OT: How do you make a dmg ? Is there a (simple) command line tool for this ?
Thanks, Sebastian Haase
On Wed, Apr 23, 2008 at 9:46 PM, Christopher Barker
[EMAIL PROTECTED] wrote:
Christopher Burns wrote:
I've built a Universal Mac binary for numpy 1.1.0. http://1.1.0. If
Mac people
On Fri, 2008-04-25 at 11:17 +0200, Sebastian Haase wrote:
OT: How do you make a dmg ? Is there a (simple) command line tool for this ?
.dmg is just an iso 9660 file (e.g. a CD fs), which is recognized by
Mac OS X as such. It really is not different than mounting an iso on any
unix (you can
2008/4/25, tournesol [EMAIL PROTECTED]:
Hi All.
I just want to conver Fortran 77 source to
Python.
Here is my F77 source.
DIMENSION A(25,60,13),B(25,60,13)
open(15,file='data.dat')
DO 60 K=1,2
READ(15,1602) ((B(I,J),J=1,60),I=1,25)
60 CONTINUE
Hi All.
I just want to conver Fortran 77 source to
Python.
Here is my F77 source.
DIMENSION A(25,60,13),B(25,60,13)
open(15,file='data.dat')
DO 60 K=1,2
READ(15,1602) ((B(I,J),J=1,60),I=1,25)
60 CONTINUE
1602 FORMAT(15I4)
DO 63 K=1,10
DO
why not using something like numpy.repeat?
In [18]: B = numpy.random.rand(4,3)
In [19]: A = numpy.repeat(B[:,:,numpy.newaxis],2,axis=2)
In [20]: B.shape
Out[20]: (4, 3)
In [21]: A.shape
Out[21]: (4, 3, 2)
In [22]: numpy.all(A[:,:,0] == A[:,:,1])
Out[22]: True
hth,
L.
On Fri, Apr 25, 2008 at
On Thu, 24 Apr 2008, Keith Goodman wrote:
A Gaussian never reaches zero.
Keith,
I know, and that's why I need to find another way to draw these curves.
While mathematically any 'y' value 0.2 (the default) is equivalent to
zero, the curves must reach zero in the figures.
Briefly, this
Hi all,
Actually -- it seems like view() doesn't work with strided arrays at
all. (?)
In : a = numpy.ones((4,32), dtype=numpy.uint8)
In : a.view(numpy.uint16).shape
Out: (4, 16)
In : a[:,:16].view(numpy.uint16)
ValueError: new type not compatible with array.
I think this might be a
2008/4/25 Alan G Isaac [EMAIL PROTECTED]:
2008/4/25 Alan G Isaac :
So, if X is 2 by 2, then X[0] will be a row vector.
But if X is 1 by 2, then X[0] will be a scalar?
Ouch!
Bye bye generic code.
On Fri, 25 Apr 2008, Stefan van der Walt apparently wrote:
Yup. That's the
Other suggestions for bounded bell-shaped functions that reach zero on a
finite interval:
- Beta distribution: http://en.wikipedia.org/wiki/Beta_distribution
- Cubic B-splines:http://www.ibiblio.org/e-notes/Splines/Basis.htm
2008/4/25 Bruce Southey [EMAIL PROTECTED]:
Rich Shepard wrote:
On Fri, 25 Apr 2008, David Huard wrote:
Other suggestions for bounded bell-shaped functions that reach zero on a
finite interval:
- Beta distribution: http://en.wikipedia.org/wiki/Beta_distribution
- Cubic B-splines:http://www.ibiblio.org/e-notes/Splines/Basis.htm
Thanks, David. I'm
I think the use of the term 'vector' in this
thread is becoming a bit confusing.
An M by N matrix is a vector. (I.e., it is
an element of a vector space.)
Many people use the terms row vector and column
vector to refer to special matrices. What is
special is *not* that they are vectors (since
On Fri, 25 Apr 2008, Stéfan van der Walt apparently wrote:
In current SVN:
In [6]: x[0]
Out[6]: matrix([[0, 1, 2]])
I must have misunderstood:
I thought the agreement was to
provisionally return a 1d array for x[0],
while we hashed through the other proposals.
Cheers,
Alan
Hello all,
Attached is code (plus tests) for allocating aligned arrays -- I think
this addresses all the requests in this thread, with regard to
allowing for different kinds of alignment. Thanks Robert and Anne for
your help and suggestions. Hopefully this will be useful.
The core is a
2008/4/25 Alan G Isaac [EMAIL PROTECTED]:
I must have misunderstood:
I thought the agreement was to
provisionally return a 1d array for x[0],
while we hashed through the other proposals.
The agreement was:
a) That x[0][0] should be equal to x[0,0] and
b) That x[0,:] should be equal to
On 25/04/2008, Stéfan van der Walt [EMAIL PROTECTED] wrote:
2008/4/25 Alan G Isaac [EMAIL PROTECTED]:
I must have misunderstood:
I thought the agreement was to
provisionally return a 1d array for x[0],
while we hashed through the other proposals.
The agreement was:
a) That
On Fri, Apr 25, 2008 at 10:04 AM, Alan G Isaac [EMAIL PROTECTED] wrote:
I think the use of the term 'vector' in this
thread is becoming a bit confusing.
An M by N matrix is a vector. (I.e., it is
an element of a vector space.)
Sure, but the important thing is the multiplication. If it
2008/4/25 Alan G Isaac [EMAIL PROTECTED]:
I must have misunderstood:
I thought the agreement was to
provisionally return a 1d array for x[0],
while we hashed through the other proposals.
On Fri, 25 Apr 2008, Stéfan van der Walt apparently wrote:
The agreement was:
a) That x[0][0]
On 24/04/2008, Rich Shepard [EMAIL PROTECTED] wrote:
Thanks to several of you I produced test code using the normal density
function, and it does not do what we need. Neither does the Gaussian
function using fwhm that I've tried. The latter comes closer, but the ends
do not reach y=0
Anne Archibald wrote:
Yes, well, it really looks unlikely we will be able to agree on what
the correct solution is before 1.1, so I would like to have something
non-broken for that release.
+1 on that!
___
Numpy-discussion mailing list
Robert,
Can we check this in somewhere under numpy.core? It seems very useful.
Stéfan
2008/4/25 Zachary Pincus [EMAIL PROTECTED]:
Hello all,
Attached is code (plus tests) for allocating aligned arrays -- I think this
addresses all the requests in this thread, with regard to allowing for
I was hoping to get NumPy 1.1 tagged today, but it seems very unlikely
at this point. Unfortunately, I haven't followed the matrix
discussion as closely as I would like, so I can't tell if there is
anything so uncontroversial that it would make sense to change for the
1.1.0 release. If there is
On Fri, 25 Apr 2008, Jarrod Millman apparently wrote:
I would like, so I can't tell if there is anything so
uncontroversial that it would make sense to change for the
1.1.0 release.
I think it is clear from reactions that the revision r5072
to matrix behavior should NOT go into any release.
2008/4/25 Alan G Isaac [EMAIL PROTECTED]:
1. This is **not** what I understood as the agreement
(and I think the current solution is bad).
Reverted in r5084.
Cheers
Stéfan
___
Numpy-discussion mailing list
Numpy-discussion@scipy.org
I had b = Ax working where A is sparse using scipy.sparse.
I'm now using the latest svn and b = Ax is not working and returns garbage
results.
Nothing has changed except the latest svn. Any thoughts?
Dinesh
___
Numpy-discussion mailing list
On Fri, 25 Apr 2008, Stéfan van der Walt wrote:
workaround would break x[0] == x[0,:]
But there is not universal agreement that x[0] == x[0,:] is
desirable. In contrast, there *is* universal agreement that
x[0][0]==x[0,0] is desirable. Or so I've understood the
discussion.
As you know, my
2008/4/25 Stéfan van der Walt [EMAIL PROTECTED]:
I'm starting to see Chris Barker's point; allowing x[0] is causing
more problems than it is worth. On the other hand, how would you
index into a vector (as in
http://en.wikipedia.org/wiki/Vector_(spatial)) without it?
To answer my own
2008/4/24 Jarrod Millman [EMAIL PROTECTED]:
On Thu, Apr 24, 2008 at 1:22 PM, David Huard wrote:
Assuming we want the next version to : ignore values outside of range
and
accept and return the bin edges instead of the left edges, here could be
the
new signature for 1.1:
h, edges =
2008/4/25 David Huard [EMAIL PROTECTED]:
2008/4/24 Jarrod Millman [EMAIL PROTECTED]:
On Thu, Apr 24, 2008 at 1:22 PM, David Huard wrote:
Assuming we want the next version to : ignore values outside of range
and
accept and return the bin edges instead of the left edges, here could
On Fri, 25 Apr 2008, Dinesh B Vadhia apparently wrote:
where A is sparse using scipy.sparse. ... I'm now using
the latest svn and b = Ax
1. Please post a small example.
2. Do you have the *very* latest SVN (post r5084)?
Cheers,
Alan Isaac
___
On Fri, 25 Apr 2008, Stéfan van der Walt apparently wrote:
Reverted in r5084.
Thank you.
I think we have discovered that there is a basic conflict
between two behaviors:
x[0] == x[0,:]
vs.
x[0][0] == x[0,0]
To my recollection, everyone has agree that the second
On Fri, 25 Apr 2008, Robert Kern wrote:
In that case, you need to search the literature of your field for precise
details on how to construct the curve that you want.
Robert,
Considering how few of us work in this subject area there's not much in
the way of resources.
Regardless, for
On Fri, Apr 25, 2008 at 12:02 PM, Alan G Isaac [EMAIL PROTECTED] wrote:
On Fri, 25 Apr 2008, Stéfan van der Walt apparently wrote:
Reverted in r5084.
Thank you.
I think we have discovered that there is a basic conflict
between two behaviors:
x[0] == x[0,:]
vs.
On 25/04/2008, Charles R Harris [EMAIL PROTECTED] wrote:
On Fri, Apr 25, 2008 at 12:02 PM, Alan G Isaac [EMAIL PROTECTED] wrote:
I think we have discovered that there is a basic conflict
between two behaviors:
x[0] == x[0,:]
vs.
x[0][0] == x[0,0]
To my
On Fri, 25 Apr 2008, Bruce Southey wrote:
Just use a truncated distribution as these are well known:
http://en.wikipedia.org/wiki/Truncated_distribution
http://en.wikipedia.org/wiki/Truncated_normal_distribution
Bruce,
I considered the truncated normal distribution, but having the tails
On Fri, 25 Apr 2008, Charles R Harris wrote:
You can use something like f(x) = (1-x**2)**2 , which has inflection
points and vanishes at +/- 1. Any of the B-splines will also do the trick.
Chuck,
Thank you. I need to make some time to understand the B-splines to use
them appropriately.
Alan G Isaac wrote:
Please return 1d arrays in response to scalar
indexing as the provisional arrangement.
+1 (for the provisional solution)
This has clarified it a bit for me. The current situation allows one to
create row vectors and column vectors by generating matrices (in
various ways)
David Cournapeau wrote:
To get to your point: hdiutil is the command you are looking for.
yup. Here's an example:
hdiutil create -srcfolder YourDir -volname A Name -ov Something.dmg
It will build a disk image from the directory: YourDir
-Chris
--
Christopher Barker, Ph.D.
Oceanographer
On Fri, 25 Apr 2008, Christopher Barker apparently wrote:
I think a Vector object would allow both of:
M[i,j] == M[i][j]
and
M[i] == M[i,:]
The problem is that it would be a crime to give up
the natural production of submatrices. The NATURAL RULE
is: to get a submatrix, use nonscalar
Thanks Chuck,
I didn't know there were other tests for histogram outside of
test_function_base.
The error is now raised only if bins are passed explicitly and normed=True.
David
2008/4/25 Charles R Harris [EMAIL PROTECTED]:
On Fri, Apr 25, 2008 at 12:55 PM, Jarrod Millman [EMAIL PROTECTED]
On Fri, Apr 25, 2008 at 2:57 PM, Alan G Isaac [EMAIL PROTECTED] wrote:
On Fri, 25 Apr 2008, Christopher Barker apparently wrote:
I think a Vector object would allow both of:
M[i,j] == M[i][j]
and
M[i] == M[i,:]
The problem is that it would be a crime to give up
the natural production
On Fri, Apr 25, 2008 at 2:46 PM, Dinesh B Vadhia [EMAIL PROTECTED]
wrote:
Alan
I posted this on the scipy list:
I have a working program with b=Ax, where A is a large sparse matrix.
However, I need the int8 support in the sparse library to utilize much
larger matrices. I managed to get
On Fri, 25 Apr 2008, Christopher Barker apparently wrote:
I think a Vector object would allow both of:
M[i,j] == M[i][j]
and
M[i] == M[i,:]
On Fri, Apr 25, 2008 at 2:57 PM, Alan G Isaac
[EMAIL PROTECTED] wrote:
The problem is that it would be a crime to give up
the natural
1. Please post a small example. 2. Do you have the very
latest SVN (post r5084)?
On Fri, 25 Apr 2008, Dinesh B Vadhia apparently wrote:
I have a working program with b=Ax, where A is a large
sparse matrix. However, I need the int8 support in the
sparse library to utilize much larger
On Fri, Apr 25, 2008 at 01:41:14PM -0500, Robert Kern wrote:
As Anne notes, bell-shaped curve, while seemingly generic, usually
specifies Gaussians, and Gaussians do not have the properties you need.
There are any number of curves which we could (and have) suggested as
looking bell-shaped,
On Fri, Apr 25, 2008 at 1:25 PM, Rich Shepard [EMAIL PROTECTED]
wrote:
On Fri, 25 Apr 2008, Charles R Harris wrote:
You can use something like f(x) = (1-x**2)**2 , which has inflection
points and vanishes at +/- 1. Any of the B-splines will also do the
trick.
Chuck,
Thank you. I need
Another suggestion from machine learning stuff to throw into the mix:
A soft step function that we use often is y = e^(ax) / ( 1 + e^(ax)).
It has the nice property that the result y is always in (0,1). If you
invert this, you get x = -(1/a)*log(y - 1); this maps (0,1) to the
whole real line,
OK, we are not converging in time for the release.
So can we at least raise a TypeError on scalar
indexing of matrices, so that we remain free to choose
the ultimate behavior?
Those who have spoke up have generally favored
letting x[0] return a 1d array, if I count correctly.
And I think that is
Hi All.
Is there a easy way to insert 1D(j) array into another 2D array(B:jxk)
and conver B to B:ixjxk ?
ex:)
from numpy import *
a=arange(4)
a
array([0, 1, 2, 3])
b=arange(9)
b.shape=3,3
b
array([[0, 1, 2],
[3, 4, 5],
[6, 7, 8]])
I just wanna insert A into B
B:1x3x3,
[[[ 0, 1, 2, 3],
[
On Fri, Apr 25, 2008 at 6:38 PM, Alan G Isaac [EMAIL PROTECTED] wrote:
OK, we are not converging in time for the release.
So can we at least raise a TypeError on scalar
indexing of matrices, so that we remain free to choose
the ultimate behavior?
Those who have spoke up have generally
Alan G Isaac wrote:
OK, we are not converging in time for the release.
So can we at least raise a TypeError on scalar
indexing of matrices, so that we remain free to choose
the ultimate behavior?
I think this is wise for the time being.
At this point, I'm leaning in the direction of the
On Sat, Apr 26, 2008 at 10:27 AM, Charles R Harris
[EMAIL PROTECTED] wrote:
On Fri, Apr 25, 2008 at 6:38 PM, Alan G Isaac [EMAIL PROTECTED] wrote:
OK, we are not converging in time for the release.
So can we at least raise a TypeError on scalar
indexing of matrices, so that we remain free
There is also a gui, Disk Utility.app which is what I used for the
installer.
Chris
On Fri, Apr 25, 2008 at 2:17 AM, Sebastian Haase [EMAIL PROTECTED] wrote:
OT: How do you make a dmg ? Is there a (simple) command line tool for this
?
Thanks, Sebastian Haase
On Fri, Apr 25, 2008 at 1:35 PM,
Hi,
In the upcoming release of numpy. numpy.core.ma ceases to exist. One
must use numpy.ma (for the new interface) or numpy.oldnumeric.ma (for
the old interface). This has the unfortunate effect of breaking
matplotlib(which does from numpy.core.ma import *) - I cannot even
import pylab with a
On Fri, Apr 25, 2008 at 11:19 PM, Anne Archibald [EMAIL PROTECTED]
wrote:
Hi,
In the upcoming release of numpy. numpy.core.ma ceases to exist. One
must use numpy.ma (for the new interface) or numpy.oldnumeric.ma (for
the old interface). This has the unfortunate effect of breaking
54 matches
Mail list logo
