I found that the NumPy regression test error for MKL that was reported a
while ago happens with MKL 10.0.3.020, but not with MKL 10.0.1.014
(everything else equal)
Here is a dump of the regression test on my machine with 10.0.3.020
import numpy
numpy.test()
Numpy is installed in
On Fri, Jul 11, 2008 at 1:14 PM, Francesc Alted [EMAIL PROTECTED] wrote:
So, it seems that setters/getters for matplotlib datetime could be
supported, maybe at the risk of loosing precision. We should study
this more carefully, but I suppose that if there is interest enough
that could be
i would like to load my data without knowing the length, i have explicitly
stated the rows
data = loadtxt('18B180.dat', skiprows = 1, usecols =
1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30,31,32,33,34,35,36,37,38,39,40,41,42,43,44,45))
and would like to use
On Sat, Jul 12, 2008 at 3:56 PM, Jan Tore Korneliussen
[EMAIL PROTECTED] wrote:
I found that the NumPy regression test error for MKL that was reported a
while ago happens with MKL 10.0.3.020, but not with MKL 10.0.1.014
(everything else equal)
It is more likely a bug in the MKL. Please update
why not using:
data = loadtxt('18B180.dat', skiprows = 1, usecols = xrange(1,46))
obviously, you need to know how many columns you have.
hth,
L.
On Sat, Jul 12, 2008 at 10:07:06AM -0400, Bryan Fodness wrote:
i would like to load my data without knowing the length, i have explicitly
stated the
Yes, I downgraded from 10.0.3.020 to 10.0.1.014, and then the test
worked.
Since 10.0.3.020 is the newest version, perhaps it should be reported to
Intel to prevent it from appearing in coming versions? (If it is
actually a bug in MKL)
On Sat, 2008-07-12 at 16:31 +0200, David Cournapeau wrote:
PyArray_DescrFromType can return NULL
Yah, you noticed ;)
Yet it is unchecked in several places:
Pity about that. Easy enough to fix though -- just don't lose track of
ref counts. In fact, I've already submitted a patch to this function (but
not addressing this issue).
static int
The function trapz accepts x axis vector only for axis=-1. Here is my
modification (correction?) to let it accept a vector x for integration along
any axis:
def trapz(y, x=None, dx=1.0, axis=-1):
Integrate y(x) using samples along the given axis and the composite
trapezoidal rule.
Nadav Horesh wrote:
The function trapz accepts x axis vector only for axis=-1. Here is my
modification (correction?) to let it accept a vector x for integration along
any axis:
def trapz(y, x=None, dx=1.0, axis=-1):
Integrate y(x) using samples along the given axis and the
Greetings,
The merchant account processor that we use for the SciPy Conference
online registration has been experiencing some inexplicable problems
authorizing some registrations. Apologies to those who have struggled
to register and have not been successful. Because of the problems,
Christopher Barker Chris.Barker at noaa.gov writes:
I'm also imaging some extra utility functions/method that would be nice:
aDateTimeArray.hours(dtype=float)
to convert to hours (and days, and seconds, etc). And maybe some that
would create a DateTimeArray from various time units.
The
On Sat, Jul 12, 2008 at 8:42 AM, Michael Abbott [EMAIL PROTECTED]
wrote:
PyArray_DescrFromType can return NULL
Yah, you noticed ;)
Yet it is unchecked in several places:
Pity about that. Easy enough to fix though -- just don't lose track of
ref counts. In fact, I've already submitted a
On Sat, Jul 12, 2008 at 10:13 AM, Charles R Harris
[EMAIL PROTECTED] wrote:
On Sat, Jul 12, 2008 at 8:42 AM, Michael Abbott [EMAIL PROTECTED]
wrote:
PyArray_DescrFromType can return NULL
Yah, you noticed ;)
Yet it is unchecked in several places:
Pity about that. Easy enough to fix
Here is what I get with the orriginal trapz function:
IDLE 1.2.2
import numpy as np
np.__version__
'1.1.0'
y = np.arange(24).reshape(6,4)
x = np.arange(6)
np.trapz(y, x, axis=0)
Traceback (most recent call last):
File pyshell#4, line 1, in module
np.trapz(y, x, axis=0)
File
Nadav Horesh wrote:
Here is what I get with the orriginal trapz function:
IDLE 1.2.2
import numpy as np
np.__version__
'1.1.0'
y = np.arange(24).reshape(6,4)
x = np.arange(6)
np.trapz(y, x, axis=0)
Traceback (most recent call last):
File pyshell#4, line 1, in module
On Sat, Jul 12, 2008 at 13:11, Charles R Harris
[EMAIL PROTECTED] wrote:
Numpy uses a mix of snprintf and PyOS_snprintf. The Python version is there
because snprintf wasn't part of the standard until C99. So either we should
stick to the python version or make the decision that we only support
On Fri, Jul 11, 2008 at 11:04 AM, Lou Pecora [EMAIL PROTECTED] wrote:
If your positions are static (I'm not clear on that from your message),
then you might want to check the technique of slice searching. It only
requires one sort of the data for each dimension initially, then uses a
simple,
I am aware that the error is related to the broadcasting, and that it can be
solved by matching the shape of x to that of y --- this is how I solved it in
the first place. I was thinking that the function promises to integrate over
an array given a x vector and the axis, so let obscure the
Hi All,
This is apropos ticket #805 http://scipy.org/scipy/numpy/ticket/805. The
reporter wants to change the signature of the functions PyArray_FromDims and
PyArray_FromDimsAndDataAndDesc, which we really can't do at this point
because they are part of the Numpy API. The problem can be seen in
On Sat, Jul 12, 2008 at 10:30 PM, Nadav Horesh [EMAIL PROTECTED]
wrote:
I am aware that the error is related to the broadcasting, and that it can
be solved by matching the shape of x to that of y --- this is how I solved
it in the first place. I was thinking that the function promises to
20 matches
Mail list logo
