Can I get rid of the loop in this example? And what is the fastest way
to get v in the example?
ar = array([1,2,3])
for a in ar:
for b in ar:
v = a**2+b**2
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On Sat, Nov 7, 2009 at 1:51 PM, Stas K stanc...@gmail.com wrote:
Can I get rid of the loop in this example? And what is the fastest way
to get v in the example?
ar = array([1,2,3])
for a in ar:
for b in ar:
v = a**2+b**2
ar[:,None]**2 + ar**2
array([[ 2, 5, 10],
[ 5, 8,
On 11/7/2009 1:51 PM, Stas K wrote:
Can I get rid of the loop in this example? And what is the fastest way
to get v in the example?
ar = array([1,2,3])
for a in ar:
for b in ar:
v = a**2+b**2
a2 = a*a
np.add.outer(a2,a2)
array([[ 2, 5, 10],
[ 5, 8, 13],
Thank you, Josef
It is exactly what I want:
ar[:,None]**2 + ar**2
Do you know something about performance of this? In my real program
ar have ~ 10k elements, and expression for v more complicated (it has
some trigonometric functions)
On 07.11.2009, at 21:57, josef.p...@gmail.com
2009/11/7 Stas K stanc...@gmail.com:
Thank you, Josef
It is exactly what I want:
ar[:,None]**2 + ar**2
Do you know something about performance of this? In my real program ar have
~ 10k elements, and expression for v more complicated (it has some
trigonometric functions)
The construction
