Dear Vishal,
It won't. The reason is because you attach two TCP agents to two nodes.
Each node attach to different link. But the packets generated by both
TCP agents will go to the same place. When the packets reach the
destination, it would simply be destroy.
Of course, the contention would be at the link connecting into the
sink node. But that is the nature of packets sharing the node.
For more information about Links, Nodes, Agents and Applications, see the
following book from Springer:
T. Issaraiyakul and E. Hossain, Introduction to Network Simulator
NS2, Springer 2008.
http://www.springer.com/engineering/signals/book/978-0-387-71759-3
You may also find the following website useful:
http://www.ece.ubc.ca/~teerawat/NS2.htm
On 5/27/2009, Vishal Agarwal vis...@gmail.com wrote:
But would both the agents will fight for channel contention or packets from
both the sources will go regardless of transmission from other end..??
On Wed, May 27, 2009 at 9:56 PM, Teerawat Issariyakul
teera...@ece.ubc.cawrote:
Dear Vishal,
Only one sink is necessary. But you do need to connect both tcp agent to
the same sink by using $ns connect $tcp1 $sink and $ns connect
$tcp2 $sink. The result would be the same as when you have two sinks.
Best,
Teerawat
On 5/27/2009, Vishal Agarwal vis...@gmail.com wrote:
Hello users,
I am attaching 2 tcp agents at one source so do i need to attach 2 sinks
at
destination also or only 1 is sufficient. And when the agent tries to
access
the channel will there be any difference if there are two sinks rather
than
one?
Thanks,
--
Vishal Agarwal
--
Vishal Agarwal
