Re: Trying to understand bn_div_words()

levitte bn_div_words(0xC383,0x838B4B53,0x8000) Hmm, a call like that gave me an aruthmetic error on Linux... According to bc 0xC383838B4B53 / 0x8000 = 0x18707. The result is 33 bits or in other words the operation *overflows*. According to IA-32 manual overflow is

Re: Trying to understand bn_div_words()

In message [EMAIL PROTECTED] on Mon, 02 Dec 2002 10:51:30 +0100, Andy Polyakov [EMAIL PROTECTED] said: appro levitte bn_div_words(0xC383,0x838B4B53,0x8000) appro appro Hmm, a call like that gave me an aruthmetic error on Linux... appro appro According to bc 0xC383838B4B53 /

Trying to understand bn_div_words()

I don't understand what BN_div() expects from bn_div_words(). I see calls like this: bn_div_words(0xC383,0x838B4B53,0x8000) and I wonder what the hell is expected to come out of that. The result of dividing 0xC383838B4B53 with 0x8000 is 0x18707, which can't be correctly

Re: Trying to understand bn_div_words()

In message [EMAIL PROTECTED] on Mon, 02 Dec 2002 01:19:21 +0100 (CET), Richard Levitte - VMS Whacker [EMAIL PROTECTED] said: levitte bn_div_words(0xC383,0x838B4B53,0x8000) Hmm, a call like that gave me an aruthmetic error on Linux... -- Richard Levitte \ Spannvägen 38, II \ [EMAIL