: divide with decode
Now why didn't I think of that? :)
Jared
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Author: Jared Still
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Srinivas:
What you're looking to do is find the value of physical reads/db block gets.
So, you want the value1/value2 where value1 is 'physical reads' and value2
is 'db block gets'. So, what you need to do is put the literals 'physical
reads' and 'db block gets' in the where clause somehow
recipients of list ORACLE-L
Subject: divide with decode
hi lists
can anybody help me for the flwng :
i need to do calculation dividing phy reads value/db block gets
i am following the principle
select decode(name,'physical reads',value)/decode(name,'db block
gets',value)
from v$sysstat
where
hi lists
can anybody help me for the flwng :
i need to do calculation dividing phy reads value/db block gets
i am following the principle
select decode(name,'physical reads',value)/decode(name,'db block
gets',value)
from v$sysstat
where name in ('db block gets','physical reads')
just this
Srinivas,
That's because the values are in 2 different rows.
Notice that your query returns 2 rows. One row
will have the 'db block gets', the other will have
the 'physical reads'.
This will do it:
select a.value/b.value
from v$sysstat a, v$sysstat b
where a.name = 'physical reads'
and
