Re: match two conditions in relayd(8)
On Mon, Jan 27, 2020 at 09:22:40PM +0100, Sebastian Benoit wrote: > Joel Carnat(j...@carnat.net) on 2020.01.27 18:21:43 +0100: > > Hi, > > > > I'm setting up an HTTP(S) Reverse Proxy with relayd(8). > > > > I have one listener with multiple FQDN allowed. > > But I also have a common path that must be treated separately. > > > > As for now, I have: > > http protocol "https" { > > match request header "Host" value "one.domain.local" forward to > > match request header "Host" value "two.domain.local" forward to > > match request path "/common/*" forward to > > } > > relay "domain.local" { > > listen on egress port 443 tls > > protocol "https" > > forward toport 80 check tcp > > forward toport 80 check tcp > > forward to port 80 check tcp > > } > > > > With this configuration, both "/common/" are rendered by . > > But I want > > "one.domain.local/*" to be rendered by > > "one.domain.local/common/" to be rendered by > > "two.domain.local/*" to be rendered by > > "two.domain.local/common/" to be rendered by > > > > Is there some way to achieve this? > > Try using "quick" or possibly "tag" and "tagged". > > /Benno > tag/tagged seem to do the trick. Thanks a lot!
Re: match two conditions in relayd(8)
Joel Carnat(j...@carnat.net) on 2020.01.27 18:21:43 +0100: > Hi, > > I'm setting up an HTTP(S) Reverse Proxy with relayd(8). > > I have one listener with multiple FQDN allowed. > But I also have a common path that must be treated separately. > > As for now, I have: > http protocol "https" { > match request header "Host" value "one.domain.local" forward to > match request header "Host" value "two.domain.local" forward to > match request path "/common/*" forward to > } > relay "domain.local" { > listen on egress port 443 tls > protocol "https" > forward toport 80 check tcp > forward toport 80 check tcp > forward to port 80 check tcp > } > > With this configuration, both "/common/" are rendered by . > But I want > "one.domain.local/*" to be rendered by > "one.domain.local/common/" to be rendered by > "two.domain.local/*" to be rendered by > "two.domain.local/common/" to be rendered by > > Is there some way to achieve this? Try using "quick" or possibly "tag" and "tagged". /Benno
match two conditions in relayd(8)
Hi, I'm setting up an HTTP(S) Reverse Proxy with relayd(8). I have one listener with multiple FQDN allowed. But I also have a common path that must be treated separately. As for now, I have: http protocol "https" { match request header "Host" value "one.domain.local" forward to match request header "Host" value "two.domain.local" forward to match request path "/common/*" forward to } relay "domain.local" { listen on egress port 443 tls protocol "https" forward toport 80 check tcp forward toport 80 check tcp forward to port 80 check tcp } With this configuration, both "/common/" are rendered by . But I want "one.domain.local/*" to be rendered by "one.domain.local/common/" to be rendered by "two.domain.local/*" to be rendered by "two.domain.local/common/" to be rendered by Is there some way to achieve this? Thank you.