n' after 'tag'.
I've tried to enclose the whole string or just \n in  or r but
nothing good happens (either I get 'n' or 'rn').
Is there a way to do what I want to do?

Thanks in advance
Francesco

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Re: [Matplotlib-users] hide labels

2011-02-04 Thread Francesco Montesano
Dear all again,

I've tried to play with it again, but I couldn't find a solution for
the problem.
For clarity I report an example of what each of the subplots looks like:

 import numpy as np
 import matplotlib.pyplot as plt
 mean = np.array([-0.9206394,  -0.90127456, -0.91983625, -0.97765539, 
 -1.02991184, -1.02267017, -0.97730167, -0.93715172, -0.94324653, -0.92884379])
 stddev = np.array([0.16351397, 0.15075966,  0.13413909,  0.15404823,  
 0.13559582,  0.13109754,  0.12128598,  0.11589682,  0.11921571,  0.10866761])

 ax = plt.figure().add_axes([0.1,0.1,0.8,0.8])
 ax.errorbar(np.arange(10,20)/100., mean, yerr=stddev)

 ax.set_xlim([0.095, 0.195])
 lab = ax.get_ymajorticklabels()

 print lab
 for i in lab:
  print i

 plt.show()

as output of this script I get
 a list of 7 Text yticklabel objects
 Text(0,0,'')
 Text(0,0,'')
 Text(0,0,'')
 Text(0,0,'')
 Text(0,0,'')
 Text(0,0,'')
 Text(0,0,'')
In the plot instead I only have only 5 y tick labels, as visible from
the attachment. In this case if I set the first and the last label
invisible, nothing changes, and if I have other plots under this the
plot becomes ugly/unreadable.

I hope to have been clearer than in my previous mail.
Any suggestion on how to fix or find a workaround in order to get the
same number of tick labels as the ones actually plotted.

Thank in advance
Fra


2011/2/1 Francesco Montesano franz.berges...@googlemail.com:
 Dear all,

 I'm producing a single figure with subplots arrange in a single columns.
 They all share the same x range but the y variable change from subplot to
 subplot

 In order have a nicer figure I hide the first and the last y label of each
 subplot in the following way

 ytl = subpl.get_ymajorticklabels()
 ytl[0].set_visible(False)
 ytl[-1].set_visible(False)

 It was well in most cases. But I've noticed that in some plot the first
 and/or the last label remains.
 In this cases, if I print ytl, it writes a list of n Text yticklabel
 objects, where n is larger by 1 or 2 than the number of labels shown
 before I make them invisible.
 So I end up having some label (nearly) exactly on the upper and/or bottom
 range of the plot.

 Is there a way to force the axis to return exactly the number of labels
 shown in the plot?

 Thanks in advance,

 Francesco






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Re: [Matplotlib-users] Limits with errorbar

2011-02-02 Thread Francesco Montesano
Hi Paul,

2011/2/1 Paul Ivanov pivanov...@gmail.com

 I'm not sure what you're hoping to see, but you should either use
 xerr with xuplims, or yerr with uplims.


Thank you for the reply. As usually I checked everything except the correct
one.
By the way, if one uses (by error) yerr and xuplims/xlolims or xerr and
uplims/lolims, no error bar shows up. Is this a bug or a feature?

Cheers,
Fra
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[Matplotlib-users] Limits with errorbar

2011-02-01 Thread Francesco Montesano
Dear all,

I am trying to make a plot with errorbars and upperlimits.
I've found the following pylab example
http://matplotlib.sourceforge.net/examples/pylab_examples/errorbar_limits.htmland
it works fine both on a Mac OSX10.6 with python 2.6.1 and on Kubuntu
10.04 with python 2.6.5.
I've tried the to reproduce the example using matplotlib.pyplot but the
limits do not show up, regardless of syntax or system (matplotlib 1.0.0 on
Mac and 1.0.1 on Kubuntu)

I attach a sample code which does not work.

import numpy as np
 import matplotlib.pyplot as plt

 #create function to plot plus random error
 x = np.linspace(0,3,100)
 y = np.sin(x)
 err = np.random.random(100)

 plt.errorbar(x,y, yerr=err, color='g',linestyle='None',xuplims=True)
 plt.show()


Does anyone know how to solve this problem?

Thanks in advance,
Francesco
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[Matplotlib-users] hide labels

2011-02-01 Thread Francesco Montesano
Dear all,

I'm producing a single figure with subplots arrange in a single columns.
They all share the same x range but the y variable change from subplot to
subplot

In order have a nicer figure I hide the first and the last y label of each
subplot in the following way

 ytl = subpl.get_ymajorticklabels()
 ytl[0].set_visible(False)
 ytl[-1].set_visible(False)


It was well in most cases. But I've noticed that in some plot the first
and/or the last label remains.
In this cases, if I print ytl, it writes a list of n Text yticklabel
objects, where n is larger by 1 or 2 than the number of labels shown
before I make them invisible.
So I end up having some label (nearly) exactly on the upper and/or bottom
range of the plot.

Is there a way to force the axis to return exactly the number of labels
shown in the plot?

Thanks in advance,

Francesco
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Re: [Matplotlib-users] Legend for contour plots

2011-01-22 Thread Francesco Montesano
Dear Paul,

Thank you, it does exacly what I want to do. I searched a bit into the
contour instance, but I was biased since I was looking for something
like get_line.

cheers

Francesco


2011/1/21 Paul Ivanov pivanov...@gmail.com:
 Francesco Montesano, on 2011-01-21 15:44,  wrote:
 Dear All,

 I am using contour plot and I am drawing different contours with
 different colors and linestyles and I would like to have a legend with
 a caption for each contour function used.
 Here you can see an example of what I would like to do

  #create the 2D histogram and the x and y axis
  x, y = np.random.normal(0, 0.5, 1000), np.random.normal(0, 1, 1000)
  h, xe,ye = np.histogram2d(x,y, bins=25)
  xe, ye = (xe[1:]+xe[:-1])/2, (ye[1:]+ye[:-1])/2
 
  lines,text = [], []   # initialise lists
 
  #contour plots
  lines.append(plt.contour(xe,ye,h, levels=[10,9], linestyles=-, 
  colors=k))
  text.append(level=10, 9)
 
  lines.append(plt.contour(xe,ye,h, levels=[5,4], linestyles=--, 
  colors=r))
  text.append(level=5, 4)
 
  plt.legend(lines, text)

 Everything goes well untill I plot the legend. At the end of the mail
 I report the error that I get.
 Anyway, if I do
  plt.legend(lines)
 I don't get any errors but it's quite useless, since the text of the
 legend is just like:
 matplotlib.contour.ContourSet instance at 0x6bedc20
 as you can see from the attached figure.


 I've the feeling that the problem is that contour gives back a
 matplotlib.contour.ContourSet instance, while the functions like
 plot gives back a matplotlib.lines.Line2D object.

 Does anyone knows how to do what I want?

 Hi Francesco,

 here's one way of getting what you want, instead of calling
 legend on your 'lines' variable as you had it, do this:

  actual_lines = [cs.collections[0] for cs in lines]
  plt.legend(actual_lines, text)

 As you note, the call to plt.countour does not return lines, it
 returns contour sets (which is why I called the variable 'cs' in
 my example). Poking around in ipython, I saw that each contour
 set has a collections attribute which holds the actual lines.

 hope that helps,
 --
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Re: [Matplotlib-users] Smooth contourplots

2010-09-07 Thread Francesco Montesano
Dear Joe,

finally I had time to come back to my python scritp for the contour plots.
You're code works very nicelly and does exactly what I need.

Thank you for the help

Francesco

2010/7/26 Joe Kington jking...@wisc.edu:
 It sounds like you're wanting a gaussian kernel density estimate (KDE) (not
 the desktop!).  The other options you mentioned are for interpolation, and
 are not at all what you're wanting to do.

 You can use scipy.stats.kde.gaussian_kde(). However, it currently doesn't
 take a weights array, so you'll need to modify it for your use case.

 If you prefer, I have faster version of a gaussian KDE that can take a
 weights array.  It's actually slower than the scipy's gaussian kde for a low
 number of points, but for hundreds, thousands, or millions of points, it's
 several orders of magnitude faster.  (Though the speedup depends on the
 covariance of the points... higher covariance = slower, generally speaking)

 Here's a quick pastebin of the code.  http://pastebin.com/LNdYCZgw

 To use it, you do something like the below... (assuming the code in the
 pastebin is saved in a file called fast_kde.py)

 import numpy as np
 import matplotlib.pyplot as plt
 from fast_kde import fast_kde

 # From your description of your data...
 weights, x, y = np.loadtxt('chain.txt', usecols=(0,4,6)).T

 kde_grid = fast_kde(x, y, gridsize=(200,200), weights=weights)

 # Plot the grid
 plt.figure()
 plt.imshow(kde_grid, extent=(x.min(), x.max(), y.max(), y.min())

 # Reverse the y-axis
 plt.gca().invert_yaxis()

 plt.show()

 Hope that helps a bit,
 -Joe




 On Sat, Jul 24, 2010 at 3:56 AM, montefra franz.berges...@googlemail.com
 wrote:

 Hi,

 I am writing a program that reads three columns (one column containing the
 weights, the other two containing the values I want to plot) from a file
 containing the results from a MonteCarlo Markov Chain. The file contains
 thousends of lines. Then create the 2D histogram and make contourplots.
 Here
 is a sample of the code (I don't know if is correct, it's just to show
 what
 I do)

  import numpy as np
  import matplotlib.pyplot as mplp
  chain = np.loadtxt(chain.txt, usecols=[0,4,6])   #read columns 0
  (the
  weights), 4 and 6 (the data), from the file chain.txt
  h2D, xe, ye = np.histogram2D(chain[:,1],chain[:,2],
  weights=chain[:,0])
  #create the 2D histogram
  x = (xe[:-1] + xe[1:])/2. #x and y values for the plot (I use the mean
  of each bin)
  y = (ye[:-1] + ye[1:])/2.
  mplp.figure()   #open the figure
  mplp.contourf(x, y, h2D.T, origin='lower')  #contour plot

 As it is the contours are not smooth and they look not that nice. After
 days
 of searches I've found three methods and tried, unsuccesfully, to apply
 them
 1) 2d interpolation: I got segmentation fault (on a quadcore machine
 with
 8Gb of RAM)
 2) Rbf (radial basis functions): I got wrong contours
 3) ndimage: it creates spurious features (like secondary peaks parallel to
 the direction of the main one)

 Before beginning with Python, I used to use IDL to plot, and there is a
 function 'smooth' that smooth for you 2D histograms. I haven't found
 anything similar for Python.
 Does anyone have an idea or suggestion on how to do it?

 Thank in advance
 Francesco

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