A Thursday 01 November 2007, Timothy Hochberg escrigué:
On Nov 1, 2007 7:14 AM, David M. Cooke [EMAIL PROTECTED]
Another issue is that numexpr is still in the scipy sandbox, so
only those who enable it will use it (or use it through PyTables).
One problem with moving it out is that Tim
A Thursday 01 November 2007, David M. Cooke escrigué:
At any rate, we would be glad if you would like to integrate our
patches
in the main numexpr, as there is not much sense to have different
implementations of numexpr (most specially when it seems that there
are
not much users out
A Wednesday 31 October 2007, Timothy Hochberg escrigué:
On Oct 31, 2007 3:18 AM, Francesc Altet [EMAIL PROTECTED] wrote:
[SNIP]
Incidentally, all the improvements of the PyTables flavor of
numexpr have been reported to the original authors, but, for the
sake of keeping numexpr simple,
On Nov 1, 2007, at 08:56 , Francesc Altet wrote:
A Wednesday 31 October 2007, Timothy Hochberg escrigué:
On Oct 31, 2007 3:18 AM, Francesc Altet [EMAIL PROTECTED] wrote:
[SNIP]
Incidentally, all the improvements of the PyTables flavor of
numexpr have been reported to the original authors,
On Oct 31, 2007 3:18 AM, Francesc Altet [EMAIL PROTECTED] wrote:
[SNIP]
Incidentally, all the improvements of the PyTables flavor of numexpr
have been reported to the original authors, but, for the sake of
keeping numexpr simple, they decided to implement only some of them.
However, people
Timothy Hochberg wrote:
On 10/29/07, *Christopher Barker* [EMAIL PROTECTED]
mailto:[EMAIL PROTECTED] wrote:
(incidently, the kind of things 'we' are doing seem like the most
simple things to JIT).
Wouldn't a numpy-aware psyco be cool then?
Oh well, I'm not going to
On Thu, Oct 25, 2007 at 04:16:06PM -0700, Mathew Yeates wrote:
Anybody know of any tricks for handling something like
z[0]=1.0
for i in range(100):
out[i]=func1(z[i])
z[i+1]=func2(out[i])
Something like:
z[0] = 1.
out = func1(z)
z[1:] = func2(out[:-1])
HTH,
Gaël
Gael Varoquaux wrote:
On Thu, Oct 25, 2007 at 04:16:06PM -0700, Mathew Yeates wrote:
Anybody know of any tricks for handling something like
z[0]=1.0
for i in range(100):
out[i]=func1(z[i])
z[i+1]=func2(out[i])
Something like:
z[0] = 1.
out = func1(z)
z[1:] = func2(out[:-1])
Gael Varoquaux wrote:
On Thu, Oct 25, 2007 at 04:16:06PM -0700, Mathew Yeates wrote:
Anybody know of any tricks for handling something like
z[0]=1.0
for i in range(100):
out[i]=func1(z[i])
z[i+1]=func2(out[i])
Something like:
z[0] = 1.
out = func1(z)
z[1:] = func2(out[:-1])
On Fri, Oct 26, 2007 at 01:56:26AM -0500, Robert Kern wrote:
Gael Varoquaux wrote:
On Thu, Oct 25, 2007 at 04:16:06PM -0700, Mathew Yeates wrote:
Anybody know of any tricks for handling something like
z[0]=1.0
for i in range(100):
out[i]=func1(z[i])
z[i+1]=func2(out[i])
On 10/26/07, David Cournapeau [EMAIL PROTECTED] wrote:
P.S: IMHO, this is one of the main limitation of numpy (or any language
using arrays for speed; and this is really difficult to optimize: you
need compilation, JIT or similar to solve those efficiently).
This is where the scipy - sandbox
On 10/26/07, Sebastian Haase [EMAIL PROTECTED] wrote:
On 10/26/07, David Cournapeau [EMAIL PROTECTED] wrote:
P.S: IMHO, this is one of the main limitation of numpy (or any language
using arrays for speed; and this is really difficult to optimize: you
need compilation, JIT or similar to
Anybody know of any tricks for handling something like
z[0]=1.0
for i in range(100):
out[i]=func1(z[i])
z[i+1]=func2(out[i])
??
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