On Jan 23, 2008 9:07 PM, SimonS [EMAIL PROTECTED] wrote:
Hi,
I'm curious about the effect of the following code:
var d = new Deferred();
d.addCallback(function() { alert('f'); throw new
GenericError('foo'); });
d.addErrback(function() { alert('e'); });
d.addCallback(function() { alert('s'); });
d.callback('success');
The result I observe is that all three alerts fire, in the order 'f',
'e', 's'. This happens even though the first callback (f) throws an
exception. My question is why is the last alert fired?
The docs say that a callback that throws an exception will put the
deferred into an error state. Since the deferred transitions to an
error state, why does it continue calling the 'success' chain?
Is there a simple way to abort the callback chain from one of the
callbacks?
It continues calling the success chain because the errback doesn't
return an error or raise an exception.
-bob
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