On 10/12/2014 7:08 PM, Xan wrote:
and
\item $\startdet[n=3]
\NC yz \NC \frac{1}{x} \NC x \NR
\NC zx \NC \frac{1}{y} \NC y \NR
\NC xy \NC \frac{1}{z} \NC z \NR
\stopdet$
puts x over 1 in the second row
in a next beta ...
Another bug.
@Hans: At least for user view point it's a bug.
@Thangalin: thanks. A bigskip will solve me problems, but thanks.
\definemathmatrix[det]
[left={\left\lvert\,},right={\,\right\rvert}]
\starttext
Calculeu els determinants següents:
\startitemize[a,columns]
\item $\startdet[n=4]
and
\item $\startdet[n=3]
\NC yz \NC \frac{1}{x} \NC x \NR
\NC zx \NC \frac{1}{y} \NC y \NR
\NC xy \NC \frac{1}{z} \NC z \NR
\stopdet$
puts x over 1 in the second row
___
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On 10/7/2014 8:06 PM, Thangalin wrote:
Looks like a bug; adding blank rows works around the problem (but
looks terrible):
\definemathmatrix[pmatrix] [left={\left(\,},right={\,\right)}]
\starttext
Digueu quines de les matrius següents són regulars. Quan ho siguin,
trobeu la inversa
On Thu, 9 Oct 2014, Hans Hagen wrote:
On 10/7/2014 8:06 PM, Thangalin wrote:
Looks like a bug; adding blank rows works around the problem (but
looks terrible):
\definemathmatrix[pmatrix] [left={\left(\,},right={\,\right)}]
\starttext
Digueu quines de les matrius següents són regulars. Quan
Hi Xan,
It's not exactly what you want, but maybe it'll give you some other ideas:
\definemathmatrix[pmatrix][
left={\left(\,},
right={\,\right)},
]
\definenumber[pmatrix]
\resetnumber[pmatrix]
\define\nextmatrix{
\incrementnumber[pmatrix]
\getnumber[pmatrix].
}
\define[2]\pmatrices{
Looks like a bug; adding blank rows works around the problem (but
looks terrible):
\definemathmatrix[pmatrix] [left={\left(\,},right={\,\right)}]
\starttext
Digueu quines de les matrius següents són regulars. Quan ho siguin,
trobeu la inversa
\startitemize[a,columns,four]
\item
