Re: [NTG-context] content of xml node (element) in lua

2020-10-17 Thread Jano Kula 
On Sat, 17 Oct 2020 at 12:02, Hans Hagen  wrote:

> On 10/17/2020 12:16 AM, mf wrote:
> > (sorry, I sent it before refining it)
> >
> > Il 16/10/20 20:57, Jano Kula ha scritto:
> >> Hello!
> >>
> >> Processing XML I want to manipulate content of XML elements inside Lua.
> >>
> >> I can define the Lua function xml.functions.name
> >> (t), where processing happens, and use the
> >> command \xmlfunction{#1}{name} to pass the current node #1from ctx to
> >> lua as described in the xml-mkiv.pdf manual. To access the element
> >> content xml.text(t,"/element") Lua function is used.
> >>
> >> However, using the same function xml.text("#1",/element) directly
> >> inside Lua doesn't work for me. Node #1 is available, but not the
> >> content of /element.
> >
> > In your lua fragment, node #1 is available as "xml:name::4" or
> > "xml:name::6", but not as a lua table.
>
> when you're at the lua end you can use lxml.getid to access that node,
> assuming that you somehow pass #1 (being a string)
>
>
> > When node #1 is passed to a \xmlfunction, the function gets a lua table
> > as argument.
> >
> > To write direct lua code instead of a xmlfunction you'd need a function
> > to transform those "xml:name::..." into the lua tables representing the
> > xml elements in the xml tree.
> >
> > Which is what \xmlfunction does, so I wouldn't expect any performance
> gain.
>
> actually one has the same function at the lua end, so once you passed
> the node id you can use
>
> xml.first(lxml.getid("xml:name::4"),"foo/bar")
>
> and alike (the lxml.* function pipe back to tex)
>
> Hans
>
>
Hello,

just finished the exploration of the \xmlfunction definition based on
Massi's advice when Hans' answer arrived. This is the working code:

\startluacode
local node = "#1"
local content = xml.text(*lxml.getid(*"#1"*)*,"/color")
context.par() context("node: ") context(node)
context.par() context("lua: ")  context(content)
\stopluacode

Added a note to XML Lua  wiki page.
I do understand the code better now, thank you.

Jano
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Re: [NTG-context] content of xml node (element) in lua

2020-10-17 Thread Hans Hagen 

On 10/17/2020 12:16 AM, mf wrote:

(sorry, I sent it before refining it)

Il 16/10/20 20:57, Jano Kula ha scritto:

Hello!

Processing XML I want to manipulate content of XML elements inside Lua.

I can define the Lua function xml.functions.name 
(t), where processing happens, and use the 
command \xmlfunction{#1}{name} to pass the current node #1from ctx to 
lua as described in the xml-mkiv.pdf manual. To access the element 
content xml.text(t,"/element") Lua function is used.


However, using the same function xml.text("#1",/element) directly 
inside Lua doesn't work for me. Node #1 is available, but not the 
content of /element.


In your lua fragment, node #1 is available as "xml:name::4" or 
"xml:name::6", but not as a lua table.


when you're at the lua end you can use lxml.getid to access that node, 
assuming that you somehow pass #1 (being a string)



When node #1 is passed to a \xmlfunction, the function gets a lua table 
as argument.


To write direct lua code instead of a xmlfunction you'd need a function 
to transform those "xml:name::..." into the lua tables representing the 
xml elements in the xml tree.


Which is what \xmlfunction does, so I wouldn't expect any performance gain.


actually one has the same function at the lua end, so once you passed 
the node id you can use


xml.first(lxml.getid("xml:name::4"),"foo/bar")

and alike (the lxml.* function pipe back to tex)

Hans

-
  Hans Hagen | PRAGMA ADE
  Ridderstraat 27 | 8061 GH Hasselt | The Netherlands
   tel: 038 477 53 69 | www.pragma-ade.nl | www.pragma-pod.nl
-
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Re: [NTG-context] content of xml node (element) in lua

2020-10-16 Thread mf 

(sorry, I sent it before refining it)

Il 16/10/20 20:57, Jano Kula ha scritto:

Hello!

Processing XML I want to manipulate content of XML elements inside Lua.

I can define the Lua function xml.functions.name 
(t), where processing happens, and use the 
command \xmlfunction{#1}{name} to pass the current node #1from ctx to 
lua as described in the xml-mkiv.pdf manual. To access the element 
content xml.text(t,"/element") Lua function is used.


However, using the same function xml.text("#1",/element) directly inside 
Lua doesn't work for me. Node #1 is available, but not the content of 
/element.


In your lua fragment, node #1 is available as "xml:name::4" or 
"xml:name::6", but not as a lua table.


When node #1 is passed to a \xmlfunction, the function gets a lua table 
as argument.


To write direct lua code instead of a xmlfunction you'd need a function 
to transform those "xml:name::..." into the lua tables representing the 
xml elements in the xml tree.


Which is what \xmlfunction does, so I wouldn't expect any performance gain.

Massi
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[NTG-context] content of xml node (element) in lua

2020-10-16 Thread Jano Kula 
Hello!

Processing XML I want to manipulate content of XML elements inside Lua.

I can define the Lua function xml.functions.name(t), where processing
happens, and use the command \xmlfunction{#1}{name} to pass the current
node #1 from ctx to lua as described in the xml-mkiv.pdf manual. To access
the element content xml.text(t,"/element") Lua function is used.

However, using the same function xml.text("#1",/element) directly inside
Lua doesn't work for me. Node #1 is available, but not the content of
/element.

\startluacode
local node = "#1"
local content = xml.text("#1","/color")
context.par() context("node: ") context(node)
context.par() context("lua: ")  context(content)
\stopluacode

MWE (mkiv, beta) attached.

I haven't found an example, so is it even possible? If so, which way is
more efficient?

Thanks,
Jano


xmlluanode.tex
Description: Binary data
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